I've binged all of your kinematic videos, after feeling lost in physics 11 for ages. I can't thank you enough. I feel like it's starting to make a little more sense now.
You probably dont care at all but does someone know of a way to get back into an instagram account? I stupidly lost my password. I love any tips you can offer me
Honestly, you will save my academic life - I'm doing Biomechanics this semester and in week one, my head is spinning! How do you know so much Professor Dave?!
if you find the acceleration/deceleration confusing, you're not alone. A lot of education places only use acceleration and the direction is indicated by positive or negative. They do this to avoid confusion and even though people are used to the colloquial "deceleration" once you get used to the idea of "there is only acceleration" and the direction is indicated by positive or negative, it can make it a lot easier to keep the directions straight in your head.
I am confused of why they halved acceleration when looking for the origin of x. I might need to consider changing my perspective of acceleration to understand.
Your explanation of understanding motion using a graph (grid) to show the starting and ending positions in order to observe the changing (+- or -) of the vector's displacement, velocity and acceleration now allows me to understand physics of motion. I hope to now pursue basic calculus.
Thank you thankyou thankyouuhh very muchh, I have a final physics exam tomorrow and u explained me a whole chapter thankuu you’re literally saving my life
Thank you very much for the amazing explanation! But may someone explain why for stage c and d(reverse acceleration and reverse deceleration) For D (Displacement Vector) the direction is Forward instead of backward? Because I thought you are going back to the original starting point that's why should be backward instead？ Thank you
Reverse acceleration has a forward direction displacement does not make much sense. So does this mean the direction of the object itself is the direction of the arrow, not the direction of the velocity? 6:58
Only 4 years late. I guess it's because the displacement is still positive relative to the starting point, but getting smaller again till it's zero. If the car continued in reverse gear and went beyond it's initial starting point, then the displacement would be backwards?
You should be in charge of a government agency somewhere and/or someday. This is sort of kind of like the re-beginning of an Italian Renaissance. It comprises the acculumation of and review of all ascertained scientific fundamentals, put in a more visible and comprehensive form. Added details is the success to these videos.
This was a great video but it did kind of leave me asking myself what displacement actually is. For those also confused it's the position in reference to the origin, so if I travel 4 meters to the right from the bus stop and one meter to the left, the distance traveled would be 5 meters but the displacement would be three meters to the right since that is where you are relative the bus stop (regardless of how you got there).
sir i have a doubt, if a horse pulls a cart by a certain force then according to newton 2nd law cart should also pull him with same force so how does a cart move.
I have a question. In the answers of the check your comprehension, the answer for reverse deceleration and reverse acceleration states that the Displacement is moving forward and the magnitude is decreasing. Shouldn't the displacement be moving backwards, and the magnitude decreasing too? Since we're reversing back towards our starting location, I thought the displacement's vector would be backwards to where its original starting point was.
so don't forget that displacement will always begin from your starting point, so the only way for it to become negative is for you to go past where you started and begin traveling in the opposite direction from there. so it's not that displacement is moving forward, it's just that it's always pointing forward, until you get back to your starting point, where displacement is zero.
@@ProfessorDaveExplains In reverse acceleration and reverse deacceleration displacement is in forward and velocity is in backward directions How can it be? The direction of velocity will be in the direction of displacement isn't it?
@@ydhanusree4126 because by 'displacement' here he meant 'overall displacement (ie.from displacement from the starting position). So if you look at the position of body even during reverse acceleration/deceleration, the position (ie. the overall displacement) of the body is forward to the starting point. Though the instantenous displacemnt will be in the backward direction therefor the instantenous velocity is also in the backward direction. The catch here is that here according to Prof Displacement = Overall displacement; Velocity = Instantenous Velocity I guess he should've been just a bit more clear about that. Nevertheless a sweet and simple way of explaining by him.
