A university accepted me because of the help I got from watching your videos for them and physics... Man, you're a hero throughout my first semester too. I'm sending love and appreciation from South Africa🙏💙
so glad to finally see you with 1 million subscribers! Keep it up bro. I'm 2nd year college with electronics engineering degree. i live in a third world country and I'm doing my best to study hard so that I can help my poor country. Keep helping people, ur doing a very good job.
Your videos have helped me 100% through my physics course. Thank you, it really clarifies the chapter text which can be a bit overkill at times, the concepts it explains. THANK YOU!
This video is so good! I just had a question... Are there standards for the temperature coefficient of materials? Could you theoretically work out the resistance of wires at a certain temperature without knowing the specific temperature coefficient?
Thank you so much for this video, I was stuck on a problem involving the top equation at the 11 minute mark. I was given the resistances and one of the temperatures and I had to find the other T and I never would have been able to do it without you showing the bottom equation in the red box with R instead of rho. Thanks again!
I'm scholar in agricultural mechanisation but I need you to upload all videos support in electrical engineering component in basic engineering module , however,. you exceptional tutor.thanks
Air conditioning units are mostly used during summer period. A simple electrical circuit may represent the set-up of the aircon: a rheostat connected in series with the whole cooling mechanism (represented by a single resistor) and these combination is then connected in series with the power switch. The whole circuit is supplied by a 220 V power supply. The following are the values of the components: rheostat (10 ohms to 10,000 ohms) and the cooling mechanism (100 ohms). By theory, the higher the power consumption of the cooling unit, the higher the current flowing in the cooling mechanism. Given the following scenarios, answer the following: b) Let us assume that the current value of the rheostat is 1000 ohms. Assuming that the value of the total current represents the current temperature (2 A for 18 degrees and 0.2 A for 25 degrees). Draw the electrical diagram and calculate the temperature at 1000 ohms.
May God bless you so much sir , my brother who is now in his 3rd year in medicine recommended you to me , and I'm 14 years and im in my finals I'm about to enter University but it's a bit hard for me and because of God and your help I will pass , your videos help us a lot ❣️ you can't imagine how grateful I am
Hi, just a question to do with the difference between single-core cable and twin cable. If you have a Cross-Sectional-Radius (CSA) on a cable of 2.5mm and it is a twin cable, do you double the Cross-Sectional-Raduis (CSA) to 5mm as you are sending a set voltage( Let’s say 230v for me in the UK) down 2 cables, in which case you half the voltage as it’s going down 2 separate cables? Because this would then change the value of resistance at the end of the circuit. Cheers
I have a question, I'm working through my Electrotechnics N4 model now and am busy with resistivity. I have the length of a wire which is 25 but in my example in the handbook, where R=PL/A, they still timed Lx2 to give a length of 50m which I don't understand why. Think you can help?
Someone clear my confusion please. Isn't R0 supposed to be the resistance at 0 C?? So, aren't we su[pposed to do it the other way?The alpha s will cancel and then by putting the values we can get the answer. In my book, two different tempuratureds are given and one of the resistance in one of those two twmpuratures are given. We are asked to find tempurature coefficient. So, they didn't put the 25C (which is R1) in place of R0..cuz that's suppposed to be the resistance at 0C.
Given Rm = .74 @ 20 Celsius, what will Rm equal at BHT if Total Depth is 2400m and the Geothermal Gradient is 2 Celsius/100m (Surface temperature 20 Celsius) ?
Thank you so much! I have a question at 16:50 when you wanted to calculate voltage drop for a 300m copper wire length. Why did we divide V by 15 when we wanted to calculate voltage drop for 15 meters, but then multiply it by 300 when we wanted to calculate voltage drop for 300m? Shouldn't we take the original resistance at 20 C (1.783 mv) and divide it by 300m instead?
