40:12 Before dropping m2, Let the height depressed from natural length be h1 Now, m1g = kh1 ( At Equilibrium) h1 = m1g/k Now, m2 is dropped and the height depressed from natural length be h2 At equilibrium position, (m1 + m2) g = kh2 h2 = m1g/k + m2g/k h2 = h1 + m2g/k So the max displacement from mean position is h2 - h1 ( It is clearly evident if we draw the diagram) So, Amplitude, A = m2g/k And Time Period is T = 2π√[(m1+m2) /k]
1:46 basics of shm 9:44 energy of a particle in shm 15:11 variation of KE and PE 17:38 how to find time period of shm in a physical situation 20:50 shm of simple pendulum thanks to pratikk
It's my humble request to PG Team that they must upload checklist as soon as it is made because it would help us more and quickly :) Those who think it would be more beneficial please tell PG Team.
@@physicsgalaxyworld sir after jee main if all chapters are not covered then are you stop uploading checklist ...... Plzz sir it's a kind request don't stop this........it uplift my concept 5 times for exams....💪💪💪💪💪
1:46 basics of shm 9:44 energy of a particle in shm 15:11 variation of KE and PE 17:38 how to find time period of shm in a physical situation 20:50 shm of simple pendulum
40:10 New mean position=> (m1+m2)g=kh2 New extreme position h3(Velocity=0)=> Equate energy in h2 and the extreme position(h3) *h3-h2 is your amplitude*
@@gurjotsinghmann1639 Actually they are not blind , because of getting such a crystal clear concept video on SHM they couldn't get the equilibrium position of brain and because of SHM they thought clicking the dislike button will become like as thumb will attain equilibrium after some period of time. 😂😂😂🤣🤣🤣
BASICS OF SHM- 1:45 ENERGY OF A PARTICLE IN SHM- 9:45 VARIATION OF KE AND PE IN SHM- 15:12 HOW TO FIND TIME PERIOD OF SHM IN A PHYSICAL SITUATION- 17:40 SHM OF A SIMPLE PENDULUM- 20:52 SHM OF A SPRING BLOCK S/M - 24:40 SHM OF A BLOCK UNDER SPRING COMBINATIONS- 28:13 SHM OF A PLATFORM WITH A MASS- 31:46 DIFFERENT CASES OF SPRING- BLOCK S/M- 35:45 SHM OF A FLOATING BLOCK: 43:16 ANGULAR SHM -47:53 TORSIONAL PENDULUM-55:21 SHM OF A PISTON ON A GAS CYLINDER- 1:00:32
At 40 minutes 28 seconds First of all I calculate the equilibrium distance of block M1 Can I calculate the equilibrium distance of the combined body of block M1 and M2 The equilibrium position of block M1 will act as the mean position for the component system of the bodies and then I calculate the height difference between them and I took this as the amplitude of the combined body Means amplitude is equal to H2-h1 Where H2 is the equilibrium position of the combined what is and H1 is the equilibrium position of the M1 block.
Sir i am JEE 2023 aspirant. I make short notes from your checklist and my class notes ! Literally my coaching institute provide 7-8 ( 90 minutes ) lecture for SHM but still there were some topics which were not covered. But your checklist video helps alot. It changes the way of thinking!❣️ Thank uhh PG team! ❤️🙏
Thank you very much sir....eventhough many teachers taught this, i didn't understand anything. But after i watched your video, now i'm able to answer the questions with logic....
Very very thankyou sir........ From by point of view ASHISH ARORA SIR deserves BHARAT RATNA ...... NOBLE PRIZE as well....... sir you are really a brand
40:00 answer for the question would be (m1+m2)g/k-m1g/k I calculated the mean position as mg=kh1 then (m1+m2)g= k h 2 then subtracted the 2 lengths . Can you clarify if this is correct thank you @Physics Galaxy
These revision checklist are really very helpful and after watching them I can solve previous year problems very quickly and with great understanding... Thank you very much sir for providing such quality education for free...
