The link for other useful videos: 1) Decoder in Digital Electronics: ruclips.net/video/a3wh7xV5PBU/видео.html 2) Multiplexer Explained ruclips.net/video/aQlF-9i3fAA/видео.html 3) Digital Electronics (Playlist): bit.ly/31gBwMa
You are doing god's work by making such great and understandable videos! May God Give you more and more success in Life and give you more popularity! You are helping us Engineering Students all over the world!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
At 4:48 you said , demux input 'I' is connected to decoder .There are two possibilities '1' and '0' .As you said if input is logic high (1) then it works well but if logic 0 means then the decider itself not works irrespective of the input given to decoder then how the input I is appear depending on the input combination given to decoder .Please clear this doubt Sir .
when the input I (Enable input ) is 0 then of course all the outputs will be 0. (please see at 5:33). But if the changing with the time (1 and 0 with the time) then you will get that input at the specific output pin. If you consider a static input which remains 0 then yes, all the outputs will appear to be logic '0' level. But in reality, the input to the logic circuit is continuously changes between 1 and 0. So, that output will appear at the specific pin depending on the value of A, B and C. I hope, it will clear your doubt.
Both are used for different purposes. One is used for decoding, another one is used for demultiplexing the inputs. The different names are based on their functionality.
hello sir, at 8:15 , instead of using a 1*2 demux , we can simply use enable of both 1*8 demux by connecting the E1 to inverted S3 and E2 directly to S3, as we did in mux designing. and sir one more doubt, like in logic implementation , if we want to implement a 4 bit logic using mux, we can use a mux with 2 , 3 , 4 select lines , all can implement the logic, so can we do the same in demux or decoder also or shall we need same number of select lines or input lines as the number of variable in the expression?
for your first claim. We will lose the ability to have a chosen input. We can never turn off the circuit because we have lost our "enable"/"input" input, so we can now never have it where all of them are 0. I know he did that with the decoder one but meh whatever
Yes, you can do so. But the thing is, after addition you will have two outputs. The sum and carry output. If you implement it using the multiplexer, then you can generate only one of them. To generate two outputs, you need one more multiplexer.
In this video only demultiplexer is covered. But one should also know that, how to use decoder as demultiplexer, as many commercially available ICs can be used as both decoder and demultiplexer. So, that aspect is also covered in the video.
The link for other useful videos:
1) Decoder in Digital Electronics:
ruclips.net/video/a3wh7xV5PBU/видео.html
2) Multiplexer Explained
ruclips.net/video/aQlF-9i3fAA/видео.html
3) Digital Electronics (Playlist):
bit.ly/31gBwMa
You are the only channel that completes a full topic in a single vdo covering all subtopics
You are doing god's work by making such great and understandable videos! May God Give you more and more success in Life and give you more popularity! You are helping us Engineering Students all over the world!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Exactly
English is not my mother language I feel a little difficulties but ur teaching way is just amazing thanks a lot sir
Thank you sir 🙏 ☺️ appreciate all your lectures from Nepal 🇳🇵 🙏 😊
Iam having my exams tomorrow and Iam seeing this video now Hope that I can attend all the questions from this video
brother 😇💜
Nice video and useful information. 👍
Need a full explained video on Data transmission through MUX And Demux where input data is given in ASCII code
At 4:48 you said , demux input 'I' is connected to decoder .There are two possibilities '1' and '0' .As you said if input is logic high (1) then it works well but if logic 0 means then the decider itself not works irrespective of the input given to decoder then how the input I is appear depending on the input combination given to decoder .Please clear this doubt Sir .
when the input I (Enable input ) is 0 then of course all the outputs will be 0. (please see at 5:33). But if the changing with the time (1 and 0 with the time) then you will get that input at the specific output pin. If you consider a static input which remains 0 then yes, all the outputs will appear to be logic '0' level. But in reality, the input to the logic circuit is continuously changes between 1 and 0. So, that output will appear at the specific pin depending on the value of A, B and C. I hope, it will clear your doubt.
@@ALLABOUTELECTRONICS Thank you for your reply Sir .Now it's clear .
A lot of thanks to you sir, 🙏🙏🙏😌
Thank You again and again :)
Please help me with this: Why two different terms than, Decoder and DeMux, when both are interchangeable?
Both are used for different purposes. One is used for decoding, another one is used for demultiplexing the inputs. The different names are based on their functionality.
@@ALLABOUTELECTRONICS Based on functionality, Ok it makes sense now :)
Rushal you are a star
Very very nice 👍
Super video
🖐 can we create the ' 1 to 8 demultiplexer ' circuit diagram using ' 1 to 4 demultiplexer ' and ' 1 to 2 demultiplexer '?
Yes, definitely. You require two 1 to 4 demultiplexer and one 1 to 2 multiplexer.
hello sir, at 8:15 , instead of using a 1*2 demux , we can simply use enable of both 1*8 demux by connecting the E1 to inverted S3 and E2 directly to S3, as we did in mux designing.
and sir one more doubt, like in logic implementation , if we want to implement a 4 bit logic using mux, we can use a mux with 2 , 3 , 4 select lines , all can implement the logic,
so can we do the same in demux or decoder also or shall we need same number of select lines or input lines as the number of variable in the expression?
for your first claim. We will lose the ability to have a chosen input. We can never turn off the circuit because we have lost our "enable"/"input" input, so we can now never have it where all of them are 0. I know he did that with the decoder one but meh whatever
Sir please can the multiplexer be used to add more than 3 bits addition
Yes, you can do so. But the thing is, after addition you will have two outputs. The sum and carry output. If you implement it using the multiplexer, then you can generate only one of them. To generate two outputs, you need one more multiplexer.
👌👌👌
👌🏻👌🏻
if you are teaching demultiplexer teach only demux otherwise evrything just mess up ....
In this video only demultiplexer is covered. But one should also know that, how to use decoder as demultiplexer, as many commercially available ICs can be used as both decoder and demultiplexer. So, that aspect is also covered in the video.
You are the only channel that completes a full topic in a single vdo covering all subtopics