TSD Relative Speed 5 | CAT Preparation 2024 | Arithmetic | Quantitative Aptitude
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- Опубликовано: 10 апр 2019
- CAT PREPARATION 2024 I QUANTITATIVE APTITUDE PREPARATION for CAT 2024
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I love it, how he calls some questions as super questions, beautiful questions and very very good question ,
Instead of calling it hard , very hard , tricky or tedious questions. I love his positive selection of words...✨
Yess, I really agree with the positive approach of sir
That is so TRUE!
"That's the answer for this very very beautiful question" all-time favourite
Yes.
I really appreciate sir, after solving the question. He tells these nice words,
+1
Beautiful beautiful question
Please tell 2022 cat score
@@kavyaagarwal8337beautiful beautiful dp 😅
4:58 For question 1, remaining part of train B can simply be calculated as 25m/s (speed of train B) * 3 Sec (time taken by B - time taken by A) thus giving remaining part =25*3 =75m
i also did same thing
I am just mesmerized with the concepts
My observation in 1st question
Ta= 45 sec
Tb= 48 sec
Their difference is 3 sec
So in 3 sec 2nd exiting train will travel 3*25= 75m. So this much portion is inside the tunnel when 1st train exit the tunnel.
same
No, I think answer would be only 37.5m because because the tran is under tunnel and 75 m which is left is the addition of both tunnel and tran..
@@ExamLauncher you have raised a very important query. But i don't think we can simply divide the answer by 2.
@@ExamLauncher thats the most illogical statement i have ever read.
@@sandeepsahoo7277 🤣🤣
Sir, in Question of train and tunnel (7:42) why we added distance of tunnel to find the the time to cross two trains? wouldn't it will be same time required to cross train with or without tunnel present?
If your doubt is clear plzz explain me also. i have same doubt
Same doubt if anyone is clear please explain
We have to take the length of tunnel as the distance between the tails of train is 1500, and we are taking relative speed in deno. So tunnel length cant be ignored.
Yes, my doubt is clear we have to add tunnel length because we are calculating time when both trains are 600 meters apart. Before meeting their engines to each other they have to first cover 600 meter totally. some by Train A and some by train B . We we have to add that distance too.
If train wasn't apart from each other then we can directly calculate by taking only trains distance.
@@saurabhhase6871 But in the 33.33 sec slower trains should be also be crossing the tunnel because we have taken the length of the tunnel also.
At 08:28 , In second question of first question ,Isn't the slower train is the second one (whose speed is 25 m/s ) ?
by slower train the qs. meant slower in speed. And not slower to exit.
Don't know why but i love when he says Fantaastic set, fantaastic question. Excellent work sir
Can anyone help me if rodha sir has uploaded any videos on trains TO AND FRO MOTION ?
Haha..that "rodha sir" got me here 😂
Shouldn't the distance between point where rear ends of the trains meet and the ENTRY point of the SLOWER train be 600m - 366.66= 233.34 m? Sir has taken distance from the entry point of the 300 m train which is FASTER.
300m train is slower one, 20m/s
same doubt i think its 266.66
sir in 1st question the total distance of tunnel and train is 1200m so the distance of the train left inside the tunnel will be 75/2 as tunnel length will remain as it is
Thank sir ,
Your way of teaching is awesome.
Excuse me did u find polygon videos in geometry plx share if u can
Wlcm beta😊
the "starts" crossing the second motorcycle in half an hour
Sir In train & tunnel question:
Distance between the rear end of both train should be 0 when they crossed. For example a person sitting at last seat in both trains when they cross each other their distance will be 0.
Question should be how much slower train traveled distance in tunnel when they crossed. Then it makes more sense.
truly goated this man
Ans for the last question is 9:45:20, sir have calculated meeting time when m1 was at 9:30 and m2 was at 9:30:20 thats why 10 sec more sir has got in final ans but i think for meeting time calculation, they should start from same time only in order to calculate properly and thus, i got final ans as 9:45:20, correct me if i am wrong.
No.. first bike travelled travelled for half an hour ..and reached 18.2km away from the second bike @9:30:20
In the last question - the M1 position should be at 18.2 km is what i feel because that is when the M2 comes into picture. When M1 is at 18km M2 is still not visible. Correct me if i am wrong!
you are wrong, The motorcycle has definitely travelled some distance in those 20 seconds but it will be used to just calculate length of the train. At 09:00:20, we have train front 200m ahead of motorcycle.
