This is literally the best explanation out of literally soooo many (including my past instructors) that I've seen! My only regret is not finding you sooner, new subbie for sure.
I updated this chart with several steps that anyone could use to find a subnet and BC address. I would love to share it with you, if at all possible? Also, I added your name to my updated chart that my study buddies and I are using. I want to make sure they use this tutorial only for subnetting. It truly is a lifesaver! 🙌🏾❤️
Hi Shauntae, I am thrilled to see that my work has helped you and your buddies. Yes, I would love to see the updated chart, and possibly share it with everyone here. How would you like to connect with me? Do you have LinkedIn, Facebook, etc.?
Awesome video and thanks for that table. It will help me a lot. I allready had a smaller table from another video, though, but this one goes a little farther. However would be awesome if you can explain a little bit more of how to use the Power of 2 part of the table. THanks.
I know there are a lot of methods that help you understand and perform subnetting problems....this one is for me its like having the IP calculator in your hand (easy to construct from a blank sheet of paper) and now I am able to solve most subnetting questions quickly....most not all. But now for some strange reason all the other CCNA topics have become easier to understand and retain, subnetting was my weakness but not anymore. Great Job Arpit !!!!!
This is absolutely legendary. My previous method was very manual and time consuming, extremely fast method. But also I suggest everyone learn the long way and get a fundamental understanding before using this chart.
this video is amazing! I have been struggling with understanding subnetting in my cisco I class for several weeks. I will share this with my classmates for sure. thank you again!
Ray Pashoukos Thank you so much for your kind feedback. It means a lot to me. Really glad that you found it useful. Make sure you practice it well. All the best for your CCNA exams. Plz do share with your friends.... And if you've any questions, feel free to ask me.
Pretty good. I was writing down multiples of 4 on my chart. Knew that wasn't sustainable, until I found the multiples of 8. Thank you. I think this is the method I'll be sticking with.
Leonard Banks really glad that you found my video useful. Kindly share this video with your friends so that they may also benefit from it. Thanks for watching.
345th here! And I'm Here to support the supporters. Thanks friend for the support I know you will return :D I got 79.6% on my CCNA lol but thats a pass :D 800% scrap in :D
Thank you SO much Arpit for helping me futher understand subnetting. I am newer to networking in school and I feel that this video really made the concept click for me! With more practice I'll be a subnetting master and a bit more ready for my CCNA.
Free BONUS:- LINK to the printable layout (PDF version) for my subnetting chart :- drive.google.com/file/d/0B74wQpf0jMGJbW9zS29FR0REQWs/view?usp=sharing&resourcekey=0-GufC1MTi14Uey821EbLJjw As explained in the video, with the above PDF, you'll be able to convert this chart into a neat little card that will fit into your wallet :)
Thx man! Memorized the chart(easy because straightforward) an reproduced at the exam. Subnetting was never so easygoing. Also the powers of 2 table is very powerfull: like "we need 4000 hosts" -> 12 0's from the right ;)
Here are the steps after you have written out the chart: 1) Look at the subnet mask from your question and find it in the octets chart. 2) Scan to the right to the increment column to see what your increment will be. This will be the range between networks. 3) Go to multiples of 8 chart with the number from the octet in your IP address in your question and find it within the increment. The lower number of the range is your network ID. 4) The next number within the increment range is the next network. Subtract one from that and you have your broadcast ID. 5) Everything between the network ID and the broadcast ID are your usable hosts.
Great video. The only thing I would add is a demonstration of using the power of 2 chart for solving a question. You use the rest of the chart in examples but not the power of 2 chart
Great chart! Wish there would have been a little less explaination of how to add and a little more of how to get a subnet from the number of hosts or networks needed. But still a great tool!
Yes, just before the exam starts, you get few minutes to fill some agreements and all. Just use the time to make the chart. Takes only 2 minutes if you practiced it.
@@sarahchua2811 hey, sorry for the super late reply. Could you elaborate your question, as I couldn't understand what you meant by "No. Of IP addresses"?