Thanks a lot sir In my coaching institute semiconductors, communication syatem and other mains related topics are not covered but i completed all thes through pg lectures Thanks a lot
Great sir.... Sometimes I wonder that if studying online from you is so great than how would offline mode be😀😊 Thankyou so much sir.. Have a huge respect for you sir🙏🙏🙏🙏
Brother sir ne shi likha h kyuki at mean position we get equilibrium and at equilibrium potential energy=0 and kinetic energy is max [see the graph brother] thank you
For 40:00 Before dropping m2, Let the height depressed from natural length be h1 Now, m1g = kh1 ( At Equilibrium) h1 = m1g/k Now, m2 is dropped height displaced from natural length be h2 At equilibrium position, (m1 + m2) g = kh2 h2 = m1g/k + m2g/k h2 = h1 + m2g/k max displacement from mean position is h2 - h1 So, Amplitude, A = m2g/k And Time Period is T = 2π√[(m1+m2) /k] sir have I correctly solved it?
I have a request to all the viewers , if you watch the video and gain even 1% knowledge then plzzz do like the video , it will give physics galaxy team motivation.. THANK YOU.
Thankyou sir for uploading these checklists these are very very benefical, but can you please arrange checklists of maths and chemistry . PS: i was able to score 72 in physics by following these revision checklists thankyou sir
at 42:00, in third case can anyone confirm Amplitude expression with mine? process i did, just like in case 1, A will be h0-h1 if we consider elongation ho after the addition of mass m2, so equation of motion now = (m1+m2)g=kh0, and A-h0-h1 now we substitute, am i right ashish sir?? or anybody?
I have a doubt at 40:00 ,i mean H2 should act as the new mean ,so shm should take place about H2 ,H2 - H1 should not be the answer ,there should be an h3 that exist where the velocity becomes 0 and extention must be h3-h2. But how am I supposed to calculate h3? That's where my question lies.
I am studying in class 11 jee main division of resonance but I never get good faculty of physics due to this reason my 11th physics totally destroyed but due to physics galaxy all concept and revision checklist I am covering fully physics and this time my physics is good condition and I am also solve all type of question of resonance sheets and this totally credit goes to you sir
Correct me if I'm wrong, I think there are two mistakes at 1:03:52, formula of shm of piston. Possibly in the formula there should be use of volume final and pressure final..?
Revision Checklist for Class 12 LIVE today! - ruclips.net/video/DJw9Vnt-kE4/видео.html
Sir 4th case ka video bataye....
🙏🙏
Thank you sir very helpful
Can you tell me that in the forth part 42:10 what is that amplitude..????? Please help
Sir aapki Kuch checklist videos show Nahi ho rahi h from waves till ray optics
40:12 Before dropping m2,
Let the height depressed from natural length be h1
Now, m1g = kh1 ( At Equilibrium)
h1 = m1g/k
Now, m2 is dropped and the height depressed from natural length be h2
At equilibrium position, (m1 + m2) g = kh2
h2 = m1g/k + m2g/k
h2 = h1 + m2g/k
So the max displacement from mean position is h2 - h1 ( It is clearly evident if we draw the diagram)
So, Amplitude, A = m2g/k
And Time Period is T = 2π√[(m1+m2) /k]
Thanks
Thanks.
@@adityaverma2496bhai sahi hai uska soln
Answer matched
yesss i also got this but dont know if its correct...
1:46 basics of shm
9:44 energy of a particle in shm
15:11 variation of KE and PE
17:38 how to find time period of shm in a physical situation
20:50 shm of simple pendulum
thanks to pratikk
Abhi kahan ho bro??
Reply?
thanks bro i am really trying for iit b this year could only make it to iit delhi this time
40:00 (M2 mass placed over M1 pan gently)
The amplitude is (M2)g/k
The time period is 2π.sqrt{(M1+M2)/k}
Please verify the answer.
I got same answer
correct!!
gg
Shi h bhai
Same
It's my humble request to PG Team that they must upload checklist as soon as it is made because it would help us more and quickly :) Those who think it would be more beneficial please tell PG Team.
They also tried their best as they mentioned it on previous video comments.......
