Instead of looking at f(x) you can study 1/f(x) and since [1/f(x)]' = f'(x)/f^2(x) and f(x) is never 0 in the interval [0,3]. In such a way the computation is much easier since g(x)=1/f(x) = x-1+1/x. g'(x) = 1 - 1/x^2 = (1-x^2)/x^2. Then, x=\pm 1 and only 1 is accettable. f(1) = 1 f(0) = 0 f(3) = 3/7 and so on
For the right most critical point c, you know f(x) must always go up or always down. How much so we don’t know. That’s why the end point is important to check
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Keep up the great work! Struggled with a few problems written in this exact format in my course and you explained everything so clear and concise!
Thanks. I'm glad it helped.
U always make my study easier,,,well explained
the only video that really cleared all my doubts. thank you teacher!
Lagranzh's Theorem say it: if a
Thanks for your great explanation sir
Instead of looking at f(x) you can study 1/f(x) and since [1/f(x)]' = f'(x)/f^2(x) and f(x) is never 0 in the interval [0,3]. In such a way the computation is much easier since g(x)=1/f(x) = x-1+1/x.
g'(x) = 1 - 1/x^2 = (1-x^2)/x^2.
Then, x=\pm 1 and only 1 is accettable.
f(1) = 1
f(0) = 0
f(3) = 3/7
and so on
Always enjoy your videos.👏👏👏
Thanks a lot . Completely understood
Glad it helped.
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thank you this is really helpful and keep on smiling cuz my god you've got a beautiful smile
Excellent expln
For the right most critical point c, you know f(x) must always go up or always down. How much so we don’t know. That’s why the end point is important to check
Porque no se hace ese análisis de crecimiento al resolver un ejercicio de estos, pero ahí está la idea de la demostración de ese teorema.
The goat
Thanks Sir