ac: Mutual Inductance Example #2

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  • Опубликовано: 7 янв 2025

Комментарии • 59

  • @sanwellbeatz1630
    @sanwellbeatz1630 2 года назад +2

    Searched all over the internet for this and finally found it

  • @kuya445
    @kuya445 9 лет назад +7

    About the second voltage induced by the first inductor, i think it should have a sign of +- because the current enters the dotted side of the first inductor then it should follow the sign

  • @240mains
    @240mains 5 лет назад

    Hi again .
    this is the most info i can get out of book "Engineering Circuit Analysis" , year 1993 from publisher McGraw-Hill .
    Writing All Self terms is the same as with DC equation writing with NON coupled coils .
    Now , assuming 2 coupled coils , I2 flowing thru L2 gives an
    induced term of jwMI2 onto mesh I1 ( easy to realize ) . Next , using the Dot Convention with I2 Arrow and the
    Dot of L2 , we easily know the induced +-polarity onto L1 .
    Now we need to determine the correct +-sign of , jwMI2 .
    To find this +-sign , we use the same KVL traverse direction that was used when writing the Self term of L1 .
    Example :
    if we had Traversed L1 Clock-Wise and if we used the +-sign of L1 as we Entered L1 , then that is the same location
    we must use to pick the +-sign for the Induced term .
    Effectively , L1 will have 2 pair of +-polarities .
    +-pair One was used to write the Self term of L1 . the other +-polarity across L1 came from the Dot of L2 with
    I2's current Arrow direction, either entering the Dot or Exiting the Dot , of L2 .
    Example :
    + - is the +- pair across L1 , used when writing Self Term of L1 , Traversing\Entering L1 on the Left side , at the +plus ,
    thus the Self Term of L1 is + ( + jwL1I1 ) , KVL is +pos and Ohm's Law is +pos
    if we determined the Induced +-polarity across L1 ( using L2's Dot with I2's Arrow direction ) as:
    - + , we need to use KVL Traverse in the same way that was used during the writing of L1's Self Term , thus we use -
    which is again Entering L1 from the Left side and the Induced term onto Mesh I1 is ( - jwMI2 ) , KVL only .
    I see nothing else the book is doing\saying . All the above can be done in One's head , with nothing extra to write on the
    diagram . Very implicite , once someone sees how to do it . Deriving the +-sign of the Induced Term does NOT use
    Ohm's Law , instead uses just KVL Traverse direction in the exact same way as performed when the Self Term of L1
    was written .
    It is actually very simple to do , even though the book's sometime suggest otherwise .
    i have no issues wrting the initial mesh equations in Chapter 14 , of the above mentioned book .
    The initial mesh equations can easily be Directly wirtten with No intermediate steps, and No extra drawing on the diagram .
    what do you think ?

  • @vasiqshair
    @vasiqshair 4 года назад

    The method of using dependent voltage sources is very helpful. Thank you!

  • @DiogoPedrosaMusic
    @DiogoPedrosaMusic 6 лет назад +1

    THIS VIDEO SAVED MY LIFE!

  • @LantiSpahiu
    @LantiSpahiu 11 лет назад +6

    Should have been 3(I2-I1)+ j4I1 + jI2 + 1I2 + (-j)I2? I think you forget jI2 near j4I1 in the second equation.

    • @nonya1119
      @nonya1119 6 лет назад

      I noticed that also

    • @phuongnguyen-kc8hi
      @phuongnguyen-kc8hi 4 года назад

      Yup but he fixed that right before finishing his equation.

  • @baselmarji7145
    @baselmarji7145 2 года назад

    How is the way you drew the dependent voltage source "Positive on the same side as the dot"?

  • @RoseHulmanOnline
    @RoseHulmanOnline  12 лет назад

    Glad to hear you found it helpful!

  • @vinchester5105
    @vinchester5105 11 лет назад

    thank you just one question when we signify dependant sources (+) must look to point is it right ? İt works always does it?

