Japanese | Can you solve this ? | A Nice Math Olympiad Algebra Problem.
HTML-код
- Опубликовано: 14 окт 2024
- This is an interesting question with amazing concepts!
Hope you are well
Playlist to watch all videos on Learncommunolizer
• Maths Olympiad
And
• Maths
Subscribe: / @learncommunolizer
![[4K] Watch SpaceX Catch A Starship Rocket From Space!!! #IFT5](http://i.ytimg.com/vi/pIKI7y3DTXk/mqdefault.jpg)
Multiply ab bc ca . We get a square, b square c square. So we get abc whole square. By way of this we get the value of abc. Then divide by the values of ab, bc, ca and get the value of a,b,c. Then just add and get the value of a + b + c. Simple
Simple in three steps🎉
This method is easier than your solution procedure sir.
a= √150 ; b=√(200/3); c=√600
a+b+c= 5√6 + 10√2/√3 + 10√6
=5/√6+10√6/3+10√6
= √6(5+10/3+10)
=√6(15+10/3)
=√6(55/3)
a+b+c = 55√6/3
100+200+300=600
a+a+b+b+c+c=600
a+b+c. =300..very simple .and easy..Total letter =600..than.you take half..
Of Total letter equal 300..
It is too lengthy procedure
Erry puvvava nuvvu
Lengthy process,find a²b²c² first,then a,b,c ,add three
49.49 its simple (a+b+c)^2 formula ab bc ca value already given you can get 2ab 2bc 2ca and then you can also get a^2 b^2 c^2 value by multiplying each with each other like ab*ca from here you can get a^2*bc and bc value already given
After you got a^2 b^2 and c^2 you could radicalize both side and add the results. Before of you go a lot of steps but the video is good keep it up🎉
Сравнив 1-ое и 2-ое видим, что с= 2а.
Из 3-его следует- 2а^=300; отсюда-а=5√6;с=10√6;в=20/√6; в итоге: а+в+с =55√6/3;Самое простое решение.
А сравнить зачем?
Вроде выражаем, подставляем - должно решаться элементарно (система для пятого класса школы).
LCM of (1,2,3)=6
6abc=6cx100=600c
3abc=3a×200=600a
2abc=2bx300=600b
Add 11abc=600(a+b+c)
ab×bc×ca=100x200x300
(abc)^2=(1000)^2×6
abc=1000√6
11x1000√6=600(a+b+c)
a+b+c=110/√6=(55√2)/√3
ruclips.net/video/TDFfjc00nvk/видео.html
Your method seems much simpler but I still had problems following it. Where can I go to practice your method?
@@joseeoliviero6078 How do you think about this method?
(3) / (1) gives c / b = 3 : 1
(2) / (1) gives c / a = 2 : 1
∴ a : b : c = 3k : 2k : 6k
By (1), 6k^2 = 100
∴ k^2 = 50/3
k = +- (5√2) / √3
Their sum equals 11k.
∴ a + b + c = +- (55√2) / √3
= +- 55√6 / 3
Done.
@@N_Kumar26 And you missed the negative solution
This type of question is asking in exam then you quickly make answer. You can practice your self like ab=400
bc=200
ca=800 find value of a^2+b^2+c^2
Here you tube link you could know more class wise questions and answers.
ruclips.net/video/TDFfjc00nvk/видео.html
Excellent sollution
a+b+c also admits its negative value. With a b c negative.
Thanks sir 🎉
Your welcome. Thanks
Very nice. I just recollected my mind for 70 years back momery
abc=100c
abc=200a => 11abc=600(a+b+c)
abc=300b
(abc)^2 = 100*200*300 => abc = +- √(100*200*300) = +- 1000*√6
a+b+c = 11abc/600 = +-11*1000*√6/600 = +-110/√6
Good idea
To simplify, let p=10a, q=10b and c=10c then
pq=1,qr=2, rp=3 and pqr^2=6
pqr=√6 or pqr=-√6
For pqr=√6
From pq=1 and pqr=√6, r = √6 since pq = 1
Also q = √6 / 2, p = √6 / 3
Finally a+b+c
= 10p+10q+10r
= 10 (p+q+r)
= 10 (√6/3+√6/2+√6)
= 10 (11√6 / 6
= 110√6 / 3
= 55√6 / 3
For pqr = -√6, a+b+c = -55√6/3
Sol: 55√6 / 3, -55√6 / 3
c / b = 3 : 1
c / a = 2 : 1
∴ a : b : c = 3k : 2k : 6k
By (1), 6k^2 = 100
∴ k^2 = 50/3
k = +- (5√2) / √3
Their sum equals 11k.
∴ a + b + c = +- (55√2) / √3
= +- 55√6 / 3
Done.
Easiest solution
Hats off
simplest one.
a=100,b=0 c=200
No need of formula
Yes directly we can do.
Beautiful
Thank you! Cheers!
ab*bc*ca=(abc)^2=100*200*300. Then abc=1000*6^0.5. Then a=abc/bc=5*6^0.5
b=abc/ca=10/3*6^0.5
c=abc/ab=10*6^0.5
Then a+b+c=6^0.5(5+10/3+10)=55/3*6^0.5
awesome
Your welcome
how is c/b 3:1? how do you kno this? can you explain please
during calculation 600 is left out in place.
