Hi all, there are some corrections regarding the best line. In my video (34:13) there is one point below and four points above the line. It is actually unbalanced. The line needs to be adjusted so that the number of point differences above and below the line can't be more than one. And the distance between the line to the point can't be more than 0.5cm. Please take note. TQ
@@wani_siroj Hi Shazwani, the scale must be 1 unit: multiple 1, 2, 5, 10... In this experiment 0.1 or 0.2, it depends on your reading, scale of axis X and Y can be different. The size of graph you draw must be at least half a page of the graph paper.
@@wani_siroj Hi, do you mean 0.215 (between 0.21-0.22)? Should be no problem for 0.000, 0.005. It is not accurate to plot 0.001, 0.008.... Hope you get what I mean.☺️🙏
@@MrPehKH ouhh understood means if i want to plot the point 0.342 then i should round off to 0.34 to get accurate plotted point right sir.. Tqvm sir for helping🥺
@@pavalaambigai1070 Wow👏👏 Thanks for your comment! It is an encouragement for me to continue contribute more teaching video 😘😘 Very happy to hear you can do well in your paper 3. Paper 1 & 2 revision will start this Sunday until March. Come and join me and AYU physics teams 🤗😊💕
Hi, thank you for your video, I just have a small question At 31:14 , shouldnt the x-axis be "sin i", since x-axis is the manipulated variable? Why do we put the sin i in the y-axis? Thanks sir ;)
Hi KM, we plot based on the question. The question in my video asked to plot sin i against sin r. So that the gradient = refractive index, n. If question ask you to plot sin i against sin r and the gradient = 1/n.
Thanks sir, this came out. However for the graph part it was plot r against i, so the gradient was 0.6 something. They also asked "What would happen to the gradient of the 'r vs i' if a diamond block was used instead. The answer should be reduced right? since r will be reduced in denser medium
Hi KM, you are right. The gradient decreases as r decrease (move towards normal). The higher the refractive index, the slower the speed of light, the light move towards normal, r decreases.
@@nameremixx9311 Hi, the graph should be slightly curve from origin. However, the marker will follow the results of your teacher. And 2 marks for graph only... 😁
Hi, better to draw at beginning so that you can place your semicircle at the same position. Or you can just mark the initial position of semi circle... the most importance need to show the angle of incidence and refraction
Hi Kendric, NO... Have you gone through my live video? Dp of Primary data need refer to sensitivity of apparatus. Example: smallest division of protractor 1 degree so no d.p needed; smallest division of metre rule 0.1cm, so 1d.p.... calculation data can remain in 2, 3 or 4 d.p. Make d.p for all data that are consistent.
Hello sir, I'm quite bit confused with the triangle part. Are we not supposed to draw the line at the last coordinate? How did u get 0.6,0.83? Thank you ❤️
Hi Azzam, no problem for you to draw until you last coordinate. Sometimes, best line not meet the last point. So, need at least draw you triangle with 4 x 5 unit. So, my end point for the triangle is at 0.6, 0.83. Hope you understand. TQ
Hi sir, how to know if they want us to write the procedure for determining the refractive index or the critical angle? Can see in activity 6.3 where the same apparatus and materials are provided.
Hi Jole, both experiment using the same apparatus. To determine critical angle, light rays are directed to the curve edge. Refractive index can get from formula n = 1/sin c. However, refractive index normally we determine i and r. So the light beam directed to the flat edge. Pls see my live teknik menjawab to get more info. Link: ruclips.net/user/livedFSAv6pEXaI?feature=share
@@jole3212 Hi Jole, yes. As optical density increases, n increases. this can be discussed with this formula n = 1/sin c. Example diamond has higher n, smaller c, so that total internal reflection occurs easily in diamond. And make diamond shiny
HI slurpidubb, I think you are refer to textbook activity 6.3, Pg 242. This is the experiment to determine critical angle and total internal reflection. If you want to get a refractive index, the light ray is directed to the flat edge which is opposite Activity 6.3. Pls refer to my live video which I did the comparison between these two experiments. Link: ruclips.net/user/livedFSAv6pEXaI?feature=share
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Hi all, there are some corrections regarding the best line. In my video (34:13) there is one point below and four points above the line. It is actually unbalanced. The line needs to be adjusted so that the number of point differences above and below the line can't be more than one. And the distance between the line to the point can't be more than 0.5cm. Please take note. TQ
Sir for graph i can use any scale right?.. N if i use scale 0.1 for x acxis then should it be the same for y axis?
