You are sooooo very helpful! Thank you so much for posting all these Physics topics. I hope to find that you have videos that cover all of Physics 1 =) because I'd be lost without you.
I the last case shouldn't we do that-- the velocity of the observer with respect to ground is 10-5=5m/s towards the right. then we subtract it from the velocity of the ball - 30-5= 25m/s.
I always tell my students, feel free to do a problem any way you like. I will show them one way to do it but then they can choose to do it in a different way.
Think about it this way: what would be worse, two cars colliding head-on with one car traveling at 100 km/hour and the other car traveling at 99 km/hour or the faster car colliding the slower car from the back.
If a top is moving on a table and the the table is. also moving in apposit direction with the same speed as the top .what will see the observer standing near table ?
If you are talking about a spinning top, the friction between the top and the table is not sufficient to have the typical relative velocity situation. If it is a car moving in a straight line, then the car will appear stationary to the observer
i don't get why the velocity of the ball relative to A is 20 +10 (30m/s)? Why do we need to add both velocities? Isn't it asking for the velocity of the ball only, why do we need the velocity of the car as well? < 20m/s?
The concept described here is what we call the RELATIVE velocity. We are finding the velocity relative to another moving object, or as seen by a person in a moving object. The ball will APPEAR to have a different velocity when seen by a person standing on the side of the road as opposed to being seen by a person in the car.
Hi. Thanks for the video. A question about the velocity of the ball for viewer b: I get it that you need to subtract the vb because it is moving opposite to the car, but why does it become positive then? Why subtracting again to make it positive? It looks like a trick to me although I know that it isn't.? Thanks for any explanation given
Don't overthink it. You can determine the sign just by looking at it. If a ball is approaching a standing oberver at velocity V1 and a second observer is moving TOWARDS the moving ball at velocity V2 then the apparent velocity of the ball according to the second observer is V1 + V2
Because the speed of the ball (as seen by the observer that is standing still) is equal to the speed of the car added to the speed of the ball (relative to the moving car).
Thx Sir, its helpful.... I want to ask Sir, Is that same for Vball(relative to C) if a person doesnt run on a skateboard, but he is on the edge and suddenly he jump to to left with velocity 5 m/s? thx so much...
Poor?! Like really?!!! If u can't appreciate the marvelous job done by sir which has helped n continues to help millions of students across the globe then at least shut ur mouth up n don't post such offensive comments
You are sooooo very helpful! Thank you so much for posting all these Physics topics. I hope to find that you have videos that cover all of Physics 1 =) because I'd be lost without you.
You should include a donate button because you helped me a lot
ur great physicist
i watch your every vedio sir!!!!!
your great...
I the last case shouldn't we do that-- the velocity of the observer with respect to ground is 10-5=5m/s towards the right. then we subtract it from the velocity of the ball - 30-5= 25m/s.
I always tell my students, feel free to do a problem any way you like. I will show them one way to do it but then they can choose to do it in a different way.
Sir, I don't get this. Person B is moving oppositely to the car. I think we just need to minus 5m/s. Why do we need one more subtraction?
Think about it this way: what would be worse, two cars colliding head-on with one car traveling at 100 km/hour and the other car traveling at 99 km/hour or the faster car colliding the slower car from the back.
Sir. really you are help ing a lots of student and your lecture make IIT easy
best channel
Now I can finally understand this thing.....thanks a ton !!
that is a fine bow tie ;)
I find it easier to think in terms of collisions,or seperations, in relation to momentum.
If a top is moving on a table and the the table is. also moving in apposit direction with the same speed as the top .what will see the observer standing near table ?
If you are talking about a spinning top, the friction between the top and the table is not sufficient to have the typical relative velocity situation. If it is a car moving in a straight line, then the car will appear stationary to the observer
i don't get why the velocity of the ball relative to A is 20 +10 (30m/s)? Why do we need to add both velocities? Isn't it asking for the velocity of the ball only, why do we need the velocity of the car as well? < 20m/s?
The concept described here is what we call the RELATIVE velocity. We are finding the velocity relative to another moving object, or as seen by a person in a moving object. The ball will APPEAR to have a different velocity when seen by a person standing on the side of the road as opposed to being seen by a person in the car.
Michel van Biezen oh!! I get it, thank you so much!
Do we have any video that talks about frame of reference in relative motion such as Earth frame reference, zero reference, etc.. Thank you very much.
Only in terms of special relativity. See playlist: PHYSICS 62 RELATIVITY ruclips.net/p/PLX2gX-ftPVXUHWgsWbVG3__1dC8nKMvEi&disable_polymer=true
seriously, this guy is amazing... You just save my ass off Sir!!
Hi. Thanks for the video. A question about the velocity of the ball for viewer b: I get it that you need to subtract the vb because it is moving opposite to the car, but why does it become positive then? Why subtracting again to make it positive? It looks like a trick to me although I know that it isn't.? Thanks for any explanation given
Don't overthink it. You can determine the sign just by looking at it. If a ball is approaching a standing oberver at velocity V1 and a second observer is moving TOWARDS the moving ball at velocity V2 then the apparent velocity of the ball according to the second observer is V1 + V2
Sir, why did you added V of car to the V of ball in the first case?
Because the speed of the ball (as seen by the observer that is standing still) is equal to the speed of the car added to the speed of the ball (relative to the moving car).
Good Morning Sir,
Same to you
Nice video sir
Thanks
Thx Sir, its helpful.... I want to ask Sir, Is that same for Vball(relative to C) if a person doesnt run on a skateboard, but he is on the edge and suddenly he jump to to left with velocity 5 m/s? thx so much...
Good vedios
v=dv/dt w=how short that dt is
In the limit as dt goes to zero. That is the concept of calculus.
@@MichelvanBiezen thank you for helping me
Love from india
Thank you and welcome to the channel!
you need to hurry up and set up google wallet so i can donate to the site, you helped me out a ton
+Maxbr7t There is a donate button on the home page if you are able and so inclined. Much appreciated.
Thank you for the video. I find it very helpful.
It is too long !
I just used my imagination through life experiences.
poor explanation.......could have been done better....still great job...thanks !!
Gagan Mandal Care to explain how?
Poor?! Like really?!!! If u can't appreciate the marvelous job done by sir which has helped n continues to help millions of students across the globe then at least shut ur mouth up n don't post such offensive comments
Pritha Bhattacharya Lmfao millions right, on a video that only has 70,000 views?
@@danielbetancourt1483 lol agree though but i got a test in an hour lol
@@danielbetancourt1483 you do realize that he has multiple videos on his channel, not just this one, right?
Do we have any video that talks about frame of reference in relative motion such as Earth frame reference, zero reference, etc.. Thank you very much.
Only in terms of special relativity. See playlist: PHYSICS 62 RELATIVITY ruclips.net/p/PLX2gX-ftPVXUHWgsWbVG3__1dC8nKMvEi&disable_polymer=true
Do we have any video that talks about frame of reference in relative motion such as Earth frame reference, zero reference, etc.. Thank you very much.