You helped me pass genetics and O. chem the second time around. Now here I am drowning in physics and I find out you teach that too... BLESS YOU PROFESSOR DAVE :')
I just wanted to take the time to genuinely thank you sincerely. For the past 2 weeks in my physics class I have been extremely lost, and your video helped me apprehend the necessary conceptions. Thank you so much.
Astonished with your unbelievable teaching skills, I never understood its concept in my whole life till I came across this video, what a time and life savor, thanks man, much appreciated!
this is like the first time ive ever really commented on anything, but you have helped relieve so much stress about not being able to understand whats happening In my class. Thank you a ton, seriously.
Wow. I can't believe I learned more in this one video than my physics teacher has even tried explaining in the whole term. I wrote a few pages of notes from this and I finally understand instead of feeling overwhelmed and stupid. I really wish more teachers could explain subjects like this, it seems so much easier now.
I may be way too mathematically illiterate to grasp everything in this video, but at least you have helped me figuring out a few things about physics and basic algebra with this single video. Thank you, Professor Dave!
I'm relying on you, professor Dave. I've been struggling so hard with this the past few days... Let's see if you save my quiz tomorrow, or hopefully my test next week!
You explain things so well. I listen to inclass lectures and read the book, but learn the most from watching your videos. I watched for biology and organic chem, and did well in both classes. Now on to physics. Thanks professor Dave!
ABSOLUTELY MIND-BLOWN! (I mean that in the best way.) Something from an entire chapter that I just couldn't comprehend you explained it in less than 7 minutes! You are a talented person with a gift in teaching! Thanks for your help! You just got a new subscriber! God bless you!
Why is Prof. Dave so good at explaining these difficult and intricate topics? I am doing advance readings and this video I mean youtuber, helps me in doing it😂😀keep up prof. Dave!
ik this is pretty late but what i did is I rearranged the equation to get "a" (acceleration) by itself. Which is (vf^2 - vi^2)/2d. All i did from here was plug in the values which we know are [vf=0] cuz it skids to a stop, [vi=15] cuz that's our initial velocity before the skid, [d=50] cuz that's the total displacement traveled during the skid, then with a trusty calculator it comes out to -2.25m/s^2. If you're confused on why it's negative it's because it's going in the opposite direction of the velocity, thus slowing the bike down until a full stop! 🛑
Your videos are incredibly helpful and well explained. I love how you color the things you are explaining. Your videos have helped me in Calculus & now Physics. This year I got hired as a math tutor at my college, I recommend your videos to students all the time & sometimes I watch them with students I'm helping because you explain things so much clearer & more concise than I can. Thanks Professor Dave!
Right now taking STEM classes and can't understand some topics but with the help of you I passed all my exams❤❤❤much appreciated and thankyou very much.. PROFESSOR DAVE🎉🎉🎉
thank you SOOO much for making this. I've been struggling with kinematics really badly in class, and this explained it in such an easy and understandable way
super bro.i am 11 years old trying to learn calculus and this kinematics.I HAVE BEEN SELECTED BY MY STATE GOVERNMENT FOR AN EDUCATION PROGRAMME FOR THE BLESSED,SO I HAVE TO LEARN EVERYTHING EARLY.U HAVE HELPED ME A LOT .THANKQ BRO.I CANT UNDERSTAND HOW TO THANK U
For the last word problem, I used d=(Vi+Vf/2)t to solve for the time. Then, I calculated the acceleration since I already have Vi, Vf and time. I arrived on the same answer which is a=-2.25 m/s^2. :)
There's also a method where you plot a graph with the x axis being time and y axis being velocity, the area of the polygon in the graph is the displacement of the time, velocity and acceleration of the problem.