The end questions were outclass ...... thankyou very much for this video 🥰🥰🥰🥰🥰🥰🥰🥰🥰🥰❤❤❤❤❤❤❤😍😍😍😍😍😍😍😍😍😍😍😍😍🤩🤩🤩🤩🤩☺☺🤩☺☺☺☺☺☺☺☺☺☺🥰🥰🥰🥰🥰😮😮😮😮😮💘💘💘💘💘💘💘💘💘💘🥰🥰🥰🥰💋💋💋💋💋💥💥💥💥💥💥
Vivid explanations ,I really admire that ,you are good at it ,....but would you give explanation for the comprehension part specially I am having trouble in the determination of the direction of the quantities displacement ,velocity and acceleration in some cases .
I have this written in my book, can someone explain it to me. "when brakes are applied then the direction of velocity and acceleration are opposite to each other"
well so if you are moving in the forward direction you have a positive velocity, and if you hit the brakes the acceleration will be in the negative direction, so until you stop completely you'll have a decreasing but positive velocity and a negative acceleration, opposite directions.
Sir, I have a doubt - 1. In the cases of reverse acceleration and reverse deceleration, why does the displacement points in forward direction.. 2. Also, by modifying the data given in the (checking Comprehension) question, please state me some instances in which the magnitude of the acceleration of the car will increase or decrease.. Thanks...
Well, I'm not professor Dave, but 1. The displacement points forward because the car is always technically located in front of its starting position, and not behind it. 2. The acceleration (change in velocity) does not increase or decrease because it doesn't in real life (or at least I think so)
@@petarblag I think that the acceleration is constant bcs the change in velocity is constant Say that the velocity of the car during the first five seconds increases from 0m/s to 10m/s. In the next 5 seconds it increases to 15m/s but then in the next 5 it increases to 35 m/s So in this case the acceleration is not constant. For the first 5 sec its 2m/s² In the next 5 sec its 1m/s² and in the 5 sec after that it's 4m/s² So I think if the velocity increases or decreases inconsistently so will the acceleration
Hi Professor 😊 I’d like to ask, for the Checking Comprehension part, how is the acceleration for Initial Decelaration “backward” and for reverse deceleration “forward”? Kindly enlighten me, Sir. Thank you so much and apologies for the inconvenience. 😊
Reverse deccelaration means the car has changed its initial direction means Velocity vector become backward and as we have to deccelarate it accelration vector become forward(so that velocity vector in forward direction opposes velocity vector in backward direction)
Nice video and explanations. Thanks . Still not clear: What is the difference between distance and displacement? BTW, thanks for clarifying velocity and speed.
so like if you walked ten meters forward and then ten meters backwards to where you started from, you would have travelled a distance of twenty meters, but your displacement would be zero, as you're back in the same spot.
Sir, i have a wrong perception with respective direction. Please help me to correct in required places If displacement is shortest distance between two(A,B) points, it will have single direction A to B And Velocity is displacement/time velocity should have single direction. Why it is given as velocity can change by changing direction or speed or both.
since displacement is the shortest distance from one point to another (always a straight line), it'll always be in a single direction, so velocity is also in one direction in that case. It is still velocity because it is still moving in some direction. But velocity is a vector quantity, which means it has direction and spee
Because the displacement in the problem is measured relative to your original starting point, rather than relative to the starting point of the interval. You never touch the negative x-positions in this example, so your displacement is never negative.
During reverse acceleration why does the displacement vector point forward, shouldn't it point backwards instead since the car is moving in reverse direction
I have a question will direction of displacement change in uniform velocity. Also velocity means rate of change of displacement does it mean that both direction and magnitude of displacement change
Yes , direction of displacement can be changed in uniform velocity. Suppose a body is moving in uniform velocity on x-axis from negative x-axis to positive x-axis. Till is crosses the origin , its displacement is negative and after crossing the origin its displacement is positive. Not necessarily. Velocity is vector quantity having magnitude and direction. It is defined as rate of change of position with respect of time. If body position and direction , or any of both changes , we can say body has velocity. For details watch Path Length and Displacement, Average Velocity on PhysicsNama.
