EVALUATING MEAN, MEDIAN AND MODE OF A GROUP DATA

This video explains in detail, clear and simple terms how to evaluate the mean, median and mode of a group data. Finding the mean, median and mode of any statistical data is very important in statistical analysis, it is also in most exams questions in secondary schools and most courses in tertiary institutions hence the importance of the video.
/ @begechorimaths2975

[@user-xl7xz1kd1v]

Ur doing it 👍👍

[@nativemuno]

Very helpful, thanks God bless you Sir.

[@kaylarichards6700]

You miscalculated the 41-50 part, 45.5*11 is 500.5 , instead of 555.

[@kaylarichards6700]

610.5 *

[@begechorimaths2975]

thank you for the notice, will correct it.

[@GiftyPeku]

Thanks

[@user-dt2bb4qw2v]

GOOD EXPLANATION ALL IS UNDERSTOOD WELL

[@emmanuelbantai8135]

this was a very elaborative tutorial i have understood every thing thank you

[@begechorimaths2975]

thank you so much...

[@edwardmuriuki]

Thank uu

[@ShamimHassad-mz8hm]

Thank u sir its my exam 2morrow

[@begechorimaths2975]

wishing you the very best in your exams...

[@KimbowaDaisy]

Thank you sir.

[@FirminohRobertoh]

Is it not important to first find the real class boundaries before finding the mean..like to close the gaps between the class limits??

[@VishalKumar-qv7bv]

I appreciate you man..
You cleared
my doubt..

[@begechorimaths2975]

you are welcome bro..

[@JusticeImolore]

According to my study, I found out there are inclusive and exclusive grouped data. Which I believe that the grouped data is inclusive, why didn't you convert it to exclusive grouped data before solving?

[@mohamedkamara6762]

Thank you for your good work , but you miscalculated the fx of 41-50

[@eseyinawe]

Good day. I thought the cumulative frequency is 20+11/2 but why did you start start with 4 when solving for the median

[@deopraise5669]

great

[@begechorimaths2975]

thanks a lot

[@eseyinawe]

Good day. I thought the cumulative frequency is 20+11/2 but why did you start start with 4

[@user-ti4kb3dx8g]

For the mean the answer is 46.5 not 48.7

[@user-fn9ce4ez1d]

Please is it possible to approximately the mean to 49 instead of 48.7

[@begechorimaths2975]

Yeah, but it depends on the instruction from the question, so I advise you do as instructed.

[@NomenSojini]

What is 11×45.5 when calculating the m

[@chas_nomnom]

500.5 is the right answer, he miscalculated it ig that's why

[@ndithomas1958]

Please, I don't understand how you got 0.64 in the calculation for median

[@begechorimaths2975]

okkk... in the bracket you have 25-18=7, 7÷11=0.64 approximately.
Hope you are OK now?

[@ndithomas1958]

@@begechorimaths2975 yes, thanks

[@estheranyanwu9627]

How did you get the class C

[@begechorimaths2975]

class width (C) can be found through different methods but one of the easiest is to subtract the upper limit and lower limit of the class boundaries of what you are looking for e.g for median class
50.5 - 40.5 = 10
hence C= 10
hope you are satisfied ?

[@AlapRoy.007]

bro 45.5*11= 55.0

[@user-mg5ky7ub6l]

Mean is wrong

[@venkateshpani7814]

A facul Salim go 1 point also not understood go why are you doing the channel

[@eseyinawe]

Good day. I thought the cumulative frequency is 20+11/2 but why did you start start with 4 when solving for the median