I think in the second problem you multiplied the applied force to acceleration due to gravity rather than the weight of the object its should be -88.29N and + 88.29N PLEASE CORRECT ! THANK YOU
Karol Marella Topacio because frictional force is always the opposite sign of your regular force. I generally just say all left forces are negative and right is positive
breayonna pearson thank you! I was surprised because I was taught the opposite rule.. still going to use that rule though it’s against our lesson 😂 coz that’s what I thought too
Karol Marella Topacio it balances out to be the same. As long as ur acceleration and force is the same sign and ur friction is the opposite sign, then it doesn’t really matter which way u do it
The results differ if you don't, and you have to distinguish between forces going in certain directions because they are vectors and vectors have direction and magnitude.
I’m confused about one thing. I got a fbd and it already has 2 downward forces and 1 upward force. Do I still need to find the gravity force or what? What I do with the 2 downward forces?
F(g) was calculated using 11n instead of 9kg for the second 0rob
i realised that too. its an error i think
I realised too
yeah
Thank you for the kind comment.
Thanks for taking the time to comment, I will recheck my math.
Just taking out some unwanted umms and uhhs. Thanks for watching!
I think in the second problem you multiplied the applied force to acceleration due to gravity rather than the weight of the object its should be -88.29N and + 88.29N PLEASE CORRECT ! THANK YOU
Thank you! You are the best lecturer!
i see u removed the first one :O make more video's related to grade 11 physics :) plz and thank you
Excellent classes! Congrats!
Thank you very much for commenting
The video quality is very good.
Tq very much.. it's really helpful
You are very welcome. Thanks for commenting.
shouldn`t we put 9 instead 11? when we calcuate F_g in second equation
Yes, sorry...I have seen that mistake before. It is a 9 kg object so the Fg should be 9kg times 9,81 m/s2.
@@stepbystepscience do you have problems, where F_a is not given?
thank you!
Hi Brian could you explain the graph related to the subject video above....is it straight line, linear or square graph. Thank you
you could just do 5/6 because 1 newton is the amount of force needed to move a kilogram a m/s
Great job thank u
breayonna pearson hi! I was just wondering why the applied force to the leftward force is negative?
Karol Marella Topacio because frictional force is always the opposite sign of your regular force. I generally just say all left forces are negative and right is positive
breayonna pearson thank you! I was surprised because I was taught the opposite rule.. still going to use that rule though it’s against our lesson 😂 coz that’s what I thought too
Karol Marella Topacio it balances out to be the same. As long as ur acceleration and force is the same sign and ur friction is the opposite sign, then it doesn’t really matter which way u do it
Sir, why is it necessary to have negative applied force when it is going to the left?
The results differ if you don't, and you have to distinguish between forces going in certain directions because they are vectors and vectors have direction and magnitude.
I’m confused about one thing. I got a fbd and it already has 2 downward forces and 1 upward force. Do I still need to find the gravity force or what? What I do with the 2 downward forces?
4 sure
Why is Fa = -11 not + 11?
Forces are vectors so going left is considered negative
Thank you!
Welcome!