U SAVED MY LIFE. I WAS REALLY BLUR THE WHOLE TIME WHEN MY LECTURER EXPLAINS THIS DURING MY MECHANICS CLASS BUT BRO U SAVED ME. NOW IM DOING MY HOMEWORK IN THE SPEED OF LIGHTNING AFTER WATCHING THIS. GOD BLESS U.
You are doing a deed which is the highest of ranks..you are serving knowledge!.. May god bless you for doing this in this century,where people are just spoiling others. Thanks a lot ,this helped me more than you think: )
I am doing engineering level 3 and I joined in late when they already finished this topic. I am grateful that I finally have learnt from you. Thanks for the video again. Keep on posting more great stuff.
What a brilliant video, I failed this topic first time around now I’m revising for it again and my lecture it’s the best. So this video has helped me a lot !
Thanks sir for the refreshment because it’s been like six years now I studied this. If I am not confused I believe the angle for the resultant force should be 360°-18.5° since all the angles of the other forces were taken from the posive x-axis for the calculation
The figure does help to point out the sign convention and I have used a symbol at 11:00 to indicate the sign convention. I do agree with John that including a diagram to indicate the sign convention could be useful to avoid any doubt as I have seen several questions about the angle and the negative sign with the 18.5 degree angle in the comments section of this video.
Isn't the angle supposed to be read from the positive x-axis in an anticlockwise direction?? Which will make the reference angle for 18.5 degrees to 341.7?? I need clearance please
Yes, you are correct. 341.5 would be a suitable answer (-18.5 is also a suitable answer). The angle is to be read from the positive x-axis, in an anticlockwise direction based on the convention I have used. Some people may give you the requirement that the angle must be postive, and between 0 and 360 degrees.
Please check your 5N force components. Why did you take 5cos150 as your x component? It should be y component as per the position of the angle 150deg. As the sine component always lies opposite to the angle whereas the other side is given to the cos component. Please check the resolution of the 5N force. I might be wrong too. Please correct me in that case. THANKS
he get does degree from the reference angle which from Qudrant 1 cos going counter clockwise to the respected vector and then he subtract the given angle by. 90, 180, 270, and 360. (e.g F2 got 30 degree, so from the x axis from quadrant 1 counter clockwise to x axis of quadrant 2 therefore 180-30=150 degrees.
Thank u so much this video had helped me but , if i may ask why did u add all the forced and their angles together I thought there was a formula for this how can I use the formula to solve it
Not sure if I am answering your question but I will have a go. The reason for adding the forces together is because this could lead onto finding out the overall force acting on a system. This would/could then help us to find out loads and stresses within the system. You might notice that I am quite hesitant to write a formula. I have been stung in the past by being taught a formula only (it was a math exam when I was 17), but then I was given a question in a test that required proper understanding of what I was doing. As a result i wasn't able to even try the question. For this reason, I try to teach based on understanding the basic idea. However, here is a formula that may be useful for you Sum of forces in x direction = F1 * cos (theta1) + F2 * cos (theta2) + F3 * cos (theta3)+..... Sum of forces in y direction = F1 * sin (theta1) + F2 * sin (theta2) + F3 * sin (theta3)+..... Resultant = [ (sum of forces in x-direction)^2 + (sum of forces in y-direction)^2 ]^0.5 Angle = atan ( (sum of forces in y-direction)/(sum of forces in x-direction) ) **Note that for the angle you need to be aware that for tan there are multiple solutions between 0 and 360 deg and you will need to find the correct value.
If you are representing the forces as phasors (like I am in the video above) then you would. Some people, including me, sometimes solve these questions by treating each of the forces as the hypotenuse of a triangle and use the values obtained at @2:15.