Dear all, sir is recording videos on the go. We are not holding back. We are standing with you in your support.
@@physicsgalaxyworld sir after jee main if all chapters are not covered then are you stop uploading checklist ......
Plzz sir it's a kind request don't stop this........it uplift my concept 5 times for exams....💪💪💪💪💪
@@addractivetri sir jo kaam karte poora karte hai to complete to kar he denge checklist bhale he mains ke baad tak kyu na ho
@@physicsgalaxyworld please start uploading jee mains checklists
28:09 pogy cleared it in such a lightening speed that we could not even see the movement of him, he sure is evolving with time.........
1.5x me dekh Rahe the kya
@@sasikk1763 2x
@@sasikk1763 nahi 2x
16:49
Sir Poji ne aapki man ki baat phle hi sunli thi 😁😁
😅😅😅😅
🙊🤣🤣🤣
🤭🤭
😂😂😂😂exactly
Bhai konse college mein cse
1:46 basics of shm
9:44 energy of a particle in shm
15:11 variation of KE and PE
17:38 how to find time period of shm in a physical situation
20:50 shm of simple pendulum
40:10
New mean position=> (m1+m2)g=kh2
New extreme position h3(Velocity=0)=>
Equate energy in h2 and the extreme position(h3)
*h3-h2 is your amplitude*
Is answer g/k × m 2
Yes mera and bhi yhi h
Mera m2g/2k aa raha
Please toda ache se explain kardo bhai 😰😰
Bhai final - initial hi toh Altitude hoga
This shows how beneficial this is for us
~4k views
~410 likes
~0 dislikes
Thank you so much sir..
119K views
4.4k likes
67 dislikes
Dkmkb
@@RoyBoyLab
~191K views
~6.8K likes
~106 dislikes
Thank you so much sir..
~ 245k views
~8.3k likes 👍🏻
~126 dislikes👎🏻(maybe mistake from some blind person or a person jo akal se andha ho)
@@gurjotsinghmann1639 Actually they are not blind , because of getting such a crystal clear concept video on SHM they couldn't get the equilibrium position of brain and because of SHM they thought clicking the dislike button will become like as thumb will attain equilibrium after some period of time. 😂😂😂🤣🤣🤣
@@roneet9027 bro bot BHI rehte h dislike Kabhi 0 nhi rehta
BASICS OF SHM- 1:45
ENERGY OF A PARTICLE IN SHM- 9:45
VARIATION OF KE AND PE IN SHM- 15:12
HOW TO FIND TIME PERIOD OF SHM IN A PHYSICAL SITUATION- 17:40
SHM OF A SIMPLE PENDULUM- 20:52
SHM OF A SPRING BLOCK S/M - 24:40
SHM OF A BLOCK UNDER SPRING COMBINATIONS- 28:13
SHM OF A PLATFORM WITH A MASS- 31:46
DIFFERENT CASES OF SPRING- BLOCK S/M- 35:45
SHM OF A FLOATING BLOCK: 43:16
ANGULAR SHM -47:53
TORSIONAL PENDULUM-55:21
SHM OF A PISTON ON A GAS CYLINDER- 1:00:32
Thx
At 40 minutes 28 seconds
First of all I calculate the equilibrium distance of block M1
Can I calculate the equilibrium distance of the combined body of block M1 and M2
The equilibrium position of block M1 will act as the mean position for the component system of the bodies and then I calculate the height difference between them and I took this as the amplitude of the combined body
Means amplitude is equal to H2-h1
Where H2 is the equilibrium position of the combined what is and H1 is the equilibrium position of the M1 block.
Helps too much in last month revision from the checklist series rather than studying from books👍
True
absolutely....by the way if you know any similiar kind of short revision videos for Maths or Chemistry too then also tell me....Please!!!!🙏🙏
@@l052_jeeveshpathak8 math on go
Yep
@@l052_jeeveshpathak8 for maths neha ma'am mathematically inclined and for chemistry unacademy atoms
35:59
Ans.of third one
T=2pi root m1+m2/k
w= root k/m1+m2
got the same answer ;)
16:47 Pogee rocked , sir shocked
😂😂
pogee bunked the class
Sir your checklist are great.
