Newton's 2nd Law (3 of 21) Calculate Acceleration w/o Friction, Net Force Above the Horizontal

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  • Опубликовано: 16 дек 2024

Комментарии • 48

  • @nickpetrowski7182
    @nickpetrowski7182 6 месяцев назад +1

    finally, videos that make sense! Too often physics teachers talk in circles too much about the "what ifs" thank you for being direct.

    • @stepbystepscience
      @stepbystepscience  6 месяцев назад

      You're very welcome! I'm glad it was helpful for you.

  • @mr.olorinthemaia
    @mr.olorinthemaia 4 года назад +1

    Sir, I must admit I watch your videos with love. I'm from Eastern Europe, Romania, and in our country physics isn't taught well. The fact that I can understand these types of problems so well from your, sir, is unbelievable. Much love.

  • @lamnguyen-bi8jm
    @lamnguyen-bi8jm 9 лет назад +15

    Awesome! u have literally saved my life with all the videos! Thank a lot for ur contribution to our society with these amazingly educational video.

    • @stepbystepscience
      @stepbystepscience  9 лет назад +4

      +lam nguyen Just trying to take a topic that seems a little complicated and break it down into manageable steps. Thank you very much for the positive comment.

  • @Thumbsme12
    @Thumbsme12 11 лет назад +1

    I just want to tell you how much I love you and that you probably saved my life and my final exam

  • @georgeathan9475
    @georgeathan9475 4 года назад +1

    Greetings from Greece , currently preparing for master's exams in Human movement sciences and your videos are like heaven. Thank you very much !

    • @stepbystepscience
      @stepbystepscience  4 года назад

      Wonderful! Good luck with the exams and thanks for the comment.

  • @Juicyvale14
    @Juicyvale14 7 лет назад +4

    Thank you for taking the time to make this videos. I watched a few for my last test and they helped me so much. For this test I was trying to find your channel and I couldn't remember the name of your channel on my subscription list lol but I'm glad I've founded it. Now I feel much better after reviewing with your videos.

    • @stepbystepscience
      @stepbystepscience  7 лет назад

      Hopw the test goes well, thanks for commenting. You can see a full listing of all my videos at www.stepbystepscience.com

  • @bellajagitay9964
    @bellajagitay9964 3 года назад +1

    this is beautiful the only channel that made me switch to premium

  • @ev3rn1ght89
    @ev3rn1ght89 3 года назад +2

    Thanks so much your videos are extremely helpful

  • @sankagrero2042
    @sankagrero2042 9 лет назад +3

    These are amazing video! So simple and I can follow along quite easily. Just wish I found you at the beggining of the semester. Keep up the great work Mr. Swarthout!

    • @stepbystepscience
      @stepbystepscience  9 лет назад

      Sanka Grero Thank you, I put a lot of time into that series of videos and I think they turned out pretty good.

    • @sankagrero2042
      @sankagrero2042 9 лет назад

      Brian Swarthout Absolutely sir! And thank you for doing so.

  • @SomiVelu
    @SomiVelu 6 лет назад +4

    6 X 9.8 = 58.8 btw and good job 👌🏿

  • @harmonicposting
    @harmonicposting 5 лет назад +1

    nothing against my current teacher (hes a cool dude) but you are just amazing, concise and short explanations, simple and clean. thank you

    • @stepbystepscience
      @stepbystepscience  5 лет назад

      I try to just get to the point and explain everything step by step.

  • @bienramos7587
    @bienramos7587 3 года назад +1

    Very clear and detailed explanation.. thanks

  • @AdmiredDisorder
    @AdmiredDisorder 3 года назад +1

    this was so easy to understand, thank you

  • @andrewogden1480
    @andrewogden1480 11 лет назад

    Thank you for the help. Your voice reminds me of Dustin Hoffman which helps to keep my attention.

  • @breayonnapearson2596
    @breayonnapearson2596 7 лет назад +1

    Great breakdown

  • @katherine3257
    @katherine3257 6 лет назад +1

    You have made this so clear, the only thing that would make this playlist better is if they were automatically in order! lol

    • @stepbystepscience
      @stepbystepscience  6 лет назад

      I believe they are in order in this playlist. Newton's 2nd Law
      ruclips.net/p/PLcJ1NYursFxhzXs4bqmXaeSWvHbZrSjpQ

    • @katherine3257
      @katherine3257 6 лет назад

      Step-by-Step Science it starts at video 13 of 21 on that playlist link :)

    • @katherine3257
      @katherine3257 6 лет назад

      I guess the "(13 of 21)" is what is throwing me off

  • @musaadebisi9105
    @musaadebisi9105 5 лет назад +2

    U are nothing but a genius to me bro ! Much love please I need you to help me with projectile motion

    • @stepbystepscience
      @stepbystepscience  5 лет назад +1

      Thanks for the great comment. I have videos on projectile motion, just search "step by step science projectile motion"

    • @musaadebisi9105
      @musaadebisi9105 5 лет назад

      OMG I HAVE SEEN PROJECTILE MOTION VIDEOS THANKS

  • @user-cp3id7du9e
    @user-cp3id7du9e 2 года назад

    Thanks for the video. Can you explain again why Fay has an acceleration of 0 again?

    • @stepbystepscience
      @stepbystepscience  2 года назад

      Good question! Because the only motion of the object is horizontal, there is no motion in the y direction

  • @rafaelalvarez1585
    @rafaelalvarez1585 3 года назад +1

    Thank you so much !!

  • @ann-mariekoger2907
    @ann-mariekoger2907 5 лет назад +1

    Why would the horizontal not be the surface of the table? I get the 35 deg from the horizontal, but why not make the horizontal bottom of the box? Does it make any difference?

    • @stepbystepscience
      @stepbystepscience  5 лет назад

      No it does not make a difference. When you pull something you usually do not pull from the bottom.

  • @biancaar8032
    @biancaar8032 2 года назад +2

    Does that mean the object will rise due to this force applied in an angle?

    • @stepbystepscience
      @stepbystepscience  2 года назад

      Only if the vertical component of the force is greater than the weight of the object.

    • @biancaar8032
      @biancaar8032 2 года назад

      @@stepbystepscience thank you

  • @stepbystepscience
    @stepbystepscience  11 лет назад

    thanks

  • @0.3nergy
    @0.3nergy 7 лет назад

    question, dont you have to use the acceleration on the y-axis?
    why are you only using the one Ax
    To find the acceleration over the Y-axis = the sum over the Y-Axis 50+ -58.6= -8.6 m/s2
    Clarify please.

  • @gianny2977
    @gianny2977 6 лет назад +1

    Great video thank you, on to video 3

  • @theusedblueandyellow
    @theusedblueandyellow 10 лет назад

    excellent videos.