You're very welcome, Ŕicky Kurosawa. Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Best regards :)
With quadratic equations if you put in anything as A B and C you'll get a simple answer. In cubic equations only a fraction of equations are simple, most are very long
Thank you so much Aisha for your continued love and support. Take care dear and stay blessed😃 Keep smiling😊 Enjoy every moment of your life 🌻 Jazakallah!
Simply put x=1 or -1 and check whether it is equal to 0 or not. That little complicated stuff you showed for checking x=1,-1 came from the same logic but the former idea doesn't need anything to be to be memorized. Thanks for a good explanation in other cases. Liked it.
thank you so much for this 🥺 we learnt this during online school and i didn’t understand a thing 😭 i feel more prepared for my test tomorrow thank youu 🤩
You are very welcome Aaliya! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
You’re an absolute legend sir, I’m cramming one day before my exams and these tips are so useful sir thank you so much for taking the time and effort to make this video ❤️❤️
You're very welcome Malik Saab! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep supporting my channel. Kind regards :)
Thanks for this. I've been working on a new math module and this gave me a really solid start at solving polynomial equations, as these techniques were easy to implement.
Glad to hear that Jonathan! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃
It was really very helpful Sir.....I was searching for the video in which for the equation whose x^3 coefficient is not '1'......here I found......Your professional students are very luck.
You're very welcome! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep supporting my channel. Take care😃
You are very welcome Vinutha! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and stay blessed and healthy😃 Keep smiling😃
guys this guy is legit doing it the wrong way it's like a really basic thing we can simply differentiate this equation and then with the gradient solve it for x and y...
Dear sun flower, you are very welcome. Thank you so much for taking the time to leave this comment. I'm glad you liked the vid. Your feedback is always appreciated. Keep it up. Kind regards :)
You are very welcome Mery from beautiful Morocco! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃 Keep smiling😊
You are very welcome Flash! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
You are very welcome Amy! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
So nice of you dear! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃 Have a very happy and blessed New Year!
You're very welcome Arpita! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear 😃
Glad to hear that Raghupathi! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
You are very welcome dear! You are awesome 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃
In case of cubic equation point of view, At first one of the root should be obtained by applying "hit & trail method "(Although it needs some simplification in some cases ), Then other roots may come out by deviding the first root (suppose the first root is 7, then you have to devide the given equation by x-7), then move on (personal opinion )
You are very welcome Devdatt! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃 1
You're very welcome! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep supporting my channel. Kind regards :)
Thank you so much Kevin for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and all the best 😃
You are very welcome! I've already made few videos on trig. Please search videos in my channel. If you want me to make videos on specific questions, please send it on my email: math@mycollege.org Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and all the best 😃
You are very welcome Kailen! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
You are very welcome! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
I think the method explained is rather a trial-and-error approach and the following method will be more logical: Let us consider the LHS of the equation as y and as x approaches to plus infinity, y also approaches to plus infinity; similarly, when x approaches to negative infinity, y also approaches to negative infinity. What does this mean? This means y is a continues function sloping in the NE-SW direction. Meantime, x = 0, y = 6 and x = 1, y = -7 which means that there will be a real root between 0 and 1. As y is sloping in the NE-SW direction, we can deduce that there has to be 3 real distinct roots to y. When x = -1, y = 18; This clearly indicates that the 3 real roots to function y namely α, β and γ (say α
sire, would you consider making a video? a transcript is difficult to follow at once, hence a video such as khanacademy's or this style would be much appreciated. this method may be "easier" however i'm unable to read it/remember it in this format. thanks.
You are very welcome! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and all the best 😃
Thank you so much Harsh ji for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and all the best😃
2x^3+x^2-13x+6=0 On observation, x=2 satisfies this equation (x-2)=0 is a factor of 2x^3+x^2-13x+6=0 (2x^3+x^2-13x+6)/(x-2)=(2x^2+5x-3)=0 using synthetic division. In 2x^2+5x-3 b^2>4ac therefore 2x^3+x^2-13x+6 has three real roots. (x-2)(2x^2+5x-3)=0 x= -3 is a solution by observation (x+3)=0 is a factor of (2x^2+5x-3)=0 (2x^2+5x-3)/(x+3)=(2x-1)=0 using synthetic division. (2x-1)=0 is a factor of 2x^3+x^2-13x+6=0 Therefore,(2x^3+x^2-13x+6)=(x-2)(x+3)(2x-1)=0 Hence x=2,x= -3 and x=1/2 are the three real roots of 2x^3+x^2-13x+6=0 Thanks for the puzzle PreMath.
