My mates and I are very grateful for all your videos sir. We appreciate you. My final is after tomorrow, and if I get a good mark, I truly owe some of it to you! Also, I became interested in Physics after understanding it with your simple and interesting explanations.
You know that feeling when you come across a goldmine of a channel... well now I do lmao. These videos are so good, is there any chance you teach Maths AAHL as well?
Resistance can vary in many materials, like gases, electrolytes, semiconductors and even in metals at high current densities. Ohm's law really only works for metals when the current isn't too high but it is nevertheless a very useful formula.
The cross section refers to the cross-sectional area of the wire, which is usually but not always in the shape of a circle. It's a 2D area, not a line like a diameter
My mates and I are very grateful for all your videos sir. We appreciate you. My final is after tomorrow, and if I get a good mark, I truly owe some of it to you! Also, I became interested in Physics after understanding it with your simple and interesting explanations.
So so wonderful to hear, thank you!
You know that feeling when you come across a goldmine of a channel... well now I do lmao. These videos are so good, is there any chance you teach Maths AAHL as well?
Thanks so much! Alas only IB physics
Your teaching are so simple to understand. My first time. You have another subscriber bro. Keep up
thank uou❤❤
Resistance can vary in many materials, like gases, electrolytes, semiconductors and even in metals at high current densities. Ohm's law really only works for metals when the current isn't too high but it is nevertheless a very useful formula.
could you consider resistance to be the speed at which you are losing volts?
In the example isn't the diameter rhe cross section of the wire
The cross section refers to the cross-sectional area of the wire, which is usually but not always in the shape of a circle. It's a 2D area, not a line like a diameter
@@AndyMasley ok so I have to use πr^2 to find the cross sectional area. Thank you sir.
epci