Exactly. My current teacher (in a related course that uses all this stuff but higher level) is pretty nice, but the stuff is just tough. And this stuff... I can sit there for 6 hours not knowing something going across all sorts of resources, then sit here and in 5 minutes learn a crap ton on these videos. I started watching this channel almost 2 years ago and am still dumbfounded by how well it works.
The fact that he solves the problem with us is what is so helpful to me. My professors use old solutions that sometimes have errors and they just say "this equals so and so" expecting me to know how they arrived at their answer. Dr. Hanson, thank you for TEACHING us your ways. I would be so lost without this channel.
you are saving me. in statics. i love you. you are so hilarious and helpful and you’re so good at breaking these things down to be understandable and manageable questions. i love your mantra that you say, when you talk about where it gets difficult, and you’ll say “but that’s okay, because i’m here with you!” you make these problems seem so not daunting and so much less intimidating. i wish every teacher was as incredible and funny and kind as you!
"let's just do a couple of joints, and we're gonna be there!" - That's priceless! :D I wish my lecturers had been able to explain how to find a zero force member as well as you have. Many thanks!
Learning statics is literally the only reason why I went to university, and here I am back to watching RUclips videos to learn its anyway! Subbed. This is so much more useful than mindlessly memorizing trigonometric identities and functions just so you can write a series of equations to prove that the sky is blue.
4:44 is actually crazy. He asked a question, looked at me to answer, and I answered "LB for starters!" He was like yea ok LB. What an incredible teacher to be able to read his students without even talking to them. insane
thank you for explaining the steps and showing how they apply properly. this theory will help me in my quiz. tho i like my professor as a person....he doesn't teach very clear....this helped a lot! Thank you so much!
Would have prevented myself from getting a quiz question wrong if I'd just watched this yesterday. smh xD Very helpful for the near future! Structural analysis feels like statics all over again but on steroids. thanks
Had the same query. Likely because its a symmetric truss and we have the roller on one side (where reaction would only by along y-axis), and there are no external forces in x direction. Therefore on the pinned connection, the reaction along the x-direction would be zero.
Can anyone confirm this alternative way of solving for KD and KJ: @12:20, we could instead rotate the axis so that x and y align with KD on the y-axis and KJ on the x-axis, and then solve from that?
If i calculate Moment in G, I have 10KN*8m + 20KN*6m + 10KN*4m - Ay*12m, where Ay=15KN. Although it makes sense to have both Ay and Gy be 20KN each, the formula gives a different result. What am I missing?
Why at the end you did not count the force in the Y direction going down that is equal to 20 KN and will make JD be 13.3 KN? Please let me know if it was just a little mistake or I am missing something.
Idk if you still need this but if we do the FBD at joint D and do the sum of the forces in the y direction it would be [DJ - 20 - 7.46sin63.4 - 7.46sin63.4 = 0] Therefore DJ = 33.341 It looks like you forgot to add the 20KN force
I don't know if you are still answering questions on here or not. But... I see you have 2 different supports, a hinge and a roller. The hinge has 2 reactions (x,y) and the roller only has 1 (y). So I assume the support is irrelevant?
@@dirtmoto2780 its all good bro, thats not even that bad. If you would of started studying sooner, like a week or even more instead of 2 hours before you would of got an A most likely, keep grinding bro!
I finally found out which members are zero force in my example, I struggle with finding them... Zero force members are simply forces that has no reaction to equate the joint to zero force in any direction.
Compression is when the force is acting towards the joint; He assumed the member to be in compression so it ended up being a positive value. Typically when you don't know which direction the force should go, you can assume Tension and then any negative values would indicate that the member is in compression.
He used to have this wooden truss system model or something. Anyone know which video he uses it in? or perhaps where to buy something like that? I'd like to have some models to play with so I don't have to imagine everythng in my head :-)
Because there are no applied forces that have an X component to them, so he found the Reaction at A in the X to also be zero (There's nothing to react to).
can someone solve for KJ and KD without using the system calculator thing he is talking about (manually). im trying to find ways but im hitting a roadblock. help
Just imagine the world with this type of teachers 🥺🥺❤️❤️
You don't know how good a teacher is until you lose'em
Like your's 🙂
Exactly.
My current teacher (in a related course that uses all this stuff but higher level) is pretty nice, but the stuff is just tough.
And this stuff... I can sit there for 6 hours not knowing something going across all sorts of resources, then sit here and in 5 minutes learn a crap ton on these videos.
I started watching this channel almost 2 years ago and am still dumbfounded by how well it works.
