Razavi Electronics2 Lec24: Response of Emitter/Source Followers, Input & Output Impedances

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  • Опубликовано: 30 окт 2024

Комментарии • 20

  • @coolwinder
    @coolwinder 3 года назад +14

    01:25 - Intro and Review
    03:40 - Frequency Response of Followers
    10:26 - Finding the Transfer Function of Followers
    19:38 - Conclusions from the Transfer Function
    21:40 - Input Capacitance of Followers
    30:25 - Intuitive Explanation of Input Capacitance Lowering with Bootstrap Amplifier
    39:15 - Output Impedance of Followers

  • @deveshdangi7209
    @deveshdangi7209 6 лет назад +11

    Sir I am very happy that u brought out 2nd series of this course while I am studing the first one

  • @abdxlive
    @abdxlive 7 месяцев назад +1

    Output Impedance: (Vx/Ix) = (1+sCgs*Rg)/(gm+sCgs)

  • @zinhaboussi
    @zinhaboussi 7 месяцев назад

    01:29 Frequency response of emitter and source followers
    04:20 Emitter/Source followers act as buffers to prevent significant gain drop due to lower impedance loads.
    10:06 Analyzing the transfer function of the source follower circuit.
    13:30 Analyzing current through RG and capacitance at gate node
    20:01 In analyzing followers, numerical values are required to determine poles due to lack of flexibility
    22:36 Finding input capacitance using Miller multiplication and input pole of a circuit.
    28:24 Input capacitance of source follower lower than CGS
    31:31 Voltage change in amplifier with gain of 1 does not deliver charge to capacitor.
    38:15 The input capacitance of the source follower is affected by the gain.
    40:57 Using a resistor in certain cases for impedance matching
    46:56 Introduction to emitter/source followers
    Crafted by Merlin AI.

  • @enesog
    @enesog 4 года назад +6

    For Vout/Vin I have got the following:
    Vout/Vin = N / D
    N = (Cgs/gm)*s + 1
    D = (Csb Cgd + Csb Cgs + Cgd Cgs) * (Rg/gm) * s^2 + ((Csb/gm) - (Cgs/gm) + Cgd Rg) * s + 1

    • @AK-mz9yk
      @AK-mz9yk 4 года назад +10

      I also got the same but in the expression for D, the "-" sign in "(Csb/gm) - (Cgs/gm)" should actually be a "+" sign

    • @abdxlive
      @abdxlive 7 месяцев назад

      How Can We Remember This? Please Arrange The Terms In Such A That It Becomes Easy To Remember

  • @zaehyumpark2043
    @zaehyumpark2043 2 года назад +2

    Thank you i geted a+grade

  • @mnada72
    @mnada72 3 года назад +4

    Waiting eagerly for circuit theory I & II and the rest of the series.

  • @anku348
    @anku348 5 лет назад +1

    @45:12 why is the current through RG same as the current through the capacitor Cgs?

    • @gopimarvathi3733
      @gopimarvathi3733 4 года назад

      Apply kcl at that node then
      current through rg+current through Cgs=0
      now I(rg) = -I(Cgs)

    • @RaviNagar16
      @RaviNagar16 Год назад

      As current cant flow through gate, so it has nowhere else to go.

    • @zinhaboussi
      @zinhaboussi 7 месяцев назад

      because it's the same wire

  • @aliasghartabrizi8288
    @aliasghartabrizi8288 5 лет назад

    ممنون عالی بود

  • @visweshramkumar9428
    @visweshramkumar9428 6 лет назад +2

    Is the output impedance at 47:00 is right?

  • @zaehyumpark2043
    @zaehyumpark2043 2 года назад +1

    아 시발 이 명장을 이제 봤네

  • @mrpossible5696
    @mrpossible5696 5 лет назад

    30:30