I got 90% for theory work and 100% for practicals in general physics and planning to get at least a 95% in my exam tomorrow. Thank you so much for these videos.
do you never lay awake at night and think oh I still dropped ten percent .to be honest they should have told me,that we regret to inform you that you scored minus ten percent on your lifetime test exam!I might have to sweep floors and scrub toilets for fifty cents an hour! I jest good sir! What a performance,! Imagine if you scored ninety percent with the ladies!you'd be living in Caesar's palace before your nineteenth birthday!ninety percent,? This is a very difficult subject.you didn't, even have the answers in front of you!
New teaching aid called Learning Glass. He's writing normally on the back of a glass pane, the image ricochet's off of a mirror placed diagonally in front of the glass, and then enter's a camera. Without the mirror, everything would appear backwards.
@@carlatteniese2 You can see that his wedding ring is on the hand he isn't writing with, which is traditionally worn on the left hand. He is writing with his right hand, and from his point of view, he is writing normally. There is a mirror between the glass board and the camera, that inverts the video footage.
I have to write an essay about this, and when I looked the three laws of planetary motion elsewhere, it seemed very confusing to me; however, you explained this realllyyy well. Thank you!
2020/7/2 searching for important adds to my E-class project and I feel like I found a treasure in this video.. Thank u veeeeery much mr.matt Anderson best lecture ever 😘👏🏻👏🏻👏🏻👏🏻
حسين علي عبد الجليل كاضم, You're very welcome. Glad you're enjoying the videos. You might also like my new site: www.universityphysics.education Cheers, Dr. A
Idk why but when you talked about helly's comet it really made me enjoy the lesson more because it's so crazy that we might be able to see it in 2061, so crazy! I'm really enjoying this
Pls I have 2 questions: 1. If the sun attracts the earth, and the earth attracts the sun, then why do they not collide? 2. Why do we use Kepler's constant for all bodies in our solar system if they do not all move in a circular orbit but the formula for Kepler's constant includes 4π?
@@yoprofmatt Hello sir.. The whole video and the concept was crystal clear to me but there is this one part that I didn't understand. 08:55 is the part.. How did we reach to this equation and why did we use V?
@@ishac18120 Since the planet is rotating around the Sun, the planet have a circular motion and a centripetal force is acting on the planet. The magnitude F of the centripetal force is equal to the mass m of the body times its velocity squared v 2 divided by the radius r of its path: F=mv2/r. V is the velocity at which the planet is moving so we use V because their will obviously be a velocity when something moves! Hope this helps! :)
The orbits are elliptical because the speed at which the planet's are orbiting the sun prevents them from falling into it , but due to the high speed , they kinda get flung off from the circular orbit and after travelling for a some distance the speed they got after flinging off(idk if am I using the write word here) is lost and the sun's gravity is able to pull them back
Thank you. It makes a lot more sense now.. i am not completely there but getting there, slowly. (Small distraction: How does that "chalkboard" work? Wouldn't it appear backwards on our side?)
Q: When a planet moves a around a star, with different velocities at it’s perihelion and it’s aphelion, does that mean that time on that planet goes slower or faster, because time goes slower when an object moves faster?
Your question regarding the semi-major axis is astute but it turns out that the semi-major axis is the same for a circular or elliptical orbit having the same period. The key is that in an elliptical orbit, one can no longer state that the semi-major axis is equivalent to the radius. It must be defined as 1/2 the length of the entire major axis of the ellipse. Since the Sun does not occupy the center of an elliptical orbit you must shift your perspective away from the circular image provided by Professor Anderson, and envision an ellipse with the Sun at one of its foci. In this case, the Sun’s position has nothing to do with how we measure the semi-major axis.
Professor Anderson has simplified the problem to that of the Earth in a circular orbit around the Sun. This allows for two simplifications. First, the radius r can be assumed to be equal to the semi-major axis. Second, the Sun’s mass far exceeds the Earth so that it can be assumed to be at the center of the circle. There are more general derivations based on the center of mass for both bodies but my attempts to link you to them have been blocked.
