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Some= 1 ,p=1 There Some =1, p=1 -b/a=1/1 => c/a =1/1, b/a =-1/1 Therefore a=1,b=-1,c=1 A(x)²+b(x)²+c (x)²+(-1)x+1 =(X)²-x+1 answer Ye asan tarika hai Aur sirf 2 marks ka hai 😎
X^2-4x+1 Like if your ans is also same Pray for me that I get 98% in 10th 😢 My father is an army officer He stays away from us for 6-7 months because of duty to serve our nation I want to make him feel Pride that his son is doing amazing in academics Plz pray for me
51:55 = x²-4x+1 Thank you so much sir ❤ aapki wajah se mujhe math achha lagne lga hai aap nhi hote to mai fail ho jati math me thanks a lot again sir ❤❤😊
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51:56
K(x2-4x+1)
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51:49
(vi). 4,1
Solution. We know that general equation of quadratic polynomial is:
x2 - (sum of roots x ) + (product of roots)
Hence
x2 - 4x +1
👍
Right bruda
Same
x²-4x+1
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51:49 -
(vi) 4, 1
We know that the general equation of a quadratic polynomial is:
x2 - (sum of roots) x + (product of roots)
x2 - 4x + 1
Yes..
Sum of zeroes and product of zeroes *
Ya..
@@parisharma689 hm bolo
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Class 10 attendance laga do jo bhi 10th me 99% lana chahta h i wish sabke aa jaye❤❤
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51:51
The answer to the last question (vi) from exercise 2.2 is x² - 4x + 1 :)
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Everything is understandable 🙂
23:27 : isme b ki value (-4) hai aur formula hai -b/a. To ye hoga -(-4) jo ki plus +4 ho jayega.
Nahi -4 he hoga kyuki ye ek formula hai jisme negative hona must hai
Ax- bx +c yeh formula hai bhai
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Some= 1 ,p=1
There
Some =1, p=1
-b/a=1/1 => c/a =1/1,
b/a =-1/1
Therefore
a=1,b=-1,c=1
A(x)²+b(x)²+c
(x)²+(-1)x+1
=(X)²-x+1 answer
Ye asan tarika hai
Aur sirf 2 marks ka hai 😎
51:54 answer = x^2 - 4x +1
a+B=4
aB=1
Quadratic polynomial is
K[x²-(sum of zeroes)x+product of zeroes]
K[x²-4x+1]
If K=1
then the quadratic polynomial is x²-4x+1 Answer
X^2-4x+1
Like if your ans is also same
Pray for me that I get 98% in 10th 😢
My father is an army officer
He stays away from us for 6-7 months because of duty to serve our nation
I want to make him feel Pride that his son is doing amazing in academics
Plz pray for me
Sir I am so thank to pw and ritik sir specially , today was my preboard result and I got 78/80 😢 ❤❤❤❤❤
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x2-4x+1 Ans last bale ka
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52:36 thank you soo much sir ❤❤❤❤❤
X^2 - 4x + 1 h.w
51:52
Solution
K[x²-(sum of zeros)+(product of zeros)
1 [ x² -4+1]
So
Ans x²-4+1
Me to bro
x^2-4+1 ans 51:52
X²-4x+1 hoga
51:47 H/W = x²-4x+1😊
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51:58
Answer is x^2 - 4x + 1
Shi h
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q-2,part-6,
sum=4 and product=1
k[x^2-{sum of zeroes}x+ product of zeroes]
k[x^2-{4}x+1]
k[x^2-4x+ 1]
let, k=1
x^2-4x+1
X square - 4 x + 1 answer of the last question
Thanks sir for explaining chapter 2 😊
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4,1
= k{x2 - 4x + 1 }
= x2 - 4x + 1
Ans 🎉🎉🎉
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Good sister
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51:55 = x²-4x+1
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4,1
Answer:- x²-4x+1
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x2-4x+1=0
Answer of Homework Question
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K(x²-4x+1) 51:55 😊
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( Let "K" = 1 )
therefore the polynomial is ( x^2 - 4x =1 ) Which having sum of zeroes is 4 and product of zeroes is 1
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51:49 Answer is x2-4x+1
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What we did at 17:37 I understood that, but my doubt is why are we not repeating at 24:40 ?
bx place is diff in first que
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52:03 Answer of last question is = x²-4x+1 is 💯 correct 💯....
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x²-4x+1 ans of homework 🙂🙂
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X2-4x+1 hw last question🎉
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HW question answer 51:55
quadratic polynomial = x^2 - 4x + 1
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51:51 ans. x2 - 4x + 1 will be the polynomial...😊😊
51:57 solution----- K[x²-4x+1] ....
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Answer is x2-4x+1
Wrong
It's x² -4x + 1
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Last question answer is x2-4x+1 52:41
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51:56 ANSWER WILL BE x2-4x+1 where 2 is the power of x.....
51:53
X²-4x+1
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