Thanks for the video. But while working I didn't see you taking into consideration the quadrant of the various functions (sin, cos) 🙄Like in the second quadrant cos is negative
Hello Tierra, I dealt with them by using an angle from the positive x-axis. The sine of an angle is positive from 0 degrees to 180 degrees, and negative from 180 degrees to 360 degrees. The cosine of an angle is positive from 0 to 90 degress, and 270 to 360 degrees; and negative from 90 degrees to 270 degrees. Check cos150 and you will see that this is a negative value. (x component for 5N force) Check sin150 and you will see that this a positive value. (y component for 5N force) Check cos300 and you will see that this is a positive value (x component for 15N force) Check sin300 and you will see that this is a negative value (y component for 15N force) Hope this helps
Idk if this is too late but He already took into account the opposite directions when taking the angles from the x axis. You would only do the subtraction stuff if you left the angles the way they were given in the diagram.
This is a great video but I have a question?? I’ve been given a problem with a negative angle -30* would I assume this would be negative x and y axis so 330*?
U SAVED MY LIFE.
I WAS REALLY BLUR THE WHOLE TIME WHEN MY LECTURER EXPLAINS THIS DURING MY MECHANICS CLASS
BUT
BRO
U SAVED ME. NOW IM DOING MY HOMEWORK IN THE SPEED OF LIGHTNING AFTER WATCHING THIS.
GOD BLESS U.
Yuri Ikutsuki Glad I could help. Thanks for your message.
Cornelis Kok same
@@CornelisKok Fake account lmao
Wowohhhz
This video has helped more than any textbook or lecture slide could ever do. Studying online isn't bad after all thank you!!
thanks a lot for the tutorial a lot has been learned....You have just educated a kid in Gaborone,Botswana,Africa through the power of internet
Glad this has been helpful for you!
How did it go with physics?
I'm watching in 2024❤
Same here
Same here
Same here
Me too got a test tomorrow 😅
Frr
You are doing a deed which is the highest of ranks..you are serving knowledge!..
May god bless you for doing this in this
century,where people are just spoiling others.
Thanks a lot ,this helped me more than you think: )
If you look around closely, you will find that everyone is serving knowledge. One just have to open himself to get the effect!
Cheers mate
*G
The way my lecture calculated this was so confusing me, but now I get it, I will surely use this method..thank you so much
I am doing engineering level 3 and I joined in late when they already finished this topic. I am grateful that I finally have learnt from you. Thanks for the video again. Keep on posting more great stuff.
Bro still in high school😢 and we do this in Fm
this is much more easier than what our prof. taught us !! thank you so much!
You are one of the best tutors I have ever met on RUclips
This was wayyyyyyyyyyy more easier than all of those laws that was needed to solve for this, thank you so much
What a brilliant video, I failed this topic first time around now I’m revising for it again and my lecture it’s the best. So this video has helped me a lot !
Thank you, I hope you did well in your assessment.
lifesaver, my maths lecturer only explained everything using 2 vectors but then gave us an assignment to find the resultant of 3 vectors
so thank you!
Imagins 6yrs ago and it's very useful for me today thanks man 🙏
Thanks sir for the refreshment because it’s been like six years now I studied this.
If I am not confused I believe the angle for the resultant force should be 360°-18.5° since all the angles of the other forces were taken from the posive x-axis for the calculation
thanx mate i was able to clear my internal exams thanx to you
Great to hear!
Thanks for the lesson way more easier than the way my physics teacher taught me
Thanks very much, you have made me understand what i didn`t understand in class. Am humbled.
Thank you so much..after searching a lot got your perfect video
GOOD lecture of high standard , thank you very much hope to see more in the subsequent days.
thankyou, you're a life saver from my physics class, you taught me very well than my prof, we love you :)
🥰
Shout out to those who watching at exam time
Thank youuuu, I did not understand this at all until now
Thanks to this man for making our maths classes easier
You do a much better job of explaining this than my tutor. Thanks.
thank u so much, i have mideterms coming up and this rly cleared stuff up
Awesome, good luck for your midterms.