Good day! I'd like to ask, Kepler's 3rd Law in valid only in our Solar System or another (solar) systems, too, (most likely) pls ? And how about the g (constant 6,67 x 10^-11) ? Thx
Planetary system is the general term for a group of planets orbiting a parent star. The solar system is the sun's planetary system specifically, since Sol means sun. Kepler's third law is valid in other planetary systems as well, but only among the planets that orbit in that particular planetary system. A hypothetical planet orbiting the sun at 8 AU would have an orbital period of 4 years, which fits Kepler's third law with the planets of the solar system. However, don't expect a planet orbiting a completely different star at the same 8 AU distance to also have an orbital period of 4 years. It is uppercase G that has a value of 6.67e-11 N-m^2/kg^2, and to the best of our knowledge, this is a universal constant. Lowercase g is gravitational field strength, and is specific to an individual world.
He's not actually writing backwards. He uses a mirror between the camera and the transparent board, to film this. Students who see him teach in the flesh, will see the backwards writing on the board. On a screen to the side, they see a live feed of the footage you are seeing, so that the writing is legible.
I believe that Newton's law of Universal Gravitation was derived from Kepler's laws, so 5:01 you said "Kepler's laws are derivable from Newton's law of gravitation" is somewhat inaccurate. With that being said, I still love your videos!
Kepler's laws are derived from Tycho Brahe's observational data. Newton came up with his law of gravitation to prove Kepler's laws, from the fundamentals of how he believed the mathematics of gravity would work. The multiplication of masses in Newton's law of gravitation is a direct consequence from the empirical observation that force of gravity is proportional to mass, and Newton's third law that gravity like all forces is a two way street. The inverse square part of the law comes from the way a field with no divergence would spread out in space from a spherically symmetric source. Putting these together, we get the M*m/r^2 part of his law of gravity, and the big G is a constant of proportionality to make the units work out. Cavendish's experiment, over a century later, was the first to measure the big G.
@Abdullah Orilonise It's a lightboard so he either mirrors the video while editing or has some kind of mirror in front of the camera. From his point of view he is writing normally.
Im an Indian student, but the way our teachers teach us is like they want us to memorise the things and not understand them. Everyone is in a rat race to remember everything for their exams but nobody clearly understands things. But i have to say american teachers do explain well along with yt indian teachers unlike indian school teachers.
Indeed you are correct. We're trying to simplify the physics. Circular orbit is an ellipse of ellipticity = 1. We approximate this to make sense with Newton's laws for circular motion. Since Earth is in a near circular orbit, it works great. Cheers, Dr. A
G MAN, Can you explain a bit more what you mean by that? There are, of course, "flaws" in Kepler's Laws that are only fully explained by general relativity, but it sort of depends on what you call "major." Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
Some you can, some you can't. It's about geometry. The Earth is tilted on its axis. This allows different looks at different times of the year. Polaris is due North so it is always visible in the Northern Hemisphere and never visible in the Southern Hemisphere. The Southern Cross is due south so it is always visible in the Southern Hemisphere and never in the Northern Hemisphere. The Constellation Aquarius lies along the plane of the ecliptic (the plane our planet orbits the Sun in). From 16 Feb to 12 March the Sun will block portions of Aquarius. This would be in daytime. At nighttime, you're predominantly looking away from Aquarius and may only see portions during dawn and dusk.
how would I solve this question: if Kepler's constant for a STAR is 6.00x10^-12 s^2/m^3, what would the mass of the planet be in scientific notation? I've been struggling about it for a while, and can't find a way to isolate mass in the equation with no info on the Period or the Radius: Ta^2/Ra^3=Tb^2/Rb^3. Thank you...
You still helping people after 8 YEARS nice video you explained everything soo good thank you so much!!!
That's the great thing about video. I never go gray.