@@arunadityarajjain1129 which motorcycle are you talking about. After half an hour , we should calculate the distance at 9:30:20 of M1 , but in question, it's calculated at 9:30:00 but M2 is at 9:30:20 . So it's worng
@@priyasuthar840same doubt here, is this final ans right or wrong ?
@pranavpadole5499 I feel ans is wrong as post the initial 30 secs, M1 will move 18 km so M1 will cover a total distance of 18.2 km and M2 will cover 18 km, is what I feel.
Sir has done vice versa
At 8:00 why we added tunnel length, we want to calculate time taken in crossing each other...? .
Train part still in the tunnel could have been 3second * 25 m/sec =75 metre
Instaed of calculations
You are questioning sir😠
Diagram for the last question is wrong.. because at 9:30 tge rear end of the train covers 36km.. and at 9:30 front end of the train meeta with M2.. hence the distance between M1 and M2 will be 18km+200m=18200m
In question one they asked for the part of train which is in the tunnel, so from my thinking it should be 75/2 ie. 37.5 mtr
I also think that... Sir plz reply which answer is right?
@@siyajaju4190 no , the moment the train fully get into the tunnel , the distance of tunnel is covered , whatever is leaving outside the tunnel is the distance of train . Like wise whatever is left in the tunnel is also train's distance
Does anyone know, In which video sir has covered a question which one says" two bombs exploded at some interval, a person walking away from point A and B ..."??
in one of tsd basic video
Allah hu akbar😂❤
In 2nd question why we add length of tunnel (8:28) and we have to find the distance and your answer in time
becuz the rear ends
@@rkgpmusic7666 I don't understand!!
len of train is very less compared to the dist coverd i.e 36 km so it can be ignored ? just asking
That is the only trick in the question , if u ignore that then it's only a school level ques.
I have just 3 days for exams with many topics to cover , I havent touched quants topics till now but hoping this might help as last moment dose...Lets see what happens 🤞...
same here bruh
kitna score kiya?
99.98
@@visuder7412 😮
can anyone tell why we are adding the length of the tunnel because question it is mentioned when will train cross the rear ends i.e will cross each other completely so why we are adding tunnel length
See, in order to just add the lengths of both trains the trains should be at face of each other right?? but in the question they are length apart from each other(equal to the length of tunnel) so when we add the length of tunnel then they will be at face of each other and then they will have to cross each other lengths to completely cross each other. Hope this helps.
@@killerlook111 thankyou very much. it helped me.
If we will not consider the tunnel that means train will never cross the tunnel I.e the train is in stationary condition but for relative speed either one of the object must be traveling at certain speed as tunnel is stationary so train must have to cross the tunnel with certain speed,
dear sir
train overtake the bike in 20 sec. so the distance lying in fron of the bike 1 and the bike 2 is 36km+200m. so i have a doubt, the distance covered by bike in 30 min should be half of the distance remaining. so why the distance is not taken as 18km + 100m becaue when we are dividing the distance in km by 2 , why are we not dividing the 200m distance by 2?
train speed is 20mps which means in 20 seconds, it travels 400 m. So the total distance accounts to 36km + 400m. In that time, 1st bike also travels 30 min and 20 seconds. 20 seconds at 10mps is 200m. So 1st bike travelled 18km 200m. So the remaining distance, 36km 400m - 18km 200m = 18km 200m
my question is that when train overtook the motorcycle in 20 sec and travelled for 0.5 hr further then in the meantime the motorcycle must have travelled for 0.5 hr+ 20 sec?? plz explain
20 sec of overtook means to say that after 20 sec their front part is on a say starting line
Same question
The motorcycle has definitely travelled some distance in those 20 seconds but it will be used to just calculate length of the train. At 09:00:20, we have train front 200m ahead of motorcycle.
At 18:23 i think sir has done a small calculation error 9:30+15min10sec=9:45:10sec
In the last question, why do we assume the train and 1st motorcyclist are travelling in same direction?
the train is overtaking the motorcyclist and thus by the literal meaning they have to travel in same direction because if they travel in opposite direction the right term used its "cross".
Why the Relative speeds are not used? why the speeds are not added in the 2 trains tunnel ques?!
