True Anomaly vs. Mean Anomaly

Поделиться
HTML-код
  • Опубликовано: 26 авг 2024
  • This video explains what the Mean Anomaly is, how it relates to the True Anomaly, and how to use the Mean Anomaly to propagate a simple 2-body orbit.
    In case the links don't work within the video:
    orbitnerd.com/b...
    orbitnerd.com/b...
    As promised, here are the scripts which will do the conversions between True Anomaly, Mean Anomaly, and Eccentric Anomaly: github.com/lba...
    This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

Комментарии • 71

  • @8100834
    @8100834 8 лет назад +19

    Thank you very much! why have you stopped?

  • @kirkhamandy
    @kirkhamandy 4 месяца назад +1

    What a shame only 3 videos were ever made.

  • @martinB4203
    @martinB4203 4 года назад +2

    Its a pity you stopped making videos. they are awesome and helped me a lot!

  • @jagdishchawla8489
    @jagdishchawla8489 3 года назад

    This is the simplest and best explanation of mean and true anomaly.

  • @LeFoUv3r7
    @LeFoUv3r7 5 месяцев назад

    You know thoses videos are so usefull I use them as references since years each time I need a remainder ? Thank you.

  • @thomasarmstrong9212
    @thomasarmstrong9212 Год назад

    This chanel probably isnt active anymore but if it is, I would love a walkthrough of the second long problem on the USAAAO NAO competition. Its about orbits!

  • @MaheshKalpande
    @MaheshKalpande 6 лет назад

    3 hrs of web search and finally 6 min video and all done, thanks

  • @anarquismoverde
    @anarquismoverde 5 лет назад +7

    link for the script is not working :(
    can someone fix it, please?

  • @human.earthling
    @human.earthling 10 лет назад

    Thanks I am taking orbital mechanics as a class, but I still feel that videos like these are the best way to learn the material.

  • @butterfacepilot
    @butterfacepilot 3 года назад

    Hey mate! Thanks for the video! Studying orbital mechanics at the moment in uni (Space Science) and your simple explanation and engaging drawings have helped me understand the concept so much better than my lecture has!

  • @Freak80MC
    @Freak80MC 3 года назад

    22 seconds in and just pausing at that picture I think I already get this more than I did through trying to read wikipedia!

  • @markusaurelius4015
    @markusaurelius4015 6 лет назад +1

    Love this video! What a fantastic explanation. We actually played this for the class in orbital mechanics class.

  • @Allitnils
    @Allitnils 10 лет назад

    Fantastic video, great job keeping the visuals up with the pace

  • @MyFavoriteDisease
    @MyFavoriteDisease 9 лет назад +2

    Great video! Enlightening, comprehensible and somewhat funny too.

  • @VKachan
    @VKachan 4 года назад +1

    NEED MOAR VIDEOS CAUSE YOU ARE AWESOME. kthx

  • @rockycool4387
    @rockycool4387 9 лет назад +1

    can anybody please say me while doing that problem how did he find out the Mean anomaly ?? i mean he wrote down the True anomaly and then he writes down Mean anomaly, and after that done with finding Mean anomaly at different positions how did he find out the True anomaly back again using the Mean anomaly at different positions ???

  • @henfjo
    @henfjo 6 лет назад

    Your video was increadibly helpful!

  • @OrbitNerd
    @OrbitNerd  10 лет назад +6

    I used a program called Octave. It's very similar to Matlab, but is available for free.

  • @ProtoTangelo
    @ProtoTangelo 8 лет назад

    Nice interesting video again. Very useful. but why aren't you making anymore videos?

  • @muhammadtalha5402
    @muhammadtalha5402 3 года назад

    Very helpful video, and good method of teaching. 😍💗

  • @TheNikhilmishras
    @TheNikhilmishras 7 лет назад

    great video! needed to brush up on these terms for my solar system simulator.
    BTW, why did you calculate mean anamoly three times?

  • @kensukesakamoto1370
    @kensukesakamoto1370 10 лет назад +1

    what is the program you used to model the motion in 3:37 ?

