Equipotential Lines & Surfaces, Electric Field, Work & Voltage - Physics
HTML-код
- Опубликовано: 6 дек 2017
- This physics video tutorial provides a basic introduction into equipotential lines and equipotential surfaces. It discusses the relationship between equipotential lines and electric field. It discusses how to calculate the work done by a charge as it moves across an equipotential surface and how to calculate the voltage between two equipotential lines.
Physics 2 - Basic Introduction:
• Physics 2 - Basic Intr...
Electric Charge - Physics:
• Electric Charge - Physics
Conservation of Electric Charge:
• Law of Conservation of...
Coulomb's Law and Electric Force:
• Coulomb's Law - Net El...
Electric Fields:
• Electric Field Due To ...
________________________
Electric Dipole Moment:
• Electric Dipole Moment...
Electric Flux:
• Electric Flux, Gauss's...
Gauss Law Problems:
• Gauss Law Problems, In...
Electric Potential:
• Electric Potential
_______________________
The Electron Volt:
• Electron Volt Explaine...
Electric Potential Energy:
• Electric Potential Energy
Parallel Plate Capacitor:
• Parallel Plate Capacit...
Energy Stored In a Capacitor:
• How To Calculate The E...
Physics PDF Worksheets:
www.video-tutor.net/physics-b...
Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html
Full-Length Videos & Exams: www.patreon.com/MathScienceTutor/collections
how do u know everyhting jesus
Summary
• Equipotential surface is a surface which have same potential at all points.
• Electric lines of force is always perpendicular to the Equipotential surface.
Thank You for this brother
@@codingkiddo glad to see my 1 year old comment is still valueable...
It still is!!!
Yepp
• Electric field lines always go from high potential to low potential, with charges taken into accord, where -80 > -120.
•E=-(delta)V/d
Wow! You explain everything as simple as it could be.Thank you very much.
You are always my first choice!!
so amazing explanation
Dang wish I knew about this channel in physics 1... def gonna use this to learn physics 2 this semester though. My professor is literally not teaching the majority of the stuff we need to know 😭 First midterm Monday. Time for last minute studying. :)
Where are u from
hey! did you pass physics 2?
@@CerenYener60 Barely. Ended up passing with a C+ after a large curve. By far the worst I have ever done. Haven't done nearly as bad in the rest of my courses since then tho. Def blame the sh**y professor.
Please we need METHOD OF IMAGE tutorial 🙏🙏🙏🙏
YOU ARE THE GOAT
Are you answering questions?
How do i calculate the change in voltage if the value of the voltage is not given on both surface
V is higher on the line closer to the electric field source and lower on the line farther from the source.
is the equation E = -deltaV/d or E = +deltaV/d?
lol I hope you have figured it out by now but it is the negative version
he helped us a lot but we dont even know his name?????
Bakit ba kasi ako nag-STEM? :)
Where did you get the 1.6?
From the charge of a proton. Sometimes it's 1.6x10^-19 and sometimes it's 1.67^-19 but the first is the most frequently used as far as I know
1.6 is like constant electric charge in both proton and electron. for proton is positive 1.6 x 10^-19 and electron -1.6 x 10^-19
why does he use 1.6*10^-19 for the second question and -1.6*10^-19 for the third question?
Nvmd I got it; in the second question he moves a proton and the third question he moves an electron
because the second question is *proton* while the third question is an *electron*
why is the equation W=-q(v2-v1) instead of W=q(v2-v1)???
Think about kinetic energy. When you hold a ball still above the ground, it has no kinetic energy but "x" potential energy (x is just some energy, it doesn't matter what it is). Then, you drop the ball. As the ball falls to the ground, that potential energy is being transformed into kinetic energy. In that sense, potential energy is decreasing while kinetic energy is decreasing. Right before the ball makes contact with the ground, the all of the potential energy from when it's in your hand is kinetic energy. Work is a force being done over a distance, so something is moving. That something is losing potential energy, just like our ball. So the sign for translating work into potential is negative.
it seems like you have mixed up the work done by the electric field with the work done against the electric field
Please note that one critical distinction (clarification) is missing from this video...
When the tutor talks about calculating the work (at least in this video), he is referring to the work done BY (repeat BY) the electric field. Sometimes he uses the phrase "required work". This also misleading as it implies that WE have to do some work. It is the field that is pushing positive charges away from positive charges or (in other words) from areas of higher electric potential to areas of lower electric potential. It is also the field that is slowing down the negative charged electron as it moves away from the positive charge.
@@andrewwarren3633 thank you
@@andrewwarren3633 yes correct, you should be a teacher because you seem to care about rigour.
goat
Correct me if I'm wrong: the way I got taught for potential difference, it must always be one position with respect to another position and not necessarily with respect to direction. So if I am looking for the potential difference of A with respect to B, VsubAB, you'd do Va - Vb and vice-versa. That's honestly the only part of the video that I disagree with.
Sidenote: W = -DeltaVq and I think E = DeltaV/d. Finding potential per meter doesn't require a negative sign I think as long as you move along the direction of the electric field lines.