Just wanted to update. I'm about halfway through the semester now. Currently have a 99 (highest score in the class). My professor is very pleased. Can't thank you enough for giving me a head start this semester. Really has helped me balance school, work, and life. Thanks Professor Hanson and Professor Zaurin!
All I can say is "WOW!" As a first-year engineering student, I found these truss problems extremely daunting but these tips, tricks and other videos helped so much! I actually feel more confident to write my test later today thanks to you Prof Hanson!!
Haha was confused with min: 6:36 until i listened carefully to his lil song - "If the force is in the Y then the distance is in the X". I did not know that. Makes Moment much more clear now!
These tips are very helpful in helping me go fast. Thank you. Particularly the bit about taking moments at a point just outside the chosen section. It came in very handy on a question I was solving.
i believe he's talking about what would be the matrix function on the ti-84. you need to press 2nd then x-inverse scroll to edit to fill out the matrix, then 2nd mode, to exit then 2nd x-inverse scroll to the middle find rref, short cut to there should be ALPHA then B, 2ND X-inverse again select in the NAMES list the matrix you entered then hit enter and it will solve your equation. if you are unfamiliar with matrix equations i suggest looking up videos on what they are. Its a function used extensively in Linear Algebra.
you use( A^-1)*(B) where A and B are matrices. Works exactly the same as the system solver on his calculator. You most definitely learned the matrix way in an algebra course
Great video. Learned a lot. at 10.47 a point is reached where 2 equations are formed that Jeff then solves using a programmable calculator. I would suggest solving using the simple method of 'simultaneous equations' :- If equation #2 is subtracted from equation #1 then you get only one unknown, which is Fe. This is then easily solved and results in Fe = 9.49. If this answer is then plugged into equation #1, or #2 you then get Be as '-12' and not '8.49'. Am I wrong?
They are simultaneous equations. Solving with calculator is a preference and may reduce errors for some. Subtracting equation 2 from equation 1 will give FE = -9.49 N. Plugging this value in either equation 1 or 2 will give BE = 8.49 N: Equation 1: BE = (- 3 - 0.949 (- 9.49)) / 0.707 ≈ 8.49 N Equation 2: BE = (9 + 0.316 (- 9.49)) / 0.707 ≈ 8.49 N
When doing the equilibrium equations, hoe come you do not have to include the non-cut members? For example at 6.36 which do you not have to include forces in the members ED and CD?
Sorry sir ,for sum of Fy at point E , should it not be "-6kN" instead of "-9" ? Also thank you for all the help and video content , we really appreciate it
I'd use a calculator with a system solver if it were allowed. I can't so I gotta stick with good old fashion lin. algebra and a simple scientific calculator
I have a Question regarding finding Moment at a point which is even not in your FBD , in the case u solved Force at joint E (FE) comes out 9.49KN ..But if wetake moment at that point which is not visible normally on our FBD means at joint B my ans for (FE) comes out to be 18.96 rather than 9.49....why is it so... i took the distance 3m as a moment arm for (FE) for both of its component ... I have exam after 2 days so kindly reply that what mistake i have made Thank uh for these useful videos 😍
When i put the 16.98 kN into the Fx=0 equation, my equilibrium equation became zero. But if i put the 8.49 as the answer, my equation didn't equal zero.
![I.N "HALLUCINATION" | [Stray Kids : SKZ-PLAYER]](http://i.ytimg.com/vi/n5B5q1Hwt_U/mqdefault.jpg)
Just wanted to update. I'm about halfway through the semester now. Currently have a 99 (highest score in the class). My professor is very pleased. Can't thank you enough for giving me a head start this semester. Really has helped me balance school, work, and life. Thanks Professor Hanson and Professor Zaurin!
lol zaurin from ucf?
Ricardo?
All I can say is "WOW!" As a first-year engineering student, I found these truss problems extremely daunting but these tips, tricks and other videos helped so much! I actually feel more confident to write my test later today thanks to you Prof Hanson!!
@@DaljeetSingh-yv7ch 💀💀
@@DaljeetSingh-yv7ch hello saar we like waamen saar
I gotta say it. You are a pretty fantastic teacher. Honestly one of the best I've seen. you are doing a great service here, thank you
Haha was confused with min: 6:36 until i listened carefully to his lil song - "If the force is in the Y then the distance is in the X". I did not know that. Makes Moment much more clear now!
Lol I love that you always make me laugh and learn something new at the same time.
Much love Jeff
i would die without jeff hanson, if i could have jeff for every engineering class i would in a heartbeat.
I like watching this type of video. It really feels as if you are in a real classroom. Appreciate it, Jeff!
dear engineer, doctor, You are joy of engineers! I am happy to join you.
my gosh i gotta say, u wont find someone other than prof hanson solving questions with such sense of humour!
Sir, you made everything sound easier than what I learned from my uni… Thank you!
he's the best engineering teacher out there I swear
Wish I could find this tutorial 4 years a go when I was doing my studies.. but it doesn't matter i still love this...statics
7:00 what about CD?
this guys an absolute legend
These tips are very helpful in helping me go fast. Thank you. Particularly the bit about taking moments at a point just outside the chosen section. It came in very handy on a question I was solving.