Hello, I was hoping you could help me possibly. I was planning on maybe getting into some silver and gold purchases and learned of the rather large problem with fake metals being placed inside gold and silver products . However I also learned that there is a device called a sigma metalitics precious metals verifier the will test metals authenticity based on resistivity. Well knowing that the multimeter tool from the store costs like 40 bucks and measures resistivity ohms and all that stuff and that this gold tester costs over $2,500 dollars I was wondering,.... well I've been pondering that there must be a way using equations such as yours to verify a metal resistivity and thereby the metal itself since they all have a different resistivity .... such as taking a reading from the multimeter and then performing an equation on it that should always come out to that metals exact resistivity..... otherwise it would not be authentic gold or silver.... There has to be a way... that must be what they are doing with the expensive machine.... im sure you figured out by now I am wanting to use the resistivity test using the math equations and $40 tool rather then the $2500 dollar tool. What equations' for a coin and bar would I use.... always at room temp... to determine if the metal is authentic.... I am thinking that if I know the equations I should be able to use a multi meter and do the calculations myself with a calculator rather than paying 2500 dollars for something to do the calculations for me.. That's one high priced calculator. Please let me know and Much Thanks For Any Help You Can Provide to me!!!!!!
Hi,can somebody help me with this problem?Intensity of the electric field in steel wire of cross-sectional diameter 0.8mm equals 20 mV/m. Find the current flowing in it if the resistivity of steel is 1.2·10^-7 Ω•m (pi=3)
Using ohm's law V=IR, U can find that I=V/R where V is given and to find resistance R use the formula R=P(resistivity given)L/A.But I can't help u how to find L.
metal on heating expands. so, larger the wire more will be the resistance. that's why metal resistance increase with increase in temperature right? is this correct? can we use this reason? :/ help!
use the water analogy. voltage is pressure current is water resistance is the valve or in this case wire. longer the pipe the more water is needed to get to the other side meaning higher resistance. smaller pipe will transfer even less current/water so higher resistance and vice versa
At min 12.56 you calculate the area as pi(3*10^-3)^2 but we got told to do pi(3*10^-6) Which gives you a different result. I had this same thing repeated in university as well.
Final Exams and Video Playlists: www.video-tutor.net/
Hello Sir! Can you recommend me some books where I could find some more practice problems about this?
Thank you!
I suppose that you are the super hero of engineering students sir thanks a lot.
Bruh not just eng students learn through this channel😳
We are facing this in class 10🙄
harbı varya bu adam olmasa fizikten kalırdım
@@yunusemreaslan3016 ben yine de kaldm.d
Mid term in a few hours lmao
A university accepted me because of the help I got from watching your videos for them and physics... Man, you're a hero throughout my first semester too. I'm sending love and appreciation from South Africa🙏💙
so glad to finally see you with 1 million subscribers! Keep it up bro. I'm 2nd year college with electronics engineering degree. i live in a third world country and I'm doing my best to study hard so that I can help my poor country. Keep helping people, ur doing a very good job.
goodluck :)
That's a very positive mindset. It's nice that you want to contribute to your country. Good luck!
good luck!! i hope everythings going well
good luck brother
hru
You are the BEST. Only reason I got an A in Physics I. Thanks man!
Your videos have helped me 100% through my physics course. Thank you, it really clarifies the chapter text which can be a bit overkill at times, the concepts it explains. THANK YOU!
Are calculators allowed?
i only watched this guy for math tutorials but it turns out he has videos on literally everything
I'll be taking the Electrical Engineering board exam on April 24-25, 2024. You helped me a lot. Praying that I pass the exam. ❤❤❤
How did it go
How did you do?
You passed?
Currently you are one of the only ways I am learning electrotech right now because our teacher does screw all, thank you.
Loving this guy even more as I watch him explaining
If such mentors are available in a country then this is definite that the country would never decline....
You are a god! My teacher couldn't even teach me this and I've been doing this in college for the last 4 weeks!
Good Job ! this channel is just making an ausome progress ..
thank you so much for these videos!! i always study by watching them they are so clarifying
This video is so good! I just had a question... Are there standards for the temperature coefficient of materials? Could you theoretically work out the resistance of wires at a certain temperature without knowing the specific temperature coefficient?
thank you so much for posting this video. this is very helpful and useful and clear!!!
Thank you so much for this video, I was stuck on a problem involving the top equation at the 11 minute mark. I was given the resistances and one of the temperatures and I had to find the other T and I never would have been able to do it without you showing the bottom equation in the red box with R instead of rho. Thanks again!
This video is so helpful! It is clear and understandable in my difficultyies.
good job-havnt done physics in 30 years
helped me a lot since high school and still now in college thanks!
Nice video . Understood everything .
Keep up the good work .
I'm scholar in agricultural mechanisation but I need you to upload all videos support in electrical engineering component in basic engineering module , however,. you exceptional tutor.thanks
Learnt so much in such a small period of time thank you
I totally agree. Our teacher hardly teaches our class but this has helped me alot.
