it's more easy for me just multiply by 3 until you get to the 11 power result (177147) and then rest the 2 power result (9) 😅; but that's because my maths are extremely basic and can't understand well the method showed in this video.
don't undervalue yourself. your method is better. I would choose to multiply by 9 instead of 3 because 9x=10x-x and multiplication by 10 doesn't require anything. just add a 0 at the end. this means that, instead of two multiplications by 3, I only need a simple substraction. a bit faster and less prone to errors. your idea, as simple as it may be, is better than what's shown on the video.
if redundant was a video
less work to just do 3^11-3^2 = 3^2(3^9 - 1) = 9(27*27*27 - 1). Multiplying 27 3 times isn't very hard.
And more intuitive...
Or, you could, you know, solve 3¹¹ then subtract 9. Works too. Takes less than 9 minutes at least.
it's more easy for me just multiply by 3 until you get to the 11 power result (177147) and then rest the 2 power result (9) 😅; but that's because my maths are extremely basic and can't understand well the method showed in this video.
don't undervalue yourself. your method is better.
I would choose to multiply by 9 instead of 3 because 9x=10x-x and multiplication by 10 doesn't require anything. just add a 0 at the end.
this means that, instead of two multiplications by 3, I only need a simple substraction. a bit faster and less prone to errors.
your idea, as simple as it may be, is better than what's shown on the video.
{0+0 ➖} ^9=1^9 1^3^2 1^3^1 3^1 (x ➖ 3x+1).
And why do 90% students fail it?
Yea, even if they have to do it the long way (3^11-9), should still be correct. Maybe a tiny time limit? Maybe to much reliance on calculators?
@JaimeWarlock I lean towards a dirty clickbaiting OP
90% of zero students failed it.
If this was a real question, there'd be a source given.