By watching them I can solve previous year problems chapterwise with ease of understanding .
Thank you sir
Thanks a lot for your appreciation Adarsh. Fulfills our objective.
Bhai you are neet aur jee aspirant
@@aaryansingh7176 no upsc aspirant
@@predatordeacon5946 wow taking Physics in UPSC very interesting hope you clear exam with this interesting and amazing subject . 🙏🙏🙏🙏🙏👍👍👍👍
@@roneet9027 he’s being sarcastic 🤦🏼♀️
Wonderful... Bas basics pata the pahale...abhi HCV bhi solve ho rhi ess video se. Thanks sir
Now my 12 physics is almost finished from NCERT now I start 11 physics thanks sir for this checklist
Sir please Errors and Analysis par checklist bna dijiye.... Aapki checklist se Revision and Confidence ko boost mil rha h...
40.12
Ans1= amplitude=m2g/k
And. Time period is =====2π√m1+m2/k
At 30:09 case 3 is a direct question of jee 2022 🔥🔥
😮
you are a ideal teacher for every aspirant ❤️
Bhai ji kya aap in checklist se revise krte ho
16:48, aur 28:10, isse hame yeh pta chalta hai ki aaj kal poggee ka kaam main dhyaan nhin hai
Thank u sir for such condensed lectures ; helping a lot in quick revision
Good to know tarun, pl subscribe and tell your friends, that'll be the best way to thank
@@physicsgalaxyworld Nhi to whoo competition mee aage aa jayenge 🤣
Sir i am JEE 2023 aspirant.
I make short notes from your checklist and my class notes !
Literally my coaching institute provide 7-8 ( 90 minutes ) lecture for SHM but still there were some topics which were not covered.
But your checklist video helps alot.
It changes the way of thinking!❣️
Thank uhh PG team! ❤️🙏
🌚 Ik you were from ARJUNA JEE
BTW where r u now?
@@ADITI_kriarre pagal vo 1 saal purana hai comment hai tab tumhara arjuna jee tha bhi 😂😂
Rank?
Sirs diagrams are drawn perfect like if they are printed on a paper
Well well the best revision series for physics ☝️
T=2π sqrt((m1+m2)/k) and A=m2g/k. using the analysis explained in Example 1
Wouldn't A be (m1+m2)g/K?
@@syedsabahuddin9470 Bro
m1g=kh1
(m1+m2)g=kh2
A=h2-h1 = m2g/k
@@adityasingh1423 oh right, I confused h2 with A, thanks for clearing :)
@@syedsabahuddin9470 No Problem bro :)
correct bro getting same answer
600K completed sir ! CONGRATULATION MY DEAR SIR
1st case @ 36:05 answer of amplitude is (m2)g/k
please verify
Ya I've got the same answer.
Yes bro u r right
My kind request to PG team and Ashish Arora sir... please add time stamps to the videos which would help us revise a particular topic quickly...
The best physics teachers
At 42:00 For the pan and mass question in point 9 answer is
Amplititue : M2g/k
Time Period : 2π root [(M1+M2)/k]
Thank you very much sir....eventhough many teachers taught this, i didn't understand anything. But after i watched your video, now i'm able to answer the questions with logic....
Very very thankyou sir........
From by point of view ASHISH ARORA SIR deserves BHARAT RATNA ......
NOBLE PRIZE as well.......
sir you are really a brand
I wish I would have such useful checklist for maths and chemistry
Yeah I would wish too.. if you find one for math/chem let me know :D
Ya even i wish 🥺
ruclips.net/p/PLEtM3gLiyRkhdMa87N-Dn7Xjnmue2RAr8
This one is for Mathematics by VMC teachers.
Hope this will help
esaral revision checklist is also good.
For maths go to Neha Agarwal madem youtube channel there u can find oneshot videos
40:00 answer for the question would be (m1+m2)g/k-m1g/k I calculated the mean position as mg=kh1 then (m1+m2)g= k h 2 then subtracted the 2 lengths . Can you clarify if this is correct thank you @Physics Galaxy
yes, you gave the correct solution.
