Ma'am I am also a teacher but your teaching style is unique than other ,you are the best teacher in the world,I am very lucky to watch your video.. thank you so much ma,am
Mam in the topic enthalpy of formation and enthalpy of combustion problem in question no 2 can't we use the formula product-reactant if we use the formula the answer will be 1 ?
You're teaching methods are so simple and easily understandable ma'am 😍 You have no idea how helpful your videos are ❤️💯💯 Thank you so much ma'am You would be the first teacher I recommend to people finding chemistry tough 😍
Thankyou mam..such a awesome explanation. When this topic taught in my class I had a doubt 🤔 but now it is very clear mam.😄🙏🙏🙏🙏🙏 Mam your way of teaching shows how honest u r to share the knowledge... Mam ur just looking like my sister
Komali Mam= best mentor of chemistry 👍👍👍 Mam I didn't know what this concept is and how to calculate it but as I am watching urr videos I am getting all the concepts of chemistry 👍💯💯🆙 Thank u mam 🙏🙏🙏👍👍
in case of bond enthalpy and enthalpy of combustion we need to take reactants - products......but in almost all other cases (eg. entropy ,enthalpy of formation,etc..)its products-reactants itself.
But mam for the last qus they are asking enthalpy of formation so we have to take product - reactant then the equation - X1-(6X2 + 3X3) ....correct me if I'm wrong 🙇
That is when enthalpy of (formation of products) and (reactants) are given and you are to find the enthalpy of formation for the (reaction) but in the problem you are given with enthalpy of combustion of each reactant and product so you need to take reactant-products
Mam ur videos are soo much helpfull to me. Very very tnks for videos. By seeing other videos I use to get head ache. After watching ur videos. Easily I can understand everything mam. Tq soo much
In last ncert ques if we solve we could not get that ans... Plzz replyy mee mam.. I think x1 value should be -3267 instead of 3267 so that ans. 48.51 can come.. Session is really helpfull...👍👍
Mam your way of teaching is superb ...but I just want to recommend one thing that is to clarify the doubt of students in comment section..I know it's may difficult with respect to time ...but still whenever u make another video .u should clarify previous videos students doubt...If this will is not possible..then try to make doubt session separately on the basis of comment section. Thanku.
Tq so much ......... with full filled heart i wish u all successful and happiness in ur life mam.... i am very happy ....i used to struggle to solve that last model problems but now u made it easy....thank you so much mam 😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘............
Miss In the last question..it says the heat is liberated from benzene combustion....the sign convention says that heat lost is -ve...Why aren't we putting the signs thn??
The standard enthalpy changes of formation of carbon dioxide and water are -394 kj/mol and -286 kj/mole respectively if the standard enthalpy change of combustion of propyne is -1938kj/mol . what is its standard enthalpy of change of formation? if some one knows how to solve it then kindly tell me ....i tried to solve this ques by making equations but one thing that is confusing me is that for carbon dioxide and water heat of formation is given and for propyne heat of combustion is given .....and in the end ques is about to find standard enthalpy of change in formation ?
I think in second question... Sign should be positive as u said in previous video.... Delta h formation is negative times delta h combustion.... Mam please respond to this doubt
I never seen a teacher like you (it means your teaching is excellent)
PW KO BHUL GAYE KYA
Komali mam is better than pw
@@priyanshuhazra6353😂then why you came here da deii
In last problem, combustion of Benzene is given as 3267 kj of energy is released.So,we have to assume it as -3267 indirectly.See, carefully 🙂
Thank bro
Yes since its an exothermic rxn
Ma'am I am also a teacher but your teaching style is unique than other ,you are the best teacher in the world,I am very lucky to watch your video.. thank you so much ma,am
Mam, no words to say... It was just amazing lecture....may god bless you for ur work for us...luv u ... From KERALA
MAM....Lots of love from kashmir.you are my inspiration..may God bless you !!!
This channel's my confident booster 💪👍
Mam,
3267.0 kj heat is liberated
That means we should take as -3267.0
Excellent teaching mam, useful for students preparing for jee
Heat of formation ias for 1 mole product...
And heat of combustion is for 1 mole reactant ..
Thank you so much for this ❤️🙏🏻😁
Thanks mam mera 2 years mein first time concept clear hua about thermodynamics thanks a lot mam we need teachers like u love u mam
You are the single teacher handled all the topic in chemistry
Mam in the topic enthalpy of formation and enthalpy of combustion problem in question no 2 can't we use the formula product-reactant if we use the formula the answer will be 1 ?
thank u soo much ma'am. Ur simple way of teaching helps a lot 🙏
Thank you so much madam...