Cheers,
Dr. A
I got 90% for theory work and 100% for practicals in general physics and planning to get at least a 95% in my exam tomorrow. Thank you so much for these videos.
do you never lay awake at night and think oh I still dropped ten percent .to be honest they should have told me,that we regret to inform you that you scored minus ten percent on your lifetime test exam!I might have to sweep floors and scrub toilets for fifty cents an hour! I jest good sir! What a performance,! Imagine if you scored ninety percent with the ladies!you'd be living in Caesar's palace before your nineteenth birthday!ninety percent,? This is a very difficult subject.you didn't, even have the answers in front of you!
I need help
What you did
You are my favorite physics teacher
Wow, great to hear. Thanks for the comment.
Cheers,
Dr. A
Matt Anderson
Thank you so much
Honestly I wish one day
I will get master degree with you sir
Sounds promising.
Cheers,
Dr. A
i fully agree
YEAH DUDE ME ALSO
After a decade...it is still the most useful explanation...thanks a lot...you make physics interesting
still helping GREATLY after 6 years!
Who else is confused about how he is writing backwards perfectly or is it only me ....
Yeah, this drives me crazy too--and I can write backward and upside down.
Actually, he is doing what we all do; he is writing left to right behind a piece of glass. He happens to be left-handed.
New teaching aid called Learning Glass. He's writing normally on the back of a glass pane, the image ricochet's off of a mirror placed diagonally in front of the glass, and then enter's a camera. Without the mirror, everything would appear backwards.
@@carlatteniese2 You can see that his wedding ring is on the hand he isn't writing with, which is traditionally worn on the left hand. He is writing with his right hand, and from his point of view, he is writing normally. There is a mirror between the glass board and the camera, that inverts the video footage.
The video stream could also be digitally reversed before display.
I have to write an essay about this, and when I looked the three laws of planetary motion elsewhere, it seemed very confusing to me; however, you explained this realllyyy well. Thank you!
I’m middle-aged and taking Life in the Universe. Thank you for this video. It helps me visualize Kepler’s Laws!🙌🏿
2020/7/2 searching for important adds to my E-class project and I feel like I found a treasure in this video.. Thank u veeeeery much mr.matt Anderson best lecture ever 😘👏🏻👏🏻👏🏻👏🏻
حسين علي عبد الجليل كاضم,
You're very welcome. Glad you're enjoying the videos.
You might also like my new site: www.universityphysics.education
Cheers,
Dr. A
After 10 years, this video still helps! Thanks so much for your input!
Crystal clear explanation - Great thanks Prof Matt Anderson
Idk why but when you talked about helly's comet it really made me enjoy the lesson more because it's so crazy that we might be able to see it in 2061, so crazy! I'm really enjoying this
Your explanations are so smooth!
Animesh,
Great comment, thanks.
You might also like my new website: www.universityphysics.education
Cheers,
Dr. A
thanks for your help professor, im working on tomorrows exam and this video really helped, greetings from turkey.
I am so thankful for your great lectures. Was very helpful even after 9 years love from India.
So grateful, cant thank you enough. I wish was thought this way in Secondary school days.
You are great sir
Love and respect from Nepal 🇳🇵 🇳🇵
kundan Poudel,
Thanks for the comment, and keep up with the physics!
You might also like my new website: www.universityphysics.education
Cheers,
Dr. A
Sir you are a very good physics teacher
you are the best !!!! perfect explanation
thank you Dr.
Ha a,
You're very welcome. Glad you're enjoying the videos.
You might also like my new site: www.universityphysics.education
Cheers,
Dr. A
Wait…… I was watching and thinking…and then I realized… ISN’T THIS GUY WRITING MIRRORED TO US???
My 1st year engineering lecturer made me hate physics, you have restored my love for physics
Am I the only one who thinks you look like doctor Strange without facial hair!?
YES! I thought the same thing too.
No he don't
@@xixizang2798 haha...give him a red cloak.
@@lordlwando wow I wrote that comment in my 11th grade...now I'm in a university.
sir, you're amazing
thanks
Thanks for watching!
