Kindly make sure to *watch* the *full video* and answer the *homework question* in the comment section. *Like* the video and *Subscribe* to the channel for more awesome content. All the best!
Sir I am in 11 class sir can you tell me what are the important chapters or topics in class 11 so I can make the chapter more strong please please please sir
On the basis of bond order, n2 has triple bond so bond energy of n2 is maximum, and on the basis of least bond order F2 and H2(single bond), but if we compare in these 2, size of H2 is small so bond energy would be greater hence least bond energy would be of F2
Three lone pairs on F-F bonding will increase the force of repulsion. Then the distance between F and F bond will increase and hence it will cause less bond Energy. Got the point. Bond Energy is inversely proportional to Bond Length
Your organic chemistry free videos on unacademy are very good. The videos there and ncert book helped me solve many questions in jee advanced. Thank you for your efforts.
I didn't get any rank cuz I did not clear the cutoff of maths....my comment above is only regarding ORGANIC chemistry...I did the above (plus ncert) and was able to solve majority questions of organic
Sir I didn't understand chemical bonding but now I know chemical bonding very well . It's because you . Thanks sir and keep educating IIT aspirants.you are really a great mentor.
Sachin sir minimum will be F2 and maximum will be in N2 the min could be H2 but as there is more repulsion in F due to LP-LP It will take the minimum BDE
N2>O2>H2>F2 H2 has the highest bond energy for a single bond between atoms of any element.Please refer NCERT Chemistry textbook 2 pg no.278 last stanza. Maximum B.E is for N2 and minimum B.E os for F2.
HW; N2>O2>H2>F2 N2 _ triple bond. O2 _double bond Both H2 and F2 have single bond,but B.L of H2 is less than F2, There for N2 max BE F2 min BE. Is this right sir????
N2>O2>H2>F2 correct order of energy. 1- N2, O2, H2 & F2 have triple double & single single bond 2- & in H2 & F2 both have sb but size of H2 is less then F2 so energy to break short bond is greater then long bond. I hope this will right. Is it? Pranam sir🙏❤
Sir minimum bond dissociation energy required will be for F2 because of l.p-l.p repulsions whereas maximum bond dissociation energy required will be for N2 due to bond order- 3 incase of no resonating structures
One doubt, In N2F4, there is repulsion from N as well as F so even if Nitrogen atom is trying to push far the other nitrogen but again fluorine is pushing back. Whereas in N2H4 N-N is repulsive, nd no one is Pushing nitrogen from the other side. So shouldn't bond length of N2H4>N2H6? Answer is N2(max, due to B.O.3) and F2(min)
Nitrogen has triple bond so it require more energy (but you have shown us only two bonds between nitrogen) and fluorine has one bond with three lone pairs so there will be greater repulsion between them so bond length will increase and bond enthalpy will decrease so your answer is [nitrogen has more and fluorine has less bond enthalpy]
If there is lone pair lone pair repulsion then the bond length should decrease as they would make the Oxygen in F2O2 closer to each other and the same in N2F4 as we are not comparing the atoms that have lone pair lone pair repulsion
Hello Sachin Bhaiyya! I have a query. I am a dropper. I am starting to read JD Lee for the extra part in Inorganic since I've done the Ncert well. What should be the best way to study it and what portions of it(extra part) should I avoid?. Also I'm starting with Chemical Bonding. Also thanks for the tips in the video. Will apply!
Kindly make sure to *watch* the *full video* and answer the *homework question* in the comment section. *Like* the video and *Subscribe* to the channel for more awesome content. All the best!
Max for n2 and min for f2
Was it right
Bhaiya can I get your email id as I have to ask many question #dropper for 2020
N2 strongest and F2 weakest!!
Sir I am in 11 class sir can you tell me what are the important chapters or topics in class 11 so I can make the chapter more strong please please please sir
On the basis of bond order, n2 has triple bond so bond energy of n2 is maximum, and on the basis of least bond order F2 and H2(single bond), but if we compare in these 2, size of H2 is small so bond energy would be greater hence least bond energy would be of F2
Three lone pairs on F-F bonding will increase the force of repulsion. Then the distance between F and F bond will increase and hence it will cause less bond Energy.
Got the point.
Bond Energy is inversely proportional to Bond Length
Lowest bond energy is of F2 (due to multiple lp) and highest BE is of N2 (due to triple bond)
If we compare on the basis of bond Oder then also same ans
@@richasingh156 yes 😄
So is that way of comparing also true!!
@miss curiosity , b.o. of both h2 and f2 is 1
@@naveenraj2422 one with least antibonding electron has less bond energy
Your organic chemistry free videos on unacademy are very good. The videos there and ncert book helped me solve many questions in jee advanced. Thank you for your efforts.
Rank?
I didn't get any rank cuz I did not clear the cutoff of maths....my comment above is only regarding ORGANIC chemistry...I did the above (plus ncert) and was able to solve majority questions of organic
College kaun se chosse kiye bhai😢
@@donno9984it's a state govt college which I got in state counseling
@@rekhamishra2000 your rank ?