Nice video! Good explanation. Very concise, straight to the point as I like it :3
watching your videos from India
Thanks for your help
i'm excited to use this to my day to day life yay!
These videos are helpful 😩❤️❤️🔥Thank you very much sir
Thanks so much sir may God bless you 🙏💯 you're a super hero for engineering students salutations 💯✅
Air conditioning units are mostly used during summer period. A simple electrical circuit may represent the set-up of the aircon: a rheostat connected in series with the whole cooling mechanism (represented by a single resistor) and these combination is then connected in series with the power switch. The whole circuit is supplied by a 220 V power supply. The following are the values of the components: rheostat (10 ohms to 10,000 ohms) and the cooling mechanism (100 ohms). By theory, the higher the power consumption of the cooling unit, the higher the current flowing in the cooling mechanism. Given the following scenarios, answer the following:
b) Let us assume that the current value of the rheostat is 1000 ohms. Assuming that the value of the total current represents the current temperature (2 A for 18 degrees and 0.2 A for 25 degrees). Draw the electrical diagram and calculate the temperature at 1000 ohms.
In 30 sec answer many of my question. Thanks a lot!
Thank you so much! You're a lifesaver 😁😁😁😁
May God bless you so much sir , my brother who is now in his 3rd year in medicine recommended you to me , and I'm 14 years and im in my finals I'm about to enter University but it's a bit hard for me and because of God and your help I will pass , your videos help us a lot ❣️ you can't imagine how grateful I am
why are you going to entry university at 14? Enjoy your childhood, best years of your life
Hi, just a question to do with the difference between single-core cable and twin cable. If you have a Cross-Sectional-Radius (CSA) on a cable of 2.5mm and it is a twin cable, do you double the Cross-Sectional-Raduis (CSA) to 5mm as you are sending a set voltage( Let’s say 230v for me in the UK) down 2 cables, in which case you half the voltage as it’s going down 2 separate cables?
Because this would then change the value of resistance at the end of the circuit.
Cheers
You teach better than my old grandpa teacher
I have a question, I'm working through my Electrotechnics N4 model now and am busy with resistivity. I have the length of a wire which is 25 but in my example in the handbook, where R=PL/A, they still timed Lx2 to give a length of 50m which I don't understand why. Think you can help?
You are a wonderful teacher 👏👏
I love people like you. Always helping other people understand!
It helped me a lot thank you
Someone clear my confusion please. Isn't R0 supposed to be the resistance at 0 C?? So, aren't we su[pposed to do it the other way?The alpha s will cancel and then by putting the values we can get the answer. In my book, two different tempuratureds are given and one of the resistance in one of those two twmpuratures are given. We are asked to find tempurature coefficient. So, they didn't put the 25C (which is R1) in place of R0..cuz that's suppposed to be the resistance at 0C.
Thanks for helping me for the electrical technology course finals, tomorrow is exam wish me well.
May Allah give u more knowledge brother.
Awesome lesson 😌💯💯💯
Given Rm = .74 @ 20 Celsius, what will Rm equal at BHT if Total Depth is 2400m and the
Geothermal Gradient is 2 Celsius/100m (Surface temperature 20 Celsius) ?
You're amazing. Much better than my professor!
Thanks a lot 🙏
You are so cool, JG.
I'm so thankful to you.
Thank you so much!
I have a question at 16:50 when you wanted to calculate voltage drop for a 300m copper wire length. Why did we divide V by 15 when we wanted to calculate voltage drop for 15 meters, but then multiply it by 300 when we wanted to calculate voltage drop for 300m? Shouldn't we take the original resistance at 20 C (1.783 mv) and divide it by 300m instead?
0.119 mV is voltage per meter so for 300meters will be 0.119 x 300
I got temp as 34.7 . Is it close enough cause I don't want to use more than 2 decimal places (I can't use calculator in exams)
Thanks that's fantastic
Excellent. Thank you for your efforts.
Thank you so much
Thanks dude! Woot woot
You are the best
Teacher forgot by saying 'p' for resistivity throughout , it's actually greek 'rho' ( Greek R )
Thanks a ton! Keep up your good work👍
No problem
We say thank you as MULUNGUSHI UNIVERSITY students, Zambia ❤
im in need of a calculator for my exams, got any suggestions on what to buy, scientific or Graphical?
this was a very great video and i learnt a lot from you today, thanks .... But what's up with the siren from 14:00 to around 14:40
bravo. could you please make video also for callendar van dusen constant?
