I got some of these ULN2803 ICs but the *fake* ones or which is called as Potato ICs in here :) they are not capable of sinking all the current down (like 20-30mA @ 5V) while sourcing the base with furious 5V GPIO. That was a total surprise. I have ordered it as smd, from some another source and that one works like it is expected. Characteristics are just like a single dalington npn for a pulse like 10us @ 5V.
Today I would always use specialized stepper-motor driver-ICs. They give you much more functionality in one chip that trying to build a driver out of standard ICs.
@@KainkaLabs The problem with those chips is that often they implement the control logic themselves. I wanted just to have a low level class D amplifier stage so that I can program the switching myself both to account for the RL circuit of the exact motor and to implement some sort of FOC using an absolute encoder
Im currently using Irf3205 n-channel mosfet and ir2110 MOSFET driver for Bldc Motor control using Arduino. MOSFET is not completely turning on by the MOSFET driver IC ?
You should describe your setuup a bit more detailed. The ULN/UDN Driver-chips are not well suited as gate-drivers for power-MOSFETs (too slow, no push-pull output). Use special push-pull MOSFET-driver ICs for switching power MOSFET.
That´s basic electronics: Put a constant voltage at an inductor and current rises linearly (until either ohmic resistance or saturation of the ferrite material sets in)
read carefully what I wrote, also that in the brackets. Look up your textbook or wikipedia about inductors and capacitors. Capacitors are the inverse elements to inductors. Exchange I and V and you understand the other part. With a capacitor, charge it with a constant current and you get a linearly rising voltage --> with an inductor, put a constant voltage to it´and you get a linearly rising current (until........... see above)! Case closed.
@@KainkaLabs We are both correct in a sense. The current in an ideal inductor in isolation will rise linearly when charged with a constant voltage. However, ideal inductors don't actually exist. In that case there is always some resistance, and when resistance is present, the current in the inductor will rise exponentially as per the formula I provided. I hope we can agree on that.
Yes, it is basic electronics. I recommend Michel van Biezen's video "Electrical Engineering: Ch 7: Inductors (7 of 24) DC Current Through an Inductor" where he explains the exponential behavior of current through an inductor with constant voltage and takes into consideration the resistance with time constant L/R. Seems like you were unaware of that.
![Gucci Mane & Sexyy Red - You Don't Love Me [Official Music Video]](http://i.ytimg.com/vi/j7IBqyFKT4c/mqdefault.jpg)
Bless the boomers that share their knowledge on this kind of youtube channels.
Sir, The best video on ULN family. Thanks
Cool, I'm setting up for VFD's and It looks like high side drivers are on the shopping list. Well done
I got some of these ULN2803 ICs but the *fake* ones or which is called as Potato ICs in here :) they are not capable of sinking all the current down (like 20-30mA @ 5V) while sourcing the base with furious 5V GPIO. That was a total surprise. I have ordered it as smd, from some another source and that one works like it is expected. Characteristics are just like a single dalington npn for a pulse like 10us @ 5V.
this is great video..thank u
Which chip to use depends on whether your multi-segment display device is common-cathode or common-anode.
thank you sir
Good morning, Very useful video. But printed materials can not be seen clearly. They need to be enlarged. Thanks.
Good video
I'm using uln2803 driving relays using 3.3V input from a PIR motion sensor
It was very good !!!
Is it possible to combine both ICs to have an array of 8 half bridges to drive, for example, a bipolar stepper motor?
Today I would always use specialized stepper-motor driver-ICs. They give you much more functionality in one chip that trying to build a driver out of standard ICs.
@@KainkaLabs The problem with those chips is that often they implement the control logic themselves. I wanted just to have a low level class D amplifier stage so that I can program the switching myself both to account for the RL circuit of the exact motor and to implement some sort of FOC using an absolute encoder
Im currently using Irf3205 n-channel mosfet and ir2110 MOSFET driver for Bldc Motor control using Arduino. MOSFET is not completely turning on by the MOSFET driver IC ?
You should describe your setuup a bit more detailed.
The ULN/UDN Driver-chips are not well suited as gate-drivers for power-MOSFETs (too slow, no push-pull output).
Use special push-pull MOSFET-driver ICs for switching power MOSFET.
wery naise your clase ant wery slow your teacghing am stading this metheed
am wery happy to waching this video
(god +you ) thanks teacher
3:42, current rises, but I don't believe it rises linearly.
That´s basic electronics: Put a constant voltage at an inductor and current rises linearly (until either ohmic resistance or saturation of the ferrite material sets in)
@@KainkaLabs But I=V/R(1-e^(1-tR/L)), so with V being constant, I believe it's an exponential rise.
read carefully what I wrote, also that in the brackets. Look up your textbook or wikipedia about inductors and capacitors. Capacitors are the inverse elements to inductors. Exchange I and V and you understand the other part. With a capacitor, charge it with a constant current and you get a linearly rising voltage --> with an inductor, put a constant voltage to it´and you get a linearly rising current (until........... see above)! Case closed.
@@KainkaLabs We are both correct in a sense. The current in an ideal inductor in isolation will rise linearly when charged with a constant voltage. However, ideal inductors don't actually exist. In that case there is always some resistance, and when resistance is present, the current in the inductor will rise exponentially as per the formula I provided. I hope we can agree on that.
Yes, it is basic electronics. I recommend Michel van Biezen's video "Electrical Engineering: Ch 7: Inductors (7 of 24) DC Current Through an Inductor" where he explains the exponential behavior of current through an inductor with constant voltage and takes into consideration the resistance with time constant L/R. Seems like you were unaware of that.
If the gate drivers turn off with the mosfet turn off aswell
Is that a question or a statement? The ULN and UDN drivers are bipolar and not MOSFET (and not intended as MOSFET gate-drivers)