There isn't enough information to know for sure that acceleration is constant, in the given problem. To keep it simple, introductory kinematics assumes constant acceleration unless otherwise specified.
Because displacement is a measure of how far the car has moved in a particular direction, in this case forwards. As the car reverses, its forward displacement from its original position gradually decreases until it is back where it started. If it continued reversing from here, then the direction would change to backwards.
Depends on whether you just mean magnitude of acceleration, or acceleration in its full vector form. Because it is only when acceleration is perpendicular to velocity, that it exclusively causes a change in direction of velocity. This is called centripetal acceleration. One example of a constant acceleration vector, is projectile motion in a uniform gravitational field. Throw a ball in a direction that is perfectly horizontal. Initially, the acceleration is perpendicular to the velocity, and only causes a change in direction. But once you let the effects of that acceleration accumulate, the ball starts descending, and the velocity is no longer perfectly horizontal. Due to the fact that part of velocity now aligns with the acceleration, acceleration causes a change in speed in addition to a change in direction. There is only an instantaneous point, where the acceleration is purely centripetal, without also being tangential. In uniform circular motion, the acceleration is constant in magnitude, and so is the speed. But both the acceleration and speed have to change direction constantly, so that acceleration is always perpendicular to velocity. These two kinematics quantities remain constant in magnitude, but not constant in direction. Because they are vector quantities, it is incorrect to call them constant if direction is changing.
4:30 i don't understand this concept. if acceleration means change in velocity over time, shouldn't be the acceleration itself increased? why velocity increases?
Suppose you graph position as a function of time, for an object moving along a straight line path. You graph location on the y-axis, and time on the x-axis. The position itself is the y-coordinate of your graph. The velocity is the slope of the tangent line to the graph. The acceleration relates to the curvature of the graph. Technically, the second derivative of this function. A constant acceleration means that this graph will take the shape of a parabola. The second derivative of the function is constant. The slope is changing, and the output of the function is changing.
Why do you look all happy and friendly during the theme song, and then completely serious and without a smile at all during the explanation?!? I thought you liked explaining this stuff?
I've binged all of your kinematic videos, after feeling lost in physics 11 for ages. I can't thank you enough. I feel like it's starting to make a little more sense now.
sgutup
@@eddieflores7779 The way you're illiterate
@@tiactus haha lol
update i failed that class
You probably dont care at all but does someone know of a way to get back into an instagram account?
I stupidly lost my password. I love any tips you can offer me
Honestly, you will save my academic life - I'm doing Biomechanics this semester and in week one, my head is spinning! How do you know so much Professor Dave?!
Thank you for making this video I'm in 6th and doing a science project about free fall and measuring velocity I really appreciate it!!!
respectfully you deserve absolute toe-curling, aneurysm-inducing, eye-rolling, spiritual awakening, mind-boggling head. Thank you professor Dave.
hahhahhahahaha wtf dude😂
What the fuck bruh 😂
WHAT
bro 😭
3:32 "If they are quick little devils"
LOL
some fun in science
lol
lmao he kept the straight face perfectly
Looool came to the comments right away
if you find the acceleration/deceleration confusing, you're not alone. A lot of education places only use acceleration and the direction is indicated by positive or negative. They do this to avoid confusion and even though people are used to the colloquial "deceleration" once you get used to the idea of "there is only acceleration" and the direction is indicated by positive or negative, it can make it a lot easier to keep the directions straight in your head.
I am confused of why they halved acceleration when looking for the origin of x. I might need to consider changing my perspective of acceleration to understand.
Its like acceleration doesn't take effect immediately
currently cramming for my upcoming college admission exams and ur videos had been SAVING me. thank u so much professor
Hey
Back off bro, or
Your explanation of understanding motion using a graph (grid) to show the starting and ending positions in order to observe the changing (+- or -) of the vector's displacement, velocity and acceleration now allows me to understand physics of motion. I hope to now pursue basic calculus.
I've got you covered for calculus too! Please check out my calculus content, it's got everything you need!