Sorry i have a question in 4:03 pls someone explains me, im not good at english for sure so forgive me 'bout my grammar. Now i want to ask. I thought that the acceleration was 2.5m/s^2 so each second the point would probably move a distance equal to its instantaneous velocity. Let take an example: in the first second, the velocity became from 0 to 2.5m/s because of the acceleration so the distance which the point had ride must be 2.5m. The next second ( about 1s ) the velocity continiously changed its instantaneous velocity from 2.5m/s to 5m/s so propably the distance the point had ride were also equal to its instantaneous velocity at that time and its equal to 5m. So all of the distance which the point had ride = 2,5 + 5 = 7,5m. But if we use the principle in this video, the distance will be: 1/2at^2 =1/2 x 2,5 × 2^2 = 6,25m. So if we follow this principle, the point will ride a distance = 6,25m, but like i've talked about, the distance must be 7,5m. I definitely thinking about it and i dont know what exactly the true question, so i ask and hope that somebody will answer me. Thank all of you, first. Oh, oh so im talking about uniform variable motion so the displacement probably = the distance the point had ride in Ox Tks for reading, and pls help my by answering this ques. Have a good day !
i think this single video provided me with exactly what i was looking for to calculate suicide burn altitude in kerbal space program, and for that i thank you
Ill never understand why in academia we skip so many steps in explanations. if you wrote down the formula x=x0+vi(t)+1/2a(t)^2 and then saw him use x=vi(t)+1/2a(t)^2 you would be confused until you realized they took out the xo lol. the question never gave a distance therefore I guess you can set it to zero. For somebody who never studied instantaneous velocity or physics they would wonder how the car had velocity an no displacement. failure in communication is the biggest setback in science and engineering.
for anyone wondering how the kinematic equations are derived, here is what i think is the solution (i'm not that good at calculus, but i think this gives the general idea.) starting with the basics, velocity is the derivative of position, or v = dx/dt and acceleration is the derivative of velocity, a = dv/dt solving for v just involves integration, dv/dt = a dv = a dt v = at + C1 (C1 i think here is the initial velocity) solving for position is just integration again, but using the previous equation dx/dt = at + v(i) dx = at + v(i) dt x = (at^2)/2 + vt + C2 (and C2 here initial position.) solving for the final equation: Δx = (v + v(i))/2 * t = d solve the first kinematic equation for time: v = at + v(i) v - v(i) = at (v - v(i))/a = t Δx = (v + v(i))/2 * (v - v(i))/a Δx = (v^2 - v(i)^2)/2a 2aΔx = v^2 - v(i)^2 v^2 = 2aΔx + v(i)^2 v^2 = 2ad + v(i)^2
wow, this was a great video. So basically we have to find out first what we have and what we need to find out in order to know which equation we have to use? The first day of Physics was so confusing and now that we're on the 3 chapter (Freefalling) we have an exam on the first 3 chapters but I still feel somewhat lost. I'm gonna have to watch videos and apply it to what I'm reading to get a better understanding.
tbh your the only person that i go to if i need help in anything my guy your AMAZING LIKE REALLY Thank you professor Dave i would spend money for you and congrats 1M
Im struggling so much in class my teacher said to quit physics and drop put of school Ill prove her wrong Ill make her clap for me one day Thankyou so much for helping me out i can understand better
It’s crazy how I can actually understand the equations in your videos since you’re good at explanations, but I still can’t figure out why you would 1/2at^2.
I just want to thank you Professor Dave, it is really hard to study especially this subject, Physics during this challenging time (Pandemic) combined with the Online Schooling. You act as a bulb that lights our mind thanks! You made it simple but effective.
I think it's because you put the exponent to the -8.4 instead of the m/s the thing is, you put the whole expression (?) into the calculator except for the units, but the squared (^2) is supposed to just be for the m/s, but you left the exponent there after removing the m/s even though you're meant to also remove the exponent (^2) after removing the m/s itself, which in turn, squared the -8.4 instead.
Thank you for showing the working at the end! I followed along and just... Didn't really know how to get the correct units, I wasn't paying attention to how the squared velocity applies the squared aspect to the units as well.
