How to use the shortcut for solving elastic collisions | Physics | Khan Academy

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  • Опубликовано: 28 июл 2016
  • In this video, David solves an example elastic collision problem to find the final velocities using the easier/shortcut approach.
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Комментарии • 39

  • @kyratulamira
    @kyratulamira 6 лет назад +24

    this actually works, thank you so much! wish me luck for my finals next week :)

  • @Hollowfires
    @Hollowfires 7 лет назад +9

    Thank you so much. This was extremely helpful.

  • @chronic295
    @chronic295 7 лет назад +1

    Phenomenal work! This is quite valuable.

  • @jaffarkeikei4323
    @jaffarkeikei4323 6 лет назад

    This' wonderful, gonna prove to Physics teacher

  • @vikthorjon6592
    @vikthorjon6592 6 лет назад +1

    This is gold 👑👑👑👑❤❤❤❤

  • @SuckerforMetal
    @SuckerforMetal 7 лет назад +3

    Thank you for your clear explanation, our prof didn't explain this but he still put it in our midterm

  • @osama3195
    @osama3195 3 года назад

    Thank you 🖤🖤

  • @fentaboy4769
    @fentaboy4769 3 года назад

    Thankx

  • @nicolaigetz3841
    @nicolaigetz3841 4 года назад

    Beautiful

  • @FrankishHistory
    @FrankishHistory 7 месяцев назад

    Thank you Khan, I'm going to pass my momentum test in my physics class

  • @gridpaper2980
    @gridpaper2980 2 месяца назад

    THANK YOU

  • @hotyogaoceanave8778
    @hotyogaoceanave8778 3 года назад

    Thank you for making that video
    I totally understood it
    Only request is if you could enlarge your writing
    Wow thk you

  • @tomertiferet2002
    @tomertiferet2002 5 лет назад

    Does it keep its value with springs?

  • @nicholasgalliano8541
    @nicholasgalliano8541 Год назад

    Thanks for this - however, how would this work if the balls were heading from different angles and hitting at a specific angle at point of collision?

  • @houndcake1
    @houndcake1 6 лет назад +1

    Once again, Khan Academy saves my butt. Thanks guys

  • @jhuvezbiyok8175
    @jhuvezbiyok8175 2 года назад

    What's the formula if you have to find the velocity of the second object?

  • @terrellstarks7088
    @terrellstarks7088 5 лет назад +5

    Where can I find the derivation for this handy shortcut ?

    • @perspective8369
      @perspective8369 3 года назад

      I have the same question

    • @videoupload6898
      @videoupload6898 3 года назад

      ruclips.net/video/9yXrEZy5WME/видео.html

    • @videoupload6898
      @videoupload6898 3 года назад

      @@perspective8369 ruclips.net/video/9yXrEZy5WME/видео.html

  • @MegaJayLover1
    @MegaJayLover1 5 лет назад +1

    how come this only work with some problems? i tried it with a problem of mine and it gave completely wrong answers (and yes i checked my work, all calculations are correct)

  • @PhoenixNTZ
    @PhoenixNTZ Год назад

    My teacher is saying that there is 2 sets of solutions. Can I use this method to find both sets? If so, how?

  • @yumi-jx5nz
    @yumi-jx5nz 5 лет назад

    what if the mass is unknown?

    • @samuelknight618
      @samuelknight618 Год назад

      If the mass is unknown there is no way of calculating the final velocities if just the initial velocities are known. The final velocities would be very different between a tennis ball and a golf ball and a tennis ball and a bowling ball, even if they were travelling at the same initial velocities.

  • @interview1296
    @interview1296 3 года назад +1

    Wat

  • @kristendelgado7933
    @kristendelgado7933 4 года назад +1

    I thought tennis balls would not be considered elastic collisions because some kinetic energy is lost in the deformation of the tennis ball when it hits the golf ball??
    Billard balls = elastic collisions
    Tennis balls = inelastic collisions

    • @dr.c.meenakshi1651
      @dr.c.meenakshi1651 3 года назад

      we just consider

    • @R4G3L3GiTSn1PZ
      @R4G3L3GiTSn1PZ 3 года назад

      There's a reason why in physics and similar classes you see the phrase "we will assume..." . Really messes up visualizing problems for me though lol

  • @aryensujjan
    @aryensujjan Год назад

    Do problems in reference to center of mass it takes 10 seconds

  • @DanHartwigMusic
    @DanHartwigMusic 7 лет назад +3

    Very nicely done, but please mind significant figures. The masses only provide 2 sig figs total. Very technically, we only can provide an answer up to 1 sig fig because 40 m/s and -50 m/s only provide one.
    Written as 4.0*10^1 m/s and -5.0*10^1 m/s provide 2 sig figs, which would still yield -38.64 m/s and 51.36 m/s technically incorrect.
    The final answers should be
    Vtf = -39 m/s, and
    Vgf = 51 m/s
    in that case.

    • @TheScienceCube
      @TheScienceCube 6 лет назад +4

      Hey Daniel, you're absolutely correct but I guess it is more about the concept than the math :)

    • @michaelmcdonald3427
      @michaelmcdonald3427 3 года назад +1

      this is actually kind of useful, thank you

  • @briansanchez6699
    @briansanchez6699 Год назад

    I owe you an an apology

  • @tauseefmalik551
    @tauseefmalik551 5 лет назад +3

    What is trick in that fool.
    It comes from conservation of energy.