The theme song is such a meme lol
I agree
Lol
lmao
smh
When my teacher played the video the whole class started laughing at the intro
Your friend walks up the driveway like a normal person lol...I love your subtle humor
5:01 because if it wasn't your favorite animal you would just go ahead and run it over
Lmaoo
Read this comment just as he was saying it...i am ROFL
I am watching all this vids for my test at 2pm today , pliz wish me luck
same time
How did it go ?
Same but it's currently 1 am
@berylliumpear1026 all the best hey this was 4 yrs ago.
@@musrifasangga8335 how did it go
I have been searching for a proper explanation to this since long but ultimately I got it. I am highly obliged to you sir😊.
Thank you thankyou thankyouuhh very muchh, I have a final physics exam tomorrow and u explained me a whole chapter thankuu you’re literally saving my life
Thank you professor Dave, your explanation are more helpful in our daily life, you make us understand better what was so difficult to understand ✍️♥️
I'm Brazilian and I love your Channel, because I study English and sciences at the same time. :)
Jonathan Augusto no one cares
Evan_ Armo shutup bro
No one cares about your comment either even armo!
Guys it’s his opinion
tbm
Best teacher ever I had been blanked during physics lectures during class
Best teacher
subscribe to him and share with your friends
Son of a Physician
Doc ?
@M A Abhijith Did you meant to say "You're Welcome"?
Yeah, You are welcome
Cha
Easy, precise, and brief. Nice video, worth a year of knowledge
I am watching a variety of your videos and after having learning gaps, it seems like I am learning an that means a lot. ♥
thank u dave, u have no idea how much u mean to me
The best explanation video ever
Man, Why are you so good at explaining things, Thank you
watching all of these the night before my physics 11 final. its so easy to understand
I WISH I FOUND THIS SOONER OMFG ❤❤
Nice man. Your small effort made a big difference in my mind❤
Terimakasih untuk Professor Dave dan untuk orang yang menerjemahkan subtitlenya ke dalam Bahasa Indonesia. Salam dari Indonesia.
Get this man to a million
Thank you, sir!
This was really useful. Got a physics exam for grade 10, wish me luck!
I hope this explains the relations between distance unita, force units, and mass units
Thanks a lot man!
Got an IGCSE exam tomorrow wish me luck
did u passs?
Naveen Sundar Thanks for asking, I actually got full mark ^_^
@@goldensmith9954 bro I wanna ask something ,can l?
Can’t believe I’m actually watching this late at night for nerve calming before bed 😢
This single video taught me more than the public school system
im in physics 111 and I needed this man, I know my maths so I took the harder one but dsmn
this explained it way better than my science teacher last year
Great video, my teacher will give me extra points all thanks for this video !!
Thank you very much for the amazing explanation!
But may someone explain why for stage c and d(reverse acceleration and reverse deceleration)
For D (Displacement Vector) the direction is Forward instead of backward?
Because I thought you are going back to the original starting point that's why should be backward instead？ Thank you
^^^^ yes
It still begins from your starting point.
Man, you need some serious cramming.
Reverse acceleration has a forward direction displacement does not make much sense. So does this mean the direction of the object itself is the direction of the arrow, not the direction of the velocity? 6:58
and of course same question applies to reverse deceleration forward arrow
Only 4 years late. I guess it's because the displacement is still positive relative to the starting point, but getting smaller again till it's zero. If the car continued in reverse gear and went beyond it's initial starting point, then the displacement would be backwards?
@@ExiLeZH yes exactly :)
@@ExiLeZH I was wondering the same thing, thanks
You should be in charge of a government agency somewhere and/or someday. This is sort of kind of like the re-beginning of an Italian Renaissance. It comprises the acculumation of and review of all ascertained scientific fundamentals, put in a more visible and comprehensive form. Added details is the success to these videos.
ooh neo-italian renaissance! i like the sound of that.
