Nusselt be like- Ye toh gold hai(Kulkarni sir🙏). Me- i am waiting such conceptual videos for Mechanical Engineering. Plz be continue sir and Margdarshan dete rahe. Aapko live dekh ke din ki suruwat ho... Ye hamari khudkismti hai. This 20's era we have Kulkarni sir... This is our goodness🙏
Such a great teacher with so much potential who can inspire students to learn such complicated topic in a joyful way and can explain it with simple examples..you really are a great teacher sir..👏👏👏🙏🙏
Thank you so much sir, before seeing the video I struck with a problem of nusselt number....but now I'm very confident about it....Ur teaching boosts my interest 🤩 once again thank u so much number
I am glad that I have searched the topic of 'Nusselt Number' this morning! I have graduated in Mechanical Engineering and currently preparing for Job Exams. If I would be taught by him, I would certainly love the subject itself and wouldn't be so frustrated about it like now lol. Heartfelt respect for such amazing enthuasist teacher!
The Nusselt number for fully developed laminar flow in a pipe first increases and then decreases. O is a fixed number and remains constant. O depends on the existing Reynolds number and Prandtl number. O depends on pipe diameter.
Thanks for such a elaborate explanation sir, n Regardig EXAMPLE : comparing convection b/w 30-60 & 40-70 case.. Why you took more HT for 40 -70 case ( i.e. 42 ).
Sir by your logic the values of nusselt number in 1 case and third case should be same but In first case and third case when all the parameters are same but nusselt number is different it is 39 in first case and 42 in third.
Hello sir, If nusselt no. equals to 1 than why you said, there is only heat transfer through conduction and not through convection. Instead, mathematically shouldn't it be like Qconv. = Qcond. will it not be possible?
No, 1. Vertical walls have more efficiency in heat transfer as more & more fluid will come naturally (buoyantly with density difference without interfering with busy fluid particles while expanding & rising) so enhancement in nusselt number. 2. The same efficient picture will not be there in case of naturally cooling horizontal wall surfaces as we can only use upper exposed surface as compared to lower one which will not be economical. Here fluid will get sufficient energy to buoyed up only at bottom surface as compared to vertical one where there is long path for continuous energy to buoyed up. In horizontal case fluid will have limitation to naturally buoyed up to accelerate other fluid particle (bulks) flux as they will interfere again with newer ones which definitely will not be there in vertical case......
Nu = h*l/k find kf (conductivity of fluid for the temp you're considering, if it is a heat exchanger then find k for the fluid flowing in the HX at the average temp of inlet and outlet. Length will be any characteristic dimension, could be inner diameter, also could be equivalent diameter depending on the situation.
sir, in last example is it possible to calculate the nusselt number by the first two container then put the same nusselt number for the third and fourth container like, if we calculate by it nusselt number is 39/26 which can be equated to 42/x by doing it we got 28.coz all the properties are same so nusselt number is constant. please reply sir this is ur student Gaurav(delhi)
i cant believe this..how can a teacher deeply indulging with their subject..MY generation is lucky to have sir LIKE YOU
Pro tip: watch series at flixzone. Been using them for watching lots of of movies recently.
a trick: watch movies at Flixzone. Been using them for watching lots of of movies lately.
@Cesar Fernando Yup, I've been watching on flixzone} for months myself :)
i love this guy. i wish my prof was at least 1/4 as enthusiastic as him lol
Unbelievable teaching,god bless you sir
I learned fluid mechanics from him. he is the best teacher.
Finally found a men who enjoys his way of teaching , also clearing our doubts . Such an amazing person 😍
Nusselt be like- Ye toh gold hai(Kulkarni sir🙏). Me- i am waiting such conceptual videos for Mechanical Engineering. Plz be continue sir and Margdarshan dete rahe. Aapko live dekh ke din ki suruwat ho... Ye hamari khudkismti hai. This 20's era we have Kulkarni sir... This is our goodness🙏
Yaru samy ivan , salute sir💥💥💥💥💥💥💥💥💥💥💥💥
Sir nice explaination I was too much confused about nuselt no before your explanation now it is clear. Thanks 😊
Pakka explanation sir,
For conduction connection radiation
I never ever seen...
Khatarnak hai re baba...guru jee is at his best
Such a great teacher with so much potential who can inspire students to learn such complicated topic in a joyful way and can explain it with simple examples..you really are a great teacher sir..👏👏👏🙏🙏
Amazed by your energy.....a complicated topic simply explained...
