Enthalpy of Formation Reaction & Heat of Combustion, Enthalpy Change Problems Chemistry

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  • Опубликовано: 23 дек 2024

Комментарии • 256

  • @TheOrganicChemistryTutor
    @TheOrganicChemistryTutor  11 месяцев назад +3

    Thermochemistry - Free Formula Sheet: bit.ly/3TP4U4u
    Final Exams and Video Playlists: www.video-tutor.net/
    Chemistry 1 Final Exam Review: ruclips.net/video/5yw1YH7YA7c/видео.html

  • @zacharyh5419
    @zacharyh5419 5 лет назад +272

    I was stuck for hours on combining equations of formation to make a regular equation and the first 10 seconds of your video enlightened me. God bless you

  • @charlene.w.6124
    @charlene.w.6124 4 года назад +150

    When you have to learn Chemistry else where because you're under lock down and your teacher won't answer your emails ....
    btw. you just taught me something is less than 20 mins, which i've been trying to understand for the past 6 days so thanks

  • @aishahasan686
    @aishahasan686 4 года назад +600

    This man has been carrying my grades from high school into college lolol

  • @hollysu1
    @hollysu1 6 лет назад +36

    I cannot thank you enough for your videos!!! I went and bought some chemistry books but they hardly give any practice problems! You make it much easier and approach problems from different angles, thank you!!!!

  • @awaisahmed5489
    @awaisahmed5489 3 года назад +637

    Best luck all of you for exam tomorrow 🤣🤣

  • @afaceonthewater
    @afaceonthewater 3 года назад +35

    No one teaches this as simply as you do. Thank you

  • @FarrOutt1
    @FarrOutt1 Год назад +26

    I stopped listening during Chemistry lessons cause I literally don't understand my teacher's teaching..I just can't wait to come home and listen to your explanation on this topic...Thank you...I'm now the highest scorer in Term 1 ..Just scored (98/100)...Everyone was shocked..I'm just sad that I discovered your channel late...I'm now in my last year of high school...Should have started watching you from Junior level 😢😢....

  • @robertsterenchak8431
    @robertsterenchak8431 6 лет назад +102

    Thank god this video exists....

    • @degraj418
      @degraj418 4 года назад +2

      Thank him...but then he IS god

    • @datboi1861
      @datboi1861 4 года назад +2

      @@degraj418 Woah chill

  • @AkinOla-bi4ob
    @AkinOla-bi4ob Год назад +7

    It's a great pleasure meeting a wonderful teacher make difficult topic more clearer. I now understand better now.
    Put it up and God will bless you

  • @GSU_Panther_Nation
    @GSU_Panther_Nation Год назад +7

    Thank you. You are a blessing when it comes to straight to the point lectures. In fact, better than Khan Academy, and teaches way better than my chemistry professor. Just have to search the textbook for a certain topic and then search it on RUclips

  • @basketballmentality5407
    @basketballmentality5407 5 лет назад +79

    I learn here more than in my class

  • @caitygart
    @caitygart 6 лет назад +19

    Thank you so much! All of your videos have been a huge help for my first year of pharmacy school. Cheers!

  • @georgesadler7830
    @georgesadler7830 7 месяцев назад +1

    Professor Organic Chemistry Tutor, thank you for a step by step explanation of How to Calculate the Enthalpy Change of a reaction using Enthalpy of Formations in AP/General Chemistry. The problem selection for this material are excellent. Every problem in this video also reviews the concept of balancing Chemical Equations in Modern Chemistry. This is an error free video/lecture on RUclips TV with the Organic Chemistry Tutor.

  • @helpontheway7856
    @helpontheway7856 6 лет назад +8

    So glad I waited for you to graduate before beginning this journey. Much love bro. South Florida love

  • @RambunctiousVA
    @RambunctiousVA 5 лет назад +159

    woah I didn't know a 1/2 coefficient was allowed

    • @feitan8033
      @feitan8033 5 лет назад +23

      The coefficient of the product has to be 1 unless stated otherwise, so a 1/2 is required for the reactants

    • @feitan8033
      @feitan8033 5 лет назад +1

      @Megan choo To form water you need one oxygen and 2 hydrogen atoms

    • @yabombo8145
      @yabombo8145 3 года назад +1

      Do you like black people?