I am from India, thanks sir for such a great video
Hey brother I'm also from India are you from Maharashtra
How can anybody dislike this video....its great keep it up
Good step🎉🎉🎉
I'm watching this for my final exam today. Wish me good luck, guys!
Thank you for making it less complicated than it was explained back then in school😂
I understood more after watching your video.
thankyouu
This was a great video but it did kind of leave me asking myself what displacement actually is. For those also confused it's the position in reference to the origin, so if I travel 4 meters to the right from the bus stop and one meter to the left, the distance traveled would be 5 meters but the displacement would be three meters to the right since that is where you are relative the bus stop (regardless of how you got there).
Yeah I thank that's what displacement is
i ❤ physics
I did it 🎉🎉
You ethiopians are every where hh😮
Professor coming thru with the clutch save once again
you explained very well brother
You are great awesome and brilliant teacher. You already helped me and thank you from Sweden.
Never understood why you put the square in s^2 in that equation. But when you put it in English the light just turned on. Thanks.
English was my best subject in school and math was my worst, so I felt this.
sir i have a doubt,
if a horse pulls a cart by a certain force then according to newton 2nd law cart should also pull him with same force so how does a cart move.
check out my tutorial on newton's third law! will clear this right up.
Very well explained!! Keep it up sir ❤
Thank you very much, this video really helps me with my studies
Thank's Dave for science and more, it helps the viewer comprehend the world around us.
Hello. I am a Nigerian and I love your videos which are very good for learning. I want to share it by embedding them on my site.
if you embed a youtube player so that i still get the views, go for it!
That's exactly what I did
You still get your views and I encourage them to Like And Subscribe as well
awesome thanks!
Excellent teaching method 👏
Very good ✌️
👍👍great ..finaly i get it right
Thank you for these videos professor
you just saved my physics grade! I hope both sides of your pillows are cold at night :)
now i got the proper difference between acceleration and velocity 👍👍👍👍👍
awesome teacher thanks sir ur videos help me alot
my best friends sisters uncle's brother took a dump on my lawn, i used this video to accelerate my car into him
hands down the best videos!!! Thank you so much!!!!!!
hey professor, could you please do a video on symmetry operations?
thanks
Thank you very much for your work 😁😁😁
I’m so cooked 😔
Why?
Bro same
I have a question.
In the answers of the check your comprehension, the answer for reverse deceleration and reverse acceleration states that the Displacement is moving forward and the magnitude is decreasing.
Shouldn't the displacement be moving backwards, and the magnitude decreasing too? Since we're reversing back towards our starting location, I thought the displacement's vector would be backwards to where its original starting point was.
so don't forget that displacement will always begin from your starting point, so the only way for it to become negative is for you to go past where you started and begin traveling in the opposite direction from there. so it's not that displacement is moving forward, it's just that it's always pointing forward, until you get back to your starting point, where displacement is zero.
Oscar Lim I was thinking the same thing
@@ProfessorDaveExplains
In reverse acceleration and reverse deacceleration displacement is in forward and velocity is in backward directions
How can it be?
The direction of velocity will be in the direction of displacement isn't it?
when something is slowing down but still moving in the forward direction, only the acceleration is negative
@@ydhanusree4126 because by 'displacement' here he meant 'overall displacement (ie.from displacement from the starting position). So if you look at the position of body even during reverse acceleration/deceleration, the position (ie. the overall displacement) of the body is forward to the starting point.
Though the instantenous displacemnt will be in the backward direction therefor the instantenous velocity is also in the backward direction.
The catch here is that here according to Prof
Displacement = Overall displacement;
Velocity = Instantenous Velocity
I guess he should've been just a bit more clear about that. Nevertheless a sweet and simple way of explaining by him.
Great explaining
You are my hero!!!!! Thank you so much!!