So essentially it wouldn't be practical to create a multiple of 4s chart coz it would be huge. So in case the subnet size is 4, try to figure out the middle values between each multiples of 8 which would essentially turn out to be a multiple of 4. For eg. You wanna find the network address of 10.0.0.173 /30 Try to find 173 in the múltiples of 8 chart, you'll see it lies between 168 and 176. For multiple of 4, find the middle value of 168 and 176, which is 172. Now question yourself, does 173 lie in between 168 and 172 or 172 and 176? 172 is the answer, and the network address is 10.0.0.172. You've gotta gradually narrow it down till you find the nearest and lowest multiple of 4 from the octet. If you are still having trouble, let me know and I'll explain you over the call.
@@arpitroy627 Thanks for the explanation, Btw, would you please kindly go through the steps of finding out the available hosts (count wise) and How many subnets in a network?
I love this!!!! 👍Gud job bro.👍 But i want to ask 1 simple thing that is , is necessary to have graduation degree jobs after completion of CCNA course??
In rare cases, graduation degree won't be necessary, provided you're proficient and skilled. But that's a super "rare" case to find an organization who would hire you. You could offer your services to a startup who need to setup their own networks. To be on the safer side, go ahead and get yourself a degree in CS/IT to increase your chances being hired.
I see you made some effort to do this, but I think this way of presenting numbers in the table makes it much more complicated than it really is. If you are using subnetting sometimes for your work, print it out and use it, but if you want to know it really, learn binary-decimal (- and hex for ipv6) conversions in the head. When you will have to work later with IPv6, knowing this technique for IPv4 will not make it easier to learn/use.
+dong123hue Yes absolutely! Kindly check the end of the descriptions of the video for the link to the printable version of the chart. Glad you liked the video. Do share with your friends.
You don't need to memorize the entire table. You can reproduce it very easily with practice. I have also mentioned in the video on easy way to create the chart without memorizing much.
You make it too complicated. Your example at 4min 58sec: / 19 shows that we work in the 3rd octet. So we use 3 bits for the network part, so it has a value of 224. Just subtract these 224 from the total value 256 per octet and you get the increment between the subnets: 32. It follows that the network addresses are: 172.17.0.0, 172.17 .32.0 172.17.64.0 172.17.96.0 172.17.128.0 etc. The first IP of each subnet is the network address, therefore the first free host address of the respective network is 172.17.96.1. It's easy. You do not need a table :-D
The table is for quick reference. Doing work in your head allows for easier human error, especially when you are relatively new to subnetting. Nobody cares that you do it in your head, the same info is on the chart and requires basically no thinking or self doubt.
+Mohamed Zakaria -- Once you know the following: - For new subnets, the POWER is the number of *additional* 1's you'll need to add to your mask. - For total hosts, the POWER is the number of 0's present in your mask. Example: - Given this info: 192.168.0.0/16 -- a) Create 8 subnets of equal size b) Create 1 subnet with at least 500 IPs in it. For a) you should immediately ask, "What Power of 2 is 8 nearest to?" The chart says that 2 ^ 3rd = 8. This tells you to ADD *3* 1's to your subnet mask. Done. For b) you should immediately add 2 IPs to cover the unusable IPs. So now we want 502 IPs in the subnet. Now you should ask, "What Power of 2 is 500 nearest to?" Once again the chart quickly helps you see that 512 or 2 ^ 9th is the answer. This means you need to make sure a total of *9* 0's are present in your new mask. And, if you know how many 0's are in your mask, you also know how many 1's are present (since 32 bits - 9 zeroes = 23 1's = /23) For a): You started with a /16 and found out you need to add 3 1's to the new mask, giving you a /19. (Notice the other side of the chart. A /19 gives you 32 IPs/subnet which is 8 subnets. 256 / 8 = 32 or 256 / 32 = 8). For b): You started with a /16 which means there are 16 1's AND 16 0's. You found out you need to decrease the number of zeroes to 9, giving you a /23 for the new subnet.