  • @Invaderzerg
    @Invaderzerg 9 лет назад

    If you had a gauge in a spaceship that could give you one of the anomalies in deg. which one would you choose in order to get best picture of your position in an eccentric orbit. I think certainly not mean anomaly coz that has nothing to do with position at all. Could you use something like Zenith angle/flight path angle istead. What about %/Orbital period or %/orbital distance (counting from Pe) that could give a good picture of position right?

  • @renanbezerradasilveira2943
    @renanbezerradasilveira2943 6 лет назад

    Amazing explanation. Good job!

  • @mattdgarrett
    @mattdgarrett 10 лет назад

    Thank you for your helpful videos!

  • @reidbyron7662
    @reidbyron7662 7 лет назад

    fantastic visual. Thanks!

  • @NecroBones
    @NecroBones 6 лет назад

    This was a very useful video! I wanted to grab the referenced scripts, but it looks like the website has expired.

  • @SachaTholl
    @SachaTholl 3 года назад

    Hi, all the links have stopped working. If you click on the links, you get a response that the Website and account have expired, but you could log in as a site owner....could you reactivate the side or place the resources online somewhere else? Please thank you very much! Greetings from Germany.

  • @juliazeng5663
    @juliazeng5663 7 лет назад

    how do you convert from eccentric anomaly to true anomaly?

  • @lucyhancock103
    @lucyhancock103 7 лет назад

    Thank You. - Lucy

  • @spacefreedom
    @spacefreedom Год назад

    concise

  • @ankulmishra7799
    @ankulmishra7799 3 года назад

    beautifully explained🌹

  • @ahmedmusa517
    @ahmedmusa517 4 года назад

    the link for conversions does not work

  • @robertocadena7
    @robertocadena7 10 лет назад +1

    Good explation. a bit fast but good.

  • @Freak80MC
    @Freak80MC Год назад

    So how are you supposed to do the change in times to true anomaly at 5:30? It looks like the equations work one direction but stop working the other way (since eccentric anomaly is it two places in the equation I found and people say you need to do some brute force methods to get a solution)
    You skipped the most important part!
    EDIT - nevermind I created a guesser system in a spreadsheet where I guess E up to how ever many decimal points I want and then check the result against my eccentricity value to find how close they match. Once I reach 100.00000 whatever % match I stop.
    I use this equation and stop once my eccentricity result sufficiently matches my actual eccentricity:
    ((M-Eguess)/-1)/sin(Eguess) = e
    Probably will program this later in python lol

  • @gladiesthomas7946
    @gladiesthomas7946 9 лет назад

    It was very helpful. You made it so easy ! Thankyou very much :)

  • @fouziasharmin6218
    @fouziasharmin6218 4 года назад

    I really loved it.

  • @anujnandal3232
    @anujnandal3232 4 года назад

    For people coming in late, in the example the value of the semi-major axis is 26500km.

  • @aberroa1955
    @aberroa1955 3 года назад

    Website expired...

  • @FamMeierundCo
    @FamMeierundCo 4 года назад

    Great video!

  • @itaidagan1
    @itaidagan1 6 лет назад

    Great video, thanks!

  • @awbrook
    @awbrook 11 лет назад

    I like your videos, keep them coming!

  • @khongjunyong3254
    @khongjunyong3254 9 лет назад

    Appreciate for your helpful video dude !

  • @MyFavoriteDisease
    @MyFavoriteDisease 9 лет назад

    Okay, so you can calculate the motion of a satellite around earth if you know the semi-major axis, the eccentricity and the current true anomaly. But what if I only have the current position and velocity vector of the sattelite, not knowing yet how the orbit is shaped? Is it possible to calculate all the orbital characterics of the sattelite from these two pieces of information?

    • @oneMeVz
      @oneMeVz 8 лет назад

      +MyFavoriteDisease +OrbitNerd I'm looking for the same answer. With only the position, velocity, and the central mass, the shape of the orbit can be defined by first finding the specific orbital energy a specific relative angular momentum. However I do not know the equation to find the initial true anomaly.

  • @abrhmsancehz
    @abrhmsancehz 10 лет назад

    Keep up the good work!

  • @mitoand9
    @mitoand9 8 лет назад

    Gr8 explanation

  • @CsrxRacer
    @CsrxRacer 9 лет назад

    great vid, please enrich your channel with more videos, subscribed .

