The Mathis of teaching is the best.My daughter is preparing for Campos placement. She goes in coaching classes for stranthning apptitude. she told me her dought. So I advised her to see CAT APPTITUDE by RODHA.After a day she told me that going in coaching classes is simply wastage of time,money& energy.you are simply better than the best.
I too wasted but not in offline coaching, I wasted my amount in gradeup subscription. While taking gradeup classes I found that teacher, in online classroom program at gradeup (now Byju's) , runs behind syllabus and doesn't take good questions to make your concepts clear. I highly suggest not to take any online as well as offline classroom program. Ravi Sir's video are enough for every competitive exam.
I'm watching this video in 2024 and I'm going to appear for CAT 2024 and i thank you sir for your teaching and hopefully i learn from your videos to get a good percentile in CAT with all my efforts and will be graceful for your efforts in making those videos.
a simple way to solve is distance is constant i.e. 45 km so ratio of minimum time to maximize time will be ratio of minimum speed to maximize speed (30+45)/(90+45)
How will it be the ratio of speed min to speed max? As speed is inversely proportional to time we have to calculate ratio of speed max to speed min which would be wrong
This questions even more simple when you use Distance is constant concept That is Between two buses distance is same So distance is constant between two meetings (Remember relative distance) So time is inversely proportional to speed So ratio of time = ratio of inversely of speeds Time minimum when speed maximum and vice versa So T min / T max = S min / S max = 30+45 / 90+45 = 5 : 9 This is the answer (simple na) Remmner to check When car speed is 30 the meetings occur atleast twice or not Since they first meet at 3:10 so next meeting will be before 5 pm So there must be atleast 2 meeting So above answer is correct
but since speed is inversely proportional to time, the answer would come out like speed max/speed min = time min/time max ie (45+90)/(45+30) that comes out to be 9:5 which is not correct since the answer is 5:9
If we only had to find the number of busses crosses, could we do it with the concept of avg. speed for Ravi's car? As the busses are moving at a constant speed
In the qs it was asked time interval between two consecutive meetings.since there is no meeting at 2pm .It is not considered as per the qs.Hope it is helpful
you can try using 24hrs time method rather than 12 hours like instead os using 2pm use it as 14:00 and 6pm as 18:00 by this way u can take out the time difference easily. hope it helps :)
At 12 :48 in the forth bus but he maintenance 30kmpl for first 3 hrs and at 5 :00am it is 4 bus at a interval of 1 hr so logically it's speed increase after 4:24 or the third bus pls clr my doubt sir
Sir I was also able to do it mentally because of how well you taught this concept but my question is how are we supposed to read such a long question calculate all this and answer in 1.5 mins in CAT
The first question has asked for the ratio between any 2 consecutive meetings. But sir has taken 36 min and 20min which are not consecutive. Tell me if I'm wrong here.
Read the question once again. where do you see the maximum time interval in the meetings? in the beginning right. So answer is 36. Then where do you see the minimum time interval, in the end. So the answer is 20 minutes. Then you take the ratio to get the final answer.
@@swapneelrao8276 i think the answer should be 30:20 , because of the word consecutive one option is 36:30 , 2nd is 30:20 , 2nd one has more time difference. if it was not consecutive then it would be 36:20. Correct me if I am wrong. Pay attention on the word consecutive .
The question is to find the ratio of min and max POSSIBLE TIME INTERVAL between any 2 CONSECUTIVE meetings. The time diff between first and second( or 3rd and 4rth) meeting is 36 mins(which is the maximum). And the time diff between 13rth and 14rth ( or 14rth and 15th) is 20 mins(which is the minimum). Thus 20:36
I am preparing for CAT 2020. This is my 120th lecture of 192. Commenting so that I see it the future and praise Ravi Sir.
Here after CAT 2020!
@@vins686 how much did you score?
@@amankumar-gv7yx 87 percentile 😔
@@vins686 giving cat again?
@@kishankumaragarwal7768 obviously yes!!
5:9 will be the correct answer for qs1.
The Mathis of teaching is the best.My daughter is preparing for Campos placement. She goes in coaching classes for stranthning apptitude. she told me her dought. So I advised her to see CAT APPTITUDE by RODHA.After a day she told me that going in coaching classes is simply wastage of time,money& energy.you are simply better than the best.
Same Here I too Wasted my 50k for CAT preparation. Ravi sir is a great teacher.