The end questions were outclass
...... thankyou very much for this video 🥰🥰🥰🥰🥰🥰🥰🥰🥰🥰❤❤❤❤❤❤❤😍😍😍😍😍😍😍😍😍😍😍😍😍🤩🤩🤩🤩🤩☺☺🤩☺☺☺☺☺☺☺☺☺☺🥰🥰🥰🥰🥰😮😮😮😮😮💘💘💘💘💘💘💘💘💘💘🥰🥰🥰🥰💋💋💋💋💋💥💥💥💥💥💥
Vivid explanations ,I really admire that ,you are good at it ,....but would you give explanation for the comprehension part specially I am having trouble in the determination of the direction of the quantities displacement ,velocity and acceleration in some cases .
I have this written in my book, can someone explain it to me.
"when brakes are applied then the direction of velocity and acceleration are opposite to each other"
well so if you are moving in the forward direction you have a positive velocity, and if you hit the brakes the acceleration will be in the negative direction, so until you stop completely you'll have a decreasing but positive velocity and a negative acceleration, opposite directions.
@@ProfessorDaveExplains thank you so much
@@maryamzaheer2202 jazakAllahu khayr, thanky you asking this type of informative question. Via dave's explanation I remembered. Thanks.
Sir, I have a doubt -
1. In the cases of reverse acceleration and reverse deceleration, why does the displacement points in forward direction..
2. Also, by modifying the data given in the (checking Comprehension) question, please state me some instances in which the magnitude of the acceleration of the car will increase or decrease..
Thanks...
Well, I'm not professor Dave, but
1. The displacement points forward because the car is always technically located in front of its starting position, and not behind it.
2. The acceleration (change in velocity) does not increase or decrease because it doesn't in real life (or at least I think so)
@@petarblag Thanks for your clarification👍👍
@@petarblag I think that the acceleration is constant bcs the change in velocity is constant
Say that the velocity of the car during the first five seconds increases from 0m/s to 10m/s. In the next 5 seconds it increases to 15m/s but then in the next 5 it increases to 35 m/s
So in this case the acceleration is not constant. For the first 5 sec its 2m/s² In the next 5 sec its 1m/s² and in the 5 sec after that it's 4m/s²
So I think if the velocity increases or decreases inconsistently so will the acceleration
@@petarblag hey buddy but if we take instateneous displacement it would be in the backward direction
good video for learning
In the comprehension questions why is reverse deceleration magnitude decreasing?
Thank you...executive explanation!!!!!!
Wow I really impressed
wonderful work!!
I prayed to God to help me in Physics and i found a video that looks like Jesus himself . God is truly great !
Hi Professor 😊 I’d like to ask, for the Checking Comprehension part, how is the acceleration for Initial Decelaration “backward” and for reverse deceleration “forward”? Kindly enlighten me, Sir. Thank you so much and apologies for the inconvenience. 😊
Reverse deccelaration means the car has changed its initial direction means Velocity vector become backward and as we have to deccelarate it accelration vector become forward(so that velocity vector in forward direction opposes velocity vector in backward direction)
Nice video and explanations. Thanks . Still not clear: What is the difference between distance and displacement?
BTW, thanks for clarifying velocity and speed.
so like if you walked ten meters forward and then ten meters backwards to where you started from, you would have travelled a distance of twenty meters, but your displacement would be zero, as you're back in the same spot.
@@ProfessorDaveExplains thank YOU SIR
Love your work, professor.
Sir, i have a wrong perception with respective direction. Please help me to correct in required places
If displacement is shortest distance between two(A,B) points, it will have single direction A to B
And Velocity is displacement/time
velocity should have single direction. Why it is given as velocity can change by changing direction or speed or both.
since displacement is the shortest distance from one point to another (always a straight line), it'll always be in a single direction, so velocity is also in one direction in that case. It is still velocity because it is still moving in some direction.
But velocity is a vector quantity, which means it has direction and spee
im sure it isnt displacement/time, its:
how much you travelled+direction/time
Amazing explanation!
Love your channel
I have a question with regards to c and d where now we are reversing
Why is it that The displacement vector is forward and not backward
Because the displacement in the problem is measured relative to your original starting point, rather than relative to the starting point of the interval. You never touch the negative x-positions in this example, so your displacement is never negative.
