Sir, I am very thankful for the incredibly clear and logical explanations of the concepts. So many instructors prefer a muscle memory approach. This method makes it easier to apply the information.
I was hoping this was going to be shown in the "long way", however the first part of splitting the equation into 2 individual equations with individual bounds helped answer my question and got you a like.
5:54 why are you including in the second integral the value 3, I thought that X needs to be less than three not equal? Thanks. Mayb form -1 to 3+delta and then limit as delta goes to zero? Or else?
Nice video brother. But the last 2 maths you showed were wrong. Because the functions are not even continuous over the concerned intervals. So they are not integrable and the fundamental theorem of calculus doesn’t apply here. Other than that, your handwriting on the blackboard was very satisfying and the method of evaluating the integrals you showed is gonna help me a lot. Thanks.
there is 2 mistakes done in equation 2 and 3: in equ 2: x cannot be 0, so the condition should be x>0 in equ 3: x cannnot be 1, so the condition should be x>1
I am curious how you got that x can be greater than or equal to 1, in the last example? Doesn't 1 cause a vertical asymptote at x equal to 1? Why didn't you take the limit as x approaches 1 from both sides?
Hi Professor !!!! I have a function with absolute value how can you please help me the following: f(x) = e^|x| + lnx I am asked to calculate . The direction of variation - infinity to + infinity . Definition domain . Calculate the straight line of equation . The equation of the tangent . The area of the function . Graphical representation
I have a question. In the second exercise, we have |x|(x^2+1)/x; and you mentioned that this expression is positive when x > or equal than 0, but what if x=0? Then we will have an indetermination of 0/0. I think that that expression is positive only when x>0 and not equal. Is this right?
Thanks a lot for your video, my exam is about to start in 5 hours. However, for example 3, since F(x)=(x-1)(x+2)/|x-1| is not continuous in the close interval (-2,4) because of x≠1, does the integral not exist?
What would you do if you had the absolute value of x times cos(nx) dx ? I'm not sure how you would seperate this and make 2 integrals of it. But anyways great video enjoyed it very much!
@@PrimeNewtons Damn I guess my calc teacher is giving us hard stuff on purpose because we are expected to find the integral from 0 to pi/2 of |8 sin(x) − 8 cos(2x)| dx
The second and third integrals are improper integrals, because the integrands are not defined over the domains of integration. However, in these cases the integrands are only discontinuous on a point, which means that their integrals can still be evaluated by taking the limits of the integrands at their respective points of discontinuity. For example, since 𝑓(𝑥) = 𝑥 ∕ 𝑥 is not defined for 𝑥 = 0, ∫[−1, 1] (𝑥 ∕ 𝑥)𝑑𝑥 is to be understood as lim 𝑎→0⁻ ∫[−1, 𝑎] (𝑥 ∕ 𝑥)𝑑𝑥 + lim 𝑏→0⁺ ∫[𝑏, 1] (𝑥 ∕ 𝑥)𝑑𝑥. I understand that this was not the topic of this video, but I still find it important enough not to gloss over.
Engineer student here, you saved my life i have my calculus exam tomorrow
You're absolutely great teacher ❤ from Sri Lanka 🇱🇰💐
Gracias Sir.
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Bro💀💀☠️☠️😭😭😭
@@lakshya4876 ??
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Thanks a ton
Thank you for such a thorough, clear explanation. I am taking AP Calculus BC as a rising Junior and this was very helpful. Have a great day!
Good luck!
best explanation I have seen so far. kudos to you!!
Your teaching techniques are so mind blowing & absolutely kind hearted personality ❤🥺
Sir, I am very thankful for the incredibly clear and logical explanations of the concepts. So many instructors prefer a muscle memory approach. This method makes it easier to apply the information.
Those who stop learning have stopped living 😍😍
Hey from Halabja Kurdistan n plz keep up that good job sir
Hi Mr, thank you from Papua new Guinea 🇵🇬
Hello there!
Thanks a lot . I was struggling doing this type of intregrals . You made my day !!! Best of luck
I LOVE YOUR HAT. THIS VIDEO WAS SO AWESOME AND EDUCATIONAL. THANK YOU
Thanks
Your videos have helped me gain confidence in calculus
Hi sir one of your students here😁
Hello @Killer_Queen231
Hi queen killer
Is he a teacher ?
I was hoping this was going to be shown in the "long way", however the first part of splitting the equation into 2 individual equations with individual bounds helped answer my question and got you a like.