U had completely vanished my fear on physical chemistry madam
Not vanish she comforted my confidence on physical chemistry 🤭
You're teaching methods are so simple and easily understandable ma'am 😍
You have no idea how helpful your videos are ❤️💯💯
Thank you so much ma'am
You would be the first teacher I recommend to people finding chemistry tough 😍
Less time , more explanation . No time pass and at last thanks a lot mam.
Thankyou mam..such a awesome explanation. When this topic taught in my class I had a doubt 🤔 but now it is very clear mam.😄🙏🙏🙏🙏🙏 Mam your way of teaching shows how honest u r to share the knowledge... Mam ur just looking like my sister
Thank you so much for your kind words😊.. I'm Happy to listen this. Sure I will help as many students as possible..👍
Madam please make video on dry cell & lead accumulator🙏🙏🙏🙏🙏
@@KomaliMam Mam please explain how to remember IUPAC structures Easily For I.P.E 1st year
Yes mam me too
i love the way she teaches..
Your classes are very useful to us mam.....
I luvvvvvvvvvvvvv ur teching mam...kindly put tricks video for organic chemistry too mam...😊😊😊❤
Maam ur videos are short sweet...... excellent.... useful..🌞🌞🌞🌞🌞🌞
Komali Mam= best mentor of chemistry 👍👍👍
Mam I didn't know what this concept is and how to calculate it but as I am watching urr videos I am getting all the concepts of chemistry 👍💯💯🆙
Thank u mam 🙏🙏🙏👍👍
Lots of love from Himachal Pradesh mam . 😊😊😊 Your explanation is too good . Thank you mam
Bt when we have to find enthalpy of formation, we take enthalpy of product -enthalpy of reaction;but u have taken oppositevely.how?mam, plzzz reply.
I too have same doubt at 10:30
prev video mam told for enthalphy of combustion reactants - products should be taken..
in case of bond enthalpy and enthalpy of combustion we need to take reactants - products......but in almost all other cases (eg. entropy ,enthalpy of formation,etc..)its products-reactants itself.
@@megha4566 but in numerical we have to find enthalpy of formation not combustion
But u said that Hp-Hr(11:35)
Thank you so much Ma'am.. Your way of explaining and teaching is so understandable.. 😭👍👍
Mam after listening to u r class I felt very easy to solve the problems tqq sooo much
Tnxxx for spending ur valuable time for us🙏🙏🙏🙏🙏🙏🙏awesome explanation mam👌👌👌👌💕💕💕
But mam for the last qus they are asking enthalpy of formation so we have to take product - reactant then the equation - X1-(6X2 + 3X3)
....correct me if I'm wrong 🙇
sss you are crct
That is when enthalpy of (formation of products) and (reactants) are given and you are to find the enthalpy of formation for the (reaction) but in the problem you are given with enthalpy of combustion of each reactant and product so you need to take reactant-products
Mam ur videos are soo much helpfull to me. Very very tnks for videos. By seeing other videos I use to get head ache. After watching ur videos. Easily I can understand everything mam. Tq soo much
Ur classes are extremely super, 😋😇😊 thanks a lot mam for all the classes▬▬▬▬▬▬►🍀 especially for equilibrium chapter.
Hi
Thank you so much mam .. Ur tricks helped a lot 😊😊
In last ncert ques if we solve we could not get that ans... Plzz replyy mee mam.. I think x1 value should be -3267 instead of 3267 so that ans. 48.51 can come..
Session is really helpfull...👍👍
Exactly! U are absolutely right bro!!! Even I noticed the same thing.
Mam plzz reply
Bro in the question itself it is given HEAT IS LIBERATED. So we have to take -3267 KJ not + 3267 KJ. Hope you get it 🙂
Thank you so much for clearing my big dout
@@abhiiilakshmanan6293 👍👍👍👍👍🔝🔝🔝🔝👏👏👏👏👏☺tnkkuuu
mam u teach awesome....we are highly blessed to have you in youtube
Mam your explanation is very useful for us mam ,pranam
I am so weak in this part.. But now I am soo good in this.. Thank you so much
Me also now great
Thanku so much mam for the video👍👍
Thank you Ma'am.
#Mam....thnku so mch..😍😍
Really u are doing great job..💕💕
And ur tricks really helping us alot ..
Keep doing mam 😘😘
Thank you. Study well 👍
@@KomaliMam my plzrr😇😇
Mam make some videos on acidity and basicity of carbocations and carbanions and Benzene attached EWG and ERG pls
Thanks Mam to Provide Knowledge for success in life
Thank yo so much !!
For supporting us by making video!
This video help to understand!!