PLEASE SOLVE THIS A coin is pushed from the edge of a laboratory bench with a horizontal velocity of 15m/s of the height of the bench is from the floor is 1.5m. calculate the distance from the foot of the bench of the point of impact with the floor. (g = 10m/s2)
So, for 6 years I bust my ass off to save up money to get a higher education, only for my professors to be completely inadequate and to learn it all on RUclips anyway. Thank you!
Hi Sir I have been puzzled on how to solve this problem are you willing to help me? Question 1. A 35 g bullet was fired horizontally from a gun with a velocity of 320.0 m/s. If the barrel is 1.1 meter from the ground, how long will it take for the bullet to reach the ground? Question 2. A 35 g bullet was fired horizontally from a gun with a velocity of 315.0 m/s. If the barrel is 1.5 meter from the ground, how far will the bullet reach as it first hit the ground? Thank you so much
you helped me in math, then in chemistry, then Organic chemistry, and now in physics
same
@@ellington_music bc
Same
He knows a lot about science and stuff.
@@johnrubensaragi4125 'professor Dave explains'
I paid thousands for online classes just for my professor to send us a link to your videos
bruh
@@abhirajdutta327 bruh nice name
same
Hahaha same bro
Literally me too
You helped me pass genetics and O. chem the second time around. Now here I am drowning in physics and I find out you teach that too... BLESS YOU PROFESSOR DAVE :')
I just wanted to take the time to genuinely thank you sincerely. For the past 2 weeks in my physics class I have been extremely lost, and your video helped me apprehend the necessary conceptions. Thank you so much.
after acing the chemistry test a while ago, time to finish up the finals with physics, thanks a lot for helping me Jesus!
haha..... literally
Is that PUN intended? LMAO
Hahaha lol
SHHHWIFTY lol
...nailed it...ok ill go
Astonished with your unbelievable teaching skills, I never understood its concept in my whole life till I came across this video, what a time and life savor, thanks man, much appreciated!
Got my first ever physics midterm on Monday and things are DEFINITELY starting to click better after watching these videos. Thank you!!
this is like the first time ive ever really commented on anything, but you have helped relieve so much stress about not being able to understand whats happening In my class. Thank you a ton, seriously.
Why is professor Dave better than the professors I pay thousands for per semester?
You can always toss a buck my way on Patreon if you're feeling generous! :)
Does Patreon allow one time contributions, or is it strictly subscription based?
@@ProfessorDaveExplains I totally lost it proffesor,thnx for this : )
@@ProfessorDaveExplains CAN YOU PLZ OPEN A COLLEGE SO I CAN PAY THOUSANDS TO YOU AND RECEIVE CREDITS FOR IT? 😭😭😭😭😭😭
OMG HOW IS THIS SO MUCH BETTER THAN ANYTHING ELSE
Wow. I can't believe I learned more in this one video than my physics teacher has even tried explaining in the whole term. I wrote a few pages of notes from this and I finally understand instead of feeling overwhelmed and stupid. I really wish more teachers could explain subjects like this, it seems so much easier now.
You, prof leonard, and the organic chemistry tutor are in the stem hall of fame
I may be way too mathematically illiterate to grasp everything in this video, but at least you have helped me figuring out a few things about physics and basic algebra with this single video. Thank you, Professor Dave!
I'm relying on you, professor Dave. I've been struggling so hard with this the past few days... Let's see if you save my quiz tomorrow, or hopefully my test next week!
You explain things so well. I listen to inclass lectures and read the book, but learn the most from watching your videos. I watched for biology and organic chem, and did well in both classes. Now on to physics. Thanks professor Dave!
ABSOLUTELY MIND-BLOWN! (I mean that in the best way.) Something from an entire chapter that I just couldn't comprehend you explained it in less than 7 minutes! You are a talented person with a gift in teaching! Thanks for your help! You just got a new subscriber! God bless you!
