Razavi Electronics2 Lec23: Examples of High-Speed Circuits, Response of Common-Base/Gate Stage

Поделиться
HTML-код
  • Опубликовано: 30 окт 2024

Комментарии • 21

  • @bhattu2828
    @bhattu2828 2 года назад +8

    The sounds that the pen makes is so satisfying 🙈😝

  • @zinhaboussi
    @zinhaboussi 7 месяцев назад +1

    01:29 Examples of High-Speed Circuits
    04:08 Exploring high-speed circuits and their applications in real-life scenarios.
    09:21 Challenges in transmitting high data rates
    12:17 Understanding frequency response and resistor usage in common gate stage
    18:29 Finding poles by inspection simplifies analysis of high-speed circuits
    21:23 Understanding input and output poles in common base stage circuits.
    27:46 Replacing resistor with current source for higher gain
    31:09 Reduction of capacitances simplifies the circuit design
    36:55 Understanding pole frequency in high-speed circuit analysis
    39:38 Analysis of high-speed circuits with MOSFET source degeneration
    45:37 Analysis of common-base/gate stages and finding pole frequencies.
    Crafted by Merlin AI.

  • @coolwinder
    @coolwinder 3 года назад +6

    01:25 - Intro and Review of Lecture 23
    10:18 - Frequency Response of CB/CG Stages
    27:10 - Example: Frequency Response of CG Stage with the P-MOS Current Source Load
    >> 35:33 - The Output Node - Taking Channel-Length Modulation into Account

  • @armature6675
    @armature6675 2 года назад +4

    What about decomposing ro1 into input and output side according to Miller's Effect? Will the results for ω1, in and ω1, out be any different?

  • @mnada72
    @mnada72 3 года назад +8

    Waiting eagerly for circuit theory I & II and the rest of the series.

  • @inoth79
    @inoth79 6 лет назад +8

    @41:50 i think it should be ro1 not ro2 at the mosfet M1 . Brilliant video !

  • @muratt6894
    @muratt6894 6 лет назад +3

    Thank You

  • @DemosthenesKar
    @DemosthenesKar 9 месяцев назад +1

    Can't we break ro2 using miller and then have a more accurate representation?

    • @abdxlive
      @abdxlive 7 месяцев назад +1

      Miller itself is an approximation!

  • @PM-et6wz
    @PM-et6wz 5 лет назад

    Why didnt you add rpi in parallel with RE and 1/gm?

    • @tag1343
      @tag1343 4 года назад +2

      If you write the small signal model and calculate the input impedance(Vx/Ix) you will find out the it will be 1/gm. The reason is that Vx=-Vpi in the small signal model. So there is no rpi. It will be cancled out.

    • @avirathi9209
      @avirathi9209 4 года назад

      rpi is 1/gm

    • @konstantinoslagaros
      @konstantinoslagaros 3 года назад +1

      @@avirathi9209 wtf bro? rpi is are no 1/gm

    • @adityatripathi02
      @adityatripathi02 Год назад

      ⁠@@tag1343 You are right about Vx = -Vpi. However, Rpi does not get eliminated due to this reason. For simplicity if we ignore early effect in BJT(no Ro in the small signal model) and write a KCL at the emitter node for the common base topology. We would indeed find the impedance looking into the emitter to be Rpi||(1/gm). The reason it gets eliminated is because Rpi||(1/gm) = Rpi/(gmRpi + 1). gmRpi is the beta of the BJT which is assumed much greater than 1. The impedance would then just become Rpi/gmRpi which is just 1/gm cancelling Rpi.

  • @himanshubharti3491
    @himanshubharti3491 6 лет назад +1

    nice

  • @fettahyldz460
    @fettahyldz460 4 года назад

    Do you guys know how to find ro1?

    • @bappadas9547
      @bappadas9547 Год назад

      1/(chanel length modulation* drain current)

    • @fettahyldz460
      @fettahyldz460 Год назад

      @@bappadas9547 I already graduated