In that case, remove fractions first by find the LCD (LCM). Thanks Andrew for asking. I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃
The check by comparing the sum of the roots against -B/A is going to come in handy! Thx!! Quick Question: Does this answer check work when there are 1 real root and 2 complex roots?
You are very welcome dear! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
These things were taught to me in the ‘elementary differential equations’ course. I forgot them because I took that course a long a while. You refreshed it to me and you taught me something new which our teacher in the past didn’t, which is the checking methods whether the answer is x=+-1 or our set of solutions of the equation is true. This would’ve changed my grade into better if I had the chance to see it when I was taking the course. But anyways, Thanks a lot. Edit: It turned out actually you uploaded this video after I finished the course after I checked the time it was uploaded.
Hi! Is there an easier way to find the solutions, since it might take a lot of time during exams to solve all the options. But anyways great video! You helped me a lot
You're very welcome! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep supporting my channel. Kind regards :)
You are very welcome Safwan! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and stay safe😃
This is just the way I did it (taking hints from highest power, constant term and Vieta) before seeing the video solution ... 2x³+x²-13x+6=0 Looking at the equation. Based on the 2x³ term, 2x-1 might be a solution (plug in x=1/2 - it is). Based on the constant term x+3 might be a factor (plug in x=-3 - it is). Vietas rule/formula says sum of solutions = -b/a -1/2 = 1/2 -3 + r (r is the third root) r=2 verfiy ... (2x-1)(x+3)(x-2)=2x³+x²-13x+6 In this case the guesswork was fine - the above two were the only guesses I tried. It is not always so. For example I might have guessed a more complicated (2x+3) as a factor.
Dear Parveen Kachura , you are very welcome. Thank you so much for taking the time to leave this comment. I'm glad you liked the vid. Your feedback is always appreciated. Keep it up. Kind regards :)
Hey guys there is a really good explanation of the cubic and quartic formula on the channel mathloger also explains why quintic equations can’t be solved with radicals using Galo is theory
I'm glad you got it! Muhammed, I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃 Have a very happy and blessed New Year!
Thanks, this is really very helpful..continue your good work.
Cheers! ❤
You're very welcome, Ŕicky Kurosawa. Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Best regards :)
what if our equation is not factorable?
ya😄
amazing ..ruclips.net/video/JdyMqmnWJi8/видео.html
Ysss
Any bodies here after facing problem in finding characteristics equation for eigen vector
yeah
Yes😅
Yeah!! 😅
Kaise pata bhai🤩🤩
@@krishnathombre7946 😎😎😎guess
One of the clearest snd cleanesr solutions to a cubic equation.
This will make solving eigenvalues and eigenvectors easier.
Who is here after facing problems in eigen value roots
Me😂
😂😂
me
😅
Bruuuuuuuuh
Myself 😭
i cnt believe i can find a 11min vid clearing up all my doubts when an hour long lesson in my sch just leaves me ???? thanks for this :))
With quadratic equations if you put in anything as A B and C you'll get a simple answer. In cubic equations only a fraction of equations are simple, most are very long
What just happened that was such a good explanation video idk why but I felt so much smarter. You're really good at this, keep it up :D
Well done our society needs more content like this😊
Thank you so much Aisha for your continued love and support.
Take care dear and stay blessed😃 Keep smiling😊
Enjoy every moment of your life 🌻
Jazakallah!
this is the only helpful video out there on cubic polynomials, i appreciate this so much !!
Simply put x=1 or -1 and check whether it is equal to 0 or not. That little complicated stuff you showed for checking x=1,-1 came from the same logic but the former idea doesn't need anything to be to be memorized. Thanks for a good explanation in other cases. Liked it.
One of the clearest and cleaner solution on whole yt .. thanks a lot sir
Everyone tells put 1,-1,0,2,-2etc but no one tells this method 😮
thank you so much for this 🥺 we learnt this during online school and i didn’t understand a thing 😭 i feel more prepared for my test tomorrow thank youu 🤩
Same
You are very welcome Aaliya! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
You’re an absolute legend sir, I’m cramming one day before my exams and these tips are so useful sir thank you so much for taking the time and effort to make this video ❤️❤️
You're very welcome Malik Saab! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep supporting my channel. Kind regards :)
amazing ...ruclips.net/video/JdyMqmnWJi8/видео.html
This thing was so helpful, it deserved my like and subscribe
God bless you very much, you're a genius.
I finally found a lingering solutions to my eigenvalues characteristic determinant.
So nice of you, dear
Thank you! Cheers! 😀
@@PreMath I wish you show a lesson too, about vector spaces.
And also there're some of the equations I have that are not factorising.