Notes for self-reference
35:45- SHM spring-block diff cases
43:16- SHM of floating block
Sir my brother told about you he is in srg allen group
You are really fantastic
Lier
@@Jahnavi-ee2ex why
Too much helpful in revision of SHM... Thanks a lot sir ...
I feel easy to solve previous years questions of SHM after watching this.. Thank you sir for uploading this video..👍👍👍
No words to convey the greatness of ashish arora sir
0:07 Me during my passport size photoshoot :-
Hahahaa
I hear name of phisics galaxy and I come here and I see the concept clearing of sir is fantastic 👍🙏🙏🙏
At 14:52 , in first exp. of total energy +Uo will also come.
Sir u are one of the finest teacher in india
exactly...........
Imagine such checklists for chemistry tooo!!!!!!!
That will be a boon😂
Good prediction brother
I dont know if this comes across as cheesy, but not going to lie this revision checklist is not only educational, its really fun!
Jojo
These revision checklist are really very helpful and after watching them I can solve previous year problems very quickly and with great understanding...
Thank you very much sir for providing such quality education for free...
16:50 editor ne sir ko dhoka de diya
Tu mera bhai hai
@Harshit Raj nahi bhai its editing
Mujhe uska name hi ache se nahi samajh aya... Og ya poji... Waise usne sir ke kehne se pehle hi sir ka kaam kr diya
@@aniketbansal4822 poji (pg) 😊
@@gaurangmundhra2004 Aur mai tera asli baap hu .
Thanks a lot sir
In my coaching institute semiconductors, communication syatem and other mains related topics are not covered but i completed all thes through pg lectures
Thanks a lot
That's great! Please subscribe and spread a word.
Salute your dedication toward work ....your work is really inspire to study .
@40:00 new time period T=2πsqrt M1 +M2/k
Can any one tell me that in the forth part 42:10 what is that amplitude..????? Please help
@@ashku8252 bro it is (M1+M2)g/k
16:51 POGI to Aaya hee Nahin🤣🤣...
Just joking sir...
as always a great video....
Are Bhai bhai
Me too noticed same😂😂😂😂😂
Same here bro
Editor se mistake hua hai
video editing mistake !!
Jazakallah sir for this help.
@@mrmttr3 it means THANK YOU
@@mrmttr3 Simple meaning :Thank you
Literal meaning : "May Allah reward you for this with immense goodness"
Great sir....
Sometimes I wonder that if studying online from you is so great than how would offline mode be😀😊
Thankyou so much sir..
Have a huge respect for you sir🙏🙏🙏🙏
Thanks sir and to the team. It is very helpful for such lengthy chapters.
Best Way to Revise Concepts by Checklist!!!
Thank You Sir
sir ur explanation for SHM is the best that i have come across on youtube...explained from basics
Sir in 15:06 at TE at mean position there will be ½mA²w² + Uo but u have written that in Extreme position where PE is max
Brother sir ne shi likha h kyuki at mean position we get equilibrium and at equilibrium potential energy=0 and kinetic energy is max [see the graph brother] thank you
thank you very much sir...
you are doing a great work.
16:49 pakde gaye sir ji 😅😅
These checklist are best for revision in very short time with full detail
Thanks Sir a lot 🙏🏼
For 40:00
Before dropping m2,
Let the height depressed from natural length be h1
Now, m1g = kh1 ( At Equilibrium)
h1 = m1g/k
Now, m2 is dropped height displaced from natural length be h2
At equilibrium position, (m1 + m2) g = kh2
h2 = m1g/k + m2g/k
h2 = h1 + m2g/k
max displacement from mean position is h2 - h1
So, Amplitude, A = m2g/k
And Time Period is T = 2π√[(m1+m2) /k]
sir have I correctly solved it?
correct
I am also getting same answer
Correct
Very helpful video for last month rivision sir thank you sir
Jo notes chahtein hai kitaab khareed lein sir ki....they are perfect
16:58 Ashish sir is destroyed by his *pogi*😂🤣😜
I could not get this type of content in paid courses
Fabulous sir ... Thanks for such an initiative 🙏🙏
I have a request to all the viewers , if you watch the video and gain even 1% knowledge then plzzz do like the video , it will give physics galaxy team motivation..