Bcos in the 1st part we afe calculating with respect to tunnel so tunnel and train's length will be added but tunnel has no speed so from where the question of relative speed comes bcos rememeber relative speed is between 2 moving objects
In the last question why do we neglect length of the motorcycle?
Hey, did you understand @7:25, how total length is 1500? Why are we also considering the tunnel length here because the question is just asking about rear end crossing each other. Can explain once?
In Last question, how he get that 15 mins 10secs
just convert 910 in fractional value by dividing 60 you will get 15 10/60.
Sir last question may difference 17km. 800 meter hoga na ?
total distance 36km 200 m hai, 18km travel kar liya, or 18km 200m bachega
wouldnt it be 9.45.20-15 mins 10 sec?
How time is subt
How time is subt
sir the 18:47 why have we considered only M1's motion in the half hour and not M2's Motion ...since it would have also moved 18 kms just like M1 .... so shouldnt the new distance between them be 200 m instead of 18200m
answer is right..but your diagram is wrong.
in first 20 seconds engine of the train will be 400m away from start, and engine will travel half an hour more. so total travel would be 36400m.
at 9:30:20 motorcycle would have traveled 18200m.
so left with 18200m to cover.
Yeah bro that's true
In last question why the bike would travel for only 30 min why not for 30min 20 sec
The motorcycle has definitely travelled some distance in those 20 seconds but it will be used to just calculate length of the train. At 09:00:20, we have train front 200m ahead of motorcycle.
@@rahulshridhar6694 i don't know how to tell you this more than i already explained but Ravi sir is right here, we all know he makes some calculation mistakes in some videos, but he didn't consider that 20 secs here for a reason. At first i had the same doubt but then i solved more questions like this, not to sound arrogant but i know this concept better now. Don't take those 20 secs in CAT if any question like this one comes, it will be good for you, marks wise. Peace out.
@@arunadityarajjain1129 Where did you practice these kind of questions? and what LOD do they belong to?
'MY NAME IS RAVI PRAKASH AS YOU KNOW' 😁
kindly solve my query, In the last question , if the train starts over taking M1 @ 9:00 am and then starts overtaking M2 @ 9:30 am , Why are we even considering the 20 sec of overtaking process?
Can't we just take the distance traveled by the train's front part in 30 min and then subtract the distance traveled by M1 in 30 mins and get the distance between the M1 and M2 @ 9;30 am ?
11:40
won't both the train collide in the tunnel?🤣🤣
No recently we have developed self braking system
Double tracks bro
M1 IS MOVING TOWARDS M2 ANS M2 IS MOVING TOWARDS M1 ,THEY WILL MEET IN BETWEEN, SO THE TIME OF 15 MINS AND 10 SEC SHOULD BE SUBTRACTED FROM 9:30:20 SEC
FINAL ANS - 9:30:20 - 0:15:10= 9:15:10
WRONG buddy, we will add distance as 9:30:20 is the time when both are 18200 m apart and it will further take 15 min 10 s until they cross each other.so the final time will be 9:45:30
Exactly that is what I thought
Guys I've one doubt if we divide 910 by 60 we get 15min 16sec how can it be 15min 10sec please clarify
@@supritmal 15 minutes = 900 seconds and we have 910 seconds therefore 15 minutes and 10 seconds.
No, I think answer would be only 37.5m because because the tran is under tunnel and 75 m which is left is the addition of both tunnel and tran..
No brother
Train B : takes 1 sec to travel 25 meter and
The difference b|w Ta , Tb is of 3 seconds.
Hence 3 sec more taken by train b will leave its 75 m portion in tunnel.
@@Sanchofan1 No , As per your explanation, 75m has to be travelled which does mean the 75m is still inside the tunnel.
If that is the case then train has to travel 75m +75m which is 150m so it will take 6 sec to cross. I hope the correct answer is 37.5. If there is any change do let me know :)
@@monishshankaranarayanan5915 when we are calculating speed between two trains, relative distance is used, but when we calculate train with respect to tunnel, actual distance is used and hence the ans is 75mt
1st motorcycle meet 2nd should be 9:45:40
In the last question, why do we assume the train and 1st motorcyclist are travelling in same direction?
If a vehicle overtakes another vehicle, it means that both are going in the same direction.
In the last question, why do we assume the train and 1st motorcyclist are travelling in same direction?
"OVERTAKING"