How to use the shortcut for solving elastic collisions | Physics | Khan Academy
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- Опубликовано: 28 июл 2016
- In this video, David solves an example elastic collision problem to find the final velocities using the easier/shortcut approach.
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this actually works, thank you so much! wish me luck for my finals next week :)
How was your finals?
Thank you so much. This was extremely helpful.
Phenomenal work! This is quite valuable.
This' wonderful, gonna prove to Physics teacher
This is gold 👑👑👑👑❤❤❤❤
Thank you for your clear explanation, our prof didn't explain this but he still put it in our midterm
same
Thank you 🖤🖤
Thankx
Beautiful
Thank you Khan, I'm going to pass my momentum test in my physics class
THANK YOU
Thank you for making that video
I totally understood it
Only request is if you could enlarge your writing
Wow thk you
Does it keep its value with springs?
Thanks for this - however, how would this work if the balls were heading from different angles and hitting at a specific angle at point of collision?
Once again, Khan Academy saves my butt. Thanks guys
mine too
What's the formula if you have to find the velocity of the second object?
Where can I find the derivation for this handy shortcut ?
I have the same question
ruclips.net/video/9yXrEZy5WME/видео.html
@@perspective8369 ruclips.net/video/9yXrEZy5WME/видео.html
how come this only work with some problems? i tried it with a problem of mine and it gave completely wrong answers (and yes i checked my work, all calculations are correct)
Was it a elastic collision problem
My teacher is saying that there is 2 sets of solutions. Can I use this method to find both sets? If so, how?
what if the mass is unknown?
If the mass is unknown there is no way of calculating the final velocities if just the initial velocities are known. The final velocities would be very different between a tennis ball and a golf ball and a tennis ball and a bowling ball, even if they were travelling at the same initial velocities.
Wat
I thought tennis balls would not be considered elastic collisions because some kinetic energy is lost in the deformation of the tennis ball when it hits the golf ball??
Billard balls = elastic collisions
Tennis balls = inelastic collisions
we just consider
There's a reason why in physics and similar classes you see the phrase "we will assume..." . Really messes up visualizing problems for me though lol
Do problems in reference to center of mass it takes 10 seconds
Very nicely done, but please mind significant figures. The masses only provide 2 sig figs total. Very technically, we only can provide an answer up to 1 sig fig because 40 m/s and -50 m/s only provide one.
Written as 4.0*10^1 m/s and -5.0*10^1 m/s provide 2 sig figs, which would still yield -38.64 m/s and 51.36 m/s technically incorrect.
The final answers should be
Vtf = -39 m/s, and
Vgf = 51 m/s
in that case.
Hey Daniel, you're absolutely correct but I guess it is more about the concept than the math :)
this is actually kind of useful, thank you
I owe you an an apology
What is trick in that fool.
It comes from conservation of energy.