Sir really ....U r so great teacher 🙏🙏Proud of u ❤️🙏❤️
Thank you so much sir, before seeing the video I struck with a problem of nusselt number....but now I'm very confident about it....Ur teaching boosts my interest 🤩 once again thank u so much number
Waah... 😍😍😍😍😍😍😍
I am glad that I have searched the topic of 'Nusselt Number' this morning!
I have graduated in Mechanical Engineering and currently preparing for Job Exams. If I would be taught by him, I would certainly love the subject itself and wouldn't be so frustrated about it like now lol.
Heartfelt respect for such amazing enthuasist teacher!
I love the way you react at 5:12 that was sooo good i will never forget that comparison :Dd
One of the best teacher 👌👌👌👌👌👌👌👌
U r so nice ... teaching wow ❤️❤️
nice to see you sir....i am your student.
The Nusselt number for fully developed laminar flow in a pipe
first increases and then decreases.
O is a fixed number and remains constant.
O depends on the existing Reynolds number and Prandtl number.
O depends on pipe diameter.
Very nice sir
beautifully explained...thank u sir
Sir can you please come up with Online coaching classes too on your website, so that even far off students can also acquire your teaching. Please sir.
What a video sir... hats off to you...
Thanks for such a elaborate explanation sir, n
Regardig EXAMPLE : comparing convection b/w 30-60 & 40-70 case.. Why you took more HT for 40 -70 case ( i.e. 42 ).
Your my god sir......
TOOOO GOOD SIRJI...EXCELLENT
Very good afternoon sir. I am your student. U thought me IES Made Easy. So nice to see u sir.
Tq so much sir
God of mechanical engineering sir 😍😍
oh my god XDXD
good one sir!
Thank you
Good
Excellent sir..thank u
Awesome 😊☺️😘🌺
11:55 😂😂😂
Sir by your logic the values of nusselt number in 1 case and third case should be same but In first case and third case when all the parameters are same but nusselt number is different it is 39 in first case and 42 in third.
Amazing sir thank you so much sir . . .
Please do more videos.. Your video is understandable
great..... thanks sir
Hello sir, If nusselt no. equals to 1 than why you said, there is only heat transfer through conduction and not through convection. Instead, mathematically shouldn't it be like Qconv. = Qcond. will it not be possible?
Sir is it same if the vertical walls are heated instead of horizontal one?
No,
1. Vertical walls have more efficiency in heat transfer as more & more fluid will come naturally (buoyantly with density difference without interfering with busy fluid particles while expanding & rising) so enhancement in nusselt number.
2. The same efficient picture will not be there in case of naturally cooling horizontal wall surfaces as we can only use upper exposed surface as compared to lower one which will not be economical. Here fluid will get sufficient energy to buoyed up only at bottom surface as compared to vertical one where there is long path for continuous energy to buoyed up. In horizontal case fluid will have limitation to naturally buoyed up to accelerate other fluid particle (bulks) flux as they will interfere again with newer ones which definitely will not be there in vertical case......
God of KAME and also for Mechanical Engineering
Sir tumhi online classes gheta ka..?
Sir. I need to find the value oh h (conv. Heat Transfer coef.) by the value of nusselt no. How can I proceed
Nu = h*l/k
find kf (conductivity of fluid for the temp you're considering, if it is a heat exchanger then find k for the fluid flowing in the HX at the average temp of inlet and outlet. Length will be any characteristic dimension, could be inner diameter, also could be equivalent diameter depending on the situation.
Sir what is h?
Thank you sir😊
Lovely
सर plz upload complete videos of any sub
That beneficial to all students
Love u sir
Mja aagya
Pls clear my doubt
Apply this nussel nu to simple split ac for designing purpose
Take hyd whether condition in may month any location
God
😌🙏🙏🙏
Then what is advection?
sir, in last example is it possible to calculate the nusselt number by the first two container then put the same nusselt number for the third and fourth container like, if we calculate by it nusselt number is 39/26 which can be equated to 42/x by doing it we got 28.coz all the properties are same so nusselt number is constant.
please reply sir this is ur student Gaurav(delhi)
I also done the same in first attempt.
God of HMT...love u sir
11:51 see if you make mistake
11:54 🤣🤣🤣🤣
14:44 for the correct short answer,
11:52 for the dismissed short answer, xD
5:10 😂😂😂
Don't say hL/k 11:49😀😀☺️☺️
very nice sir