Great question. The answer to this relates to the subnetting concept. Now the reason I did this is because 128 is the network address of the next subnet. 127 is the broadcast address of the current subnet. Now it's impossible to write 127, or any of the broadcast addresses in the multiples of 8 chart. So, again, subnet number one is 0-127, and subnet number teo is 128-255. This multiples of 8 can only help you find the network addresses, and the broadcast addresses are self implied (by subtracting 1 from the next network address). Hope this clears it up! HAPPY SUBNETTING!
I have no idea who the fuck you are but I would kiss you on the lips right now if I could. I stayed up for 11 hours tryna figure this shit out and then I came across your video 3 hours before my test starts and you are a genius. Thank fucking YOU
you can also get a print out from the PDF I uploaded in Google Drive, and make it into a neat little card that fits in your wallet. drive.google.com/file/d/0B74wQpf0jMGJbW9zS29FR0REQWs/view?usp=sharing
@11:20 - How to create this chart!? OMG! How the hell am I supposed to make this bla bla bla.. Just take a snap of it, using the Snipping Tool on your Windows laptop. Or print it out on a piece of paper! (Good job though)
Sadly, you can't take the print out along with you to any Cisco certification exam. So one must know how to reproduce this chart during the exam, on the rough plastic board provided to you during the exam. That's what I was referring to. But I explained that it isn't very difficult at all to make the above chart in the exam, hardly takes a minute or two, and it tremendously saves time on all the subnetting questions.
Though, I've now updated the descriptions of this video with the link to a printable version of this chart, which you can cut and make a neat little card out of it, which will fit in your wallet. drive.google.com/file/d/0B74wQpf0jMGJbW9zS29FR0REQWs/view?usp=sharing
create networks and show 1 st host last host broadcast for these hosts below.. if anyone can sove this please do it for me i havent found any videos on these types of questions a)4000 hosts b)100 hosts c)60 hosts
well for the 4000 hosts you will need to start with an address in the class B range since you need Hosts addresses you will start your count from the right end of the address space (i.e. right end of the 4th octet) and count each bit moving to the left such as 1, 2, 4, 8, 16, 32,64, 128,256,512, 1024, 2048, 4096, so at this point you have used 12 bits (i.e.12^2 or 2x2x2x2x2x2x2x2x2x2x2x2=4096). this will give you more addresses than you need but at least provide you with the 4000 addresses asked for.So, your subnet address might be 172.16.0.0 to start or 10101010.00010000.00000000.00000000 in binary the net mask would be 255.255.240.0 or 11111111.11111111.11110000.00000000; notice that you have 13 host bits available for hosts addresses. the confussing part is that you have to conceptualize crossing the 256 boundary each time you increment thru each of the 16 increments. which means that each increment will have 255 hosts and role right into the next increment until you have completed all 16 increments meaning each increment of the 16 revolutions will be in the same subnet. think of the odoniter in your car for each revolution of each wheel the next wheel increments by one so the first one will role from 0-9 then as it moves from 9 back to 0 the next wheel increments 1 so think of this as the last octet value hits 255 instead of becoming 256 for the next address the 3rd octet increments by 1 and the last octet rolls back to 0 to begin the next increment. I hope this helps. follow the same process for each of the other problems. Rhys
I am being pushed to ask the same unanswered question as Bipin Nepal. What if you are only given host values. I can clearly see how they are in the "Powers of 2" chart, but where do you go from there? Why ties to it? Anyone know the answer? Help is appreciated.
Didn't exactly understand your question. You mean, what if you are given just the number of hosts in a network? See, the powers of 2 chart helps you to find out how many subnets and how many hosts per subnet you can accommodate in a particular IP address.
If you are only given host values (egg. 192.168.32.8/24) you can find all the possible subnets that are provided by the 24 mask, and then describe the valid host ranges for each subnet and then identify where your given host value lies.
This is literally the best explanation out of literally soooo many (including my past instructors) that I've seen! My only regret is not finding you sooner, new subbie for sure.
I updated this chart with several steps that anyone could use to find a subnet and BC address. I would love to share it with you, if at all possible?
