I just want to say, I have used your videos to help me study, and you are awesome. I don't think I would've passed any of my physics classes without your help.
Thank you for the visual of how to tell what part of your fingers to look at for into/out of the page! I have been so confused about how to tell and this made it so clear. You're the best!
Quantum physics has been struggling to explain the phenomena of magnetism for quite some time now. In fact, some scientists have even suggested that quantum mechanics cannot explain magnetism at all, because they have excluded Ether from their theory. The magnetic field is created by a current carrying wire, and it's based on the exchange of electric and magnetic fields. However, quantum mechanics doesn't seem to be able to account for this field very well. Some researchers believe that there must be something else involved in creating and maintaining a magnetic field-something like ether. If this is true, then quantum mechanics may need to be revised in order to include Ether as a part of its theory.
I just want to say I really appreciate your videos .Im a physics honours and although I m done with my master I still have troubles with my basics and Im all for relearning . 👍
1:13 is the direction of magnetic field line of East correct? The direction seems to disobey right hand grip rule? I thought it should be same direction with the North which is anti clockwise....
omg why couldnt my textbook talk about the point below or above the pen/wire for the right hand rule??? Thank you so much I could never pass physics with just that useless book.
This is a very organised explanation thank you but I just wanna ask if the two parallel wires having current in the same direction then the resulted magnetic field between them will be out or in the page
This is well over due for you, but since it might help someone else. You simply need to use B = u0 I / 4piR (sin(theta 1) + sin(theta 2)) where theta 1 and theta 2 are angle 1 and angle 2, respectively.
A current of 5A flow in a straight wire in a uniform flux density of 2×10−3 T . Calculate the force per unit length of the wire if it is perpendicular to the field?
Sir: with all respect, are the magnetic forces which two wires carrying current exert on each other will be affected if the two wires are insulated (they are both have plastic covers)?
I believe that it might slightly change the value, but overall not very much. Since the force is (mainly) due to the distance from the wire, the insulation will not have a great effect. The one thing it might change (i'm not sure) is whether or not it is accurate to use the permittivity of free space constant, but once again even that would not change the value of the force greatly.
yes, wherever the point is, just have the net magnetic field equal to all the currents and the distance away from the point. Use the second example and expand it to a 3-phase electrical cable.
from what i understand the radius isnt the radius of the wire, it is the radius from the center of the wire to the point of interest. so in example 2, the radius of the top wire to the point of interst is 2 and the radius of the ottom wire to the point of interst is 3
how did you typed that in the calculator, im not getting same results. permeability is just 1 right, without fancy writing. en.wikipedia.org/wiki/Permeability_(electromagnetism)
**THE EXACT PHYSICAL NATURE OF THE CREATION OF THE WIRE'S MAGNETIC FIELD** Current flow does not cause the magnetic field creation. Not in the way people think. In a 12 gauge copper wire (2mm diameter), at 1 amp, a single electron moves only 0.000023 meters per second. See en.wikipedia.org/wiki/Drift_velocity#Numerical_example I'm going to figure out the exact physical nature of the magnetic field around the wire. A couple things stand out: 1) there are no electrons flowing down the wire. How long will it take one electron in a 1 amp, 12 gauge wire to move one meter? Distance = Rate x Time. 1 meter = .000023 meters/second x Time. Time = 1 meter / .000023 meters/second = 43,478 seconds = 742.64 minutes = 12.1 hours "But that's just one electron. There's millions of electrons. You forgot about that." No. Every electron is traveling slower than frozen molasses, .000023 meters/second, 1 meter in 12.1 hours. So moving electrons do not create the magnetic field. The magnetic field appears INSTANTLY the moment power is turned on (speed of light, just like the electric field) and the electrons are taking 12.1 hours to move only one meter. And it's not the random movement of electrons either - the magnetic field around the wire would be random in that case, and the field is not random. 2) the orientation of the (rotating) magnetic field around the wire is the same every time - right hand rule. 3) it is a north magnetic pole - every time power is on. I'm starting there. The suspicion is that the field gradient is part of the reason for the consistency of the magnetic pole being north consistently.
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I just want to say, I have used your videos to help me study, and you are awesome. I don't think I would've passed any of my physics classes without your help.
I do not know how you have a video on almost everything. You are truly amazing. Thank you for all of the hard work you put into your videos.
This needs way more views
Thank you for the visual of how to tell what part of your fingers to look at for into/out of the page! I have been so confused about how to tell and this made it so clear. You're the best!
Quantum physics has been struggling to explain the phenomena of magnetism for quite some time now. In fact, some scientists have even suggested that quantum mechanics cannot explain magnetism at all, because they have excluded Ether from their theory. The magnetic field is created by a current carrying wire, and it's based on the exchange of electric and magnetic fields. However, quantum mechanics doesn't seem to be able to account for this field very well. Some researchers believe that there must be something else involved in creating and maintaining a magnetic field-something like ether. If this is true, then quantum mechanics may need to be revised in order to include Ether as a part of its theory.
This is way helpful ever.. well done . Thank you.
I just want to say I really appreciate your videos .Im a physics honours and although I m done with my master I still have troubles with my basics and Im all for relearning .
