WOW! THE BEST TUTORIAL!! I must tell you that this was the last barrier between me and the CompTIA A+ certification. Nothing scared me--until I got to this. I've researched probably close to 50 systems and this by far is the answer above all answers. The cheat sheet is easy to quickly write down from memory. For my CompTIA FCO-U51 exam, I was shocked they didn't give us anything but a flimsy 8-1/2 X 11 dry erase plastic sheet! And the pen they provided was an old, dried out dry-erase pen. If you're going to write anything down, you only had that much space to hold your chart, and you'd better have good eyesight! They didn't even give you anything to erase the plastic once you finished or made a mistake. The proctor told me I could only use my hand or clothing to wipe the marks off! So, take it from me, this tutorial not only simplifies the process, it's THE ONLY PROCESS THAT works on a flimsy dry erase plastic sheet.
Lane; I'm very happy you finally found what "clicked" for you, Like you it took me a looooooooong time of searching to finally find what worked for me. Happy Subnetting and best of luck on your A+ exam!!
That's a good video. I was taught the full course during my CCNA and CCNP days. What I figured (which I wasn't taught) was to do what suited me best. knowing 4=2 hosts, 8=6 hosts, 16=14 hosts, 32=30 hosts, 64=62 hosts, 128=126 hosts etc. Which I was taught (Drilled into me more like). If I needed 50 hosts, which I know must be more 32 as I know it would only give me 30 hosts, so it must be 64. 256 minus 64 = 192. Answer 255.255.255.192
I don't think he mentions that you need to subtract 2 if looking up the # of hosts needed from the cheat sheet - one for network ID and one for broadcast. If you need 31 hosts - you would not select 2 to the 5th - indicating the use of 5 host bits since there are only 30 hosts available on that subnet.
On 5:54 of video on second point it is said that you need to 'find the number 7 on the 'hosts' side...' but you have marked on Subnet bits N/W side (network) so I persume it is a mistake, that you actually need to write to find number 7 on Network side or.... ?
Sorry, I'm not seeing/hearing that. At 5:54 I am demonstrating finding the number of networks so we use the "N/W" side of the cheat sheet. Hope this helps!
I see what your talking about. He says networks but "hosts" is writen on the page for 1 and 2. No problem if you listening but if you are reading then it's wrong.
Thank you sir.My question is, "Given a class C address , what is the subnet mask needed to provide at least 20 subnets ? " so you directly chose 2 to the power of 5th why is that. How I know I have to choose 2 to the power of 5th in this particular question???
Ryan Hosiassohn, this chart wont, but if you subtract 10 from 32, you will get 22. I you multiply 2 to the power of 2, 22 times you get 4,194,304 (4,194,304-2) 4,194,302 hosts and 4 subnets. and mask of 255.192.0.0. why 192, and 4? because the '10' would take you into the 2nd column of bits, 2 places(11111111.11000000.00000000.00000000) and 11000000=192, and the 4 is also because you went into the 2nd column. 2 to the power of 2 is 4
+Ryan Hosiassohn That's a private class A (10.0.0.0 thru 10.255.255.255) network. 255.192.0.0 is the subnet mask, 10.0.0.1 is the first usable address thru 10.63.255.255 and the broadcast address is 10.63.255.255
I have an issue with the class "B" address question. A subnet mask of 255.255.254.0 yields 512 networks with 510 hosts in each. While technically correct, this is not the best answer. The subnet mask of 255.255.255.128 yields 128 networks with 126 hosts in each. Also, you start by asking for 100 NETWORKS, but the text of the answer mentions HOSTS twice. I'm trying to reconcile how to actually use your cheat sheet for this problem.
500 networks? Piece of cake. 500 means we will need 2^9 (which is 512). This means that the first nine bits will be used for network and the remaining 23 bits are hosts. That looks like this: 11111111.10000000.00000000.00000000 - or 255.128.0.0.
you can also use your fingers for calculating subnets. no more papers no more writing. works great when taking your ccna cert exam. thanks. great video the way.
WOW! THE BEST TUTORIAL!! I must tell you that this was the last barrier between me and the CompTIA A+ certification. Nothing scared me--until I got to this. I've researched probably close to 50 systems and this by far is the answer above all answers. The cheat sheet is easy to quickly write down from memory. For my CompTIA FCO-U51 exam, I was shocked they didn't give us anything but a flimsy 8-1/2 X 11 dry erase plastic sheet! And the pen they provided was an old, dried out dry-erase pen. If you're going to write anything down, you only had that much space to hold your chart, and you'd better have good eyesight! They didn't even give you anything to erase the plastic once you finished or made a mistake. The proctor told me I could only use my hand or clothing to wipe the marks off! So, take it from me, this tutorial not only simplifies the process, it's THE ONLY PROCESS THAT works on a flimsy dry erase plastic sheet.
Lane; I'm very happy you finally found what "clicked" for you, Like you it took me a looooooooong time of searching to finally find what worked for me. Happy Subnetting and best of luck on your A+ exam!!
That's a good video. I was taught the full course during my CCNA and CCNP days. What I figured (which I wasn't taught) was to do what suited me best. knowing 4=2 hosts, 8=6 hosts, 16=14 hosts, 32=30 hosts, 64=62 hosts, 128=126 hosts etc. Which I was taught (Drilled into me more like). If I needed 50 hosts, which I know must be more 32 as I know it would only give me 30 hosts, so it must be 64. 256 minus 64 = 192. Answer 255.255.255.192
Thank you!