Also, I added your name to my updated chart that my study buddies and I are using. I want to make sure they use this tutorial only for subnetting. It truly is a lifesaver! 🙌🏾❤️
Hi Shauntae, I am thrilled to see that my work has helped you and your buddies. Yes, I would love to see the updated chart, and possibly share it with everyone here. How would you like to connect with me? Do you have LinkedIn, Facebook, etc.?
ruclips.net/video/9XhbqNVVmQ0/видео.html
Awesome video and thanks for that table. It will help me a lot. I allready had a smaller table from another video, though, but this one goes a little farther. However would be awesome if you can explain a little bit more of how to use the Power of 2 part of the table. THanks.
I know there are a lot of methods that help you understand and perform subnetting problems....this one is for me its like having the IP calculator in your hand (easy to construct from a blank sheet of paper) and now I am able to solve most subnetting questions quickly....most not all. But now for some strange reason all the other CCNA topics have become easier to understand and retain, subnetting was my weakness but not anymore. Great Job Arpit !!!!!
This is absolutely legendary. My previous method was very manual and time consuming, extremely fast method. But also I suggest everyone learn the long way and get a fundamental understanding before using this chart.
this video is amazing! I have been struggling with understanding subnetting in my cisco I class for several weeks. I will share this with my classmates for sure. thank you again!
Ray Pashoukos Thank you so much for your kind feedback. It means a lot to me. Really glad that you found it useful. Make sure you practice it well. All the best for your CCNA exams. Plz do share with your friends.... And if you've any questions, feel free to ask me.
ruclips.net/video/9XhbqNVVmQ0/видео.html
Pretty good. I was writing down multiples of 4 on my chart. Knew that wasn't sustainable, until I found the multiples of 8. Thank you. I think this is the method I'll be sticking with.
ruclips.net/video/9XhbqNVVmQ0/видео.html
I really wish i found this video sooner. Now I have a way better understanding
Leonard Banks really glad that you found my video useful. Kindly share this video with your friends so that they may also benefit from it. Thanks for watching.
345th here! And I'm Here to support the supporters. Thanks friend for the support I know you will return :D I got 79.6% on my CCNA lol but thats a pass :D 800% scrap in :D
You made life easier man.Thank you man for sharing the trick.If you any more networking tricks please share that also.
Sure thing!
Outstanding chart. This really helped me to better grasp subnetting.
Thank you Mr. Roy. Now this calculation is very clean to me.
Best tutorial ever! i love you
Thank you very much for this, its really helping, May God bless you :)
Really it works in 10 seconds if your concepts are ok about subnets
this chart and video turned subnetting around for me completely.... thank you so much... now if only I could figure out the big 5 questions lol
Superb sir Ur brilliant, hatsoff u and Ur my subnetting master....
You are a Genius!!! Thank you so muh.
Thank you SO much Arpit for helping me futher understand subnetting. I am newer to networking in school and I feel that this video really made the concept click for me! With more practice I'll be a subnetting master and a bit more ready for my CCNA.
ruclips.net/video/9XhbqNVVmQ0/видео.html
thank you very much Mr Arpit, very very helpfull
Not a bad method - TY Arpit for posting ;-)
Can this be used for doing VLSM ? Thanks
Great video, sir! Turns out I've been doing this method all along. But the table/chart is a nice addition.
+CitizenPerkins Thank you! I'm happy you found it useful. This chart helps us solve multiple subnetting problems very efficiently.
Free BONUS:-
LINK to the printable layout (PDF version) for my subnetting chart :-
drive.google.com/file/d/0B74wQpf0jMGJbW9zS29FR0REQWs/view?usp=sharing&resourcekey=0-GufC1MTi14Uey821EbLJjw
As explained in the video, with the above PDF, you'll be able to convert this chart into a neat little card that will fit into your wallet :)
Thx man! Memorized the chart(easy because straightforward) an reproduced at the exam. Subnetting was never so easygoing. Also the powers of 2 table is very powerfull: like "we need 4000 hosts" -> 12 0's from the right ;)
ruclips.net/video/9XhbqNVVmQ0/видео.html
This guy must be a genius 😁😁. Thanks a lot for this bro
My pleasure bro! Happy subnetting! xD
Thank you Arpit!