👍
Thank you so much! I was really confused about these types of problems but not anymore
1:13 is the direction of magnetic field line of East correct? The direction seems to disobey right hand grip rule? I thought it should be same direction with the North which is anti clockwise....
omg why couldnt my textbook talk about the point below or above the pen/wire for the right hand rule??? Thank you so much I could never pass physics with just that useless book.
Buy yourself “College Physics.A strategic approach” by Knight,Jones, Field…They explain everything extremely well!
You deserve more blessings
YOUR VIDEOS ARE SO GOOD BRO......THANK U VERY MUCH...
You know what. You arr the best
Exactly how I like it: no 5-minute shit before the video starts, gets down to business at 0:00.
Yeah I understand that
This is a very organised explanation thank you but I just wanna ask if the two parallel wires having current in the same direction then the resulted magnetic field between them will be out or in the page
Is there a video for a SHORT wire?....where we include the length and angles in the equations?
This is well over due for you, but since it might help someone else. You simply need to use B = u0 I / 4piR (sin(theta 1) + sin(theta 2)) where theta 1 and theta 2 are angle 1 and angle 2, respectively.
Thank you ❤
god this is so much clearer now
6:34 shouldn't the magnetic field be the other way if your thumb is pointing to the right, with fingers wrapped inwardly facing you?
thats what I am also confused about yeah
A current of 5A flow in a straight wire in a uniform flux density of 2×10−3 T . Calculate the force per unit length of the wire if it is perpendicular to the field?
Sir: with all respect, are the magnetic forces which two wires carrying current exert on each other will be affected if the two wires are insulated (they are both have plastic covers)?
I believe that it might slightly change the value, but overall not very much. Since the force is (mainly) due to the distance from the wire, the insulation will not have a great effect. The one thing it might change (i'm not sure) is whether or not it is accurate to use the permittivity of free space constant, but once again even that would not change the value of the force greatly.
@@micah8793 hi!!
thanks a lot for everything.
Im assuming this formula will only apply to conductors in DC circuits. DC conductors flow current in one direction. How would you calculate for AC?
At 7:44 on the second wire aren’t the magnetic fields reversed?
that's what i thought too
He later corrected himself
Thanks alot sir 🙏🏻🙏🏻🙏🏻🙏🏻, your a god
My name is Alphonse Kara from PNG..I am really interested to explore my Physics contact with you...
Thx bro
Can this be used to determine the magnetic field around a 3 phase electrical cable?
yes, wherever the point is, just have the net magnetic field equal to all the currents and the distance away from the point. Use the second example and expand it to a 3-phase electrical cable.
Okaaaay so when finding the direction of the force and magnetic field we use right hand rule
Thank you !!!
Thanks
what about a point below both wires at point C?
I guess you'd add the distances, like he did when the point was above the first wire. That is, A.
So we neglect the diameter of the wire in example 2?
from what i understand the radius isnt the radius of the wire, it is the radius from the center of the wire to the point of interest. so in example 2, the radius of the top wire to the point of interst is 2 and the radius of the ottom wire to the point of interst is 3
what if i have B's and two of them are going out of the page and two of them are going inside the page
you are so good man
i love you so much and thank you so much with all my heart
Ej best in physics
What calculator are you using???? I can't find my answer in here😭😓
maybe u can simplify the 4pi x 10^-7 with 2pi, so it becomes 2 x10^-7
Is the magnetic field NOT supposed to be a vector????
Please help to solve refraction and Suspension also Len ,electrodynamic and soon an finally I love your teaching
this dude is the goat
you are the best.
Thank you once again.
i’m gonna cry😊
bless you
thanks!
Why are there different forms for different magnetic fields
Exactly this is so gay there’s like 15 different magnetic field equations you have to remember
why does my calculator keep giving me a syntax error
i love you
how did you typed that in the calculator, im not getting same results. permeability is just 1 right, without fancy writing. en.wikipedia.org/wiki/Permeability_(electromagnetism)
**THE EXACT PHYSICAL NATURE OF THE CREATION OF THE WIRE'S MAGNETIC FIELD**
Current flow does not cause the magnetic field creation. Not in the way people think.
In a 12 gauge copper wire (2mm diameter), at 1 amp, a single electron moves only
0.000023 meters per second. See en.wikipedia.org/wiki/Drift_velocity#Numerical_example
I'm going to figure out the exact physical nature of the magnetic field around the wire. A couple things stand out:
1) there are no electrons flowing down the wire. How long will it take one electron in a 1 amp, 12 gauge wire to move one meter?
Distance = Rate x Time.
1 meter = .000023 meters/second x Time.
Time = 1 meter / .000023 meters/second = 43,478 seconds = 742.64 minutes = 12.1 hours
"But that's just one electron. There's millions of electrons. You forgot about that."
No. Every electron is traveling slower than frozen molasses, .000023 meters/second, 1 meter in 12.1 hours.
So moving electrons do not create the magnetic field. The magnetic field appears INSTANTLY the moment power is turned on (speed of light, just like the electric field) and the electrons are taking 12.1 hours to move only one meter.
And it's not the random movement of electrons either - the magnetic field around the wire would be random in that case, and the field is not random.
2) the orientation of the (rotating) magnetic field around the wire is the same every time - right hand rule.
3) it is a north magnetic pole - every time power is on.
I'm starting there. The suspicion is that the field gradient is part of the reason for the consistency of the magnetic pole being north consistently.
Memorial university of Newfoundland