  • @henriquefchaves
    @henriquefchaves 2 года назад

    No longer available man. Sorry... Can you help me out?

  • @iamarugin
    @iamarugin 5 лет назад

    Links in the description doesn't work

  • @charlietown3844
    @charlietown3844 7 лет назад

    great video! make more please! :)

  • @infin7531
    @infin7531 2 года назад

    The site expired D:

  • @vibraphonics
    @vibraphonics 8 лет назад

    You somewhat brush over the fact that for M = E - esinE you cannot solve for E numerically - how did you do it?

    • @neophytefilms1268
      @neophytefilms1268 8 лет назад

      you have got to iterate. Maybe have a look at www.agi.com/resources/educational-alliance-program/astro-primer/primer80.htm

    • @salgreen2814
      @salgreen2814 3 года назад

      How to do iteration

  • @damzelfly
    @damzelfly 9 лет назад

    I like your video, Please make a new video

  • @EBgCampos
    @EBgCampos 3 года назад

    I dont get it... why call it a true anomaly when you can just call it angular position? Why complicate things?

  • @adriaansmit4389
    @adriaansmit4389 7 лет назад

    To go from mean anomaly to eccentric anomaly, there is a simple formula:
    M = E - e*sin(E)
    You'll need to iterate a few times for an accurate answer.

    • @juliazeng5663
      @juliazeng5663 7 лет назад

      how do you go from eccentric anomaly to true anomaly?

    • @adriaansmit4389
      @adriaansmit4389 7 лет назад

      +Julia Zeng
      θ=2*arctan(sqrt((1+e)/(1-e))*tan(E/2))
      where θ is the true anomaly
      e is the eccentricity
      E is the eccentric anomaly
      There are also expressions for this with sine and cosine functions, they're on Wikipedia

    • @juliazeng5663
      @juliazeng5663 7 лет назад

      thanks!

    • @salgreen2814
      @salgreen2814 3 года назад

      Adriaan smit do you know how to do iteration any idea?

  • @jimkeller3868
    @jimkeller3868 9 лет назад

    If the mean motion is in radians per second, and it is constant, couldn't you just divide the entire orbital path 2pi by the number of seconds in a year? Got completely lost at 5:00. Think the video was great to that point. But too much too quickly after that. How for example does one use the eccentric anomaly for the conversion and why

    • @OrbitNerd
      @OrbitNerd  9 лет назад

      Jim Keller Not sure exactly what your question is pertaining to the mean motion. The main problem with using the mean motion is that it only directly correlates with the mean anomaly...you can't use it directly with either the eccentric or true anomalies. However, you'll want to know what the true anomaly is since it will tell you exactly where the object is within the orbit. You use the eccentric anomaly to convert back and forth between the mean and true anomalies.
      Sorry about losing you at the 5:00 minute mark, that's where I do some hand waving and start showing you some calculations without the equations. If you have access to the book, I would suggest looking at the beginning of chapter 2 of Prussing & Conway that I mention in the video. The first few sections go into full details about converting between these anomalies. Barring that, look at the Wikipedia pages for mean, eccentric, and true anomalies...however, they don't fully explain how to determine the eccentric anomaly from the mean anomaly, this is a little tricky to do. Also, you can take a look at the scripts provided with the video. They'll provide all the equations needed, but don't provide the theory or explanations that Prussing & Conway would provide.

    • @jimkeller3868
      @jimkeller3868 9 лет назад

      OrbitNerd Thank you so much for your response.
      As for mean motion in radians couldn't you just take ωavg = 2πrad/1year (3.2×10^7 seconds in one year), to get angular velocity of 2.0×10-7 rad/s? Isn't this the same as nu = sqrt of mu/a^3 as you have above? pretty sure it works out the same.

  • @Ruben-se2me
    @Ruben-se2me 9 лет назад

    MIN KUK E SÅ HÅÅÅRD, OMG

  • @sanuyadav7883
    @sanuyadav7883 Год назад

    Tomorrow is my exam

  • @itzdampsandwich6383
    @itzdampsandwich6383 2 года назад

    man im gonna fail...

  • @TheNikhilmishras
    @TheNikhilmishras 7 лет назад

    great video! needed to brush up on these terms for my solar system simulator.
    BTW, why did you calculate mean anamoly three times?