I love this guy.
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Thank you
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This was insightful,thank you so much sir
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Gracias por el vídeo. Me gustó. Saludos desde Perú
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thanks a million !
this helped me understand it more .
Glad it helped!
5:54 why are you including in the second integral the value 3, I thought that X needs to be less than three not equal? Thanks. Mayb form -1 to 3+delta and then limit as delta goes to zero? Or else?
Thanks bro. It helps me alot
Highly appreciate excellent explanation. By rhe way, it will be better all math problems to be linked with real world stuff or real-life applications
EXCELENTE EXPLICAÇÃO.PARABÉNS. BRASIL
Thank you!
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Nice video brother. But the last 2 maths you showed were wrong. Because the functions are not even continuous over the concerned intervals. So they are not integrable and the fundamental theorem of calculus doesn’t apply here. Other than that, your handwriting on the blackboard was very satisfying and the method of evaluating the integrals you showed is gonna help me a lot. Thanks.
there is 2 mistakes done in equation 2 and 3:
in equ 2: x cannot be 0, so the condition should be x>0
in equ 3: x cannnot be 1, so the condition should be x>1
You are correct. I should have excluded 0 and 1 respectively
@@PrimeNewtons i love this video, it came in the right time for me, because i have math test next month, thank you
great video and nice hat
thanks uncle 👍🏾
i had no idea thank you
10/10 for explicat°
extraordinary
Thank you!
I am curious how you got that x can be greater than or equal to 1, in the last example? Doesn't 1 cause a vertical asymptote at x equal to 1? Why didn't you take the limit as x approaches 1 from both sides?
Those who stop learning have stopped living I like that 🤔😁
Hi Professor !!!!
I have a function with absolute value how can you please help me the following: f(x) = e^|x| + lnx
I am asked to calculate
. The direction of variation - infinity to + infinity
. Definition domain
. Calculate the straight line of equation
. The equation of the tangent
. The area of the function
. Graphical representation
Very well explained, thank you for this sir!
I have a question. In the second exercise, we have |x|(x^2+1)/x; and you mentioned that this expression is positive when x > or equal than 0, but what if x=0? Then we will have an indetermination of 0/0. I think that that expression is positive only when x>0 and not equal. Is this right?
You are correct. That was a criminal oversight
to the point thanks
can you do (x^2)*(cos(3x)), from 0 to 2 pi?
it will take you long, so im wondering if you can do it quicker
Can you please re-do the equations with the mistakes or refer me to similar videos of yours to show how to correct them?
💓💪
this is cool
for some reason i got 50/3 on example 2?
Try going over each step of your work again. I'm sure you'll find your mistake. You should get -22/3
Thanks
Thanks a lot for your video, my exam is about to start in 5 hours. However, for example 3, since F(x)=(x-1)(x+2)/|x-1| is not continuous in the close interval (-2,4) because of x≠1, does the integral not exist?
Cancel out the (x-1) . The integral exists. That's a removable discontinuity
Wow genial
Could you help me calculus?
🥰🥰🥰
What would you do if you had
the absolute value of x times cos(nx) dx ?
I'm not sure how you would seperate this and make 2 integrals of it.
But anyways great video enjoyed it very much!
You will get that in advanced calculus. So, as far as calculus 2 is concerned, this video is sufficient.
@@PrimeNewtons Damn I guess my calc teacher is giving us hard stuff on purpose because we are expected to find the integral from 0 to pi/2 of |8 sin(x) − 8 cos(2x)| dx
😊
funny how you can learn more from RUclips than in class, lol.
Chimwela
There are so many ads in you videos, jeez
The second and third integrals are improper integrals, because the integrands are not defined over the domains of integration.
However, in these cases the integrands are only discontinuous on a point, which means that their integrals can still be evaluated by taking the limits of the integrands at their respective points of discontinuity.
For example, since 𝑓(𝑥) = 𝑥 ∕ 𝑥 is not defined for 𝑥 = 0,
∫[−1, 1] (𝑥 ∕ 𝑥)𝑑𝑥 is to be understood as
lim 𝑎→0⁻ ∫[−1, 𝑎] (𝑥 ∕ 𝑥)𝑑𝑥 + lim 𝑏→0⁺ ∫[𝑏, 1] (𝑥 ∕ 𝑥)𝑑𝑥.
I understand that this was not the topic of this video, but I still find it important enough not to gloss over.