Most of you are here for eigen vectors
Finally i found a better way of solving step 👌🏻👌🏻👌🏻
U also study? 😂😂😂
I thought u r a big mesy
😂😂😂😂
You are a wonderful teacher and doing best to create good human resource.
Thanks for this. I've been working on a new math module and this gave me a really solid start at solving polynomial equations, as these techniques were easy to implement.
Glad to hear that Jonathan! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃
@@PreMath Thank you!
amazing ...ruclips.net/video/JdyMqmnWJi8/видео.html
truely speaking thanks for this video it helped me solve a very tough question whose root is 17 and other are complex numbers
Who is here after bsc 🤣
i think this the best video ever made on cubic . thank u sir
It was really very helpful Sir.....I was searching for the video in which for the equation whose x^3 coefficient is not '1'......here I found......Your professional students are very luck.
2 divided by 6 is 3! Brilliant!!!!!!
This what I want ....Lots of thanks & respect
You're very welcome! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep supporting my channel. Take care😃
U are from which country sir ?
U speak english clearly.
thank you so much sir!! Jesus bless you and your family always!
Thank u so much . It was very helpful and I was searching for this kind of teaching . l'm happy that I finally found it 😇
You are very welcome Vinutha! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and stay blessed and healthy😃 Keep smiling😃
Hello, great video. Those rules you mentioned to find if x = -1, 1 are the solutions, where can I read about it?
this is incredible, im speechless
Thank you,in Hong Kong,they did not teach us those interesting properties,and just teach us to aim higher marks
guys this guy is legit doing it the wrong way
it's like a really basic thing
we can simply differentiate this equation and then with the gradient solve it for x and y...
Ur Explaination is just awesome
thankyou so much, you are better than my teacher.
Dear sun flower, you are very welcome. Thank you so much for taking the time to leave this comment. I'm glad you liked the vid. Your feedback is always appreciated. Keep it up. Kind regards :)
thanks
thank u tecaher from morocoo (north of africa) i find this video really interesting and it really helped me a lot ♥
You are very welcome Mery from beautiful Morocco! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃 Keep smiling😊
Rabat
Thank you so much
You are very welcome Flash! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
@@PreMath aww... Your complement made my day
☺☺
We solve as math teachers cubics as well
You might look at some examples
ruclips.net/video/ircZ_M1m3I8/видео.html
Yes absolutely
this is so helpful, thank you sir! gonna pass my test now
Thank you so much your such a great teacher this really helped me keep on going!
You are very welcome Amy! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
Ram ram sitaram sitaram radhe radhe Krishna Krishna ji ki jai ♥ 🙏
0:46 ambulance!!!!
Lmao, you listening that sound 😁😁😁,instead of this
😂😂😂😂 I just couldn't ignore it either 😑
Are bhai bhai bhai 😂😂🥴
Wow! you are cool! Thanks for watching. Kind regards 😊
ruclips.net/video/CgcEEQIlpMk/видео.html
Thanks, I've been trying to solve the cubic for so long, and this video helped me a lot. Thanks again.
You are Awesome Sir !!
So nice of you dear! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃 Have a very happy and blessed New Year!
Thank you very much sir.
This is really helpful. Just keep up making this kinds of helpful videos.
Really easy to understand sir!
THANKS FOR YOUR HELP! ❤
LOVE FROM BANGALORE! 🗣
Thanxxx a lot 😊😊😊
It really helped me a lot
I shared the concept amongst my frnds & they were quite surprised that I am studying these days 😂😂😂😂
You're very welcome Arpita! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear 😃
It's a very good explanation, I understood very much
Glad to hear that Raghupathi! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
@@PreMath thank you
Thank you so much for this!! It was so helpful ^^
when the maths tutorials so good you start crying tears of joy
thank you so much sir you have tought me this solution....
You are very welcome dear! You are awesome 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃
thank you for saving my life
For x= -1 can we have same sum of alternate coefficient but opposite signs?
In case of cubic equation point of view, At first one of the root should be obtained by applying "hit & trail method "(Although it needs some simplification in some cases ), Then other roots may come out by deviding the first root (suppose the first root is 7, then you have to devide the given equation by x-7), then move on (personal opinion )
Thanks for the video, it is really very helpful.
You are very welcome Devdatt! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
1
Thank you for this video on solving Cubic Equations.
For sure time is delayed in in certain intervals, but given consistent and smooth paths, time moves in polynomial steps
My saviour.... thanks sir
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Very useful video and succinct tutorial. Thank you for this, cheers!
wtf gabs gamers dont do math
Very very very helpful..greal work..👍👍👊👊👊
I love the Rational Roots Theorem
Thank you so much Kevin for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and all the best 😃
Sir thank you very much to give a deeper idea
Most welcome, dear
Thanks! And please make a video on trigonometric identities.