Tq 🥰
Mam your way of teaching is superb ...but I just want to recommend one thing that is to clarify the doubt of students in comment section..I know it's may difficult with respect to time ...but still whenever u make another video .u should clarify previous videos students doubt...If this will is not possible..then try to make doubt session separately on the basis of comment section.
Thanku.
No words to express ur teaching methods..thanku soo much mam..excellent teaching, easily understandable👌
superb explanation mam iam really satisfied after listening to ur lecture thnx a lot mam
Mam please make some video on solution topic...... it's request mam please....thank you this video is amazing😊😍
Thank you ma'am for vanishing my fear for T.D great explanation
So nice teacher. Lots of love and blessings from pakistan🥰
I think In the last qus value of X 1 should be -3267 kj, because only then it will become +3267 and 3267-3218.49=48.51
Yes ,as in combustion heat releases that's why x1 is negative
u have given so Easy and Useful tricks.. thank you.
Tq so much ......... with full filled heart i wish u all successful and happiness in ur life mam.... i am very happy ....i used to struggle to solve that last model problems but now u made it easy....thank you so much mam 😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘😘............
Thank you mam .I'm really blessed
Mam you are a gem❤️❤️❤️❤️❤️
Mam...bundle of thanks for detail explanation
A heartful thanks to you Ma'am!!💖💖🙏
So nice teacher. Lots of love and blessings from land of God , HIMACHAL PRADESH. 🥰
Superb ,superb and superb
fell in love with ur tricks
Tq mam I feel that theromchemisry is Hard but once when Isee ur vedio I feel it very Easy mam tq so much for ur vedios Mam🙏
I have little bit confusion in combustion and formation.....u r teaching owsome....mam
mam this is only videos in u tube which am always subscribing and giving like
yes mam, we love your videos,
we gonna make solutions PHATA -PHATT
Mam your class is very interesting
I had got a clear idea about this topic
Thankyou very much mam👍🏻
Chemistry best teacher in u tube
Keep always On.Thanks again.
Mam,very helpful but it would be helpful if u make lectures on enthalpy of phase transition, atomisation, hydration,bond dissociation
Maam pls do chem equilibrium pls pls🙏🏻🙏🏻it’ll be of great help if you do it by next monday
awesome explanation and tricks maam
In 4th question but u have told enthalpy of formation =enthalpy of products _ reactants
Amazing ma'am.... tricks to find the enthalpy of formation......is osm😍😍😚 u r great ma'am 😘
mind blowing mam, great explanation
Your teaching is really very good mam
Tell me Hybridasation topics mam
Thank you Mam
Another life savior?? God bless!@!!
Thankyou so much mam for helping us .. first i was really afraid of chemistry but mam you made me fall for this subject ..thankyou so much mam☺️
You are really excellent physical chemistry teacher mam.
Thanks.....👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌👌
Tqqq Mam, can you explain once iupac structures easily for I.P.E Ist year
Superb teaching mam👏
Mam H formation is products - reactants in last sum
Answer will not come by doing this
mam last problem from ncert problem6.8 answer not coming the same as given in the book
Thanks a lot mam...i wish i could find u sooner..i am watching this 1 day before JEE
Superb mam hatts off to u💞
You are an amazing teacher ❤️❤️✔️
Miss
In the last question..it says the heat is liberated from benzene combustion....the sign convention says that heat lost is -ve...Why aren't we putting the signs thn??
The standard enthalpy changes of formation of carbon dioxide and water are -394 kj/mol and -286 kj/mole respectively if the standard enthalpy change of combustion of propyne is -1938kj/mol . what is its standard enthalpy of change of formation?
if some one knows how to solve it then kindly tell me ....i tried to solve this ques by making equations but one thing that is confusing me is that for carbon dioxide and water heat of formation is given and for propyne heat of combustion is given .....and in the end ques is about to find standard enthalpy of change in formation ?
Maam u r super duper mind-blowing teacher 🤩🤩🤩🤩🤩😍
Just keep on teaching , my great teacher
Mam your tricks help me a lot thanks
It's very helpful, thank you so much
Thumbs up !!! Thanks a lot mam
But anyhow ur way of teaching and tricks very well mam
👍👍👍👍it's really good trick
Mam u r teaching is awesome ,I am ur new subscriber💞💞💞 lots of love for ur teaching
In some case.....reactant minus product will come ...when.....
Thank youuuuuuu mam🥰🥰🥰😍😍
I think in second question... Sign should be positive as u said in previous video.... Delta h formation is negative times delta h combustion.... Mam please respond to this doubt
Thanks you mam you are great . your ways are amazing 🙏🙏
you now becomes an angel for me