Wonderful Statics lessons!! really taking the time to explain the problems along with a good sense of humor :))
you are awesome sir! hoping to be as good as you! God bless!
Great Hints professor. Well explained.
How come in the sum of the forces in the x at 8:11, does he not include the force Fed in the equation
Professor Hanson, thank you once again for a massive example that outline Trusses, Methods of Sections, Truss Tips and Tricks. These examples are fun.
THANKS
rockstar thank you for the A on my exam!!! :)
What is the "system solver" you talk about using I have a Ti-84 and would like to know how to access this.
i believe he's talking about what would be the matrix function on the ti-84. you need to press 2nd then x-inverse scroll to edit to fill out the matrix, then 2nd mode, to exit then 2nd x-inverse scroll to the middle find rref, short cut to there should be ALPHA then B, 2ND X-inverse again select in the NAMES list the matrix you entered then hit enter and it will solve your equation. if you are unfamiliar with matrix equations i suggest looking up videos on what they are. Its a function used extensively in Linear Algebra.
Check out my videos on how to use your calculator!
you use( A^-1)*(B) where A and B are matrices. Works exactly the same as the system solver on his calculator. You most definitely learned the matrix way in an algebra course
@@1234jhanson i am unable to find it ...can u plz insert the link here
Thanks so much
I just learned truss as I am completing my quiz on truss. 30 min for a multi part truss problem, barely made it.
Great video. Learned a lot.
at 10.47 a point is reached where 2 equations are formed that Jeff then solves using a programmable calculator.
I would suggest solving using the simple method of 'simultaneous equations' :-
If equation #2 is subtracted from equation #1 then you get only one unknown, which is Fe.
This is then easily solved and results in Fe = 9.49.
If this answer is then plugged into equation #1, or #2 you then get Be as '-12' and not '8.49'.
Am I wrong?
They are simultaneous equations. Solving with calculator is a preference and may reduce errors for some. Subtracting equation 2 from equation 1 will give FE = -9.49 N. Plugging this value in either equation 1 or 2 will give BE = 8.49 N:
Equation 1: BE = (- 3 - 0.949 (- 9.49)) / 0.707 ≈ 8.49 N
Equation 2: BE = (9 + 0.316 (- 9.49)) / 0.707 ≈ 8.49 N
for BE I got -12/sin45 which is like 16.97...
Thank you once again!!
Thanks 👍
When doing the equilibrium equations, hoe come you do not have to include the non-cut members? For example at 6.36 which do you not have to include forces in the members ED and CD?
Because after you make the cut these forces become internal to the system. Therefore they are not considered when solving for each external force.
Sorry sir ,for sum of Fy at point E , should it not be "-6kN" instead of "-9" ? Also thank you for all the help and video content , we really appreciate it
There is 6 kN and 3 kN force pointing in negative y-axis, so together they make -9 kN.
I'd use a calculator with a system solver if it were allowed. I can't so I gotta stick with good old fashion lin. algebra and a simple scientific calculator
this is brutal man
6:07
Every thought about teaching at Georgia Tech? As a student i endorse it
Sir please we want a video on space truss
help me Jeff Hanson, you're my only hope
I have a Question regarding finding Moment at a point which is even not in your FBD , in the case u solved Force at joint E (FE) comes out 9.49KN ..But if wetake moment at that point which is not visible normally on our FBD means at joint B my ans for (FE) comes out to be 18.96 rather than 9.49....why is it so...
i took the distance 3m as a moment arm for (FE) for both of its component ...
I have exam after 2 days so kindly reply that what mistake i have made
Thank uh for these useful videos 😍
Hahaha, your right our professor lets us bring calculator but would not give a point if the equation was solved by calculator
thats so evil
Pls for the angles I don't know how you get the 45 and 18.42 degrees 😓anyone pls?
soh cah toa, use the toa specifically
Professor please check again the value of force BE. I think your Calculator is wrong!
just subscribed 4 lyfe
I got 16.98 kN for BE
Instead of doing the system solver I summed moments at B and got 9.5 for FE and then summed the forces in the y to get 16.98 for BE
@@norapowell1327 yeah, i did the same thing, i think EB should be 16.98 kN
When i put the 16.98 kN into the Fx=0 equation, my equilibrium equation became zero. But if i put the 8.49 as the answer, my equation didn't equal zero.
agree Nora. I calculeted the same my answer was BE = 16.97 kN in Tension.I think the mistake was in 0.7071BE - 0.949 FE = 3
problem initiated by signage that's all thanks to Mr.Hanson who delvered a very good lecture. TQ Mr.Hanson
V
should have written 0.707 Be =-12, therefore Be = -16.976kN.
agree
You are right. I think He’s BE is wrong!
@@mchlcybn2406 I got that too!
it's 6 not -12
9-3 not 9+3
@@mchlcybn2406 no it's correct recheck your work