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Understand the concept of resolving and finding the resultants of current coplanar force.
So we should ignore the minus?
No and yes
Sir why u take positive value of fx when calculated tan theta?
you can just take value of fx as positive but u have to specify within brackets with left arrow key....so ans will be 68.406(
Nice video sir
You are welcome
Sir what It is not inclined at the horizontal axis, what will be the vertical n horizontal?
You either use the value given the same way, knowing fully well that upward force us positive and downward force is negative
While calculating x component of F There is calculation error. 70× cos 40 =53.62311
Thank you
Why did u not resolve the 50N force
We don't resolve vertical and horizontal force
😊
Isn’t fx calculated by sin value not cos?
It depends on the angle it is inclined to
West to South angle is 45 degrees
It was stated in the question south west 40°
70 cos 40 is 53.62
Okay
That between west and south I don't understand how the angle is 40°
It will be given
Watch and listen carefully
70 cos 40 = 53.62
That's what I'm also getting
70cos40 = 53.62
I thought I was wrong
yeah n u truly speaking yey
Nicr😅
Thanks
50 N had no a vertical trig ratios..😢
As in. What are trying to say
The direction should be 270+44.67 = 314.67
You don't have to do it that way again since I have resolved it ( resolution of force). 😊
If I didn't resolve the inclined forces then what you said applies. I appreciate your comment❤
I think the direction of the vector is incorrect.
Your reason
I think it should be 180-the angle gotten since it should be taken from the positive x-axis,Is that your reason please?
The direction should be 270+44.67= 314.67 degrees on a three digit bearing order from the North pole
Understand the concept of resolving and finding the resultants of current coplanar force.
So we should ignore the minus?
No and yes
Sir why u take positive value of fx when calculated tan theta?
you can just take value of fx as positive but u have to specify within brackets with left arrow key....so ans will be 68.406(
Nice video sir
You are welcome
You are welcome
Sir what It is not inclined at the horizontal axis, what will be the vertical n horizontal?
You either use the value given the same way, knowing fully well that upward force us positive and downward force is negative
While calculating x component of F
There is calculation error.
70× cos 40 =53.62311
Thank you
Why did u not resolve the 50N force
We don't resolve vertical and horizontal force
😊
😊
Isn’t fx calculated by sin value not cos?
It depends on the angle it is inclined to
West to South angle is 45 degrees
It was stated in the question south west 40°
70 cos 40 is 53.62
Okay
That between west and south I don't understand how the angle is 40°
It will be given
Watch and listen carefully
70 cos 40 = 53.62
That's what I'm also getting
70cos40 = 53.62
I thought I was wrong
yeah n u truly speaking yey
Nicr😅
Thanks
50 N had no a vertical trig ratios..😢
As in. What are trying to say
The direction should be 270+44.67 = 314.67
You don't have to do it that way again since I have resolved it ( resolution of force).
😊
If I didn't resolve the inclined forces then what you said applies.
I appreciate your comment❤
I think the direction of the vector is incorrect.
Your reason
I think it should be 180-the angle gotten since it should be taken from the positive x-axis,Is that your reason please?
The direction should be 270+44.67= 314.67 degrees on a three digit bearing order from the North pole