Prof. Dave . in the comprehension check .. with the last motion of reverse (ac/de)celeration, should't the displacement be backward? .. please explain
For the last question, the velocity vector isn't backwards, it is decreasing, until the car is reversing right?
well the last question is talking about the part where the car is already going the other way so the velocity vector is negative that whole time
THANKS I GOT 100 IN EXAM ;)
haci Kemal more growtopia!
During reverse acceleration why does the displacement vector point forward, shouldn't it point backwards instead since the car is moving in reverse direction
It won't point backwards until it is to the left of where it started.
I have a question will direction of displacement change in uniform velocity. Also velocity means rate of change of displacement does it mean that both direction and magnitude of displacement change
Yes , direction of displacement can be changed in uniform velocity. Suppose a body is moving in uniform velocity on x-axis from negative x-axis to positive x-axis. Till is crosses the origin , its displacement is negative and after crossing the origin its displacement is positive.
Not necessarily. Velocity is vector quantity having magnitude and direction. It is defined as rate of change of position with respect of time. If body position and direction , or any of both changes , we can say body has velocity. For details watch Path Length and Displacement, Average Velocity on PhysicsNama.
Nice way to teach my dude, Nice tat lol... (tat is just slang for tattoo 😅😅) Love the vids keep em coming!!! 😎😎😎😎
Prof. Dave, in Checking Comprehension section, why are the acceleration always constant?
Same question....
@@zarishiftikhar5520 See my response
There isn't enough information to know for sure that acceleration is constant, in the given problem. To keep it simple, introductory kinematics assumes constant acceleration unless otherwise specified.
it was so helpful
why is displacement vector positiv for revers path, when the cars is going back?
Because displacement is a measure of how far the car has moved in a particular direction, in this case forwards. As the car reverses, its forward displacement from its original position gradually decreases until it is back where it started. If it continued reversing from here, then the direction would change to backwards.
I have a question can the acceleration be constant such that it only affects the direction of velocity but not its magnitude.
Depends on whether you just mean magnitude of acceleration, or acceleration in its full vector form. Because it is only when acceleration is perpendicular to velocity, that it exclusively causes a change in direction of velocity. This is called centripetal acceleration.
One example of a constant acceleration vector, is projectile motion in a uniform gravitational field. Throw a ball in a direction that is perfectly horizontal. Initially, the acceleration is perpendicular to the velocity, and only causes a change in direction. But once you let the effects of that acceleration accumulate, the ball starts descending, and the velocity is no longer perfectly horizontal. Due to the fact that part of velocity now aligns with the acceleration, acceleration causes a change in speed in addition to a change in direction. There is only an instantaneous point, where the acceleration is purely centripetal, without also being tangential.
In uniform circular motion, the acceleration is constant in magnitude, and so is the speed. But both the acceleration and speed have to change direction constantly, so that acceleration is always perpendicular to velocity. These two kinematics quantities remain constant in magnitude, but not constant in direction. Because they are vector quantities, it is incorrect to call them constant if direction is changing.
A big yes
Thank you thank you so much!!!
Thanks you for your clearly explanation
4:30 i don't understand this concept. if acceleration means change in velocity over time, shouldn't be the acceleration itself increased? why velocity increases?
Suppose you graph position as a function of time, for an object moving along a straight line path. You graph location on the y-axis, and time on the x-axis.
The position itself is the y-coordinate of your graph.
The velocity is the slope of the tangent line to the graph.
The acceleration relates to the curvature of the graph. Technically, the second derivative of this function.
A constant acceleration means that this graph will take the shape of a parabola. The second derivative of the function is constant. The slope is changing, and the output of the function is changing.
Why do you look all happy and friendly during the theme song, and then completely serious and without a smile at all during the explanation?!? I thought you liked explaining this stuff?
because i'm both happy and serious! happy to make content and serious about explaining it as effectively as possible.
Professor Dave Explains you da man dave!!!
Kasper Vestergaard
I died