@@bibhutikumarsingh9899 Me too ;C
I too wasted but not in offline coaching, I wasted my amount in gradeup subscription. While taking gradeup classes I found that teacher, in online classroom program at gradeup (now Byju's) , runs behind syllabus and doesn't take good questions to make your concepts clear. I highly suggest not to take any online as well as offline classroom program. Ravi Sir's video are enough for every competitive exam.
@@sheetaljain4288 unacademy is amazing for CAT ravi sir and other teachers are just beyond the words
Ravi travelled from Bangalore to Pondicherry? Was it a personal experience, Sir? :p
😂
Nice interpretation 😊
I'm watching this video in 2024 and I'm going to appear for CAT 2024 and i thank you sir for your teaching and hopefully i learn from your videos to get a good percentile in CAT with all my efforts and will be graceful for your efforts in making those videos.
self or coaching?
@@Tushar_goswami_00 self
a simple way to solve is distance is constant i.e. 45 km so ratio of minimum time to maximize time will be ratio of minimum speed to maximize speed (30+45)/(90+45)
How will it be the ratio of speed min to speed max?
As speed is inversely proportional to time we have to calculate ratio of speed max to speed min which would be wrong
Sir, the first question's answer should be 5:9 I suppose. Because it's 20:36. But you as usual taught like a champ
yep, mistake, but its okay. we understood the concept
shouldn't be the ratio of 72:36 as 2:1 because question says consecutive buses
@@o_StormYTno bcz, 2 sets of consecutive which are minimum and maximum is asked.
This questions even more simple when you use
Distance is constant concept
That is
Between two buses distance is same
So distance is constant between two meetings
(Remember relative distance)
So time is inversely proportional to speed
So ratio of time = ratio of inversely of speeds
Time minimum when speed maximum and vice versa
So
T min / T max = S min / S max
= 30+45 / 90+45
= 5 : 9
This is the answer (simple na)
Remmner to check
When car speed is 30 the meetings occur atleast twice or not
Since they first meet at 3:10 so next meeting will be before 5 pm
So there must be atleast 2 meeting
So above answer is correct
I am not insulting sir
Even I learned this trick from ravi sir
I think he missed the trick here
Great teacher you are
Thank you very much sir
m surprised by this fact thank u so much for such an easy explanation rodha 2.0 lol
but since speed is inversely proportional to time, the answer would come out like
speed max/speed min = time min/time max ie (45+90)/(45+30) that comes out to be 9:5 which is not correct since the answer is 5:9
Took an hour to understand this ,just because Ravi sir said it’s important 💯✨
Direct soln, time is inversely proportional to speed, highest RS = 135, lowes RS = 75, 1/135:1/75 = 5:9
Is it realiable ? And also u have to do the whole process for the second part 🙄🤔
It's my 2nd time to watch all rodha's playlist...
ravi went from peace to rage mode
Lovely question, lovely explanation! Thank you so much for province us quality content!🙏
Amazing explanation. One of the best teacher ever.
Brilliant question to clear all conceptual doubts🙏
Best question to understand TSD
This is like the 'Bug' episode of BrBa
Bus are leaving every hour not after crossing Davis car. So @3:12 second bus should have moved some distance
good point bro
But still the distance between 2 consecutive buses will be 45km only as speed is const and they leave every hour,right?
i will leave this question if i got in exam
Sir the answer for the first part will be 5:18
super question
2:4:3ans of second questionof 1....
1st question was such amazing
5:9 is the correct ratio for 1st question
Sir in 3rd case why u r taking till 10 pm, in question it is upto 11 pm then number of buses will change and ratio become different in 2 nd question
Is it good to prepare for cat from class 11 and how should one start
Beautifully explained sir ❤❤🙏🙏🙏🙏🙏🙏🙏🙏🙏
at 1.5x speed, sir was rapping
I watched at 2x still found comfortable.
Insane question
Last bus at 8pm , there is no need to calculate further sir
exactly
@@abhinavjain8770 Last bus is at 8 pm but the car will not meet that last last bus at 8 pm, so there is a need.
Those are the timings at which car and corresponding buses (1 to 15 ) have met. The last bus that started at 8 PM met the car at 10 PM.
@@satyasandeep5503 got it thanx
If we only had to find the number of busses crosses, could we do it with the concept of avg. speed for Ravi's car? As the busses are moving at a constant speed
last bus is at 8 pm , and when ravi at 9pm then how he meet any other bus on the way?
