Orbital Dynamics Part 12 Formula for True Anomaly

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  • Опубликовано: 29 окт 2024

Комментарии • 24

  • @Freak80MC
    @Freak80MC 3 года назад +6

    A lot of this is going over my head but I thank you for having this available for us to watch. I'll probably watch it a few times after this to let it all sink in!

  • @janerikludwighorvath7761
    @janerikludwighorvath7761 7 месяцев назад +1

    This lecture was great in terms of geometrical detail, some important geometrical identities were overlooked and collapsed into just an equality sign, not even a comment, by my lecturer. This video unveiled all of those collapsed details, I do however think that this lecture was unclear regarding the linear relationship between time and true anomaly, that is only satisfied for the mean anomaly, not the true one. It was not really brought up so after following your derivation for a while I was like, oh no - what is going on here. This details was better captured by my lecturer, who instead assumed a more general form of the ellipse (shifted in x) and used the notion of angular momentum after defining the mean anomaly, then getting the derivative form and conducting integration which then led to Keplers equation. Nonetheless, I am greatful that you provide us with this detailed content. I am looking forward to your intricate explanations in the other videos as well as your animations.

  • @JamesHardaker
    @JamesHardaker 3 месяца назад +1

    amazingly clear and detailed explanation

  • @sanfah1
    @sanfah1 3 года назад +4

    it was helpfull Sir, we really gain alot

  • @GLORY-TO-ENTROPY
    @GLORY-TO-ENTROPY Год назад

    at 11:18 is theta a linear function of time? It needs to be the case for the equation to work isn't it?

  • @StarkTech47
    @StarkTech47 9 месяцев назад

    Thank you for the quick recap at the end, it is really helpfull.
    May be I am wrong but at 56:43, the formula to compute the time t seems to be wrong. To me, t should be equal to M*T / (2*pi).
    Since the mean anomaly is the "projection" of the true anomaly on an perfect circle, to compute the time it takes from an angle 0° to, let's say, 30°, we compute the eccentricity anomaly with the 30° thanks to the formula of E. Then compute the mean anomaly M and perform the formula I mentioned above.
    It seems to work for me when I want to compute the time it takes to my satellite to go from true anomaly to another.
    But may be I did not understand what t is.

  • @tnickle2156
    @tnickle2156 Год назад

    Thank you Dr Toellner for your video. I have a quick question. When you are solving for eccentric anomaly (18:45), you state that cos E and sin E produce ambiguous solutions. To get around it, you use some trig identities to write the angle in terms of a half angle identity. Is there a reason why the half angle of tangent is picked over the half angle of cosine? Both would produce an unique solution in the domain 0 to 2pi.

  • @tonyl.1426
    @tonyl.1426 3 года назад +2

    beautiful :)

  • @rondunnett7204
    @rondunnett7204 3 года назад +1

    Excellent! Thanks!

  • @shradhajason8082
    @shradhajason8082 3 года назад +3

    thank you Sir

  • @rajukhadka569
    @rajukhadka569 3 года назад +1

    When calculating true anomaly, at what condition we should add pi() to overall calculations results, which change the sign of the co-ordinates in the final calculations?

  • @agostinocavarero8590
    @agostinocavarero8590 3 года назад +5

    ruclips.net/video/rDQTZadS058/видео.html the formula for θ(t)/θ(T) is wrong and cannot be derived from the formula for t/T as the angle θ is not a linear function of time. This gets "corrected" in the following slide where mean anomaly is introduced.

    • @GLORY-TO-ENTROPY
      @GLORY-TO-ENTROPY Год назад

      yea I was thinking the same too

    • @GLORY-TO-ENTROPY
      @GLORY-TO-ENTROPY Год назад

      so just replace the theta(t) with mean anomaly right, because mean anomaly treats it like a circular orbit, which in the case of circular orbit, the anomaly angle and time are linear with each other

  • @akisdrosi2011
    @akisdrosi2011 4 года назад +7

    many thanks for this. 893 subscribers, but in a parallel universe you should have 893 million subscribers. fortunately or unfortunately, this planet prefers naked women teaching them how to put make up on before going out to get knocked up.
    greetings from a Greek guy.

    • @deniousp
      @deniousp 4 года назад +1

      lol misogynistic physics simp, I bet the only naked women you've seen are your anime waifu and your mom

    • @Nick21012
      @Nick21012 3 года назад

      @@deniousp Where was the misogyny?

    • @nondbfune9132
      @nondbfune9132 3 года назад

      @@deniousp Don't hate on waifu's man. That's the culture lol. But thanks to this channel because it's so easy for me to review this stuff and makes it easier because without using this type of knowledge daily, you lose it. I took a spacecraft dynamics and control course a couple of years ago, and it was the best class I've ever enrolled in during my undergrad.

  • @nabeelahamedk7139
    @nabeelahamedk7139 Год назад

    what's the formula you have used to calculate mean anomaly at 25:01

  • @masoudsakha
    @masoudsakha 13 дней назад

    you did not prove why M=E-e sinE ??? where it came from

  • @Anc_98
    @Anc_98 Год назад

    at 24:22 mistake in r formula, should be as 23:35

  • @ghhr321
    @ghhr321 2 года назад

    snu ece:)