Is it necessary to press the "ENG" button on the calculator in getting the final answer? For what I know the answer is still the same.
በጣም ምርጥ ነው from Ethiopia ❤❤❤
Thanks for explaining so succinctly. Understood everything
Is there a technique to memorizing resistivity of materials
Find the resistance of an iron rod 2 cm in diameter and weighing 3 kg.?
i fing love you , can you post some question to solve ? that would be great as a practice work . thanks in advance
How to know what will be the P's value?
I am trying to calculate alpha in my course, i am just missing the algebra steps and cant find it anywhere
This Guy kicks ass
Dude you're amazing....
Thank you
Hello, I was hoping you could help me possibly. I was planning on maybe getting into some silver and gold purchases and learned of the rather large problem with fake metals being placed inside gold and silver products . However I also learned that there is a device called a sigma metalitics precious metals verifier the will test metals authenticity based on resistivity. Well knowing that the multimeter tool from the store costs like 40 bucks and measures resistivity ohms and all that stuff and that this gold tester costs over $2,500 dollars I was wondering,.... well I've been pondering that there must be a way using equations such as yours to verify a metal resistivity and thereby the metal itself since they all have a different resistivity .... such as taking a reading from the multimeter and then performing an equation on it that should always come out to that metals exact resistivity..... otherwise it would not be authentic gold or silver.... There has to be a way... that must be what they are doing with the expensive machine.... im sure you figured out by now I am wanting to use the resistivity test using the math equations and $40 tool rather then the $2500 dollar tool. What equations' for a coin and bar would I use.... always at room temp... to determine if the metal is authentic.... I am thinking that if I know the equations I should be able to use a multi meter and do the calculations myself with a calculator rather than paying 2500 dollars for something to do the calculations for me.. That's one high priced calculator. Please let me know and Much Thanks For Any Help You Can Provide to me!!!!!!
Thanks a lot
thank you i love you
Hi,can somebody help me with this problem?Intensity of the electric field in steel wire of cross-sectional diameter 0.8mm equals 20 mV/m. Find the current flowing in it if the resistivity of steel is 1.2·10^-7 Ω•m (pi=3)
Using ohm's law V=IR, U can find that I=V/R where V is given and to find resistance R use the formula R=P(resistivity given)L/A.But I can't help u how to find L.
could someone explain how 9:31 . how to compute it? i still dont understand
nice work👌👌👌keep doing...... Nice class 👌👌👌👍👍👍👍
god bless you
How do u write it on a calculator? Im getting a different answer...
what if it the material was not stated in the problem but it gives the ohms
Fucking goat bro, You teach hard things in such simple way that u can teach a 5th grade these and they will understand. Keep up the good work bro
super
should have paid my college tuition to you🤣thanks a lot OCT
metal on heating expands. so, larger the wire more will be the resistance. that's why metal resistance increase with increase in temperature right? is this correct? can we use this reason? :/ help!
U r right 🙂
Thank you!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! GOD!!!!!!!!!!!!!!
You are amazing!
1:11 2) the energy that is present in the electrons when travelling from source to end point is lost midway so not all electrons will pass through
use the water analogy. voltage is pressure current is water resistance is the valve or in this case wire. longer the pipe the more water is needed to get to the other side meaning higher resistance. smaller pipe will transfer even less current/water so higher resistance and vice versa
I always have trouble knowing if "A" in a formula is the area of a cross section, or the surface area.
Instead of writing “a” or whatever the format of the equation is I write the formula out with words so I know for sure that it’s not gonna mix up.
Thanks helped alot....
At min 12.56 you calculate the area as pi(3*10^-3)^2 but we got told to do pi(3*10^-6) Which gives you a different result. I had this same thing repeated in university as well.
You have to square everything in the brackets, so (3*10^-3)^2 becomes 9*10^-6 rather than (3*10^-6)
New superconductor just dropped, feeling curious
is not the formula in Area is. pie(d)^2/4 ??
Very nice explanation 👌👌but in very low voice 😔😔
THANK YOU⭐️!
Very nice explanation but very low voice recording
may i ask up on the problem 13:05 , how did u get 0.008913 while mine is 0.008917?
May be you did a mistake while doing the math
May be you did a mistake while doing the math
Thanks I’m studies Biomedical Engineering
I just love how he doesn't like any comment or heart it / pin .
Just reading it nd being happy