Cheers,
Dr. A
Your the best physics teacher
i am only 13 but i thought that is video was very easy to understand thanks :)
Pls I have 2 questions:
1. If the sun attracts the earth, and the earth attracts the sun, then why do they not collide?
2. Why do we use Kepler's constant for all bodies in our solar system if they do not all move in a circular orbit but the formula for Kepler's constant includes 4π?
Sir u r amazing but we need deep and deeper explanations and examples of theroms thank u sir yous obediently student
Thanks for the comment. We're working on new stuff.
Cheers,
Dr. A
@@yoprofmatt Hello sir.. The whole video and the concept was crystal clear to me but there is this one part that I didn't understand. 08:55 is the part.. How did we reach to this equation and why did we use V?
@@ishac18120 Since the planet is rotating around the Sun, the planet have a circular motion and a centripetal force is acting on the planet. The magnitude F of the centripetal force is equal to the mass m of the body times its velocity squared v 2 divided by the radius r of its path: F=mv2/r.
V is the velocity at which the planet is moving so we use V because their will obviously be a velocity when something moves!
Hope this helps! :)
That's awesome you lecture behind a smart glass with a bright font
I'm probably not going to make Halley's next appearance, so that's kind of a bummer
All my respect to you sir from Egypt
Hello to my Fandersons™ in Egypt! Thanks for tuning in.
Cheers,
Dr. A
this is extremely helpful... for students post covid
Glad to hear it.
Cheers,
Dr. A
For the first time I can understand this stuff. Thanks Prof. Anderson !
Love u sir tq so much this helped me literally best teacher 😄😄😄😄😃😃😃😃😃😃😃😃😃😃😊😊😊😊😊
You are very welcome.
Cheers,
Dr. A
Thank you very much.
I am your fan + student from Oregon.
Professor but what is the reason for eleptical orbits?
the question is...Why not??
The orbits are elliptical because the speed at which the planet's are orbiting the sun prevents them from falling into it , but due to the high speed , they kinda get flung off from the circular orbit and after travelling for a some distance the speed they got after flinging off(idk if am I using the write word here) is lost and the sun's gravity is able to pull them back
Unbelievable sir Namaste🙏 from India🇮🇳
awesome explanation an osm trick
bro thank you so much I was going to fail the test if it weren't for your videos
Glad I could help.
Cheers,
Dr. A
Is he writing it backwards?
Terrific explanation Sir,
I wish you were my physics teacher
Thanks. I'll just try to be everyone's physics teacher here on RUclips.
Cheers,
Dr. A
sir do you write with left hand and flipped texts ?
I was also wondering how its done. Wether he has backwards whiting skills or if there are clever camera tricks @ play.
This is really helping me for my 10th grade
Thanks sir
Which Technique is used to write on transparent board.
best teacher
Please solve multiple choice questions related topic
You just make this subject very easy and interesting. Thanks
Thanks for the shout out!
Cheers,
Dr. A
Finally I understand Kepler's laws
Great to hear! Now grab your telescope and head to the hills.
Cheers,
Dr. A
Matt Anderson I wish I could do that😓
Cheers for Dr. A thanks Sir for the great explanation
Pralay Pati,
You're very welcome. Glad you're enjoying the videos.
You might also like my new site: www.universityphysics.education
Cheers,
Dr. A
Thank you. It makes a lot more sense now.. i am not completely there but getting there, slowly. (Small distraction: How does that "chalkboard" work? Wouldn't it appear backwards on our side?)
Lol I want to know the same thing
I think it's just video itself mirrored vertically!!
Wonderful sir love from India
Very notch way of teaching
Why do I feel like you are writing the letters backwards and doing it perfectly? 🤯
I think he writes it regularly (from his perspective), and then inverts the video.
@@m1000-n8w Could this be real or is it just your point of view?
Q: When a planet moves a around a star, with different velocities at it’s perihelion and it’s aphelion,
does that mean that time on that planet goes slower or faster,
because time goes slower when an object moves faster?
Really cool video, thanks a lot!
You're very welcome. Keep up with the physics!
