I really appreciate your deductive reasoning. It would be enjoyable to play against you, as I play with the same tactics. And have been since I was young.
At 6:38 you're saying that he has 1 of these 3 cards, but again, isn't it possible that all of his cards are those 3 cards: Orchid, Rope, Ballroom? On what basis are you confidently assuming that he has ONLY 1 card out of those 3 cards?
That is very true. I speedrun the online version and when i am shown one of 2 or 3 numbered cards, I keep the numbers incase there are overlaps with guesses
He is NOT confidently assuming that she has only 1 card out of those 3 cards. The reason he put the 1s there in the first place is because he knew she had one of those 3 cards. But when he found out that he had determined which card out of those 3 cards it was, the 1s for the other two would no longer be needed because he did not know if she had a card out of those 2. By your logic, he would have to put a 1 on every single card of someone's until finding out that they don't have that card.
Yeah he did it wrong. She definitely had the hall card. But there’s still no knowledge of anyone else definitively having the other 2, so yes she could of still had more than just that Hall card. He messed up. You’re right.
He had Peacock in his cards so he knew for sure she didn't have that card. He didn't know for sure if she had the wrench card but confirmed at 8:30 that she definitely didn't have it so knew at that point wrench was correct for the weapon. I think he took the "1" off the checkpad at 5:30 because it was no longer a situation of "she may have this room or this weapon", which I believe is the system he was using. He neither confirmed nor denied that she had the wrench at that point, only that she had the Hall card. Hope that makes sense if you're even still interested 2 months later :)
It’s impossible to win on “hard” all the time. Depending on the difficulty setting, the computer will simply lower the number of rounds it takes for the murder to be solved.
@@zmzmppi I don't think the AI is lowering the rounds. Simply put, on "hard", the computer is using the same tricks and logic that he mentions in the video, so ultimately who wins is greatly based on luck.
I dont understand why you ASSUME that at 9:33 that because she chose Scarlett and didn't have the other two picks, that she has Scarlett and suddenly doesn't have so many other cards, as if you can't draw 2 suspects or 2 locations or 2 weapons and be in lacking of 1 category. Naturally someone is going to not fall in line of all the players of having 1 of each and that takes 1 away from another player and you'll have 2 players with 0 in 1 and 2 in another as an example.
It's no assumption, Courier; his logic is absolutely sound, even if crossing out so many possibilities seems bold. The reasoning for this is as follows. As for how he knows Orchid has the Scarlett card: He knows at this point, that no- one has the Wrench or the Dining Room. Those are definitely the Murder weapon and location. That leaves only the question of whether Orchid (who made this suggestion) has Scarlett's card. Nobody ELSE has Scarlett's card or they would have answered Orchid's suggestion. So if ORCHID doesn't have Scarlett's card either, then she's won, she could just make the final accusation right then and there and end the game. Since she doesn't make the final accusation, then that means Orchid knows Scarlett isn't the suspect, and Orchid is the only one left who could possibly have Scarlett's card. Now as to how he rules out all those other possibilities afterwards: Knowing that Orchid has Scarlett's card, means the player now knows two out of Orchid's three cards. The player also has marked in his notes that Orchid responded to a suggestion earlier involving the LEAD PIPE and the LIBRARY. Therefore, Orchid's third and final card MUST be one of those two cards. (whoever the suspect in that particular suggestion was, the player already knows she couldn't have that card) Knowing this, it is safe to cross off everything else in Orchid's column. The critical factor in this deduction, is that Orchid only has ONE card left that we don't know what it is. If she had two or three cards still unknown to to us, then yes, she could turn out to have both the Lead Pipe and the Library, or only one of them, and we wouldn't be able to immediately rule out her having any of the rest of the cards. But since we know that we are only missing one of her cards, we are able to rule all those other possibilities and be certain her final card is one of those two. So yes, you can absolutely make deductions based on how many cards a player has and how many of those you know. And yes, combined with the results of a suggestion like this one, this can rule out a large number of possibilities at once. I've had many games where applying this reasoning gave me the rest of the info I needed to win. And some instances where forgetting to do this might have cost me the game. :)
Do you understand it now, did you figure it out or get an explanation? If you are still wanting the answer let me know and I can try and explain it to you:)
Thats actuallly the optimal way of gaining information. Any combination involving utilizing your own cards in a suggestion is exclusively useful in attempting to deny information to other players.
I have a question, why is it sometimes neither an “x” or a “check mark” shows up next a player’s face? In the example you have in the video, after you made an accusation, three of the players have an “x” and the first player doesn’t have an x or a check mark. I thought each player had to answer whether or not they have a card. What does it mean if an “x” or check mark don’t show up after you make a guess?
X means the player doesn't have the card. When it gets to a player who possess one of the 3 cards. It'll have a check. The person with a ? is the person asking the question. I'm terrible at explaining. Best of luck
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I really appreciate your deductive reasoning. It would be enjoyable to play against you, as I play with the same tactics. And have been since I was young.
At 6:38 you're saying that he has 1 of these 3 cards, but again, isn't it possible that all of his cards are those 3 cards: Orchid, Rope, Ballroom? On what basis are you confidently assuming that he has ONLY 1 card out of those 3 cards?
That is very true. I speedrun the online version and when i am shown one of 2 or 3 numbered cards, I keep the numbers incase there are overlaps with guesses
He is NOT confidently assuming that she has only 1 card out of those 3 cards. The reason he put the 1s there in the first place is because he knew she had one of those 3 cards. But when he found out that he had determined which card out of those 3 cards it was, the 1s for the other two would no longer be needed because he did not know if she had a card out of those 2. By your logic, he would have to put a 1 on every single card of someone's until finding out that they don't have that card.