This is the best method, hands down. Cheers
Thank you very much, i was totally confused when my lecturer taught me this. Thanks again for your help😊
THANK YOU SO MUCH YOU JUST SAVED MY LIFE IN THE HSC!!
shout out those watching at the time of quarantine
Meeeeh
Yessss. Let's get them grades!
@@moodymoe100 yes sirrrrrrrr!!!!!!
Late
Later😢@@ratava2285
I realy like your video .
U save my life those who going to darkness. Thank u sir g
Thank you!
May God bless u and you loved ones.
Great tutorial! This will help me out on my exam!
I greatly appreciate. No wonder a day teaches for one to meet his destination.
Shout out to those watching before physics externals
I UNDERSTAND WHAT I DONT UNDERSTAND I MY CLASS,THANKS.
thank u very much for helping me,love u my teacher,may god bless u
You helped me.I didn't attend those lectures.now I understand
Great to hear, glad I could help.
@@corneliskok7794 where is your review finding forces vid? Cos sin....
Really really great video!!! Thank you so much, it is very much appreciated.
Great that you have found it useful. You're welcome.
you might of just saved my T levels cheers boss
clear,neat and understandable for all pupil thanks a lot.
It's more than a help,, thanks for the great job
Felt very good. I understood. Thanks you Sir 😊
You can write it -18.5 or 341.5
thanks for your teaching, help a lot
No worries, thank you for your appreciation.
Why do you choose negative angle when it is on the positive side of the horizontal line?
This has helped a lot, thanks!
Wow you made this seem a lot more simple than when my teacher explained jt😂
Thanks for making me understand this topic
This was very helpful.Thank you.
Thank you so much sir. Helped me big time.
thank you so much, this really helped me so much!
An absolute legend this man!!!
this guy just save me, thanks !
Can you give a like if I say he is better than most of our lecturers in colleges
You should include the sign convention on the angle theta
No, The direction is mentioned in the figure he made.
The figure itself justifies the direction.. this is amazing
The figure does help to point out the sign convention and I have used a symbol at 11:00 to indicate the sign convention. I do agree with John that including a diagram to indicate the sign convention could be useful to avoid any doubt as I have seen several questions about the angle and the negative sign with the 18.5 degree angle in the comments section of this video.
Who are you so wise in the ways of science
I hope it helped.
@@corneliskok7794 oh yeah it did, thanks!❤
THANKS SIR.
HOW TO SOLVE THE ONE WITH 4 FORCES ACTING ON THE POINT
This is perfect thanks so much. God bless you and make you great in Jesus name amen
How did u find the 150° angle?
loved the explanation.... I just subed!
Thank you for subbing and thanks for watching!
thankyou for sharing this method!!
Watching in 2024 thank you so much 🙏🇿🇲🇿🇲
Is the force measured anticlockwise or clockwise just at the description and is it going to be
negative
If I understood your question correctly it's measured anticlockwise. Just like how the unit circle is.
Good lecture
Isn't the angle supposed to be read from the positive x-axis in an anticlockwise direction??
Which will make the reference angle for 18.5 degrees to 341.7??
I need clearance please
Yes, you are correct. 341.5 would be a suitable answer (-18.5 is also a suitable answer). The angle is to be read from the positive x-axis, in an anticlockwise direction based on the convention I have used.
Some people may give you the requirement that the angle must be postive, and between 0 and 360 degrees.
Oh MAN YOU'RE A FUCKING STAR...
Thank you so MUCH...
How did the angle of the final answer became negative from positive 🙏
Thanks for your valuable help
Nice video sir..
Wow
Very explained
Please check your 5N force components. Why did you take 5cos150 as your x component? It should be y component as per the position of the angle 150deg. As the sine component always lies opposite to the angle whereas the other side is given to the cos component. Please check the resolution of the 5N force. I might be wrong too. Please correct me in that case. THANKS
Very great tutariol, how can we post some questions to you for help
Wondering how you got 150° and 300°.
he get does degree from the reference angle which from Qudrant 1 cos going counter clockwise to the respected vector and then he subtract the given angle by. 90, 180, 270, and 360. (e.g F2 got 30 degree, so from the x axis from quadrant 1 counter clockwise to x axis of quadrant 2 therefore 180-30=150 degrees.