Cheers,
Dr. A
thank u very mach for the explanation.....that was awesome...thank u.....
You are great sir
Love you from India ❤❤
Sir can you teach Quantum mechanics
I love Ur teaching
How do you write backwards on the back of that board so it appears normal for us?
Equal areas in equal times is a bit imprecise! It's true only if the origin of the revolving positional vector is the Sun, not the second focus.
Your explanation is so simple😍❤..but i can't understand how radius can be same as semi major axes for elliptical orbits..
Your question regarding the semi-major axis is astute but it turns out that the semi-major axis is the same for a circular or elliptical orbit having the same period. The key is that in an elliptical orbit, one can no longer state that the semi-major axis is equivalent to the radius. It must be defined as 1/2 the length of the entire major axis of the ellipse. Since the Sun does not occupy the center of an elliptical orbit you must shift your perspective away from the circular image provided by Professor Anderson, and envision an ellipse with the Sun at one of its foci. In this case, the Sun’s position has nothing to do with how we measure the semi-major axis.
Professor Anderson has simplified the problem to that of the Earth in a circular orbit around the Sun. This allows for two simplifications. First, the radius r can be assumed to be equal to the semi-major axis. Second, the Sun’s mass far exceeds the Earth so that it can be assumed to be at the center of the circle. There are more general derivations based on the center of mass for both bodies but my attempts to link you to them have been blocked.
thanks for great lecture. But you just show Kepler third law for circular orbit. How it extended for elliptical orbit
Sir what kind of device did you use to write on
please tell me sir 🤔🤔🤔
learning.glass
Good day! I'd like to ask, Kepler's 3rd Law in valid only in our Solar System or another (solar) systems, too, (most likely) pls ? And how about the g (constant 6,67 x 10^-11) ? Thx
Planetary system is the general term for a group of planets orbiting a parent star. The solar system is the sun's planetary system specifically, since Sol means sun.
Kepler's third law is valid in other planetary systems as well, but only among the planets that orbit in that particular planetary system. A hypothetical planet orbiting the sun at 8 AU would have an orbital period of 4 years, which fits Kepler's third law with the planets of the solar system. However, don't expect a planet orbiting a completely different star at the same 8 AU distance to also have an orbital period of 4 years.
It is uppercase G that has a value of 6.67e-11 N-m^2/kg^2, and to the best of our knowledge, this is a universal constant. Lowercase g is gravitational field strength, and is specific to an individual world.
Sir...how can I practice mirror writing like you
He's not actually writing backwards. He uses a mirror between the camera and the transparent board, to film this.
Students who see him teach in the flesh, will see the backwards writing on the board. On a screen to the side, they see a live feed of the footage you are seeing, so that the writing is legible.
@@carultch Thank you
I believe that Newton's law of Universal Gravitation was derived from Kepler's laws, so 5:01 you said "Kepler's laws are derivable from Newton's law of gravitation" is somewhat inaccurate. With that being said, I still love your videos!
Kepler's laws are derived from Tycho Brahe's observational data. Newton came up with his law of gravitation to prove Kepler's laws, from the fundamentals of how he believed the mathematics of gravity would work.
The multiplication of masses in Newton's law of gravitation is a direct consequence from the empirical observation that force of gravity is proportional to mass, and Newton's third law that gravity like all forces is a two way street. The inverse square part of the law comes from the way a field with no divergence would spread out in space from a spherically symmetric source. Putting these together, we get the M*m/r^2 part of his law of gravity, and the big G is a constant of proportionality to make the units work out. Cavendish's experiment, over a century later, was the first to measure the big G.
Sir i dont understand the part where 10:53 T² = 4pie² by GMs r³ turns to T² proportional r³ ? I hope you do have the time answer my question.. , sir.
you rearrange the equation. move t^2 to one side and everything else to the other
More than class ..iam thinking about how they shoot .like wr is camera direction.....
well explained. thank you.
He write in reverse or there is kinda edit
@Abdullah Orilonise It's a lightboard so he either mirrors the video while editing or has some kind of mirror in front of the camera. From his point of view he is writing normally.
