20.5 Energy of Nuclear Reactions & Nuclear Binding Energy | General Chemistry
HTML-код
- Опубликовано: 7 авг 2024
- Chad provides a comprehensive lesson on the energy released by nuclear reactions and nuclear binding energy. In a nuclear reaction a small amount of mass is converted into a large amount of energy. The difference in mass between the reactants and the products is referred to as the mass defect. The mass defect is used to calculate the energy released in a nuclear reaction from Einstein's famous equation: E = mc^2.
The nuclear binding energy is the energy holding the nucleus together (the energy associated with the strong nuclear force). A nucleus always weighs less than its constituent nucleons (i.e. protons and neutrons). The difference in mass is also referred to as the mass defect. This mass defect can be used to calculate the nuclear binding energy once again from Einstein's famous equation: E = mc^2. Most commonly the nuclear binding energy is presented in units of Joules per nucleon. The higher the value the more stable the nucleus, and iron-56 has the highest nuclear binding energy per nucleon of any nucleus. The nuclear binding energy of iron-56 and uranium-235 are both calculated as examples to conclude the lesson.
I've embedded this playlist as a course on my website with all the lessons organized by chapter in a collapsible menu and much of the content from the study guide included on the page. Check this lesson out at www.chadsprep.com/chads-gener...
If you want all my study guides, quizzes, final exam reviews, and practice exams, check out my General Chemistry Master Course (free trial available) at www.chadsprep.com/genchem-you...
00:00 Lesson Introduction
00:30 Energy Released in Nuclear Reactions Sample Calculation
08:23 Nuclear Binding Energy
13:57 Nuclear Binding Energy of Iron-56 Calculation
19:14 Nuclear Binding Energy of Uranium-235 Calculation
www.chadsprep.com/
courses.chadsprep.com/pages/p...
Chad, I've watched all your videos about 20-21st chapters, and I hope I get a good grade on my Chem102 final, because if I don't, I'll hate Chemistry for the rest of my life... But regardless of the outcome you're the best, unfortunately my teacher is not :/
I'm glad the channel has helped you - I hope you continue to work hard and meet your challenges head on. Thanks for your kind words.
U are great teacher
Where are you from
Thanks for this, I’ve watched a bunch of your videos for MCAT prep, these videos are way better than Khan Academy. Do you have a physics channel?
Glad to hear the channel is helping you. You should check out my General Physics playlist: ruclips.net/p/PLMlqayk59Ivqix9KKsTTA27udTZe6XpRx
My gen chem 2 was chapt 14-20 and alhamdulilah i got an A from watching your videos
Im starting orgo in march and i only anticipate great content from you
Thank you prof chad 🫡
You are very welcome - Happy Studying!
The chemistry Beast 🔥
Thanks!
Awesome man thanks!
You bet!
great video, thanks
You're welcome - thanks!
Thank you sir 🎉🎉🎉
Your class was imparting 🎉🎉🎉❤
Very welcome!
good job chad
Thanks!
what about the mass of the electrons for binding energy?
I know its because its only regarding nucleons, but my textbook added in the calculations for electrons also for some reason
ur actualy goated
Thanks
My professor taught us to use the conversion factor 1 kg/6.23x10^26 amu when converting from amu to kg. I assume I should keep using my professor's conversion factor, but how come you are using 1.67x10^-27 kg/1 amu?
Note that it should be 6.023x10^26amu rather than 6.23x10^26.
Besides that one is just the inverse of the other. For comparison your could use 1 foot = 12 inches for a conversion or you could use 1 inch = 1/12 feet. Note that 1/(6.023x10^26) = 1.66x10^-27.
Hope this helps!
@@ChadsPrep thanks 👍
@@wildlifeshorts3475 You're welcome!
nice sir
Thanks.
I try solving that problem but the mass defect is negative but yours shows positive
take the modulus its fine
the best
Thank you
W video, thanks Gipsy King
Happy Studying!
@@ChadsPrep thsnks Chad you really came through🙌🏾but please do on Analytic Chemistry it would be real helpful to other students for future references
❤
Thx!
I don't understand English
I am from India
Do you know India 🇮🇳
I'm first
Welcome to the video/channel!
bro, did someone hack me. I never watched this video or commented first