    • @Abcsefghijklmnopqrstuvwxy
      @Abcsefghijklmnopqrstuvwxy 3 года назад +2

      The reason being is that the atoms of oxygen always exist in pairs; that’s why there’s a subscript of 2 in front of O. All diatomic elements are this way (H2, N2, F2, etc). If diatomic elements are always in pairs, how do we get just one atom of it? You would have to multiply the subscript 2 with something to give you one. The only way you would get one atom is by multiplying it by 1/2. Does this make sense? The 1/2 doesn’t mean half of one atom; it is half of 2 which we know is 1. It is another way of writing one atom of Oxygen in this equation.

    • @someoneelse361
      @someoneelse361 3 года назад

      @@yabombo8145 what does this have to do with anything?

  • @niche5006
    @niche5006 6 лет назад +37

    The enthalpy changes are measured kJ instead of kJ/mol since you multiply everything by moles. Love all your videos btw.

  • @vicv5828
    @vicv5828 3 года назад +5

    Better than my chemistry professor by a mile

  • @77eeq
    @77eeq Год назад +1

    Thank you so much ur carrying my grades from 9th grade to 11th grade thank youu so much

  • @nicolasaq523
    @nicolasaq523 2 года назад +1

    Organic Chemistry Tutor The GOAT

  • @Mejustme74
    @Mejustme74 6 месяцев назад

    3:31 for making this more understandable we can say whenever 1mole compound is form then enthalpy of reaction becomes eq to enthalpy of formation and when 2 or 3 etc moles of compounds are form then we have to divide the moles from enthalpy of reaction to get enthalpy of formation.

  • @rafimonir5112
    @rafimonir5112 5 лет назад +2

    THIS VIDEO IS GOLD 🥺🥺

  • @Jessicaah1
    @Jessicaah1 5 лет назад +12

    Great video, I'm wondering though why you don't use reactants minus products in the combustion reaction of c2h5oh, since it's a combustion reaction that includes oxygen. I've learned that combustion reactions are always exothermic, so in this case it brings a negative sign which means exothermic, so I'm good with that, but HOW do I know when to use products minus reactants or reactants minus products? Do I just switch signs if I get a positive value when I know it's a combustion reaction? Little confused here. Thankful for answers.

    • @aadarsha1487
      @aadarsha1487 4 года назад

      ikr shouldve dlne Reactants - Products in that one its the rule isn't it

    • @sasmitpandey4980
      @sasmitpandey4980 3 года назад +1

      Is there a balanced synthesis equation for ethanol, or does ethanol only form through combustion?

    • @sasmitpandey4980
      @sasmitpandey4980 3 года назад +1

      Never mind, I found it.

  • @laithahssan8253
    @laithahssan8253 3 года назад +2

    1:31 you have to put graphite because its the main form of carbon (solid) and thanks alot great video

  • @hussnainshakeel2372
    @hussnainshakeel2372 5 лет назад +155

    who's studying for finals with me 🥴

    • @davidgn40
      @davidgn40 5 лет назад +1

      Lmao right here

    • @andrewhill1570
      @andrewhill1570 5 лет назад +1

      Right here 🥴

    • @hussnainshakeel2372
      @hussnainshakeel2372 5 лет назад

      Good luck to both of y’all

    • @davidgn40
      @davidgn40 5 лет назад +3

      @@hussnainshakeel2372 had mine. This video saved me on the Enthalpy questions haha. Thanks. Hope your finals go/went well too.

    • @sansamman4619
      @sansamman4619 4 года назад +3

      I am studying for the finals that I will have one year from now xd, this Thermochemistry stuff is one hell of a challenge I am studying on a text book, I also have a few other "note book" things that should help with the text book, I have 50 practice problems, I have like 30 tabs opened, I will watch the mit open course ware lectures on thermochemistry and then I will be done. I don't know why I told you this, but after writing it down I feel a little better :')

  • @abrahamande1508
    @abrahamande1508 4 года назад +1

    this guy is a gem

  • @CuriousAndCuriouser1865
    @CuriousAndCuriouser1865 2 месяца назад +1

    9:19 why is the result in kJ per mol? It looks like it should be for the entire reaction.