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Thanks for the feed back!
Great tip! Thanks!
After struggling with many books and getting more and more confused, I stumbled on this book and learned to subnet. What a relief.
This was awesome!!!!! I also purchased your book on Kindle! Thank you!
Great explanation , thank you I wish you the best of luck.
there is an error in the video. with 2^0
however it was very informative thank you
very nice explanation.
Thank you. This has mystified me for quite some time.
Me too!!! Glad I could help!
Thank you so much for this video. Well explained and easy to understand.
I don't think he mentions that you need to subtract 2 if looking up the # of hosts needed from the cheat sheet - one for network ID and one for broadcast. If you need 31 hosts - you would not select 2 to the 5th - indicating the use of 5 host bits since there are only 30 hosts available on that subnet.
+John W You are right John but that is because this is a greatly condensed version of the book.
I understand your explanation
THANK YOU SIR!!!
Thanks Professor--- superb explanation.
whats the maximum bits are borrowed and how many subnets may be made in the class A, B and C
THANK YOU!!!
Wow great I wanna buy it
what if given class B and the host needed is 690?
Solution to my first problem in networking
On 5:54 of video on second point it is said that you need to 'find the number 7 on the 'hosts' side...' but you have marked on Subnet bits N/W side (network) so I persume it is a mistake, that you actually need to write to find number 7 on Network side or.... ?
Sorry, I'm not seeing/hearing that. At 5:54 I am demonstrating finding the number of networks so we use the "N/W" side of the cheat sheet. Hope this helps!
I see what your talking about. He says networks but "hosts" is writen on the page for 1 and 2. No problem if you listening but if you are reading then it's wrong.
thank u soo much...really helped me a lot....
Thanks for the video!... found it very useful
Glad you did. Spread the word! :-)
Great
Thank you sir.My question is, "Given a class C address , what is the subnet mask needed to provide at least 20 subnets ? " so you directly chose 2 to the power of 5th why is that. How I know I have to choose 2 to the power of 5th in this particular question???
+Sammy Tadele - Hey Sammy. Its because 2^4 = 16 (too few) and 2^5 = 32. Since the requirement was "20" - 2^5 comes closest.
Thanks , now it's clear.
Basic question here, when you say (for example) 12 hosts per subnet and you select 16, that is because 16 is greater than or equal to 12? Am I right?
Correct! Go to the head of the class!
Ha, thank you. It is starting to make sense now. Never dove into subnetting when I should have a long time ago.
Excellent thanks!
during the past weeks, I have done MAJOR Gym Training with IPv4; also upgraded the IOS on my 3560 to be IPv6 ready ;-)
Glad I could help!
thank you
cool cheatsheet but how would you work a : 10.0.0.0/10 find the number of subnets and hosts ?
Ryan Hosiassohn, this chart wont, but if you subtract 10 from 32, you will get 22. I you multiply 2 to the power of 2, 22 times you get 4,194,304 (4,194,304-2) 4,194,302 hosts and 4 subnets. and mask of 255.192.0.0. why 192, and 4? because the '10' would take you into the 2nd column of bits, 2 places(11111111.11000000.00000000.00000000) and 11000000=192, and the 4 is also because you went into the 2nd column. 2 to the power of 2 is 4
+Ryan Hosiassohn That's a private class A (10.0.0.0 thru 10.255.255.255) network. 255.192.0.0 is the subnet mask, 10.0.0.1 is the first usable address thru 10.63.255.255 and the broadcast address is 10.63.255.255
2 to the power of 0 is 1
Ian Nakar
I was wondering what kind of math he was using....
Anything & Everything to the zero = 1
(Even the kitchen sink)
+Ian Nakar Yeah; I saw that. The cheatsheet should not have had a 2^0 anyways since you would use it. My bad.
Its fixed later in the video
Are these slides available for download?
Sorry no, not to the public. I do have them on the school server, but that is fire-walled.
No problem I figured I would ask! thank you
I have an issue with the class "B" address question. A subnet mask of 255.255.254.0 yields 512 networks with 510 hosts in each. While technically correct, this is not the best answer. The subnet mask of 255.255.255.128 yields 128 networks with 126 hosts in each. Also, you start by asking for 100 NETWORKS, but the text of the answer mentions HOSTS twice. I'm trying to reconcile how to actually use your cheat sheet for this problem.
what u mean by class "C" address?
+Deepak Rao Class C addresses are those where the 1st octet is between 192 and 223. In binary class C addresses always begin with "110".
Thanks, why industry did this classification? how it make difference?
2^0 is 1, not 0
I know.....I gotta fix that someday!
Thanks for this video..
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kdxixiciidxkziruue llgvuckgccf😋😘😗😋😋😶😋😗😋😁
how can apply cheat sheet on class A if we need 500 network.....?????????????????
500 networks? Piece of cake. 500 means we will need 2^9 (which is 512). This means that the first nine bits will be used for network and the remaining 23 bits are hosts. That looks like this: 11111111.10000000.00000000.00000000 - or 255.128.0.0.
thanks dude
This guy sounds just like Lost in Place. If you know who that is, just listen carefully.
2 power of 0 = 0?
1
2^0=1
+kennylyuda Yeah; I saw that. The cheatsheet should not have had a 2^0 anyways since you would use it. My bad.
Are you a Pole, sir?
Yes sir. I am
John Kowalski Witam serdecznie 😊
you can also use your fingers for calculating subnets. no more papers no more writing. works great when taking your ccna cert exam. thanks. great video the way.
fuck