THANK YOU.
Thankyou sir for uploading these checklists these are very very benefical, but can you please arrange checklists of maths and chemistry .
PS: i was able to score 72 in physics by following these revision checklists thankyou sir
hi what else did u do.. only pvq and this
Sir you are a great teacher in my life 🙏
by far the best revision checklist of shm
GURU JI KO MERA PRANAM 🙏🙏🏻🙏🏼🙏🏻🙏🏼
Namaskar sirji
thank u sir
all concept revised
Thank you so much sir bahut help kiya neet ke liye to saara formula mil gya 🙏🙏 mera chapter ka revision ho gya
Sir aap itne acche kaise hain...well bahot accha kaam kar rhe hain aap
Charan sparsh
at 42:00, in third case can anyone confirm Amplitude expression with mine?
process i did, just like in case 1, A will be h0-h1 if we consider elongation ho after the addition of mass m2, so equation of motion now = (m1+m2)g=kh0, and A-h0-h1 now we substitute, am i right ashish sir?? or anybody?
yes same
Yes same
i think 2A-h0-h1
@@Raginipandey953 how to solve it
@@sachinbaghel1518 sir said that amplitude of 2 extremities is 2A
I have a doubt at 40:00 ,i mean H2 should act as the new mean ,so shm should take place about H2 ,H2 - H1 should not be the answer ,there should be an h3 that exist where the velocity becomes 0 and extention must be h3-h2. But how am I supposed to calculate h3? That's where my question lies.
h3 is extreme point so it's h2-h1 = amplitude
Really very helpful... keep uploading please 🙏
42:28 x=3(m1g)/k
ans of the question at 41:39
x=m1g/2k
How bro?
28:00 imp
40:00
17:48 sir can we use delta x/ lambda = delta phi/ two pi = time/ time period method ??? Sir pls and and help
No other teachers like u sir
Sir best lecture as used as one shot❤❤❤
At 16:48 poji is curve ka modification curve dikhaiye
Poji : sir goona advanced 🔥
Nice teaching alway respect 👍
But it's not poji it's PG (PHYSICS GALAXY)❤️
thanks sir now i am confident with shm thanks for boosting my confidence
Iam from Hyderabad thank you sir for supr revision
Thanku POGI 😇 it helped alot
Wow keya lecture hai sir super super😍😍😍
Your work is my motivation
Thank You sir.Very Helpful for fast revision of whole chapter
I have not any word for Ashih Arora sir.
Ashish Arora sir you mean? We take it as a compliment Praveen :)
I am studying in class 11 jee main division of resonance but I never get good faculty of physics due to this reason my 11th physics totally destroyed but due to physics galaxy all concept and revision checklist I am covering fully physics and this time my physics is good condition and I am also solve all type of question of resonance sheets and this totally credit goes to you sir
Sir amplitude of oscillation in 37.25 is m2g/k and time period of oscillation is 2 pie((m1+m2)/k^(1/2))
i got (m1g+2m2g)/K as the amplitude
I dnt know bro..let sir tell
can u explain how you reached at the following answer
your time being very precious a small explanation will do
Yes my answer is also same
Thank you sir for the best possible revision on SHM
No strategy videos, no motivation videos, no click baits...still such a loved channel! Thankyou so much sir for helping all of us!
These videos are very helpful sir!! Great for revision. Please upload next checklist on thermodynamics.
I am using it as a one revision thankyou so much sir
Sir you are great thanks for improving my Marks..🤩😇
Correct me if I'm wrong, I think there are two mistakes at 1:03:52, formula of shm of piston.
Possibly in the formula there should be use of volume final and pressure final..?
16:50
Sir POZI is bussy to solve Numericals
Amazing power of knowledge