Well I am from Afghanistan and resources are very less here,I am happy to find your video on youtube!
amazing work done. You are a genius and I had to mention this " with a great voice " :-)
Here are the steps after you have written out the chart:
1) Look at the subnet mask from your question and find it in the octets chart.
2) Scan to the right to the increment column to see what your increment will be. This will be the range between networks.
3) Go to multiples of 8 chart with the number from the octet in your IP address in your question and find it within the increment. The lower number of the range is your network ID.
4) The next number within the increment range is the next network. Subtract one from that and you have your broadcast ID.
5) Everything between the network ID and the broadcast ID are your usable hosts.
Great video. The only thing I would add is a demonstration of using the power of 2 chart for solving a question. You use the rest of the chart in examples but not the power of 2 chart
Great Video :) i needed something like this as a refresher.
Thanks. I wonder if we can draw chart before the exam
Yes you get a few minutes before the exam and you can draw it on the paper. Should take less than a minute to make. Good luck for your exam!
Very good explanation, I would like to ask, what software do you use for this course?
Nice Video , Clean and quick
Does this chart tell you how many subnets and host per subnet from a particular network address?
Hey bud, how would you calculate How many subnets and hosts per subnet can you get from the network 172.31.0.0 255.255.255.192? using this chart?
Great chart! Wish there would have been a little less explaination of how to add and a little more of how to get a subnet from the number of hosts or networks needed. But still a great tool!
I love this. Thank you. I got it. It will help me soooooo much.
Thanks bro it is really helpful for me....
Hello Arpit, great presentation! What application did you use to create this? I am interested in the whiteboard app you used. Thank you!!
ruclips.net/video/9XhbqNVVmQ0/видео.html
Were you recording this on a phone?
This chart is awesome, thank you!
Jason Strong glad it helped. All the best for your CCNA Preparations.
Thank you Arpit you helped me out a lot
Arpit link up mi bredda i need your assistance
Can you explain in few words how to get hosts and networks in the chart?
Just some example so we can deduct the rest.
Thank you
Do you mean the usage of the "Powers of 2s" table to find out number of hosts and subnets?
Yes. I mean this.
Great work----succint.
I could've used that chart last week
Hey bro! how do u compute it if the only given is the needed host?
Can you take an example from class A and make the video please.
Did you create this chart at the beginning of the exam? I mean before you answer all the questions?
Yes, just before the exam starts, you get few minutes to fill some agreements and all. Just use the time to make the chart. Takes only 2 minutes if you practiced it.
Thank you for your advised! I will surely practice and memorize this chart!!! Im a beginner hoping to pass ccna exam. Godbless!
Another questin Arpit. How can we get the # of IP adress on this chart? Hope you can add that too. Thanks!
@@sarahchua2811 hey, sorry for the super late reply. Could you elaborate your question, as I couldn't understand what you meant by "No. Of IP addresses"?
Arpit Roy i mean number of ip address that can be used? Thanks
Hey Arpit, Im having issue on understanding if what you get a Multiple of 4's? how does it go? thanks.
So essentially it wouldn't be practical to create a multiple of 4s chart coz it would be huge. So in case the subnet size is 4, try to figure out the middle values between each multiples of 8 which would essentially turn out to be a multiple of 4.
For eg. You wanna find the network address of 10.0.0.173 /30
Try to find 173 in the múltiples of 8 chart, you'll see it lies between 168 and 176. For multiple of 4, find the middle value of 168 and 176, which is 172.
Now question yourself, does 173 lie in between 168 and 172 or 172 and 176?
172 is the answer, and the network address is 10.0.0.172.
You've gotta gradually narrow it down till you find the nearest and lowest multiple of 4 from the octet.
If you are still having trouble, let me know and I'll explain you over the call.
@@arpitroy627 Thanks for the explanation, Btw, would you please kindly go through the steps of finding out the available hosts (count wise) and How many subnets in a network?
Can you do more Class B and Class A subnetting questions? Thanks!
Thanks very much
Good Job Arpit
Can this chart be allowed to bring during the exam?
No! but you can make this minimalist and easy chart on the worksheet provided to you during the exam.