  • @georgia5026
    @georgia5026 3 года назад +1

    That does it. Imma start building a shrine for this guy.

  • @SZombo-wt5ds
    @SZombo-wt5ds 5 лет назад +1

    Your tutorials have saved me once again, thank you

  • @minsungkim6792
    @minsungkim6792 5 лет назад +3

    Thank you for this! Not many textbooks explain this concept properly.

  • @islamwasel2023
    @islamwasel2023 5 лет назад +4

    Please strongly explain to me what is the relationship that connects the heat of combustion with the heat of the formation

  • @herminioserguei5540
    @herminioserguei5540 5 лет назад +3

    You should be my professor!

  • @ronncarlfaminialan7525
    @ronncarlfaminialan7525 6 лет назад +2

    We have an exam in thermo chemistry today. thank you for making this video. Wish me luck!

    • @milindbordia
      @milindbordia 6 лет назад

      Ronn Carl Faminialan how’d u go?

    • @AksamRafiz
      @AksamRafiz 5 лет назад +2

      @@milindbordia he probably died

  • @rosyskysong8590
    @rosyskysong8590 4 года назад +1

    Could you explain why dH(rxn) is -1396kJ PER MOL at play time 9:25. I thought dH(rxn) is -1396kJ for 4mol-NH3 and 7mol-O2.

    • @cam.r.7052
      @cam.r.7052 3 года назад

      For anyone else who wonders, I believe he made a mistake writing /mol and it should just be kJ. If you follow the units of each number on your head, the moles cancel.

  • @Joe_Joe1203
    @Joe_Joe1203 Год назад

    Around 9:30
    I have a similar question where butane is burned to produce CO2 and H2O. My professor insists that the value for liquid water is to be used in the formula instead of the water vapor one. What I don't understand is why does the value of water vapor not apply to this situation. I don't remember cooking on the butane gas stove with liquid water coming out of it.
    Any explanation that can convince me?

  • @moatlhodibagayi-vk5gt
    @moatlhodibagayi-vk5gt Год назад

    You are the best man🙏king

  • @Swetha-ii
    @Swetha-ii 4 года назад

    A PRODUCTIVE VIDEO....KUDOS TO THE TEAM

  • @lorenzdequina2306
    @lorenzdequina2306 4 года назад +1

    Thanks alot bro, it make's easy to understand thermochem

  • @aymanwhite5902
    @aymanwhite5902 2 года назад +2

    Absolutely Brilliant 👏 👌 Thank you so much 😊

  • @LilJollyJoker
    @LilJollyJoker Год назад +1

    Thank you so much for this!

  • @karroten
    @karroten 5 лет назад +1

    Another great video. Thank you!

  • @myax4500
    @myax4500 4 года назад +1

    Thank youuuu this is so helpful

  • @liamnotlast4571
    @liamnotlast4571 Год назад +1

    Why am I watching this? It's 2 minutes to midnight and I don't even go to school anymore!

  • @titusmwape2938
    @titusmwape2938 2 года назад

    Well explain and easy to understand

  • @MohammedHimedah
    @MohammedHimedah 8 месяцев назад

    Thank you very much man you're AMAZING

    • @bumxrr
      @bumxrr 8 месяцев назад

      welcome

  • @karaborose1940
    @karaborose1940 4 года назад

    You simply the best

  • @tommywagner6692
    @tommywagner6692 2 года назад +1

    He's the best

  • @saeedmohamed7008
    @saeedmohamed7008 5 лет назад +1

    Thank u so much good job keep going.

  • @hayin2041
    @hayin2041 8 месяцев назад

    May I ask how is it possible if we undergo combustion raction while still staying at standard condition (1 atm, 298 K)?

  • @fezii9043
    @fezii9043 3 года назад +3

    What about calculating the enthalpy change of formation if given the enthalpy change of combustion?

    • @hectorokereke9268
      @hectorokereke9268 Год назад

      Enthalpy change of combustion is enthalpy change of reaction
      And to solve for that is
      ∆Hproducts - ∆H reactants
      you can use algebra and finish up

    • @fezii9043
      @fezii9043 Год назад

      @@hectorokereke9268 thank you

  • @koysensei4424
    @koysensei4424 2 года назад +2

    How do i know if the product is gas liquid or solid?