At 5:30, how and why did you assume that she only had the Hall card? Isn't it possible that she actually had those 3 cards?
Yeah he did it wrong. She definitely had the hall card. But there’s still no knowledge of anyone else definitively having the other 2, so yes she could of still had more than just that Hall card. He messed up. You’re right.
He had Peacock in his cards so he knew for sure she didn't have that card. He didn't know for sure if she had the wrench card but confirmed at 8:30 that she definitely didn't have it so knew at that point wrench was correct for the weapon. I think he took the "1" off the checkpad at 5:30 because it was no longer a situation of "she may have this room or this weapon", which I believe is the system he was using. He neither confirmed nor denied that she had the wrench at that point, only that she had the Hall card. Hope that makes sense if you're even still interested 2 months later :)
Love your videos, theyve helped me so much, thank you ❤
I noticed you called your favourite player "Mr Green" but he's "Reverend Green" in the UK version and wears a dog collar. 😀
If u know the room, go to a room you Jane to throw others off
You can't win every time with that method when all of the characters are in "hard" mode. You conveniently set only Mustard on "hard".
It’s impossible to win on “hard” all the time. Depending on the difficulty setting, the computer will simply lower the number of rounds it takes for the murder to be solved.
@@zmzmppi I don't think the AI is lowering the rounds. Simply put, on "hard", the computer is using the same tricks and logic that he mentions in the video, so ultimately who wins is greatly based on luck.
I dont understand why you ASSUME that at 9:33 that because she chose Scarlett and didn't have the other two picks, that she has Scarlett and suddenly doesn't have so many other cards, as if you can't draw 2 suspects or 2 locations or 2 weapons and be in lacking of 1 category. Naturally someone is going to not fall in line of all the players of having 1 of each and that takes 1 away from another player and you'll have 2 players with 0 in 1 and 2 in another as an example.
It's no assumption, Courier; his logic is absolutely sound, even if crossing out so many possibilities seems bold. The reasoning for this is as follows.
As for how he knows Orchid has the Scarlett card: He knows at this point, that no- one has the Wrench or the Dining Room. Those are definitely the Murder weapon and location. That leaves only the question of whether Orchid (who made this suggestion) has Scarlett's card. Nobody ELSE has Scarlett's card or they would have answered Orchid's suggestion. So if ORCHID doesn't have Scarlett's card either, then she's won, she could just make the final accusation right then and there and end the game. Since she doesn't make the final accusation, then that means Orchid knows Scarlett isn't the suspect, and Orchid is the only one left who could possibly have Scarlett's card.
Now as to how he rules out all those other possibilities afterwards: Knowing that Orchid has Scarlett's card, means the player now knows two out of Orchid's three cards. The player also has marked in his notes that Orchid responded to a suggestion earlier involving the LEAD PIPE and the LIBRARY. Therefore, Orchid's third and final card MUST be one of those two cards. (whoever the suspect in that particular suggestion was, the player already knows she couldn't have that card) Knowing this, it is safe to cross off everything else in Orchid's column.
The critical factor in this deduction, is that Orchid only has ONE card left that we don't know what it is. If she had two or three cards still unknown to to us, then yes, she could turn out to have both the Lead Pipe and the Library, or only one of them, and we wouldn't be able to immediately rule out her having any of the rest of the cards. But since we know that we are only missing one of her cards, we are able to rule all those other possibilities and be certain her final card is one of those two.
So yes, you can absolutely make deductions based on how many cards a player has and how many of those you know. And yes, combined with the results of a suggestion like this one, this can rule out a large number of possibilities at once. I've had many games where applying this reasoning gave me the rest of the info I needed to win. And some instances where forgetting to do this might have cost me the game. :)
@@LupisLight perfect explanation
I understand it all except whats the difference between the little 1 and 2s ?
Do you understand it now, did you figure it out or get an explanation? If you are still wanting the answer let me know and I can try and explain it to you:)
I sometimes ask for 3 cards of which none I have - this throws other players a lot 🤣
Thats actuallly the optimal way of gaining information. Any combination involving utilizing your own cards in a suggestion is exclusively useful in attempting to deny information to other players.
so you were the one who killed Mr Body !
Is it true that games with fewer people last longer?
Ive actually found that to be false. My games with 3 are much quicker because it is less reliant on the AI
Just because somebody shows a card doesn't mean they DON'T have ANOTHER card of the guess.
true - but since there's no way to know for sure, you have to treat it one card at a time.
@@PuzzlingGames yup
Will this work for the actual board game I don’t have it just wondering I only have the app
Yes same strategy works
what is the app called?
I have a question, why is it sometimes neither an “x” or a “check mark” shows up next a player’s face? In the example you have in the video, after you made an accusation, three of the players have an “x” and the first player doesn’t have an x or a check mark. I thought each player had to answer whether or not they have a card. What does it mean if an “x” or check mark don’t show up after you make a guess?
Hope I'm answering this correctly but it goes in order so If it doesn't get past a certain character. Their cards will still remain hidden.
X means the player doesn't have the card. When it gets to a player who possess one of the 3 cards. It'll have a check. The person with a ? is the person asking the question. I'm terrible at explaining. Best of luck
scolit renth kithin
Boom
hahaha i do same strategy many years and is NOT WIN EVERY TIME!
This is so confusing
anybody has the link of FREE clue game to download ???
Boom Shaka Laka steamunlocked.net look up cluedo you can play online too, tons of other games too
As long as you are on pc
Don’t be a cheapskate is only 3.99
Free is always better 🤭