  • @aldrinjosephobis3211
    @aldrinjosephobis3211 4 года назад

    I have a question, why did in the first coil, the j4 was multiplied with I2-I1? And the second coil, why just multiply with I1? Can you elaborate a clear explanation? Tha

  • @50jegadeesan
    @50jegadeesan 8 лет назад

    in mesh 2 dependent voltage should it not be j4(i1-i2) as it was done in mesh 1 .the reflection current due to mutual inductance is i2-i1

  • @leosmi1
    @leosmi1 8 лет назад

    shouldn't be j4(i2-(-i1)) at the first dependt source? because i1 is negative on the way with no point in 1/4H...

  • @RoseHulmanOnline
    @RoseHulmanOnline  12 лет назад

    Great, glad to hear that it was helpful to you.

  • @oksky58
    @oksky58 6 лет назад +3

    thank u for clarifying the polarity!

  • @cizzie219
    @cizzie219 7 лет назад

    On the j2 inductor, what if the dot was on the right, meaning i1 is exiting the dot. Would that mean the middle dependent source would be -j4?

    • @phuongnguyen-kc8hi
      @phuongnguyen-kc8hi 4 года назад +1

      Trump 2016 I did that method which put the dependent source on the right of J2 and the sign was negative and positive which ha the value of J4(I1 - I2). The final answer is the same as his method putting the source where the dot is. I was confused at first but after watching many videos with different methods, I finally got it.

  • @furkanarpac590
    @furkanarpac590 6 лет назад

    Very clear explanations here ,thank you for the video.

  • @nonya1119
    @nonya1119 6 лет назад

    I think you missed a J2(I2-I1) in the 2nd loop equation

  • @phasorsystems6873
    @phasorsystems6873 3 года назад

    Hello could you test this software? Locate circuit solver on the playstore!

  • @nalinijatwar1804
    @nalinijatwar1804 6 лет назад +2

    one mistake you did in second equation. you forgot to consider inductance ( +j) ,(situated in the middle of circuit).

    • @phuongnguyen-kc8hi
      @phuongnguyen-kc8hi 4 года назад

      nalini jatwar He fixed it right there, please watch the video until the end.

  • @jesusalvarezfebres6592
    @jesusalvarezfebres6592 4 месяца назад

    excellent procedure and result.

  • @TheAdlcn
    @TheAdlcn 10 лет назад

    the voltage source is in "cos" so fasor notation must be 10/_90 ??

    • @zulpo
      @zulpo 10 лет назад +2

      No, you can use 10/_0rad as the source, there's no need to add 90º. Lets say you find some voltage in the circuit wich is 7/_(pi/6), in the time domain this means 7cos(4t+pi/6), its just a phase shift.

  • @gifttsundukanimashavani3806
    @gifttsundukanimashavani3806 9 лет назад

    in 1/4 F, when i use (1/WC)j im getting (1/4*0.25)j = 1j not -1j... how are you getting -1j?

    • @RoseHulmanOnline
      @RoseHulmanOnline  9 лет назад

      Gift Tsundukani Mashavani The "j" is part of the denominator, as in 1/(j*wc), and 1/j = -j

  • @TurbidSugar19
    @TurbidSugar19 6 лет назад

    My hero! You saved me from my ass-some university

  • @amiladrck
    @amiladrck 9 лет назад +2

    Thank you! This helped me a lot :)

  • @ko1997ko
    @ko1997ko 6 лет назад

    you putted the signs of dependent source wrong

  • @1972hattrick
    @1972hattrick 7 лет назад

    I understand mutual inductance for a transformer would be isolated and circuit resembles a parallel look. What device is this? Why does it look to be in series?

  • @keyranassayida9648
    @keyranassayida9648 7 лет назад

    thank u so much u make it super easier for me

  • @240mains
    @240mains 5 лет назад

    why the technique of Inserting dependent source ? I don't get it . Write any KVL equation of resistors , and no one inserts a voltage source in place of IR ( we could , but no one does that ) .
    why not just write the two Mesh equations that each contain Self-terms( as normal ) with the Mutual-terms .
    That's how the good books do it . Your way , the circuit diagram needs to be messed with to draw in the dependent source .
    Too much overhead for that approach .
    I am NOT liking that technique .
    ISBN : 0-07-027410-X "Engineering Circuit Analysis" Fifth Edition 1993 , McGraw-Hill publisher .