Yes last meeting 9:20 pr hogi so 13 buses actually
sir maximum time interval should be 1 hr 12 min that car took for the 1st meeting, then why did you take 36 min as maximum time interval?
In the qs it was asked time interval between two consecutive meetings.since there is no meeting at 2pm .It is not considered as per the qs.Hope it is helpful
the first question should be in DI
Very good question with good concept ❤️
In this playlist, time and work speed time distances, trains and boats and streams are fully covered?
Yes sir good question
1st qs, 5:9
I am cannot able to understand ,the how to equating time of 2pm (car) and bus(6am)..how we equate time ..as 2pm..please sir,help ..me sir
6am to 6pm = 12hr , 6pm-4hr =2pm so 12-4 = 8hr
you can try using 24hrs time method rather than 12 hours like instead os using 2pm use it as 14:00 and 6pm as 18:00 by this way u can take out the time difference easily. hope it helps :)
Sir ans will be 20/30 =2/3 because the 2 meetings have to be consecutive.
Sir 1st bus and 13 bus meeting consecutive kaise hogi ye nhi smjh aya.
At 12 :48 in the forth bus but he maintenance 30kmpl for first 3 hrs and at 5 :00am it is 4 bus at a interval of 1 hr so logically it's speed increase after 4:24 or the third bus pls clr my doubt sir
at 5pm his speed increases to 45kmpl which results in the increase of relative speed, hence decreasing time interval
What's the point of consecutive here?
Thank you so much Sir ❤🤘
Sir I was also able to do it mentally because of how well you taught this concept but my question is how are we supposed to read such a long question calculate all this and answer in 1.5 mins in CAT
Better to leave it for last. If you get extra time then only go for it.
The first question has asked for the ratio between any 2 consecutive meetings. But sir has taken 36 min and 20min which are not consecutive. Tell me if I'm wrong here.
Read the question once again. where do you see the maximum time interval in the meetings? in the beginning right. So answer is 36. Then where do you see the minimum time interval, in the end. So the answer is 20 minutes. Then you take the ratio to get the final answer.
@@swapneelrao8276 are you telling me that the word consecutive has no significance here?
@@kushagra4379 it definitely has bro. 20 min and 36min is difference between consecutive meetings only. That is what he has considered.
@@swapneelrao8276 i think the answer should be 30:20 , because of the word consecutive one option is 36:30 , 2nd is 30:20 , 2nd one has more time difference. if it was not consecutive then it would be 36:20. Correct me if I am wrong. Pay attention on the word consecutive .
The question is to find the ratio of min and max POSSIBLE TIME INTERVAL between any 2 CONSECUTIVE meetings.
The time diff between first and second( or 3rd and 4rth) meeting is 36 mins(which is the maximum). And the time diff between 13rth and 14rth ( or 14rth and 15th) is 20 mins(which is the minimum). Thus 20:36
5:9 is answer
le Newton at 5:00:01 pm ;"abe saale "
Sir the maximum time is 72 mins so the ratio to min : max = 12:72 = 1:6
not time, it is time interval.
Sir its time "interval"...so v need to check the maximum and minimum interval of time taken for these two objects to meet...
The last bus from pondicherry is at 8:00PM so total should be 4 +11 buses. Can someone clear it
4+7 i guess
6Am to 8Pm , we have to include both as well so difference+1 👍
sir the ratio is 5:9 not 4:9
Sir after 8pm how can he meet bus
cet puzzle level question
Super❤️❤️❤️❤️❤️❤️
Sir, Isnt the first time interval 72 mins?
exactly my doubt
Putting a comment here so later next year I come back and reply that I converted IIM
Sure u will!
I guess they will ist meet ar 320hrs
13 30 i lost sir
sir the answer is probably wrong because you forgot to take into account the condition that "the last bus was at 8pm".
Took that into account :)
The timings that we are calculating are the ones at which the car will meet the bus, not the time when bus leaves
So it's correct
watch carefully
yes right!
what answer you are getting?
11:24 after 2pm … ravi at around 3pm cover 30km so the distance between ravi. Bus at 3pm should be 90-30=60km ….. any one agree ?
This qn feels like a dilr set 😅
Thankyou sir
Dont worry agli video me phir se hai
Sir, i can't understand how after 1st meeting the distance is same 45m?
speed of each bus is 45km/hr and each bus starts after 1 hr .. so distance = 45km/hr *1hr= 45km