You are very welcome! I've already made few videos on trig. Please search videos in my channel. If you want me to make videos on specific questions, please send it on my email: math@mycollege.org
Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and all the best 😃
Its always the indians making good food and good tutorials
Thanks so much this was incredibly helpful, so clear and straightforward!
You are very welcome Kailen! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
Thank you so much sir l am yours big fan sir from now.
You are very welcome! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
Thanks for making it even more confusing
I think the method explained is rather a trial-and-error approach and the following method will be more logical:
Let us consider the LHS of the equation as y and as x approaches to plus infinity, y also approaches to plus infinity; similarly, when x approaches to negative infinity, y also approaches to negative infinity.
What does this mean? This means y is a continues function sloping in the NE-SW direction.
Meantime, x = 0, y = 6 and x = 1, y = -7 which means that there will be a real root between 0 and 1. As y is sloping in the NE-SW direction, we can deduce that there has to be 3 real distinct roots to y. When x = -1, y = 18;
This clearly indicates that the 3 real roots to function y namely α, β and γ (say α
sire, would you consider making a video? a transcript is difficult to follow at once, hence a video such as khanacademy's or this style would be much appreciated. this method may be "easier" however i'm unable to read it/remember it in this format.
thanks.
Thanks for giving such easy and simple way to solve this! The way that taught from book which is LONG DIVISION are too complicated tho
You are very welcome! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and all the best 😃
This video really helpful Sir! Thanks a lot
Glad to hear that!
Thanks for your feedback! Cheers!
You are awesome, Keziah. Keep it up 👍
Love and prayers from the USA! 😀
Stay blessed 😀
It was awesome. It helped me a lot.
✌✌
Thank you so much Harsh ji for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and all the best😃
2x^3+x^2-13x+6=0
On observation, x=2 satisfies this equation
(x-2)=0 is a factor of 2x^3+x^2-13x+6=0
(2x^3+x^2-13x+6)/(x-2)=(2x^2+5x-3)=0 using synthetic division.
In 2x^2+5x-3 b^2>4ac therefore 2x^3+x^2-13x+6 has three real roots.
(x-2)(2x^2+5x-3)=0
x= -3 is a solution by observation
(x+3)=0 is a factor of (2x^2+5x-3)=0
(2x^2+5x-3)/(x+3)=(2x-1)=0 using synthetic division.
(2x-1)=0 is a factor of 2x^3+x^2-13x+6=0
Therefore,(2x^3+x^2-13x+6)=(x-2)(x+3)(2x-1)=0
Hence x=2,x= -3 and x=1/2 are the three real roots of 2x^3+x^2-13x+6=0
Thanks for the puzzle PreMath.
Worked so far! But what do I do if my coefficients are fractions?
In that case, remove fractions first by find the LCD (LCM).
Thanks Andrew for asking.
I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃
bro you are a god amongst men. you should be recognized amongst the math world #fsal
You are so generous with your comments my friend. Take care dear and all the best 😃
Thank you 😊 sir, it helped me a lot .Now I know the best way to solve these type of questions
Thank you so much for sharing this 🙏🏼I wish you get more and more subscribers ♥️
So nice of you dear!
Take care dear and stay blessed😃 Stay connected!
The check by comparing the sum of the roots against -B/A is going to come in handy! Thx!!
Quick Question: Does this answer check work when there are 1 real root and 2 complex roots?
Solve equation 2x^3+x^2-13x+6=0
Solve:
2x^3+x^2-13x+6
=2x^3-12x^2+24x-16+13x^2-37x+22
=2(x-2)^3+(13x-11)(x-2)
=(x-2)[2(x-2)^2+(13x-11)]
=(x-2)[2x^2-8x+8+13x-11]
=(x-2)[2x^2+5x-3]
=(x-2)[(x+3)(2x-1)]
=(x-2)(x+3)(2x-1)=0
So
x-2=0
x+3=0
2x-1=0
So
x1=2
x2=-3
x3=1/2
Verify:x1=2 or x2=-3 or x3=1/2 are all the root of the original equation
解方程2x ^ 3 + x ^ 2-13x + 6 = 0
解答：
2x ^ 3 + x ^ 2-13x + 6
= 2x ^ 3-12x ^ 2 + 24x-16 + 13x ^ 2-37x + 22
= 2（x-2）^ 3 +（13x-11）（x-2）
=（x-2）[2（x-2）^ 2 +（13x-11）]
=（x-2）[2x ^ 2-8x + 8 + 13x-11]
=（x-2）[2x ^ 2 + 5x-3]
=（x-2）[（x + 3）（2x-1）]
=（x-2）（x + 3）（2x-1）= 0
所以
x-2 = 0
x + 3 = 0
2x-1 = 0
所以
x1 = 2
x2 = -3
x3 = 1/2
验证：x1 = 2或x2 = -3或x3 = 1/2都是原始方程式的根
AN - 09PF - Harold M Brathwaite SS (2482): Because the complex solution shows the students, they would like to learn the easy synthetic division.