Why is Prof. Dave so good at explaining these difficult and intricate topics? I am doing advance readings and this video I mean youtuber, helps me in doing it😂😀keep up prof. Dave!
ik this is pretty late but what i did is I rearranged the equation to get "a" (acceleration) by itself. Which is (vf^2 - vi^2)/2d. All i did from here was plug in the values which we know are [vf=0] cuz it skids to a stop, [vi=15] cuz that's our initial velocity before the skid, [d=50] cuz that's the total displacement traveled during the skid, then with a trusty calculator it comes out to -2.25m/s^2. If you're confused on why it's negative it's because it's going in the opposite direction of the velocity, thus slowing the bike down until a full stop! 🛑
early enough for me to find it and realize what I did wrong. Thx so much.
Thank you Professor Dave Explains
Me pfff physics is boring and hard.
.
Professor dave - hold my apple
... and watch this!
I love how he talks about the history of physics which shows there’s many discoveries/discrepancies in modern science physics at that point of time.
Your videos are incredibly helpful and well explained. I love how you color the things you are explaining. Your videos have helped me in Calculus & now Physics. This year I got hired as a math tutor at my college, I recommend your videos to students all the time & sometimes I watch them with students I'm helping because you explain things so much clearer & more concise than I can. Thanks Professor Dave!
literally the only reason im passing my biomechanics course thank you dave
Right now taking STEM classes and can't understand some topics but with the help of you I passed all my exams❤❤❤much appreciated and thankyou very much.. PROFESSOR DAVE🎉🎉🎉
If only your videos were around 30 years ago.
It's a little late for me now but Im still going to follow. Thank you!!
thank you SOOO much for making this. I've been struggling with kinematics really badly in class, and this explained it in such an easy and understandable way
I'm actually amazed that a young man like him is a professor. Keep it up!
i'm just a youtube personality! but i work super hard so thank you :)
nothing would ever explain how happy I am right now, thanks prof
Bro, what hasn't this guy done a video on? He's getting me through my engineering degree.
I am so thankful for you! I was getting so frustrated and now I feel hopeful. Thank you for breaking things down in a simple manner!!
hiii cara whats your age? U are so beautiful
i’m so cooked
You can't compete with me at being cooked
All you need to knows are the 3 ecuations (third one is actually derived from the other 2)
Who knew Jesus would also be saving my Science Test
super bro.i am 11 years old trying to learn calculus and this kinematics.I HAVE BEEN SELECTED BY MY STATE GOVERNMENT FOR AN EDUCATION PROGRAMME FOR THE BLESSED,SO I HAVE TO LEARN EVERYTHING EARLY.U HAVE HELPED ME A LOT .THANKQ BRO.I CANT UNDERSTAND HOW TO THANK U
Professor Dave really coming in clutch before the exam, thank god for you.
For the last word problem, I used d=(Vi+Vf/2)t to solve for the time. Then, I calculated the acceleration since I already have Vi, Vf and time. I arrived on the same answer which is a=-2.25 m/s^2. :)
There's also a method where you plot a graph with the x axis being time and y axis being velocity, the area of the polygon in the graph is the displacement of the time, velocity and acceleration of the problem.
My teacher couldn’t explain a thing! He just talks for himself, thank you for saving me from failing mechanical science!
This video just helped me catch up in my Mechanics class. I've been so lost until now. Thanks!
Sorry i have a question in 4:03 pls someone explains me, im not good at english for sure so forgive me 'bout my grammar. Now i want to ask. I thought that the acceleration was 2.5m/s^2 so each second the point would probably move a distance equal to its instantaneous velocity. Let take an example: in the first second, the velocity became from 0 to 2.5m/s because of the acceleration so the distance which the point had ride must be 2.5m. The next second ( about 1s ) the velocity continiously changed its instantaneous velocity from 2.5m/s to 5m/s so propably the distance the point had ride were also equal to its instantaneous velocity at that time and its equal to 5m. So all of the distance which the point had ride = 2,5 + 5 = 7,5m. But if we use the principle in this video, the distance will be: 1/2at^2 =1/2 x 2,5 × 2^2 = 6,25m. So if we follow this principle, the point will ride a distance = 6,25m, but like i've talked about, the distance must be 7,5m.
I definitely thinking about it and i dont know what exactly the true question, so i ask and hope that somebody will answer me. Thank all of you, first.