I love this!!!! 👍Gud job bro.👍
But i want to ask 1 simple thing that is , is necessary to have graduation degree jobs after completion of CCNA course??
In rare cases, graduation degree won't be necessary, provided you're proficient and skilled. But that's a super "rare" case to find an organization who would hire you. You could offer your services to a startup who need to setup their own networks.
To be on the safer side, go ahead and get yourself a degree in CS/IT to increase your chances being hired.
I see you made some effort to do this, but I think this way of presenting numbers in the table makes it much more complicated than it really is.
If you are using subnetting sometimes for your work, print it out and use it, but if you want to know it really, learn binary-decimal (- and hex for ipv6) conversions in the head.
When you will have to work later with IPv6, knowing this technique for IPv4 will not make it easier to learn/use.
great video, very easy to understand. Do you have a link so I can print this chart?
+dong123hue Yes absolutely! Kindly check the end of the descriptions of the video for the link to the printable version of the chart. Glad you liked the video. Do share with your friends.
Awesome!
but this chart isn't always available in exams .
Still don't understand what the Powers Of 2 table is for.
But you'd have to memorize the entire table since notes and calculators arent allowed?
You don't need to memorize the entire table. You can reproduce it very easily with practice. I have also mentioned in the video on easy way to create the chart without memorizing much.
You make it too complicated. Your example at 4min 58sec:
/ 19 shows that we work in the 3rd octet. So we use 3 bits for the network part, so it has a value of 224.
Just subtract these 224 from the total value 256 per octet and you get the increment between the subnets: 32.
It follows that the network addresses are: 172.17.0.0,
172.17 .32.0
172.17.64.0
172.17.96.0
172.17.128.0
etc.
The first IP of each subnet is the network address, therefore the first free host address of the respective
network is 172.17.96.1. It's easy. You do not need a table :-D
The table is for quick reference. Doing work in your head allows for easier human error, especially when you are relatively new to subnetting. Nobody cares that you do it in your head, the same info is on the chart and requires basically no thinking or self doubt.
can you show how to use the Power of 2 from the table (Number of subnet and host)?. TQ
+Mohamed Zakaria -- Once you know the following:
- For new subnets, the POWER is the number of *additional* 1's you'll need to add to your mask.
- For total hosts, the POWER is the number of 0's present in your mask.
Example:
- Given this info: 192.168.0.0/16 --
a) Create 8 subnets of equal size
b) Create 1 subnet with at least 500 IPs in it.
For a) you should immediately ask, "What Power of 2 is 8 nearest to?" The chart says that 2 ^ 3rd = 8. This tells you to ADD *3* 1's to your subnet mask. Done.
For b) you should immediately add 2 IPs to cover the unusable IPs. So now we want 502 IPs in the subnet. Now you should ask, "What Power of 2 is 500 nearest to?" Once again the chart quickly helps you see that 512 or 2 ^ 9th is the answer. This means you need to make sure a total of *9* 0's are present in your new mask. And, if you know how many 0's are in your mask, you also know how many 1's are present (since 32 bits - 9 zeroes = 23 1's = /23)
For a):
You started with a /16 and found out you need to add 3 1's to the new mask, giving you a /19. (Notice the other side of the chart. A /19 gives you 32 IPs/subnet which is 8 subnets. 256 / 8 = 32 or 256 / 32 = 8).
For b):
You started with a /16 which means there are 16 1's AND 16 0's. You found out you need to decrease the number of zeroes to 9, giving you a /23 for the new subnet.
Verrryyy Goood ! THX !10 Up
Thanks bro.
What address in Class C you will choose for 5 subnets with 17 hosts each any one explain?
excellent
Why are you stating a number less one of the multiples of 8? you say 127 but are circling 128
Great question. The answer to this relates to the subnetting concept. Now the reason I did this is because 128 is the network address of the next subnet. 127 is the broadcast address of the current subnet. Now it's impossible to write 127, or any of the broadcast addresses in the multiples of 8 chart. So, again, subnet number one is 0-127, and subnet number teo is 128-255.
