Given displacement (s), we obtained velocity (v) by differentiating (s) and obtain acceleration (a) by differentiating (v). The reverse process is integration. I.e., we obtain velocity (v) by integrating acceleration (a), and obtain displacement (s) by integrating (v). Please let me know if this response helped 🙏
During the 2nd second means from 1 to 2. Not that ( 0 to 1) represents the 1st, (1 to 2) the 2nd, (3 to 4) the third, and so on. Please let me know if this response helped 🙏
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how do you differentiate if a question on integration or differentiation🤔🤔🤔🤔
Given displacement (s), we obtained velocity (v) by differentiating (s) and obtain acceleration (a) by differentiating (v). The reverse process is integration. I.e., we obtain velocity (v) by integrating acceleration (a), and obtain displacement (s) by integrating (v). Please let me know if this response helped 🙏
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In part (b) why did you use 1and 2 and not 0 and 2 ... 😢
During the 2nd second means from 1 to 2. Not that ( 0 to 1) represents the 1st, (1 to 2) the 2nd, (3 to 4) the third, and so on. Please let me know if this response helped 🙏
@KevinOchola Thank you very much 👍 You've really helped
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sorry sir how did you integrate 24t
Hi! Increase the power of t by one and divide by the power. I.e. [24t^(1+1)]/(1+1) please let me know if this helped.
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Thank you sir
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