Position, Velocity and Acceleration

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  • Опубликовано: 15 сен 2024
  • 059 - Position, Velocity, and Acceleration
    In this video Paul Andersen explains for the position of an object over time can be used to calculate the velocity and acceleration of the object. If a net force acts on a object it will experience an acceleration.
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    Music Attribution
    Title: String Theory
    Artist: Herman Jolly
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    All of the images are licensed under creative commons and public domain licensing:
    “Parachuting.” Wikipedia, the Free Encyclopedia, September 15, 2014. en.wikipedia.or....
    Pigheart. Skydiving, Formation Practice and Parachute Release., 2013. Gopro camera. commons.wikimed....

Комментарии • 34

  • @omari6108
    @omari6108 Год назад +3

    I just need to say, I’m high right now, and your skydiving analogy blew my mind right now. I literally saw the people as positions moving through space, acceleration making them fall faster, and them at terminal velocity upon reaching max acceleration.
    🤯🤯🤯
    You nailed that visual lesson man.

  • @LachlanN2307
    @LachlanN2307 10 лет назад +45

    Hey Paul, I'm an Australian university student doing physics for the first time, since I never did it in high school these videos have been a big help, I have my exam coming up tomorrow and I just wanted to thank you for the tutorials on these things :)

  • @DanielVazquez
    @DanielVazquez 8 лет назад +10

    Best explanation I have seen in this topic so far. Simple and direct! Thank you!

  • @nidaburgucu5743
    @nidaburgucu5743 9 лет назад +5

    You are the best physics teacher I've ever seen. All engineer students should watch your videos :)

  • @annetteknell5922
    @annetteknell5922 8 лет назад +1

    Best physics teacher ever !! Im from peru trying to get into the best science university here and this is helping me a lot. Thank u x 100

  • @pavithras4950
    @pavithras4950 10 лет назад +6

    You are really a knowledgeable teacher. Sir,I will be happy if you just make a video about carbon and its compounds.

  • @RoseaNebulaLaeta
    @RoseaNebulaLaeta 9 лет назад +2

    This was really, really helpful! Thank you so much for sharing your lessons online, they really help so much!

  • @amymcgee6268
    @amymcgee6268 8 лет назад

    I'm in 8th grade and this has really helped me, your videos are great and will definitely show and suggest them to my fellow peers. :)

  • @laurenwickfit
    @laurenwickfit 9 лет назад

    this is helpful for people like me that have to see someone talking not just a voice coming from the speaker!

  • @tylereidelman8876
    @tylereidelman8876 7 лет назад

    teacher recommend you for our 8th grade physics test, helped out so much thank you

  • @jesuslovesyou2270
    @jesuslovesyou2270 9 лет назад +1

    i love your videos! please keep on doing them so that people like me can enjoy learning physics!

  • @micasianson2501
    @micasianson2501 9 лет назад

    I'm studying this as an elective this third year highschool. it's damn hard but you helped me... thanks

  • @antoniomarin8973
    @antoniomarin8973 7 лет назад +1

    Hello. Mr. Paul Seems nice explication.
    Please any chance to explain me how I have to Understand or deal with this formulas at the time to use. Vf=at+vi, X=1/2at to the second+ vit. vfto the second-vi to the second=2ax.
    Thanks.

    • @carultch
      @carultch 2 года назад +1

      It is much easier to understand them when you learn the background of calculus. You use the power rule, the first calculus rule you learn, and it is all crystal clear how these formulas come to be.
      The way to know which formula to use is to start by identifying which of the 5 variables you know, and which you want to know. Then select an equation that relates them as directly as possible.
      For vf=a*t+vi, we relate initial and final velocity, acceleration, and time duration. This is arranged assuming you know the acceleration, time duration, and initial velocity.
      For x=1/2*a*t^2+vi*t, this assumes we know acceleration, time duration, and initial speed, and want to know displacement x. Final velocity is out of the picture. This equation comes from integrating the previous equation relative to time. There is an unspoken xi at the end of it, for initial position. Usually this can be assumed to equal zero.
      For vf^2 = vi^2 + 2*a*x, this assumes time is out of the picture, and we know acceleration, displacement, and initial velocity. This then tells you final velocity. To understand this, it helps to think through it with work per unit mass (a*x) equals change in kinetic energy per unit mass (1/2*(vf^2 - vi^2)). We then multiply through by 2 to clear the fraction.

  • @piobrick
    @piobrick 7 лет назад

    Thank you. Very clear explanation.

  • @historyandhorseplaying7374
    @historyandhorseplaying7374 3 года назад

    Very cool, but wish he had used the CAR accelerating for the second example. Am trying to construct a mathematical model of a horse race, and graphing the acceleration over time and over distance, in order to figure out energy expended. Am having a tough time because it's counterintuitive with the negative accelerations!

  • @fistoffries
    @fistoffries 8 лет назад

    Is there a video physics app (or comparable) for android?

  • @notme7886
    @notme7886 4 года назад

    Can someone pls tell me how he got the velocity time graph from the slope of the position time graph?

    • @carultch
      @carultch 2 года назад +1

      The slope at every point in time on the position vs time graph, tells you the value of the velocity vs time graph.
      I made a public link on Geogebra that shows how this works:
      www.geogebra.org/calculator/htvdkw3y
      Suppose the blue function f(x) indicates position vs time, as a body travels from x=4 meters to x=16 meters, in 10 seconds.
      The green function g(x), is the corresponding velocity vs time for this situation. Play around with slider for variable t, for the point in time you are interested in. You'll see that it generates the red line tangent at Point A to the blue function, h(x), and the slope of h(x) gives the value of g(x) marked with Point B.

  • @shinrot9569
    @shinrot9569 8 лет назад

    Thank you so much for the video!!

  • @mirceaandreighinea
    @mirceaandreighinea 6 лет назад

    is the acceleration always a straight line in the velocity per time graph? thank you!
    (great videos you have!!!)

    • @carultch
      @carultch 2 года назад +1

      Constant acceleration implies a straight line on the velocity vs time graph.
      Kinematics in general will not always have constant acceleration.
      For the cases they simplify in introductory physics to avoid the need to use Calculus, acceleration is either constant, or is a piecewise function of multiple periods of constant acceleration. In reality, jump discontinuities between accelerations can be very uncomfortable to experience, so there will be a transition among the different periods of acceleration in some form or another. The next order derivative after acceleration is called jerk, because sudden changes in acceleration will cause your body to jerk around in response to them.

  • @omasukul1489
    @omasukul1489 4 года назад +1

    hi everyone

  • @aminamin3042
    @aminamin3042 6 лет назад

    thank you

  • @cupojoe1035
    @cupojoe1035 6 лет назад

    MR SERINO WHY DO YOU MAKE US DO THIS??!?!?!!

  • @tsaha6236
    @tsaha6236 4 года назад

    If you want to feel acceleration, you should jump out of an Airplane.
    Brought my eyes back from my phone to this video.

  • @brownlettuce1810
    @brownlettuce1810 5 лет назад

    Suggestion... Drop the “did you learn” interrogative (it’s not helpful) and just summarize.

  • @joesmith9330
    @joesmith9330 7 лет назад

    STILL WAITING THUMBS DOWN I THOUGHT U HAD AN EXPANATION OF ACCELERATION TO GET POSITION BUT U HAVE A BUNCH OF SLOPES .