@@andresmichael359 thanks. I get now
OMG, YOU SAVED ME
Great vid!
How did the angle become a negative at the final answer
Thank you for your explanation
Thanks a lot it was so helpful 👏🏻😊
Thank u so much this video had helped me but , if i may ask why did u add all the forced and their angles together I thought there was a formula for this how can I use the formula to solve it
Not sure if I am answering your question but I will have a go.
The reason for adding the forces together is because this could lead onto finding out the overall force acting on a system. This would/could then help us to find out loads and stresses within the system.
You might notice that I am quite hesitant to write a formula. I have been stung in the past by being taught a formula only (it was a math exam when I was 17), but then I was given a question in a test that required proper understanding of what I was doing. As a result i wasn't able to even try the question. For this reason, I try to teach based on understanding the basic idea.
However, here is a formula that may be useful for you
Sum of forces in x direction = F1 * cos (theta1) + F2 * cos (theta2) + F3 * cos (theta3)+.....
Sum of forces in y direction = F1 * sin (theta1) + F2 * sin (theta2) + F3 * sin (theta3)+.....
Resultant = [ (sum of forces in x-direction)^2 + (sum of forces in y-direction)^2 ]^0.5
Angle = atan ( (sum of forces in y-direction)/(sum of forces in x-direction) )
**Note that for the angle you need to be aware that for tan there are multiple solutions between 0 and 360 deg and you will need to find the correct value.
How do u know that the angle is negative?
So does this mean that in the x component we are suppose to use a cosine and in the y component we use sin
Thank you so very very very much
Me watching this video in a lecture while the lecturer is busy reading exactly what's in the Slides.🙂
Thank you for the great lesson . How will we represent the angle if it has to be represented positively instead of negatively ?
you could add 360 degrees to the value to get an equivalent number.
-18.5+360 = 341.5
Thank you so much sir👌
Do you always have to read anti clockwise
If you are representing the forces as phasors (like I am in the video above) then you would. Some people, including me, sometimes solve these questions by treating each of the forces as the hypotenuse of a triangle and use the values obtained at @2:15.
Thanks man helped alot
I have now understood thank you
Thank you Sir 🎉🎉🎉😮😮😮
But our x is negative where we use the Pythagoras theorem
How did you calculate the square root of cos and sin cause I got a different answers
Love it ❤️🫡
Thanks for the video.
But while working I didn't see you taking into consideration the quadrant of the various functions (sin, cos)
🙄Like in the second quadrant cos is negative
Cos 150 is already negative so the symbol doesn’t need to be there
I understand this solution. Only thing is, how come we didn't account for the negative values in the 2nd and 4th quadrant?
Hello Tierra, I dealt with them by using an angle from the positive x-axis. The sine of an angle is positive from 0 degrees to 180 degrees, and negative from 180 degrees to 360 degrees. The cosine of an angle is positive from 0 to 90 degress, and 270 to 360 degrees; and negative from 90 degrees to 270 degrees.
Check cos150 and you will see that this is a negative value. (x component for 5N force)
Check sin150 and you will see that this a positive value. (y component for 5N force)
Check cos300 and you will see that this is a positive value (x component for 15N force)
Check sin300 and you will see that this is a negative value (y component for 15N force)
Hope this helps
thank u so much Godbless
aren't you supposed to subtract them because they are not going on the same direction??
Idk if this is too late but He already took into account the opposite directions when taking the angles from the x axis. You would only do the subtraction stuff if you left the angles the way they were given in the diagram.
This is a great video but I have a question??
I’ve been given a problem with a negative angle -30* would I assume this would be negative x and y axis so 330*?
Sorry for the delay. Yes, that would be right.
thank you so much
Glad I could help.
It's helping a lot
Perfect!❤️❤️