  • @sasmitpandey4980
    @sasmitpandey4980 3 года назад +1

    What is the balanced synthesis equation for ethanol?

  • @degraj418
    @degraj418 4 года назад +1

    Thank you for such a great video :)

  • @amrithabhat5019
    @amrithabhat5019 4 года назад

    you are the best dude!

  • @amogh_veena
    @amogh_veena 4 года назад

    Thanks you soo much brooo made my life easier

  • @namballalakshmanarao3831
    @namballalakshmanarao3831 6 лет назад +1

    thanku sir.....awesome lecturing

  • @zettagbayani9227
    @zettagbayani9227 2 года назад

    Thankyou so much for the awesome videos!

  • @jenm1
    @jenm1 3 года назад

    You explain things so well. Are you a TA or prof or something?

  • @akazozo99
    @akazozo99 2 года назад

    Thank you so much sr.You save me from failing the exam.😞

  • @janieli
    @janieli 4 года назад

    thank you. thank you. god bless you.

  • @andyoohhh2061
    @andyoohhh2061 5 месяцев назад

    Why wouldn't your units "mole" cancel out when solving for the heat of reaction? I think it should.

  • @oluwakemiadelana7803
    @oluwakemiadelana7803 5 лет назад

    Beautiful video. Nice job

  • @옌닝-u9i
    @옌닝-u9i 8 месяцев назад

    2:01 Anyone know why there is a 2 after O? Why can't he just write O so that he does not have to put 1/2 in front

    • @darciebradley
      @darciebradley 6 месяцев назад +1

      oxygen is a diatomic molecule, each molecule of oxygen comes as 2 oxygen atoms. it is naturally found this way so you still have to write it that way. its odd and confusing but thats science for you.

  • @shaisaroussi5324
    @shaisaroussi5324 3 года назад +1

    Question:
    Enthalpy of formation of H2O is 0 or -286? What do I miss?
    Thank you!

    • @noraax
      @noraax 3 года назад +2

      This is probably a bit late but it’s -286 because H2O (L) is not a “standard state”, it’s created from the formation of H2(g) and O2(g). So the H2 and O2 are 0 not the H2O

  • @averyredonnett
    @averyredonnett Месяц назад

    If I am not given the KJ/mol of the compound how and I supposed to figure out the heat formation of a compound?

  • @tane1038
    @tane1038 3 года назад

    Thank you. This is great!

  • @kuzon2132
    @kuzon2132 Год назад

    Learned a lot

  • @lild7me
    @lild7me 10 месяцев назад

    I wish I could know which grade this lesson is for, bc I am taking it in high school second grade in Saudi Arabia, and thanks man for this video ❤❤

  • @RYOoONY
    @RYOoONY 5 лет назад +1

    16:15 isn't supposed to be +552 not negative?

    • @aryangoel9638
      @aryangoel9638 5 лет назад

      -856 = -1408 - 6x right
      552 = -6x
      divide both sides by -6
      x = -92 kj/mol

  • @fynngreen00
    @fynngreen00 3 года назад +1

    I have an exam tomorrow and I still don’t understand Heat of Combustion 😀 wish me luck before I head to my certain doom!

  • @iconicahlly9377
    @iconicahlly9377 2 месяца назад

    you've saved me for tomorrow

  • @nshimyumukizaonesime2525
    @nshimyumukizaonesime2525 3 года назад

    Do you only put elements on the reactants side?

  • @aidenwolf3558
    @aidenwolf3558 4 года назад

    will the carbon dioxide and water formation enthalpy always be the same for problems or does it rely on the textbook

  • @adycerriteno3230
    @adycerriteno3230 2 года назад

    THANK YOU SO MUCH! CAN you make for heat of combustion please...

  • @aliyahmoreno4913
    @aliyahmoreno4913 Месяц назад

    my goat 🐐

  • @abhishekshyam3427
    @abhishekshyam3427 4 года назад +1

    ohh man you are awesome

  • @seeyameanie7607
    @seeyameanie7607 5 лет назад

    Not sure if this is a dumb question or not but if I have an equation with with no pure element that is in its standard state that equals 0, then how do I find the zero to make my math work? How do I determine what the pure element is if there is none already set up in my equation?