    • @RoseHulmanOnline
      @RoseHulmanOnline  5 лет назад +1

      Yes, you are correct, most textbooks do not redraw the circuit with dependent sources to model the induced voltages. As a student learning this material I often found it difficult to get the voltage polarities correct, and later as a professor found that showing the induced voltages explicitly as voltage sources made it easier for my students to arrive at the correct analysis of the circuit.

    • @240mains
      @240mains 5 лет назад

      @@RoseHulmanOnline ok . I have found that much equation writing and analysis eventually involves a lot of implicitness . Example Reference :Node analysis , Nodes are labeled V1 V2 V3 , while each V node is + with the single Ref. node as -. +- are shown only during a First time explaining . After that , the books do NOT draw in those +- node pairs( everyone needs to Remember that ) . For Meshes , I only show I1 I2 I3 etc. in each Mesh window . I don't show the Arrows anymore, because each Arrow is implicitly known to be used in the Clock-Wise direction .
      It is not difficult , but eventually there are many things that become implicit , which need to be fully discussed at introductory level . When showing extra Steps , the reader should know that , that is NOT how they will eventually do it . The same circuit needs to be re-done in the implicit way . Other-wise some folks might get miss-lead in their analysis approach . You showed the analysis , but yet you don't actually do it that way. That can confuse and miss lead a First Timer . It needs to be followed by an implicit analysis so that everyone sees the real deal .
      The book I mentioned is very concise , Not perfect but it beats the other 2 top competing books . That book has a real Engineering approach to the discussions . The depth of technique is obvious , in the book .
      the other 2 competing books are :
      "Electric Circuits" 2nd Edition and "Basic Engineering Circuit Analysis" 4th Edition
      all 3 books are now in their 12th or so Editions . ( there is nothing new in the newest editions , so buy previous editions used )

    • @You_Tube12355
      @You_Tube12355 5 лет назад

      If we don't use dependent source we get same result ..Does it requires to use dependent source as point of view as marks

    • @240mains
      @240mains 5 лет назад

      @@You_Tube12355 I think some of the Techniques are NOT using the full concept of the "DOT Convention" , that is why some want to insert a voltage source .
      If a "Self inductance" term is + - , and we find that the "Mutial inductance" term is + - , then we know that the Mutual term "aids" the self term , and the Mutual term is written with a + .
      If we find the Mutual term opposes the +-polarity of the Self term , then the Mutual term is written with a -minus , for here the Mutual induced voltage acts to "reduce\opposes" the Self induced voltage
      There is No need to draw in\insert a "voltage source" depiction .
      Can you get a copy of this book :
      ISBN 0-07-027410-X "Engineering Circuit Analysis" Fifth Edition , 1993 McGraw-Hill publisher . It has International versions too . ( how many languages , I do not know ) That book has great depth .

    • @You_Tube12355
      @You_Tube12355 5 лет назад

      @@240mains book ki soft copy hay to bhejo sir please..

  • @alessandrademoraisandre8729
    @alessandrademoraisandre8729 7 лет назад +1

    This helped me a lot!!!!!

  • @erickmillan7863
    @erickmillan7863 5 лет назад

    The second equation is wrong

    • @phuongnguyen-kc8hi
      @phuongnguyen-kc8hi 4 года назад

      Erick Millan It is correct. I try different method and the final answer is the same (verified).

  • @rebedmos
    @rebedmos 7 лет назад +1

    Enfim eu entendi essa matéria! Bela explicação!

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  • @Fairyking75
    @Fairyking75 12 лет назад

    Thanks for the great video

  • @iangiovaanni
    @iangiovaanni 6 лет назад

    Gracias ! Thank you !

  • @dilanramoscalizaya2207
    @dilanramoscalizaya2207 3 года назад

    👍👏

  • @mohammadyousef6374
    @mohammadyousef6374 5 лет назад

    thank youuu

  • @princemazumdar8452
    @princemazumdar8452 7 лет назад +2

    yr explaination is not understandable...as it looks like u r practising by yrself...

  • @محمدسلام-ط3ط
    @محمدسلام-ط3ط 5 лет назад

    حبيبتي ماتت وكان ليها مكان ف قلبي جوا مليان احزان قتلتها بعد ما ختنها قوام حب الله مش ز حب نسوان