Too bad yours made you cook meth 💔
Had him as a professor, he was great!
school would have been easier
The fact that he solves the problem with us is what is so helpful to me. My professors use old solutions that sometimes have errors and they just say "this equals so and so" expecting me to know how they arrived at their answer. Dr. Hanson, thank you for TEACHING us your ways. I would be so lost without this channel.
you are saving me. in statics. i love you. you are so hilarious and helpful and you’re so good at breaking these things down to be understandable and manageable questions. i love your mantra that you say, when you talk about where it gets difficult, and you’ll say “but that’s okay, because i’m here with you!” you make these problems seem so not daunting and so much less intimidating. i wish every teacher was as incredible and funny and kind as you!
"let's just do a couple of joints, and we're gonna be there!" - That's priceless! :D I wish my lecturers had been able to explain how to find a zero force member as well as you have. Many thanks!
You're such an amazing teacher, sir. Wish I could meet you.... Thank you so much for the amazing lessons, you helped me a lot
DR. Hanson, thank you for solving a mammoth Trusses and Zero Force Member problem in mechanics. The explanation for this example is outstanding.
i love the way you simplify school,you make it easier....none gets bored with the way you teach
Learning statics is literally the only reason why I went to university, and here I am back to watching RUclips videos to learn its anyway! Subbed. This is so much more useful than mindlessly memorizing trigonometric identities and functions just so you can write a series of equations to prove that the sky is blue.
Studying for my PE, this is great.
I am a special inspector right now for geo tech firm, once I get my EIT, will I get a raise of 5$?
@@alfonsoperez1762 Nope, you just get a pat on the back and bragging rights
@@ethanboba5262 just more responsibilities lmao
I love this class because you actually teach us the tricks and that’s all i needed
Where you from
@@Forever-fun creep
I am mechanical engineering student this video has helped a lot.may God bless you Dr Hanson
I really enjoyed this this playlist , all the lessons were fun & engaging , thank you
You helped us a lot.Thank you professor Jeff Hanson
Love the optical illusion on your shirt, not dizzy at all lol
You make this topic so much easier for me ❤❤
4:44 is actually crazy. He asked a question, looked at me to answer, and I answered "LB for starters!" He was like yea ok LB. What an incredible teacher to be able to read his students without even talking to them. insane
Great video Jeff, I was so confused about zero force members and you did a great job explaining and solving the problem! Keep it up!
Oh now I agree the fact that to be de best is just being able to express clearly what u know and not just knowing😃.Salute sir💃💃💃
Such an excellent teacher!
Hi Jeff, thank you very much for the video. Well explained 🤟
we would all have been straight top of all our classes had we have this type of teacher
You're such a powerful tutor
woow, such a great tutor ever found, God bless you sir.Please how do I access your study materials
Thank you Dr Hanson you made my life easy. I wish you were in my college.
I used Jeff's videos while in my statics class, and here i am again studying for my FE. Still one of the best Professors on RUclips.
thank you for explaining the steps and showing how they apply properly. this theory will help me in my quiz. tho i like my professor as a person....he doesn't teach very clear....this helped a lot!
Thank you so much!
Legend!! Thanks for helping me get through undergrad and onward!
Thank you!
thank you professor , this vid was really helpful with visualizing zero force members i was struggling at ❤❤
Would have prevented myself from getting a quiz question wrong if I'd just watched this yesterday. smh
xD Very helpful for the near future! Structural analysis feels like statics all over again but on steroids.
thanks
You have helped me so much with these videos professor! Thank you so much!!! :)
I love the way u explain the problem
I have a very nice professor, however we have never gone over how to visually identify zero force members. This is amazing stuff.
Wonderful statics lessons!! really taking the time to explain the problems along with a good sense of humor :))
Why you were not my professor in school? your videos are the best!
The hero we needed
Thank you veryyyy much I'm from Algeria ❤️🇩🇿🇩🇿
How do I identify if EQUATION 1 is for KJ and EQUATION 2 is for KD, when using the system solver? Thanks.
insanely good statics man!
Thanks 😊 our teacher❤❤
Thank you sir for this lecture 13:10
Can you take sum of moments when solving by method of joints? Or can you only use sum of forces in the x-y direction at the joint in question?
this guy just rescued before the engineering statics quiz
You're a god tier teacher!
Why didn't we incorporate Ax when finding the sum of forces in Fx for AB?
i had the same question, but i doubt itll be sorted by the time i have my exam tomorrow, hah.
Had the same query. Likely because its a symmetric truss and we have the roller on one side (where reaction would only by along y-axis), and there are no external forces in x direction. Therefore on the pinned connection, the reaction along the x-direction would be zero.
Can anyone confirm this alternative way of solving for KD and KJ: @12:20, we could instead rotate the axis so that x and y align with KD on the y-axis and KJ on the x-axis, and then solve from that?
I think typically we can't do that cause KD and KJ aren’t perpendicular
I love your lectures Sir
Thankyou this was amazing help
Thank you sir. It helps.