Oh, oh so im talking about uniform variable motion so the displacement probably = the distance the point had ride in Ox
Tks for reading, and pls help my by answering this ques. Have a good day !
I have been reading on this topic in my textbook.Did not understand anything.I understood this in the duration of the video.Thanks Prof
i think this single video provided me with exactly what i was looking for to calculate suicide burn altitude in kerbal space program, and for that i thank you
Ill never understand why in academia we skip so many steps in explanations. if you wrote down the formula x=x0+vi(t)+1/2a(t)^2 and then saw him use x=vi(t)+1/2a(t)^2 you would be confused until you realized they took out the xo lol. the question never gave a distance therefore I guess you can set it to zero. For somebody who never studied instantaneous velocity or physics they would wonder how the car had velocity an no displacement. failure in communication is the biggest setback in science and engineering.
for anyone wondering how the kinematic equations are derived, here is what i think is the solution (i'm not that good at calculus, but i think this gives the general idea.)
starting with the basics, velocity is the derivative of position, or v = dx/dt
and acceleration is the derivative of velocity, a = dv/dt
solving for v just involves integration,
dv/dt = a
dv = a dt
v = at + C1 (C1 i think here is the initial velocity)
solving for position is just integration again, but using the previous equation
dx/dt = at + v(i)
dx = at + v(i) dt
x = (at^2)/2 + vt + C2 (and C2 here initial position.)
solving for the final equation:
Δx = (v + v(i))/2 * t = d
solve the first kinematic equation for time:
v = at + v(i)
v - v(i) = at
(v - v(i))/a = t
Δx = (v + v(i))/2 * (v - v(i))/a
Δx = (v^2 - v(i)^2)/2a
2aΔx = v^2 - v(i)^2
v^2 = 2aΔx + v(i)^2
v^2 = 2ad + v(i)^2
OMG...professor Dave is truly saving my a$$. Thank you for breaking everything down!!!!
Thank you Jesus for blessing me with this video.
Dave: …some simple equations…
Me: my brains on fire 😂
In all seriousness though, thank you. I’m determined to wrap my head around all of this.
wow, this was a great video. So basically we have to find out first what we have and what we need to find out in order to know which equation we have to use? The first day of Physics was so confusing and now that we're on the 3 chapter (Freefalling) we have an exam on the first 3 chapters but I still feel somewhat lost. I'm gonna have to watch videos and apply it to what I'm reading to get a better understanding.
How did your class go? I'm in the same situation. Right now, after first class covering ch 1-2 my head is swimming
@@everardomezajr3495 aye yo im in the same situation rn 😭
@@beans7622 SAME I have a test tmr and I’m so confused
Chidinma Ebere I ended up just cheating the entire semester and got pretty decent marks lmao. Good luck tho!!
@@beans7622 thanksss
tbh your the only person that i go to if i need help in anything my guy your AMAZING LIKE REALLY Thank you professor Dave i would spend money for you and congrats 1M
im a new physics student & i been struggling w grasping the whole concept. thank you so much for helping me with such vital yet easy information!
i love professor dave u helpped me very much with my FY04 voima JA liike
Thank you Professor Dave I’m feeling a lot more hopeful about Physics 1
You helped me a lot professor and my physics exam is near so wish me luck!
Im struggling so much in class my teacher said to quit physics and drop put of school
Ill prove her wrong
Ill make her clap for me one day
Thankyou so much for helping me out i can understand better
i was hoping i could learn physics from you too since your chemistry videos were amazing and im so glad u do teach physics as well!!
I love science.Your videos are great Professor.
It’s crazy how I can actually understand the equations in your videos since you’re good at explanations, but I still can’t figure out why you would 1/2at^2.
YOUR THE BEST MAN
This actually helped a good bit and I have a test tomorrow. Thanks!
BEST PROFESSER
Thanks so much i have a test tommorow and i finally understand this
Professor Dave, could you please explain about the motion of system of particles and rigid body.
