Enthalpy of Formation Reaction & Heat of Combustion, Enthalpy Change Problems Chemistry
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- Опубликовано: 22 сен 2017
- This chemistry video tutorial explains how to calculate the enthalpy change of a reaction using the enthalpy of formations found in the appendix section of your textbook. it also explains how to calculate the heat of combustion or enthalpy of combustion of a substance using the sum of products minus reactants formula. This video contains a few practice problems for you to work on.
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I was stuck for hours on combining equations of formation to make a regular equation and the first 10 seconds of your video enlightened me. God bless you
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woah I didn't know a 1/2 coefficient was allowed
The coefficient of the product has to be 1 unless stated otherwise, so a 1/2 is required for the reactants
@Megan choo To form water you need one oxygen and 2 hydrogen atoms
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The reason being is that the atoms of oxygen always exist in pairs; that’s why there’s a subscript of 2 in front of O. All diatomic elements are this way (H2, N2, F2, etc). If diatomic elements are always in pairs, how do we get just one atom of it? You would have to multiply the subscript 2 with something to give you one. The only way you would get one atom is by multiplying it by 1/2. Does this make sense? The 1/2 doesn’t mean half of one atom; it is half of 2 which we know is 1. It is another way of writing one atom of Oxygen in this equation.
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Professor Organic Chemistry Tutor, thank you for a step by step explanation of How to Calculate the Enthalpy Change of a reaction using Enthalpy of Formations in AP/General Chemistry. The problem selection for this material are excellent. Every problem in this video also reviews the concept of balancing Chemical Equations in Modern Chemistry. This is an error free video/lecture on RUclips TV with the Organic Chemistry Tutor.
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The enthalpy changes are measured kJ instead of kJ/mol since you multiply everything by moles. Love all your videos btw.
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@@hussnainshakeel2372 had mine. This video saved me on the Enthalpy questions haha. Thanks. Hope your finals go/went well too.
I am studying for the finals that I will have one year from now xd, this Thermochemistry stuff is one hell of a challenge I am studying on a text book, I also have a few other "note book" things that should help with the text book, I have 50 practice problems, I have like 30 tabs opened, I will watch the mit open course ware lectures on thermochemistry and then I will be done. I don't know why I told you this, but after writing it down I feel a little better :')
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1:31 you have to put graphite because its the main form of carbon (solid) and thanks alot great video
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THANK YOU SO MUCH! CAN you make for heat of combustion please...
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Please strongly explain to me what is the relationship that connects the heat of combustion with the heat of the formation
You explain things so well. Are you a TA or prof or something?
Great video, I'm wondering though why you don't use reactants minus products in the combustion reaction of c2h5oh, since it's a combustion reaction that includes oxygen. I've learned that combustion reactions are always exothermic, so in this case it brings a negative sign which means exothermic, so I'm good with that, but HOW do I know when to use products minus reactants or reactants minus products? Do I just switch signs if I get a positive value when I know it's a combustion reaction? Little confused here. Thankful for answers.
ikr shouldve dlne Reactants - Products in that one its the rule isn't it
Is there a balanced synthesis equation for ethanol, or does ethanol only form through combustion?
Never mind, I found it.
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will the carbon dioxide and water formation enthalpy always be the same for problems or does it rely on the textbook
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Not sure if this is a dumb question or not but if I have an equation with with no pure element that is in its standard state that equals 0, then how do I find the zero to make my math work? How do I determine what the pure element is if there is none already set up in my equation?
May I ask how is it possible if we undergo combustion raction while still staying at standard condition (1 atm, 298 K)?
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333K views. 3 years ago
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How do i know if the product is gas liquid or solid?
Do you only put elements on the reactants side?
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What would happen if Aluminium had a value (hypothetically)? How would you isolate X ?
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Could you explain why dH(rxn) is -1396kJ PER MOL at play time 9:25. I thought dH(rxn) is -1396kJ for 4mol-NH3 and 7mol-O2.
For anyone else who wonders, I believe he made a mistake writing /mol and it should just be kJ. If you follow the units of each number on your head, the moles cancel.
What about calculating the enthalpy change of formation if given the enthalpy change of combustion?
Enthalpy change of combustion is enthalpy change of reaction
And to solve for that is
∆Hproducts - ∆H reactants
you can use algebra and finish up
@@hectorokereke9268 thank you
Shouldn't the final answer be in KJ not KJ/Mol since you multiplied the Molar Enthalpies by the moles in the equation?
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Sir how to find the value of reactants and products ??
Around 9:30
I have a similar question where butane is burned to produce CO2 and H2O. My professor insists that the value for liquid water is to be used in the formula instead of the water vapor one. What I don't understand is why does the value of water vapor not apply to this situation. I don't remember cooking on the butane gas stove with liquid water coming out of it.
Any explanation that can convince me?
Yeah there is explanation
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What is the balanced synthesis equation for ethanol?
Never mind, I found it.
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Question:
Enthalpy of formation of H2O is 0 or -286? What do I miss?
Thank you!
This is probably a bit late but it’s -286 because H2O (L) is not a “standard state”, it’s created from the formation of H2(g) and O2(g). So the H2 and O2 are 0 not the H2O
Why is the enthalpy change of the reaction is equal to the enthalpy change of the copustion of 1 mole
How about o3
But how to I find enthalpy changes with enthalpy of combustions
16:15 isn't supposed to be +552 not negative?
-856 = -1408 - 6x right
552 = -6x
divide both sides by -6
x = -92 kj/mol