My online class on behavioral research statistics did not explain this process nearly as well as this video does. Thank you so much for the help. This is a great resource and I will recommend this to be used by my classmates as well.
I would really really want to thank you from the bottom of my heart that your tutorial is really helpful, definitely the best thing ever I have found, very easy to understand the whole concept, better than my professor, I attended all his lectures but could never been better to see this clip for less than 15 minutes! Thanks! : )
I haven't even taking statistics yet I'm just trying to teach myself but your videos basically teches me everything and your so good with detail thanks man your realy helping me out!
very clearly!!! oh how clear it is? Punky! think to some teachers at my school just sit there and click click click the slides!!!! thanks a lot for your teaching sir!
Did anyone else notice he took the mean in 1.83 on z table, as .4664 but my table said 46.64. What's the difference you ask? two decimal places. How can I calculate the right answer if he's jumping around making conversions and not telling us why? If this is a blooper, let me know peeps. It's about at 10:25
very very helpful video but could you please explain to me how you calculate or see the critical value on the z-table. I didn't really understand the 0,45... and with a 5% confidence is the critical value still 1,645?if not, how do you calculate that?thaanks
Professor, Could you please comment: When finding the p-value, you stated 1.83 is ".4664"? I see the z-score at ".9664" on the table & if you do 1-.9664, the answer is 0.0336, just the same as when you used ".5-.4664=0.0336". Is there a reason you subtracted .5 initially from .9664 to use ".4664"? Thank you in advance.
+Rwanda Reyes Your z-table is different from the one he is using. His table calculates areas less between the 0 and z. Your table calculates areas below z.
+FrostPulse the sample is greater than 30, the standard deviation is just the square root of the variance. other words put variance at 9000 and it fulfilled all the conditions at using the Z, not the t-test. Besides, professor Kaplan is PROFESSOR KAPLAN enough to not make such child trick "errors" . Thanks!
My online class on behavioral research statistics did not explain this process nearly as well as this video does. Thank you so much for the help. This is a great resource and I will recommend this to be used by my classmates as well.
Mr. Kaplan, you are an exceptional teacher. I totally understand the process now. You ROCK :)!
Perfectly done and easy to understand. You made it so clear to me because you didn't over complicate it. Thank you so much.
I would really really want to thank you from the bottom of my heart that your tutorial is really helpful, definitely the best thing ever I have found, very easy to understand the whole concept, better than my professor, I attended all his lectures but could never been better to see this clip for less than 15 minutes! Thanks! : )
Excellent presentation.. you’re very organized which makes it easy to follow you through the process. Thanks..
I haven't even taking statistics yet I'm just trying to teach myself but your videos basically teches me everything and your so good with detail thanks man your realy helping me out!
Thankyou so much! you are the first person to explain this to me and it actually make sense!
very clearly!!! oh how clear it is? Punky! think to some teachers at my school just sit there and click click click the slides!!!! thanks a lot for your teaching sir!
sadly i'm seeing this video after i did my finals today :( and now i totally understand
You switched your labels for the null and alternate hypotheses. H-0 is the null, and H-1 is the alternate.
Just awesome sir... keep moving on uploading more videos.
Simple and straight to the point!
He is subtracting 1-0.9664 = 0,0336 ( the number you find in table A2 when you look up the test statistic 1.83)
Correction to below for P-value: where did .5 come from? shouldn't it be .05 - .4664??
At first I thought I was going crazy over how he got that damn p-value. THXS FOR CLEARING THAT UP!!!! :) :)
i think you're wrong..
the 0.5 is half the bell curve. because the whole curve equals 1.so from the mean (half the curve) is 1/2 of 1 or the 0.5 he mentioned .
But I still don't understand if that represented the middle then wouldnt that mean that hes finding a p-value between .5 to 1.83
For the X values: for -1.645 I calculated 44,998.4. And for the X value for 1.645, I got 45,001.6.
Did anyone else notice he took the mean in 1.83 on z table, as .4664 but my table said 46.64. What's the difference you ask? two decimal places. How can I calculate the right answer if he's jumping around making conversions and not telling us why? If this is a blooper, let me know peeps. It's about at 10:25
The table you're looking at is in percent form his is in decimal form so it's the same thing
very very helpful video but could you please explain to me how you calculate or see the critical value on the z-table. I didn't really understand the 0,45... and with a 5% confidence is the critical value still 1,645?if not, how do you calculate that?thaanks
It will give it 50%
Thanks for the video helping me a lot in 2019.
great work mate.
you solved my problem. your a champ sir
where did .5 come from??? Thought the rejection region for two-tailed test would be .025
+Karmen Davis-Young I know this is late but he got .5 because it is half of the total area/ probability of the graph
Professor,
Could you please comment:
When finding the p-value, you stated 1.83 is ".4664"? I see the z-score at ".9664" on the table & if you do 1-.9664, the answer is 0.0336, just the same as when you used ".5-.4664=0.0336". Is there a reason you subtracted .5 initially from .9664 to use ".4664"?
Thank you in advance.
+Rwanda Reyes
Your z-table is different from the one he is using.
His table calculates areas less between the 0 and z.
Your table calculates areas below z.
If you had a negative z score would you still go 0.05-the z score?
Thanks, great example
Z - value represents the area under the curve
how did you rearrange the equation to solve for x?
you are extremely good
Would you fail to reject because the p-value is less than the alpha?
Yeah I thought he was wrong too
sir ,what if i take [z]>1.645 and whatabout using the ppln sd,is it correct?
what graphs are you using? i don't understand how to use them, the graphs in my book have different numbers...
There charts and they should say table V and table VI
Thank you so much, this is a helpful video, appreciation
OMG completely understand after the video
I lost contact with reality at 10:25. What??????????????????
thanks. it is clear to me now
awesome clip
i am absolutely fuck, tomorrow is the midterm and i know nothing memtioned in this video.
Michael Stuhlbarg is that you?
teacher i come from thailand i want know chi-square distribution
for the p-value where did you get .05 from?
thaaaaaaaaaaaaaaaaaaaaaaaank you sooooo much ur wonderful thats the first time i understand this and ready for solving problems !!! :) :*
Thank you sir ❤
amazing stuff, good video
thank you sir..its help a lot..
Thank you a lot!
what are the o.5- o.4664 from where did u get them?
I found it helpful, thank you :)
thanks!
Thank you!!!
good one... thnx
Thanks, very helpful :)
it is not z value it is t value xbar-u/s/sqrt(n) ~t(n-1
damla seni seviyorum
Sir you should be using a t-test not a z-test because you have the S and not the sigma!
@ProfessorKaplan
+FrostPulse the sample is greater than 30, the standard deviation is just the square root of the variance. other words put variance at 9000 and it fulfilled all the conditions at using the Z, not the t-test. Besides, professor Kaplan is PROFESSOR KAPLAN enough to not make such child trick "errors" . Thanks!
Totally failed