I just want to thank you Professor Dave, it is really hard to study especially this subject, Physics during this challenging time (Pandemic) combined with the Online Schooling. You act as a bulb that lights our mind thanks! You made it simple but effective.
This was a really informative video thanks Professor Dave
thank u so much i've been looking for these more complex formulas for an hour. glad u have them
Thankyou for this,the video link that send with our teacher is i didn't get it,but when i saw your vid i just know itttt thankyou so much
I never noticed before, but the wheels are not turning. Very well explained thanks so much
I love your intro
Ur intro can be a good meme
If all the stored digital information was suddenly lost, we can rely on Professor dave as a back up drive for all of the world's information.
He knows lot about science and stuff professor Dave explains
saw the intro and already clicked subscribe
when you hear “he knows a lot about the science stuff, professor dave explains” you know u have a test tomorrow 😂
how did you get 43 at 5:20? i put 1/2(-8.4^2)(3.2)^2 in the calculator and i get -361.26
I think it's because you put the exponent to the -8.4 instead of the m/s
the thing is, you put the whole expression (?) into the calculator except for the units, but the squared (^2) is supposed to just be for the m/s, but you left the exponent there after removing the m/s even though you're meant to also remove the exponent (^2) after removing the m/s itself, which in turn, squared the -8.4 instead.
@@lightbulb129 i didn't understand what you just wrote, pretend im a 5 yo child please
i figured it out, you are putting -8.2² and it's just -8.2
the ² on ms doesn't count because it's just there to represent acceleration
@@Ricardo-ck7zd Thanks my man!
Thank you for showing the working at the end! I followed along and just... Didn't really know how to get the correct units, I wasn't paying attention to how the squared velocity applies the squared aspect to the units as well.
Ready to see you help me Dave
I really want to watch your videos ☺️
Hi I am teacher frank and your videos help me a lot specially in physics
Most similar websites have mistakes, but no mistakes were in this video!
You are the best 👍👍
Thank you so much Sir Dave.
Thank you Physics Jesus
Great work
Thank you, very straightforward and easy to understand
Thanks for creating a free resource for learning. And also, whoever did your greenscreen work, fucking props to the dude/dudette
Thank you math jesus
Thank you Prof Dave.. you helped me in physics..
Thank you professor dave
Thanks for explaining with this perfection
Thanks alot for your effort. Are you planning on making such a play list for Engineering? That could really help.
Thanks alot
Yes I am!
He is really angle of knowledge and help
PLEASE SOLVE THIS
A coin is pushed from the edge of a laboratory bench with a horizontal velocity of 15m/s of the height of the bench is from the floor is 1.5m. calculate the distance from the foot of the bench of the point of impact with the floor. (g = 10m/s2)
I ALSO NEED EXPLANATIONS PLEASE
There were more than one equation to solve distance , how do we know which one is the best to use when solving questions?
You just have to see which variables you have defined. Choose the equation where you can plug everything in except distance so you can solve for it.
So, for 6 years I bust my ass off to save up money to get a higher education, only for my professors to be completely inadequate and to learn it all on RUclips anyway. Thank you!
Thanks for the help
beautiful explanation sir
no im not ready
I know the feeling. I'm just gonna keep trying. If you put in the work you get the grade right?
Hi Sir I have been puzzled on how to solve this problem are you willing to help me?
Question 1. A 35 g bullet was fired horizontally from a gun with a velocity of 320.0 m/s. If the barrel is 1.1 meter from the ground, how long will it take for the bullet to reach the ground?
Question 2. A 35 g bullet was fired horizontally from a gun with a velocity of 315.0 m/s. If the barrel is 1.5 meter from the ground, how far will the bullet reach as it first hit the ground?
Thank you so much
How did you get to (-225 m2/s2)/[2(50m)] Where do the numbers come from and how do you know to divide?
I finally understand what I'm learning :D
Thank you man.
you slayyyeddd! Thank you! I finally understand
Did not help whatsoever but appreciate the effort man
maybe cuz your not putting effort into learning
ur vids are rly nice