@@wani_siroj Hi Shazwani, the scale must be 1 unit: multiple 1, 2, 5, 10... In this experiment 0.1 or 0.2, it depends on your reading, scale of axis X and Y can be different. The size of graph you draw must be at least half a page of the graph paper.
btw sir is it okay if i don't round off the points? like take 0.225 i plot in between 0.21 n 0.22 bcz if not round off i get the best fit line
@@wani_siroj Hi, do you mean 0.215 (between 0.21-0.22)? Should be no problem for 0.000, 0.005. It is not accurate to plot 0.001, 0.008.... Hope you get what I mean.☺️🙏
@@MrPehKH ouhh understood means if i want to plot the point 0.342 then i should round off to 0.34 to get accurate plotted point right sir.. Tqvm sir for helping🥺
Thanks teacher,this video makes me more confident for amali tomorrow~
Hi Carmen, thank you for your comment. Good luck with your exam!
thank you, teacher. wish me luck for SPM 2022
Hi Putri, welcome 🤗 Good luck to your SPM🙏👍
👍
Thanks Teacher!!!
@VelocityFeat, Welcome 😄
tq teacher!! this is very useful
Hi Yeeqing, TQ for your comment
😍😍
Thank you very much sir , found this very useful and im confident for my amali tomorrow 👍😁
Hi Jeevan, great to hear that. Good luck 💕👍
thanks tcr i hope this video will get me full mark for amali tomorrow
Hi welcome. Just answering technique, not ramalan ya.
thank you teacher, this video helped a lot 😊
Hi Shamita, thanks for your comment. Welcome 😁
thank you sir!
Hi Syasya, welcome 🤗
Thank you so much Mr Peh ~
Hi Felix, welcome 😇
This helps me a lot tqvm👍🏻👍🏻👍🏻
Hi Alya, welcome 🤗 good luck to your exam 👍
this is very very useful video, thank you so much Cikgu Peh.
Hi Pavala, welcome and good luck to you exam 👍💖🤗
@@MrPehKH sir, i did well the physics amali today because of sir's video. without sir's video, i would have struggled. thank you so much sir.
@@pavalaambigai1070 Wow👏👏 Thanks for your comment! It is an encouragement for me to continue contribute more teaching video 😘😘 Very happy to hear you can do well in your paper 3. Paper 1 & 2 revision will start this Sunday until March. Come and join me and AYU physics teams 🤗😊💕
Tq sir
Hi Alif, welcome 🤗
Hi, thank you for your video,
I just have a small question
At 31:14 , shouldnt the x-axis be "sin i", since x-axis is the manipulated variable? Why do we put the sin i in the y-axis?
Thanks sir ;)
Hi KM, we plot based on the question. The question in my video asked to plot sin i against sin r. So that the gradient = refractive index, n. If question ask you to plot sin i against sin r and the gradient = 1/n.
@@MrPehKH Oh i see, thanks sir for swift reply 🙏
@@DK26KM Welcome and good luck to you!😁🥰
Thanks sir, this came out. However for the graph part it was plot r against i, so the gradient was 0.6 something. They also asked "What would happen to the gradient of the 'r vs i' if a diamond block was used instead. The answer should be reduced right? since r will be reduced in denser medium
Hi KM, you are right. The gradient decreases as r decrease (move towards normal). The higher the refractive index, the slower the speed of light, the light move towards normal, r decreases.