Thank u so much Sir,i didn't understand the chemical bonding in my coaching but now i have understood 😊😊
Minimum :- F >O> N> I .
Maximum:- I> N>O >F.
I to isme option nhi h sis...n hoga
Sir I didn't understand chemical bonding but now I know chemical bonding very well . It's because you . Thanks sir and keep educating IIT aspirants.you are really a great mentor.
N2(as triple bond is present) > O2 ( double bond) > H2 > F2 (lp lp repulsion)....... thanks Bhaiya
H2 N2 o2 de decreasing order for bond energy
correct
The Order of the halogen group bond length is Cl-Cl > Br-Br > F-F .> I-I
maximum bond energy- N2
and lowest bond energy- F2 in this because of lp-lp repulsion 😊
But F is most electronegative so please explain,!🤌💞
Sachin sir
minimum will be F2 and maximum will be in N2
the min could be H2 but as there is more repulsion in F due to LP-LP It will take the minimum BDE
minimum: Florine and Maximum: Nitrogen , Thank you for the clear explanation :)
N2>O2>H2>F2
H2 has the highest bond energy for a single bond between atoms of any element.Please refer NCERT Chemistry textbook 2 pg no.278 last stanza.
Maximum B.E is for N2 and minimum B.E os for F2.
Nice concept hey aap meko electron gain enthaply ka trend samjha skte ho?plzz
your way of teaching is better than those 5 hrs lectures
Bind dissociation enery order will be N2,O2,H2,F2 (based on the value taken from google in kilojule/mol)
HW;
N2>O2>H2>F2
N2 _ triple bond.
O2 _double bond
Both H2 and F2 have single bond,but B.L of H2 is less than F2,
There for
N2 max BE
F2 min BE.
Is this right sir????
Bond energy Max Will be N2 and Min will be F2 thanks bro u R the best pls continue making vids on jee syllabus
The maximum bond energy will be in nitrogen molecule as it contains highest bond order, and the minimum is in Florine as it is larger in size
Wrong
It is small in size
N2>O2>H2>F2 correct order of energy.
1- N2, O2, H2 & F2 have triple double & single single bond
2- & in H2 & F2 both have sb but size of H2 is less then F2 so energy to break short bond is greater then long bond.
I hope this will right.
Is it? Pranam sir🙏❤
Waw incognito wale guruji mja aa gya
Sir doubt kha lege aap 😅😅 respect for you 🎉🎉🎉❤❤❤
Sir at 12:46 the order of Bond energy should be cl2 >br2>f2>I2 according to actual experimental data ..please verify
YES
7:42 same question in jee main 1feb shift 2 jee mains 2023
Perfect language to understand
Sir minimum bond dissociation energy required will be for F2 because of l.p-l.p repulsions whereas maximum bond dissociation energy required will be for N2 due to bond order- 3 incase of no resonating structures
And one more thing I am studying in 8 th class
IIT BOMBAY❤ tag was enough to enter in this vedio😅
Same 😅😂
Min F2 nd max N2
N2>O2>H2>F2
The best video ever of chemical bonding thanks sir 😊
Mai chote se coaching me padhta hu yahi doubt mujhe pareshan kar raha tha waha achhe se doubt nahi btaya jata hai bahut sukriya
H2O2 > O2F2 Bond length
Due to EN the O-O bond is shorter in Oxygen Fluoride is shorter than the O-O bond in Hydrogen peroxide
Tag kar usko
Tera bara bar hai
You Are correct
Highest bond energy is N2 because in N2 three bond are present.
And lowest bond energy is H2 because in H2 one bond is present.
You are great bhaiya!!
One doubt,
In N2F4, there is repulsion from N as well as F so even if Nitrogen atom is trying to push far the other nitrogen but again fluorine is pushing back. Whereas in N2H4 N-N is repulsive, nd no one is Pushing nitrogen from the other side. So shouldn't bond length of N2H4>N2H6?
Answer is N2(max, due to B.O.3) and F2(min)
Same doubt ,did you get it cleared?
Same doubt and o-o bond length in o2f2 is smaller than that of in H2O2
@@dhasathdashath1900 bro, I cleared jee xD
@@akshaydas2021 congo
@@akshaydas2021 which iit
bro u have got a great talent of teaching that helped a lot btw IITB is kinda giving some goosebumps, hope Ur doing great in life
This is The power of IIT BOMBAY..Nice sir👌👌👌
Min- F2 and max -N2
Minimum - F2
Maximum - N2
F2 < H2 < O2 < N2
Due to lp-lp repulsion
N2 has highest bond energy and F2 has lowest
N2 then O2 then H2 then F2
In decreasing order
How?