This multiples of 8 can only help you find the network addresses, and the broadcast addresses are self implied (by subtracting 1 from the next network address).
Hope this clears it up! HAPPY SUBNETTING!
But we need to make subnet chart here
I have no idea who the fuck you are but I would kiss you on the lips right now if I could. I stayed up for 11 hours tryna figure this shit out and then I came across your video 3 hours before my test starts and you are a genius. Thank fucking YOU
i need to create one of these charts...
David K Success yup, making this chart is very easy in your certification exam and will drastically speed up the subnet calculations.
you can also get a print out from the PDF I uploaded in Google Drive, and make it into a neat little card that fits in your wallet.
drive.google.com/file/d/0B74wQpf0jMGJbW9zS29FR0REQWs/view?usp=sharing
This video was 'nothing but' helpful, and 'nothing but' time-saving. Well, it was one more thing, too ... it was 'nothing but' funny to listen to.
Glad that you found it interesting. Peace xD ✌️!
@11:20 - How to create this chart!? OMG! How the hell am I supposed to make this bla bla bla.. Just take a snap of it, using the Snipping Tool on your Windows laptop. Or print it out on a piece of paper! (Good job though)
Sadly, you can't take the print out along with you to any Cisco certification exam. So one must know how to reproduce this chart during the exam, on the rough plastic board provided to you during the exam. That's what I was referring to. But I explained that it isn't very difficult at all to make the above chart in the exam, hardly takes a minute or two, and it tremendously saves time on all the subnetting questions.
Though, I've now updated the descriptions of this video with the link to a printable version of this chart, which you can cut and make a neat little card out of it, which will fit in your wallet.
drive.google.com/file/d/0B74wQpf0jMGJbW9zS29FR0REQWs/view?usp=sharing
create networks and show 1 st host last host broadcast for these hosts below..
if anyone can sove this please do it for me i havent found any videos on these types of questions
a)4000 hosts
b)100 hosts
c)60 hosts
well for the 4000 hosts you will need to start with an address in the class B range since you need Hosts addresses you will start your count from the right end of the address space (i.e. right end of the 4th octet) and count each bit moving to the left such as 1, 2, 4, 8, 16, 32,64, 128,256,512, 1024, 2048, 4096, so at this point you have used 12 bits (i.e.12^2 or 2x2x2x2x2x2x2x2x2x2x2x2=4096). this will give you more addresses than you need but at least provide you with the 4000 addresses asked for.So, your subnet address might be 172.16.0.0 to start or 10101010.00010000.00000000.00000000 in binary the net mask would be 255.255.240.0 or 11111111.11111111.11110000.00000000; notice that you have 13 host bits available for hosts addresses. the confussing part is that you have to conceptualize crossing the 256 boundary each time you increment thru each of the 16 increments. which means that each increment will have 255 hosts and role right into the next increment until you have completed all 16 increments meaning each increment of the 16 revolutions will be in the same subnet. think of the odoniter in your car for each revolution of each wheel the next wheel increments by one so the first one will role from 0-9 then as it moves from 9 back to 0 the next wheel increments 1 so think of this as the last octet value hits 255 instead of becoming 256 for the next address the 3rd octet increments by 1 and the last octet rolls back to 0 to begin the next increment. I hope this helps. follow the same process for each of the other problems. Rhys
Here is a pocket sized version that I modified a little bit. kvisit.com/Rg/ss4B
thanks Arpit
You're welcome. Glad that you found this useful. :)
I am being pushed to ask the same unanswered question as Bipin Nepal. What if you are only given host values. I can clearly see how they are in the "Powers of 2" chart, but where do you go from there? Why ties to it? Anyone know the answer? Help is appreciated.
Didn't exactly understand your question. You mean, what if you are given just the number of hosts in a network?
See, the powers of 2 chart helps you to find out how many subnets and how many hosts per subnet you can accommodate in a particular IP address.
If you are only given host values (egg. 192.168.32.8/24) you can find all the possible subnets that are provided by the 24 mask, and then describe the valid host ranges for each subnet and then identify where your given host value lies.
who can remember two whole charts for a test really?
nice 1 bro
interesting