@@MrPehKH sir so will the graph be curve or straight a?
@@nameremixx9311 Hi, the graph should be slightly curve from origin. However, the marker will follow the results of your teacher. And 2 marks for graph only... 😁
@@MrPehKH I see , thanks sir
@@MrPehKH Hi sir if my teacher does a straight line, will the students get marks if they also do a straight line?
teacher, after drawing the refractive angle. Is the half circle glass block need to draw?
urgent. please reply. thank you teacher
23:55
Hi, better to draw at beginning so that you can place your semicircle at the same position. Or you can just mark the initial position of semi circle... the most importance need to show the angle of incidence and refraction
@@Hubbymusic , hope I not too late 😄
Hello sir. Can I use 2 decimal point to tabulate the data for every data?
Hi Kendric, NO... Have you gone through my live video? Dp of Primary data need refer to sensitivity of apparatus. Example: smallest division of protractor 1 degree so no d.p needed; smallest division of metre rule 0.1cm, so 1d.p.... calculation data can remain in 2, 3 or 4 d.p. Make d.p for all data that are consistent.
Okay thank you
Hello sir, I'm quite bit confused with the triangle part. Are we not supposed to draw the line at the last coordinate? How did u get 0.6,0.83? Thank you ❤️
Hi Azzam, no problem for you to draw until you last coordinate. Sometimes, best line not meet the last point. So, need at least draw you triangle with 4 x 5 unit. So, my end point for the triangle is at 0.6, 0.83. Hope you understand. TQ
Hello sir , can I ask will mark be deducted if I forget to write 0° when label the normal line on the diagram ?
Hi, if you label the line as normal line should be no problem 😊
@@MrPehKH thank you Mr Peh 🙏
@@haoheanchan1763 Welcome 🤗
Hi sir, how to know if they want us to write the procedure for determining the refractive index or the critical angle? Can see in activity 6.3 where the same apparatus and materials are provided.
Hi Jole, both experiment using the same apparatus. To determine critical angle, light rays are directed to the curve edge. Refractive index can get from formula n = 1/sin c. However, refractive index normally we determine i and r. So the light beam directed to the flat edge. Pls see my live teknik menjawab to get more info. Link: ruclips.net/user/livedFSAv6pEXaI?feature=share
@@MrPehKH Ok sir thanks but I would like to know one more thing.... if the optical density increases then the critical angle will decrease right?
@@jole3212 Hi Jole, yes. As optical density increases, n increases. this can be discussed with this formula n = 1/sin c. Example diamond has higher n, smaller c, so that total internal reflection occurs easily in diamond. And make diamond shiny
@@MrPehKH Thanks for answering my question sir, i'll do my best for amali tmr 😊
@@jole3212 Welcome 🤗 Good luck to your exam 👍💖
sir can we shine the light ray from the curve surface? its shown in the text book like that
HI slurpidubb, I think you are refer to textbook activity 6.3, Pg 242. This is the experiment to determine critical angle and total internal reflection. If you want to get a refractive index, the light ray is directed to the flat edge which is opposite Activity 6.3. Pls refer to my live video which I did the comparison between these two experiments. Link: ruclips.net/user/livedFSAv6pEXaI?feature=share
@@MrPehKH thank you sir, tomorrow i have to do the experiment for physics, hopefully its the same experiment as in the video, wish us luck sirr!
@@slurpidubb818 the important know the answering technique and reduced mistake you make, like tabulation, plotting graph.... Good luck to your exam 😘👍
what is time taken for this paper 3?
Hi Zheng Jie. It is 45 min including 5 min checking apparatus.
Teacher if I forgot to tick the check list will they deduct any marks ?
This should be no problem. No worry 😀
@@MrPehKH okay teacher thank you
teacher the table use pen or pencil ya ?
I think pen probably, but pencil also can.
Both can, but advice use pen. Not easily lost 😜