  • @chiamakanwazue6237
    @chiamakanwazue6237 4 года назад +6

    It’s second period and my test is fifth period, wish me luck 🥴

  • @rmsattar
    @rmsattar 4 месяца назад

    So,how do I figure out that sodium chloride is a liquid?

  • @qualityff3458
    @qualityff3458 2 года назад

    how can this piece of flesh can teach that amazing !!

  • @christopherloughran9029
    @christopherloughran9029 3 года назад

    What would happen if Aluminium had a value (hypothetically)? How would you isolate X ?

  • @tokytahmid4894
    @tokytahmid4894 4 года назад

    life saver !

  • @niladrichakraborty3795
    @niladrichakraborty3795 4 года назад

    Good one sir.

  • @Jackadman
    @Jackadman Год назад

    But how to I find enthalpy changes with enthalpy of combustions

  • @nevemaltus8275
    @nevemaltus8275 5 лет назад +11

    This guy sounds like Mark Whalberg

  • @nutritionbyelsa
    @nutritionbyelsa 2 года назад +2

    my goal is to fulfill my purpouse in life to the same degree you have fulfilled yours

  • @toxicgamer5723
    @toxicgamer5723 3 года назад +1

    Why is the enthalpy change of the reaction is equal to the enthalpy change of the copustion of 1 mole

  • @AdityaDalvi-ok8ys
    @AdityaDalvi-ok8ys 4 года назад

    thankyou so much.........

  • @Joshy1313
    @Joshy1313 6 лет назад +1

    Thank you.

  • @cheniquenatural4249
    @cheniquenatural4249 5 лет назад

    people how did he get -552 at 16:15. i tried divide the 856/-1406 but kept getting 0.60. can someone explain to me if i misunderstood pleeeeaaase

    • @betta4454
      @betta4454 5 лет назад

      Why would you divide? You have to substrate.
      -856= -1408-6x
      6x= -1408+856
      6x= -552
      x= -552/6 = -92 kJ/mol

  • @jiminpark3865
    @jiminpark3865 4 года назад

    This is so easy.

  • @neetuneetu373
    @neetuneetu373 3 года назад

    Sir how to find the value of reactants and products ??

  • @charleneo7805
    @charleneo7805 3 года назад

    Sorry, I thought that the unit for change in enthalpy is kJ, then kJ/mol for heat evolved.
    Please explain

    • @SB-qh6cr
      @SB-qh6cr 3 года назад

      I'm not sure if my answer is correct, but it makes sense to me(if you still dont understand why, just accept it as a given, lol thats what i do when i dont understand a concept).
      Per mol of the reaction, so depending on the amount of mols located in the reaction we get this amount of enthalpy. but yes, enthalpy is in kJ.

    • @charleneo7805
      @charleneo7805 3 года назад

      @@SB-qh6cr Thanks

    • @creativeink4407
      @creativeink4407 3 года назад

      he just forgot that once he multiplied by the coefficients the mold cancel out

  • @AmaKwakyewaa-y7r
    @AmaKwakyewaa-y7r 4 месяца назад

    Thanks 🎉

  • @garyyouth9354
    @garyyouth9354 3 года назад

    Shouldn't the final answer be in KJ not KJ/Mol since you multiplied the Molar Enthalpies by the moles in the equation?

  • @shanuruppi2051
    @shanuruppi2051 6 лет назад

    thanks for this video

  • @SnoozeDog
    @SnoozeDog 5 лет назад +1

    Why use O2 instead of O in #1?

    • @renaid
      @renaid 5 лет назад

      Oxygen is a diatomic element. In it's natural form, it's written O2. It's the same for hydrogen, nitrogen, fluorine, chlorine bromine, and iodine.

  • @Shahan-m1g
    @Shahan-m1g 3 года назад

    333K views. 3 years ago
    Nice ❤️

  • @Ashraf0304
    @Ashraf0304 3 года назад

    Its 8:36 and my test is at 9:20 wish me luck 🥲

  • @caldwellkaitlyn7
    @caldwellkaitlyn7 4 года назад

    where did the -856 kj/mol come from?