Position vs. Time Graph - Part 2
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- Опубликовано: 10 окт 2024
- Mr. Andersen shows you how to read a position vs. time graph to determine the velocity of an object. Objects that are accelerating are covered in this podcast. He also introduces the tangent line (or the magic pen).
My Physics teacher quit a week before school started. We are now 3 weeks into the semester and surviving off of your videos while the school figures out what they are going to do. So, thank you. You're saving my grade point.
II'm an aspiring engineer in my first year at university here in the UK. These videos are great for learning and you've done a great service for a lot people. Thank you for helping me and everyone who likes science!
man you have style, capacity, and good will to teach and that is very good for us who don't have the means to complete the education plan. Thanks, and may God give more
best. teacher. ever. literally no other physics video I have found EXPLAINS anything, they just say everything that is a rule or fact in physics eg "acceleration = change in time(change in velocity)" then they stop, that's it, not explanation. For my example its obviously simple but for everything else it is super frusterating! THANK YOU for actually making the information MEAN something.
Thank you for taking the time to put together these videos. I think they are great resources to use in my calculus class. THANK YOU!
HALELUYA HAAAALELUYAH I can't believe I found you again. My physics teacher is the worst and I am so happy you did a series on this.
ouchie
Notes:
-Slope of line always tells you the velocity
-If the line is below zero it is a negative velocity
-If the line is above zero it is a positive velocity
-If there is no slope there is no velocity
-If the slope of a line increses then the velocity increases
-If you ever get a curved line on a graph it with means the velocity is slowing down or speeding up
-A line that is perfectly parallel to the graph is called a "Tangent line."
-If a line is going down it means it's increasing but it's INCREASING IN THE NEGATIVE
- We always have an acceleration to the point of the earth 👉🏾 🌍🌎
I love your classes. I have got passionated about physics (thanks in part to you, thank you!) and broke down fears of not understanding. Would you make a class on the dynamics of motor control or dynamical system theories? Trying to get to differential equations and dynamical system to apply in my field of research (language acquisition in children). Would be forever grateful!
I think the more important question here is...
Who is the moving man?
youve taught me more in 20 minutes than my teacher has in a year!
Science is awesome if Mr. Andersen is your teacher!!
So in part 1, when you were graphing the velocity graph, you calculated the change in position over the change in time. You then drew a straight line to indicate a constant speed but at the slope over the time duration. part 2, it looks like you are doing it differently because the slope from 0-3 seconds is -5/2. So I was expecting to see a straight line at the value -5/2 on the time interval between 0-2s
where is the video you talked about in the end of this video ! i really need it
thank you so much for these amazing videos !!! i don't know why do i have to go to school when i can get educated by you here ;)
I'm still so confused 😭 I understood part one, but now I'm clueless
Awesome video. This is a great help! Thank you!
thanks a lot, the first part was really helpful. especially illustrating using the moving man
thanks a lot, this is very helpful in reviewing for online classes
You lost me around 8 minutes. Is there any way you could explain how to make that graph again? If you get the chance, it is much appreciated. Your videos are wonderful, great work!
Love your videos but... this one would be better if you had a curve around 7 seconds showing how the object speeds up from zero to a high negative velocity instead of having an instantaneous change in velocity that is so severe. Just my two cents worth (from years of teaching physics). I'm talking about the first graph at the beginning of the video.
Thank you!!
When the position go from positive to negative, shouldn't the velocity go down in 8:12
This is directed to those who are still confused.
1. From what we know about the "magic pen", as the pen shifts to become more horizontal, the slope, and therefore velocity, decreases.
2. By analyzing the initial curve in the position-time graph, the slope is decreasing (if you want, you can try multiple points along the curve from (0,3) to (2,-3) and you will notice the slope decreases).
3. From this, we know that on the velocity-time graph, arriving at the point (2, 0), or on the position-time graph (2,-3), the velocity is also decreasing. Once again, this is because, the slope decreases.
4. The movement in the position-time graph from (0,3) to (2,-3) is in a negative direction. In turn, the velocity is also going to be negative (*if it helps, pretend the curve isn't there and think of it as just a straight line. From that straight line, calculate average velocity. This will give -3m/s, and therefore on a velocity-time graph, from 0 to 2 seconds, you would graph a horizontal line along -3m/s from 0 to 2 seconds). This is why, in turn, the velocity starts in the negative.
5. Gradually, as time passes, the velocity decreases, which is why the velocity moves towards the origin.
6. In summary, this illustrates why the velocity moves from the negative to the origin.
I'm just gonna rewatch this until my science exam tomorrow and hope I don't fail
how as the exam ? x
This has helped me so much thanks
Can you please help??? I wanted to know if you can upload a video on motion maps and position versus time graphs. I watched your video on position versus time graphs but I have a question on motion maps can you help me?
so if you do rise over run for the second slope isn't it -1.5? i do understand why he is saying it is a positive slope because its going up but ... ?
can someone help me understand where he got the -9.8 m/s^2 in the acceleration graph? did he use the formula or can I count it on the graph?
Hmm not correct at the end. The velocities do not "bounce back" to the same values. They are clearly less each time as shown by the gradients of the position/time graph...
And the acceleration should spike upward to an extreme positive during every bounce, when it reverses direction.
Thank you very much! :) Why cant you replace my current physics teacher?!
I think you have an error. At t = 11 minutes, the second hump has a less steep slope than the first where they touch the x axis. So they second hump of your saw tooth should have less amplitude as the velocity does not get as high. For the third hump it should have even lower amplitude.
:( where is part 3
Agreed! These first two were awesome, now I need help on acceleration time graphs!
Hey mr I don’t understand how you can calculate the velocity on a curving p-t graph but if you can reply to my comment;
1) is it possible to graph it properly
2) if possible can you pls make a video on it
I
i wish you taught physics at my school
What program do you use for recording and drawing?
Hi!! At 9:29 isn't the velocity time graph is also supposed to be curved???
If this is a bouncing ball, in free fall between bounces, the answer is no. It should have a linear v vs t graph, because it has constant acceleration any time it is not in contact with the ground.
One thing to correct about his v vs t graph, is that it shouldn't reverse the velocity 100%, but should only reverse it partially, to what appears to be about 70% of the original speed after each bounce. Another thing to correct is that the acceleration should spike upward at every bounce, when it reverses velocity. Of course, on this graph, it isn't possible to show how high it would need to spike.
No. Science is awesome.
what