"You can draw all these and waste your time" epic 😂😂😂😂🤣🤣
3:41 No Offence just for fun.. That was an Epic Move thoughh 🗿
N2(BO =3) >O2 (BO =2) >H2 (BO=1) >F2(LP-LP repulsion)
h2 me 1s-1s overlap ki wajah se uska bond strong hota h this is the reason
at 12:47 the correct order bond energy is Cl2>Br2>F2>I2
Thanks bro Live long life. Please apply more than 10 videos in a week
Sachin bhaiya one day I will meet u in campus of IIT Bombay ☺️☺️
All the best
Jab tk tu jayega tab tk sachin sir graduated honge uss clg se nikal chuke honge pass hoke 😎😂
ab mat jaa yaar bhaiya ho chuke graduate ab koi mtlb nhi hai jaane ka mat jaa
@@naamkyubatau615 🙄🙄😬😬😒😒😒😒😂😂😂😂😂😂😶😶😶
Great👌
Superb Lecture ❤
Sir any tips for complete in IIT
N2triple bond Max be and fluorine min becoz of interelectronic repulsion within the atom . 13:05
B.L depends on
▪︎size
▪︎electronegativity
▪︎bond angle
▪︎Lp lp repulsion
B.E depends on
▪︎B.O
▪︎B.L
▪︎lp lp repulsion
May u get all the success in ur life💖
Such a nice video ...with full concepts
N2>O2>H2>F2......? Correct
Thank sir very helpful video thank you so much sir
Thanks Bhai what a great video which cover my all doughts as well as my left portion.
Teaching way is too good sir
Order of ENERGY -> N2 > O2 > H2 >F2 13:09
Sir answer is N2>O2>H2>F2. Because of Bond Order and in last case Fluorine has more lone pair.
Sir your video helped me a lot.. I got selected in vmmc for mbbs..i owe you.. Thank you sir
😍😍 vmmc
Congoooooooo
From neet aspirant 2023 🙌🌺
Nitrogen has triple bond so it require more energy (but you have shown us only two bonds between nitrogen) and fluorine has one bond with three lone pairs so there will be greater repulsion between them so bond length will increase and bond enthalpy will decrease so your answer is [nitrogen has more and fluorine has less bond enthalpy]
Thank You Sir For THis Video I didn't Understand this in my coaching but now it seens crysral clear.
H2>N2>O2>F2
Best explaination have i seen ever
6:45 cant this question be explained on basis of bent's rule?
Yes
But that's not in course
If there is lone pair lone pair repulsion then the bond length should decrease as they would make the Oxygen in F2O2 closer to each other and the same in N2F4 as we are not comparing the atoms that have lone pair lone pair repulsion
Max:-N2 Min.:-F2.
Hello Sachin Bhaiyya! I have a query. I am a dropper. I am starting to read JD Lee for the extra part in Inorganic since I've done the Ncert well. What should be the best way to study it and what portions of it(extra part) should I avoid?. Also I'm starting with Chemical Bonding.
Also thanks for the tips in the video. Will apply!
F2 less B.E
N2 More B.E due to 3 bond 🙌
thank you so much, your video help me alot☺
Woww sir you are the god of bond parameters...
Sir, 8:38 Wale example ko agar Bent rule se karenge to answer ulta aa raha hai. Idar Bent rule kyun nahi laga?🤔 Please explain.
thankyou so much to explain in short & simple way
Bhaiya ek dam clear samaj aaya
Thankyou sir for this video 🙏🙏🙏
nice video bhaiya..to the point which make your videos more beautiful..keep spreading the knowledge..
To abhi kha pe ho AIIMS ya iit😄
Thank you sir
sir but bond length must decrease as lone pair will repel the oxygen and the oxygen will move towards the second oxygen...
Sir it was really helpful and logical at the same time🤩
N2.. O2.... F2.... H2
H2 ki bond energy f2 se km kaise hogi🤔
F2 has lower be than h2 bcoz of bigger size and lp lp repulsion
Bhaiya aap aise hi aur important topics ki video banao it will be helpful for IIT aspirants
👉Max in N2(as bo. Is max)
👉Min in F2(as size of h2 is smaller so its be is more, moreover, due to lp repulsion be of f2 becomes less )
thanks u cleared my concepts
Minimum bond energy= F²
Maximum bond energy=N²( tripal bond)
your explanation best and thanku so much
12:40 The correct order of B.E is Cl2,Br2,F2,I2 , plss recheck it , you did wrong
Lamo I was also thinking that
@@s.g1620 yeah
lowest B.E F2
highest B.E N2
H2 molecule have higest bond energy because of smaller size of H and F2 molecule have lowest bond energy because of bigger size of F
I like ur videos very much .....excellent teaching
Thank you so much sir Ji 🙏🙏🙏❤️❤️🔥
OPTICAL ISOMERISM COORDINATION COMPOUND ..pls make a video
Good teaching...
Thanks bhaiya mast samajh aa gaya
Minimum bond energy in F2
Maximum bond energy in N2
Thank you sir tomorrow my exam very help full video ❤
Bhaiya aap ne equilibrium complete pada Diya ky
Thank you sir...
I really appreciate your work
Thankyou 🙂
Are bhaiya chemistry he exception bhul gye kya f-f cl-cl se bda hoga bond length me dekho
Bhaiya florine and H Have single bond then please tell me which one have lowest bond energy
Sir in OF2 and O2F2,which has large O-F bond length and why
Thank s bhai
Nitrogen is maximum BE as compared to Oxygen>F2>H2