Both of fission and fusion reaction do same thing to release energy according to the binding energy graph. The same thing is to reduce average mass (increase average binding energy). Therefore, the mass defect can use ΔE=Δm*c^2 to calculate the energy is released from the atom! 💥
The heavier elements do not undergo fusion because they are already unstable comparatively, and with further increase in mass number their stability will decrease due to fusion.
great video, though I just want to comment that when you say "we can't have fission for lighter elements", it is a bit misleading because you CAN have fission for lighter elements, though they will suck in more energy than they will generate, it is like a non-spontaneous reaction in chemistry.
I think he meant in nature... Which means that for lighter elements to undergo nuclear fission, human interference is a must. (I am not completely sure if this info tho)
We say that heavier elements are the most unstable. But if we look at the graph, the heaviest elements have more binding energy than the lighter elements. So if they have more binding energy how can they be less stable than the lighter elements?
Sir I am Pakistani but I must say that I watch the Indian teachers on youtube because they explain the best.Huge respect and hats off to u guys love from pakistan ♥
Why is Binding energy depicted as a positive value. According to the convention I have learned Binding energy is only positive for Unstable Nucleus like Cobalt 60 etc, otherwise it is always negative for stable atoms and isotopes. Nature tends to seek thte lowest energy state. It makes it somewhat confusing. If you consider it negative, it means if two lighter nucleuses fuse, binding energy becomes More negative (thus more stable). More negative binding energy can mean overall lower total (including mass) energy (thus more stable) than its constituents..the missing mass converted to energy E=Mc^2. Basically it is more helpful to think of binding energy as negative and trending down rather than up, at least for me.
Pro Level of teaching ....wish i could have teacher like u in my school days
True word
pro is abbreviation of professional and you must hate your teachers to call them unprofessional
They good teacher
Difference is the need of knowledge "the thirst "
We don't pay attention
If I ever get a chance to meet Sir Mahesh Shenoy , I would love to thank him a lot for making me fall in love with physics ❤️
Awesome....very well explained...👌🏻👌🏻👌🏻👌🏻
Both of fission and fusion reaction do same thing to release energy according to the binding energy graph.
The same thing is to reduce average mass (increase average binding energy). Therefore, the mass defect can use ΔE=Δm*c^2 to calculate the energy is released from the atom! 💥
Love the teaching style ....✨
Don't know why this channel has less subscriber and likes it's very good and simply understandable ❤❤❤❤ love from. Sikkim ❤❤❤
finally, the one video that has actually explained binding energy properly. thank you.
Also thank you sir, this helped alot
Can't get better explanation than this >>>>
Love your teaching sir 👌❤
This is the easiest and best explained physics video I ahve ever seen,I am extremely impressed!!
It finally makes sense
Ahhh I am very much satisfied and impressed from your explanation sir. Thanks a lottt
hi mahesh you are the best teacher in the world
starts to love Indian accent now;). Thanks for helping me with physics. it is brilliant
Where are the previous videos of this chapter?
GOAT 🐐🗿
I am really amazed sir , the way u teach ❤ , I am impressed 😁
totally brilliant..
Next level lecture. ❤
Damnnn great explanation
So good!
Thank you so much. You teach with such clarity that it actually makes me understand what is happening here.❤❤❤ Please keep up with the great work!
Thankyou so much
Sir ,I'm waiting for your video,,,,even if it was any topic ❤️❤️❤️❤️❤️❤️, super sir
Thank you sir! This video has helped me a lot!
Amazing explanation!
A very great way of teaching 👍 loved your video ❤️
Nice teaching .....our lectures won't tell all of this reasons tq
Really great explaining, thank you
Thank u soooo much....
Sir crystal clear
His passion speaks volumes.
You are literally amazing. I cannot thank you enough ❤️
Thanks a lot sir for this amazing video ❤🎉
Perfect
Masha ALLAH ...brilliant lecture
bhai fhat maat jana🤣
@@rohitmishra8969 what do u mean?
THANK YOU SO MUCH SIR!
Wish teachers could teach in the same way
Awsome, Just awesome
Wowwwwww👏🏽🫶🏼the best explanation thank u so muchhhh sir😌😍continueeeeb this great thing🥰
according to some book Ni is said to be stable with 8.795 MeV and Fe 56 is following with 8.792 MeV
Yeah, i was also confused a bit
Why is the irregularities in the 0-50 Mass number range not discussed
Wow thank you so much sir
No words for you💖
Wow what a fantastic session, it was the one of the lovable one thanks sir
He has a very nice voice sounds like a happy person
THANKYOU. SO MUCH.
It was excllnt to other level.....but i wanna ask that other than making graph what kind of ques can be put up from this curve??
Sir, we would love to hve more lessons o B.E.
Thank you very much fot the excellnt lecture
Thank you
Thank you!
Fantastic sir.
❤❤❤❤❤❤
am I the only one obsessing over his hand writing...
Can u pls upload videos on nuclear fission and fusion
Wwaahhh... Kya padhaya hai hai. Wwahahhhahahahah...,❣️
Best explaintion ❤😊
Can u explain what is quantum chromodynamic binding energy plz?
thx a lotttttttt!!!!!!!!!!!!😚
The heavier elements do not undergo fusion because they are already unstable comparatively, and with further increase in mass number their stability will decrease due to fusion.
Always awesome
Thank you 💗
great video, though I just want to comment that when you say "we can't have fission for lighter elements", it is a bit misleading because you CAN have fission for lighter elements, though they will suck in more energy than they will generate, it is like a non-spontaneous reaction in chemistry.
I think he meant in nature... Which means that for lighter elements to undergo nuclear fission, human interference is a must. (I am not completely sure if this info tho)
I guess he said that in order to understand the concept in less complex way
Actually these both mean same if you think clearly
I like u sir, ur voice 😘
Can you please put entire chapter in one video ?
We say that heavier elements are the most unstable. But if we look at the graph, the heaviest elements have more binding energy than the lighter elements. So if they have more binding energy how can they be less stable than the lighter elements?
Increasing binding energy, but decreasing binding energy per nucleon.
Sir please make videos in hindi of class 10th
Well
What affects binding energy
Is there more classes from the chapter nuclei???
What is that green point?
First like and view
👇👇
which software do you use? it is just amazing
i think it is not mega electron volt but million electron volt, please check i am confuse
Mega is a prefix for 10 to the power 6 (ie, 10^6) ... And also 10^6 is a million... So they are both the same.
physics but phonk
👌
Chatur from 3 idiots, is that you?
Sir I am Pakistani but I must say that I watch the Indian teachers on youtube because they explain the best.Huge respect and hats off to u guys love from pakistan ♥
1k like
Why is Binding energy depicted as a positive value. According to the convention I have learned Binding energy is only positive for Unstable Nucleus like Cobalt 60 etc, otherwise it is always negative for stable atoms and isotopes. Nature tends to seek thte lowest energy state. It makes it somewhat confusing. If you consider it negative, it means if two lighter nucleuses fuse, binding energy becomes More negative (thus more stable). More negative binding energy can mean overall lower total (including mass) energy (thus more stable) than its constituents..the missing mass converted to energy E=Mc^2. Basically it is more helpful to think of binding energy as negative and trending down rather than up, at least for me.
I think it may be a difference in conventions but for my use cases, it is more helpful to think of binding energy as negative for stable atoms...
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