Jeff, I literally love you
I'm so content with your videos..,🤝💙👍❤️🤟
thank you
this really helped me thank you!
Thank you so much, Professor, you are the best 💜💜💜
If i calculate Moment in G, I have 10KN*8m + 20KN*6m + 10KN*4m - Ay*12m, where Ay=15KN. Although it makes sense to have both Ay and Gy be 20KN each, the formula gives a different result. What am I missing?
i love thid class😍😍❤🧡❤❤
Thanks for this video ❤
I can't believe he actually solved this entire problem.
Thank you so much! OMG now I can solve my exercises easily
Why at the end you did not count the force in the Y direction going down that is equal to 20 KN and will make JD be 13.3 KN? Please let me know if it was just a little mistake or I am missing something.
Idk if you still need this but if we do the FBD at joint D and do the sum of the forces in the y direction it would be
[DJ - 20 - 7.46sin63.4 - 7.46sin63.4 = 0]
Therefore DJ = 33.341
It looks like you forgot to add the 20KN force
@@robertrobayo5744Thank You So Much Pro You Saved Me❤
Sir at point A why it only has vertical reaction and not horizontal(Ax) it is not roller support
Wow, 20mins for that scary truss!
It would've took me all the time of the exam😂😂😂
Increíble señor es un master d l. Carpintería no hay quien le pueda ganar
bro be my professor i love it
How do we know whether kj is acting inwards or outwards??
I don't know if you are still answering questions on here or not. But... I see you have 2 different supports, a hinge and a roller. The hinge has 2 reactions (x,y) and the roller only has 1 (y). So I assume the support is irrelevant?
There is no force on the x axis, so we know that the X for the pin would be = 0
Good question! I have no clue! I hope you figured this out though! And also chicken is very tasty.
Me about 10 hours before an exam:
maybe this truss thing is interesting
Lmao I got a statics exam in 2 hours and am totally banking on this guys lectures to carry me through it.
@@dirtmoto2780 Update? How was that exam?
@@sebastiancurry3714 not great got a 65
@@dirtmoto2780 its all good bro, thats not even that bad. If you would of started studying sooner, like a week or even more instead of 2 hours before you would of got an A most likely, keep grinding bro!
Yes sir! I really slacked during this summer semester, but I am ready to kick some ass in the fall!
What about Ax when calculating forces in joint A?
For KJ and IJ you have it = 23.57kN C, but then on the FBD for joint J the arrows are in T. Just a little confused.
hyee. sorry, but may i ask is there no reaction force (ax) at joint a ? why is that ?
Sir I have a doubt. KL and KJ are colinear and why they have different and opposite loads. Please.
good one
Sir love from Bangladesh
Can I get a PDF past questions for the mechanic mathematics..?
what happens when there's loading on the top?
this was so exciting
error at 15:01, it should be minus 0.447KD, not plus
Thank you so much, great review!
I finally found out which members are zero force in my example, I struggle with finding them...
Zero force members are simply forces that has no reaction to equate the joint to zero force in any direction.
Thank u Professor
May i ask sir, Why didnt you used joint D instead of J?
in the system eq i get KJ 22.37 and KD -14.14
you are the best sir!!!
excuse me sir Jeff how did you get the KJ and the KD i dont quite get it what you input in your calculator
They're simultaneous equations. Scientific calculators can solve them.
I hope I finally find my answer. I am confused I have read almost the whole day. Adult education is indeed hard.
How do we determine the direction of the forces please
God bless u
Very trussworthy info.
I bit confused on 17:12, so because it's negative it's compression?
Compression is when the force is acting towards the joint; He assumed the member to be in compression so it ended up being a positive value. Typically when you don't know which direction the force should go, you can assume Tension and then any negative values would indicate that the member is in compression.
He used to have this wooden truss system model or something. Anyone know which video he uses it in? or perhaps where to buy something like that? I'd like to have some models to play with so I don't have to imagine everythng in my head :-)
since joint A is a pin connection, shouldn't there be an Ax force?
Ax=0kN bc no forces are moving it in the x-axis
This was an amazing video, thank you, I wish my professor was as good at teaching as you are.
How did he solve for KJ and KD when both equations had 2 unknowns?
Simultaneous linear equations although u would've prolly known by now
How do you know the angles?🤔
If A is a pinned joint, why does it only have a reaction force in the vertical axis and not both horizontal and vertical axis
Because there are no applied forces that have an X component to them, so he found the Reaction at A in the X to also be zero (There's nothing to react to).
lifesaver 👍👍👍👍👍👍👍 . long live
5 star doctor
How to use calculator when finding KD and KJ value? Send helpppp
can someone solve for KJ and KD without using the system calculator thing he is talking about (manually). im trying to find ways but im hitting a roadblock. help
I See his calc for JD, but by analysis, why isnt it a ZFM?
Because KJ and JI have Y-components