Thanku very much sir 😊😊☺.
Tanya Shreee,
You're very welcome. Glad you're enjoying the videos.
You might also like my new site: www.universityphysics.education
Cheers,
Dr. A
@@yoprofmatt 🙂🙂
@@yoprofmatt 🙂🙂
How the sun"s mass was calculated.
(I understand that mass of earth could be calculated by considering "average" specific mass on earth.)
lovely story about the comet
thats a cool looking board
Im an Indian student, but the way our teachers teach us is like they want us to memorise the things and not understand them. Everyone is in a rat race to remember everything for their exams but nobody clearly understands things. But i have to say american teachers do explain well along with yt indian teachers unlike indian school teachers.
Excellent explanation sir
Thank you. Glad to be of help.
Cheers,
Dr. A
Guys, how is his inverted writing so perfect?
how does he write in the board? Does he write backwards ? Or is it a mirror trick?
Ban Nana I’m pretty sure this is a mirror trick.
Top notch explanation
Thanks much.
Cheers,
Dr. A
Thank you so much sir!
Where he is writing.any body knows please explain....
@5:30 eccentricity of 0
Can someone explain why the sum of the forces add up to Sum(F)=(Mp*V^2)/r ??? Thanks
centripital acceleration = v^2/r
accordng to 2nd law of newton f=ma
hence centripital force=mv^2/r
How log does it take to write like that and do it like it was normal Jesus Christ you have m full respect
The video is mirrored
Why derivation for circular orbits when we know that orbits motion is elliptical m???
Indeed you are correct. We're trying to simplify the physics. Circular orbit is an ellipse of ellipticity = 1. We approximate this to make sense with Newton's laws for circular motion. Since Earth is in a near circular orbit, it works great.
Cheers,
Dr. A
Thanks Matt
Paul Crooks,
You're very welcome. Glad you're enjoying the videos.
You might also like my new site: www.universityphysics.education
Cheers,
Dr. A
Hi, how do write flipped?😅
www.learning.glass
Cheers,
Dr. A
Matt Anderson... remember the name👊
شكرا.
How could you write backwards ?
GENDAI UI,
Not writing backwards (I'm not that talented). The board is called Learning Glass. You can check it out at www.learning.glass
Cheers,
Dr. A
How you write
I've actually heard there was a major flaw in keplers laws tho is that true
G MAN,
Can you explain a bit more what you mean by that? There are, of course, "flaws" in Kepler's Laws that are only fully explained by general relativity, but it sort of depends on what you call "major."
Thanks for the comment, and keep up with the physics!
You might also like my new website: www.universityphysics.education
Cheers,
Dr. A
Why has no one commented on the fact this guy is writing backwards
An great sir (he can write left
Fantastic
Nice editing
Thanks, but not sure we had much editing on this one.
Cheers,
Dr. A
Thank youuuuuuuu
how can you see the same stars in the night sky when the earth is on the othe side of the sun in the orbit?
Because gravity bends light so they appear “out of position”
Some you can, some you can't. It's about geometry. The Earth is tilted on its axis. This allows different looks at different times of the year. Polaris is due North so it is always visible in the Northern Hemisphere and never visible in the Southern Hemisphere. The Southern Cross is due south so it is always visible in the Southern Hemisphere and never in the Northern Hemisphere. The Constellation Aquarius lies along the plane of the ecliptic (the plane our planet orbits the Sun in). From 16 Feb to 12 March the Sun will block portions of Aquarius. This would be in daytime. At nighttime, you're predominantly looking away from Aquarius and may only see portions during dawn and dusk.
how would I solve this question:
if Kepler's constant for a STAR is 6.00x10^-12 s^2/m^3, what would the mass of the planet be in scientific notation?
I've been struggling about it for a while, and can't find a way to isolate mass in the equation with no info on the Period or the Radius: Ta^2/Ra^3=Tb^2/Rb^3.
Thank you...
I wanna be in his class
I wish u are my teacher