That was awsome thank you
You are very welcome dear! I'm sure you are a brilliant and bright student 👍 I'm glad you liked it! Please keep sharing my channel with your family and friends. Take care dear and all the best😃
@@PreMath Your command is my wish i would share your videos as much as possible ❤
@@nr6728 Thanks dear. You are awesome. Stay blessed 😃
This is helpful...it has really helped me
I miss 5th grade when I thought a+b=c
Lmao
Take care dear and all the best😃
These things were taught to me in the ‘elementary differential equations’ course. I forgot them because I took that course a long a while. You refreshed it to me and you taught me something new which our teacher in the past didn’t, which is the checking methods whether the answer is x=+-1 or our set of solutions of the equation is true. This would’ve changed my grade into better if I had the chance to see it when I was taking the course. But anyways, Thanks a lot.
Edit: It turned out actually you uploaded this video after I finished the course after I checked the time it was uploaded.
Hi! Is there an easier way to find the solutions, since it might take a lot of time during exams to solve all the options. But anyways great video! You helped me a lot
Explain that easier way
@@butterfly99899 that's what I am asking
@@sainandhana8828 JUST USE ANY SCIENTIFIC CALCULATOR
This is very important to me best work
omg thank you for this example only one i could find with everything i needed to studuy
Thank u for the two tricks...😄loved the video🤓
You're very welcome! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep supporting my channel. Kind regards :)
Thanks it was helpful
Thanks Bir Amrit Singh for the feedback. Please share my channel with friends as well. Kind regards :)
Thank You Sir for cubic equation concept
Glad I wasn't stuck with someone like him,....
This is such a good method. Thank u so much😊
What if roots are irrational
You are very welcome Safwan! Thank you so much for taking the time to leave this comment. I'm glad you liked it! Your feedback is always appreciated. Please keep sharing my channel with your family and friends. Take care dear and stay safe😃
Nice....but it's a time taking procedure
It's really very very helpful..thank you
He was even slower then sloth 🤣🤣😂😂🤣🤣
Can I ask about the graphic tablet and the application which you use
0.011x³+2.355x²-729.167=0
Plz solve this
THANK YOU SO MUCHHH!!! I FINALLY UNDERSTAND!!♥♥♥♥♥♥
can I have a solution of this equation from the same solution-:
z^3-5z^2+7z+21=0
thank u!
Popular Power thnx bro
but I need full solution from that method
Its your school homework ?😂😂
@@leaveitblank2625 bro this thing is not present at school level.
@@jayjain4341 oh?well it's not too hard to solve anyway or you can use online solving website if you want some complex solution 😁 .
@@leaveitblank2625 I did it....that's why I came to this video but can't find its answer by this method that's why I asked!
This is just the way I did it (taking hints from highest power, constant term and Vieta) before seeing the video solution ...
2x³+x²-13x+6=0
Looking at the equation.
Based on the 2x³ term, 2x-1 might be a solution (plug in x=1/2 - it is).
Based on the constant term x+3 might be a factor (plug in x=-3 - it is).
Vietas rule/formula says sum of solutions = -b/a
-1/2 = 1/2 -3 + r (r is the third root)
r=2
verfiy ... (2x-1)(x+3)(x-2)=2x³+x²-13x+6
In this case the guesswork was fine - the above two were the only guesses I tried.
It is not always so. For example I might have guessed a more complicated (2x+3) as a factor.
Thanks sir
Dear Parveen Kachura , you are very welcome. Thank you so much for taking the time to leave this comment. I'm glad you liked the vid. Your feedback is always appreciated. Keep it up. Kind regards :)
Hey guys there is a really good explanation of the cubic and quartic formula on the channel mathloger also explains why quintic equations can’t be solved with radicals using Galo is theory
08:00 I didn't get the next factorization process
Nevermind i got it
I'm glad you got it!
Muhammed, I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃
Have a very happy and blessed New Year!
@@PreMath
Thank you sir you too
Sir you are a life saver!!
My pleasure dear
You are awesome 👍
Take care dear and stay blessed😃 Love and prayers from the USA!