-(55√6)/3 or (55√6)/3
Yeah he missed the negative solution
i think so.
why negative
@@is7728why negative
(a+b+c)^2=6050/3
→a+b+c=+-√(6050/3)
___ ___
and in the case that all of a,b,c is negative ...
could you make
a+b+c=negative
How do you think about this ?
சிறப்பு
Your welcome
300
Helo
Чувак не правильно решил: сократив корень и квадрат скобок, должен был получиться модуль, и на выходе два решения
ab.bc/ac=b^2=200/3
b=20/root 6
similarly
a=30/root 6
c=60/root 6
a+b+c=110/root6
this is shortest method
a
a+b+c=250
What is final result?
2a+2b+2c=600
Dived by 2
a+b+c =300
Right short answer
a + b + c = 300
(a : 100 ; b: 0 dan c : 200 )
Спасибо. Я бы решила иначе, но ваш метод тоже интересен
Once you have values for a, b and c, you can simply add them.
ab±bc±ca=600
2(a±b±c)= 600
a±b±చెప్పు =300
you nedd not write every line ( a+B+C)*2put lhs an d rhs to denote left and right
ab.bc.ca = a²b²c² = (abc)² = 100 . 200 . 300 = 6 . 10⁶
then abc = 6.10⁴, a.bc = 6.10⁴ , a.200= 6.10⁴ so a=3.10² , etc
is approximately 44.9073
Total a+ b + c =600
ab+bc+ca=600. 2(a+b+c)=600. a+b+c=300
How 2a+2b+2c= ab+bc+ca ??????
how ab+bc+ca will become2(a+b+c) ????? New mathematical Theory...
a=100, b=0, c=200
1- ab = 100
2. bc = 200
3. ca = 300
1*2*3
ab*bc*ca = 100*200*300
(abc)^2 = 6000000
abc = (√ 6000000 ) = √ (6 * 1000000 ) = √6 * 1000 = 1000 √6
=>1 ab = 100 ,.abc = 1000 √6 , 100 * c = 1000 √6 , c = (1000 √6 ) / 100 = 10√6
=>2 bc = 200 , abc = 1000 √6 , 200 * a = 1000 √6 , a = (1000 √6) / 200 = 5√6
=>3 ca = 300 , abc = 1000 √6 , 300 * b = 1000 √6 , b = (1000 √6 ) / 300 = (1000/300) * √6 = (10/3) * √6
a+b+c = 10√6 + 5√6 + ((10/3) * √6) = (10+5+(10/3) √6 = (15+ 10/3 ) √6 = (45/3 + 10/3 ) √6 = (55/3 ) √6
My God!
How to have such intuition!
brother...abc is ±√6000000
@@seekingCK OK. a+b+c = ±(55/3)√6
A100. B0. C200
👏👏
Your welcome
a=12.5,b=8,c=25
350
c=10sqrt6
b=10sqrt6/3
a=5sqrt6
10
50+100+150=300
350
a+b+c=45.5
600
105
There is a easiest way to solve this problem than that.
Ab+bc+ca =100+200+300
2(a+b+c) = 600
A+b+c= 600/2
A+b+c = 300
You have left abc😮
Прикольно, но всегда мучает вопрос - нафига это?
There is another short solution if we divide equation1 buy eq2
401
60
302
A=100
B=0
C=200
Mistake ho chuki hae pl rechek caculation.
100
D 200 E 900 F2
800
500
It's ok? You lose the same with minus
Abc 300
11
6oo/11 ans
you are saying that a+b+c is equal to the numerator
6
It's ok but what is useful in our regular life.
,२००प्रतेकी
🤔
Three hundred
Цікаво 😊❤
Your welcome!
C=200
A=100
B=0
Simple
A- 100
B- 0
C- 200
A+B=100 100+0=100
B+C=200 0+200=200
C+A=300 200+100=300
A+B+C=? 100+0+200=300
A. 300
B= 0
Okay but what is the numerical value ??? That’s what my question is
The numerical value could have been found about 1/3 of tge way in. YES, it would have been approximated, the precision would depend upon how many decimal places you choose to use.
@@robertloveless4938
No more than 2-3 decimal places would be fine for me.
B=0
Есть ещё одно решение с минусом
डोक्यावरुन गेले.
Too lengthy
సి స్క్వేర్ 600 లు యేమైంది
Very primitive methods
またまた、虚数根つかうの😂辞めなよ
এত দীর্ঘ করে ভাল শিক্ষক অংক করে না। কথা শুদ্ধ করে পাঠদানে আশা উচিত।
Too waste time
Not. Posible
Very bad solution
Hello why are you going this much critical. Easy & simple way A+B =100, (A is 100& B is 0). B&C=200(B is 0&C is 200), then. C+A=300(C is 200& A is 100).A+B+C= 300. 👌
Simple and super..
Then ab=0, pl read question carefully
It is an=100, not a+b=100
ab=100
It is a×b=100 But not a+b=100
Modi ko bolo, woh bahut expert hai.
300
Helo
350
600
60
350
300
Helo
200
200