Using Cis/Trans versus E/Z to Describe Double Bonds

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Study Guide: worksheets.joec...
In this video, we'll clear the air as to when you can use cis/trans, E/Z, or neither when describing a double bond. What you'll see is that cis/trans terminology works in specific situations, and E/Z is more generally and can always be used. However, we'll see how both can be utilized with tons of examples.
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Not even taking ochem anymore but I love your energy! I know you must be helping so many struggling students out there!

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finally found a video with better details on this. I swear some people come onto youtube explaining stuff in a way that they assume people already know. Thank you so much for breaking this down even further, this makes so much more sense now!

[@paulchegele2678]

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Omg I have been looking and rereading this section in my text book for like half and hour and this video made me understand it instantly I’m so glad I found it!! Thank youuuu

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[@Hh-lc6ui]

at 4:49, you said there was hydrogen, but is it not a carbon? or I guess methyl group?

[@jorgelopez6594]

at 4:40 for the 5th molecule I am a little confused. Wouldn't that like where you said "it is a hydrogen" represent another carbon?

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Love from India

[@Xenqor]

Why did you use e/z naming at 10:40 when there is a methyl on both carbons at the double bond? Thanks if you can reply. The rest of the video was really helpful

[@jOeCHEM]

Hi @Xenqor ! So take a second look at that double bond: Those two methyl groups are on *opposite* sides of the double bond. If the two methyl groups were on the SAME carbon, then you would be right and E/Z terminology wouldn't apply. But those two methyl groups are on different carbons, so we can use E/Z terminology.

[@Sean-fw1oo]

@@jOeCHEM But doesn't this satisfy cis/trans criteria #2 "a matching group on both carbons across the double bond"? So can we say that this is Z according to E/Z terminology, but it's also cis because the methyl groups cross the dotted line? So it is both Z and cis? Or does E/Z take priority in this case?
Also, is it possible to have a molecule that is both E and cis? Like (F)(CH3)C = C(F)(Br) where F on the left is the highest priority and Br is the highest priority on the right and they are E (opposite). But then the two F's on each side of the double bond are a "matching group on both carbons across the double bond" so then it's also cis.

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[@gabrielgalindo2437]

4:58 you say you have a hydrogen to the third carbon (though it’s a methyl) is it supposed to be a hydrogen?

[@backseatoftherollstruck]

nah its just a methyl, assuming you talking about 4:48

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