FINALLY..a video that makes sense. This has been the one thing in my ENA class that totally boggled me; never understood when to add/subtract the induced voltage. Thank you.
Glad to help out! Many (most?) textbooks do not visualize the induced voltage as a voltage source, and that is the source of much confusion. Once you can see the voltage source it is easy to get the signs correct when you apply KVL.
Thank you this was very interesting and helpful. I see that at 6:12, your solution in Maple was I2=3 Amps at zero degrees, but in your written solution after that you have swapped I2 and I1. Why? Was this a clerical error?
thank you so much for explaining it like this 😭 I've been trying to understand this for DAYS and i can solve every question after i saw your video, THANK YOU SO MUCH
Thanks, Rehan! Check out the 3-phase problems on CLEO (see the link in the description box above), click Browse, then Topics, then AC Circuits; the 3-phase problems are at the bottom of the page.
holy shit man, spent 6 hours trying to figure this shit out and now you made it so simple. Mfers had me making doors at the dots and doing all that confusing shit
I use fx 570 to calculate and of course by using simultaneous equation. but then, the calculation always turn out wrong. I believe the thing got wrong when I move the number from left side to right side or vice versa. Can you show the correct way on how to solve the current by using simultaneous equation? I really need to clarify my understanding huwaa!!
yea that was exactly it. I had my final today, which covered this material..unfortunately...I was unable to solve for I1 and I2 using the laplace version of the impedance. It confused the hell out of me.
Well what i did was change convert the rectangular formed imaginery & real numbers to phasor, then replacing the current unknowns, then inserting into an equation solver which got me 3 and 17 which aint that bad i suppose
+Mete Yıldırım Assuming you already figured it out by now but for others wondering; notice the final answer. He left it terms of sin instead of making the final answer in terms of cos. Now, if we wanted to show the final answer in terms of cos then yes we should make the voltage source show as 42/-90. It just depends on how your professor wants you to show it. Since we left it in terms of sin the correct way to show it is 42/0
FINALLY..a video that makes sense. This has been the one thing in my ENA class that totally boggled me; never understood when to add/subtract the induced voltage.
Thank you.
Glad to help out! Many (most?) textbooks do not visualize the induced voltage as a voltage source, and that is the source of much confusion. Once you can see the voltage source it is easy to get the signs correct when you apply KVL.
Thank you this was very interesting and helpful. I see that at 6:12, your solution in Maple was I2=3 Amps at zero degrees, but in your written solution after that you have swapped I2 and I1. Why? Was this a clerical error?
Oops, I discovered your correction at 7:38, never mind.
Thanks so much, I have no idea what the hell this phaser stuff is but that tip with replacing the dots with v sources is a godsend
thank you so much for explaining it like this 😭 I've been trying to understand this for DAYS and i can solve every question after i saw your video, THANK YOU SO MUCH
Thanks, Rehan! Check out the 3-phase problems on CLEO (see the link in the description box above), click Browse, then Topics, then AC Circuits; the 3-phase problems are at the bottom of the page.
holy shit man, spent 6 hours trying to figure this shit out and now you made it so simple. Mfers had me making doors at the dots and doing all that confusing shit
thank you so much ive been figuring out this for 2 days but you make it easy thank you so much dude
Sir
You've made this lesson easy
like taking a candy from a baby
I think the answer is the vice versa. I used matrix methods and get the answer of I1 & I2 the other way round. Can you reconfirmed? Thanks!
Yeah, he messed up. When he solved for I1 and I2 he got I2 = 3 and then when he wrote i1 and i2 he had i1 = 3.
i inserted the equations into an equation solver after converting everything to polar from rectangular and the same thing happened to me
Are you the one behind NTS Press, about National Instrument's products? If so, God am I ever so grateful to you :D
be careful on final, check the currents. great video, TY.
How is the polarity of the dependent sources determined??
It is determined by dot ,dot side is taken as positive..
I use fx 570 to calculate and of course by using simultaneous equation.
but then, the calculation always turn out wrong.
I believe the thing got wrong when I move the number from left side to right side or vice versa. Can you show the correct way on how to solve the current by using simultaneous equation? I really need to clarify my understanding huwaa!!
Can we use this method to find Zth and Vth?
I tried on a similar problem but couldn't get the answer.
However, the T-model works perfectly fine there.
gracias por la explicacion, nunca pense que usarian una fuente de voltaje para encontrar el signo de la autoinductancia, thank you!!!!!!!!
yea that was exactly it. I had my final today, which covered this material..unfortunately...I was unable to solve for I1 and I2 using the laplace version of the impedance. It confused the hell out of me.
how can you solve those equations without using an equation solver?
Cramers Rule
Well what i did was change convert the rectangular formed imaginery & real numbers to phasor, then replacing the current unknowns, then inserting into an equation solver which got me 3 and 17 which aint that bad i suppose
i don't understand what mutual induced voltage physically mean in terms of magnetics and power.
what is the software name please?
IF YOU ARE GOOD IN CIRCUIT ANALYSIS ,SOLVE THE SAME PROBLEM BY USING NODE ANALYSIS
awesome approach to transformers
You help me a lot with this video thanks!
how does "42 sin8t" equal 42/_0'? it should be 42/_-90' i guess.
+Mete Yıldırım Assuming you already figured it out by now but for others wondering; notice the final answer. He left it terms of sin instead of making the final answer in terms of cos. Now, if we wanted to show the final answer in terms of cos then yes we should make the voltage source show as 42/-90. It just depends on how your professor wants you to show it. Since we left it in terms of sin the correct way to show it is 42/0
it just because he got the time domain value also in sin scale.
Thank you very much ..... this is really helpful
you are awesome - can you do a video on a 3 phase circuit ?
your fan #1 ^_^
If you can't use a equation solver program on your exams it gets difficult. Especially during the EIT exam
isnt the angle -90
How to find omega value
omega is given in the time domain voltage, which is 8 in this case.
Thank you very much. This was a great hand !!!!!
thank you sooo much its been very helpful
Very helpful, thanks a lot!
Edit: Spelling
thanks a lot. I'm learning...
Thanks bro! Mad helpful
Really helpful video though.
Thank you! :)
Thank you sir
thank you
türkçe yok mu yahu
ما شاء الهل والله فهمت عطيلك لايك
Thx! really helps
kuch dhng ka upload karo bkchodi na karo
español/