Learning from your videos, a person quickly becomes a technical master. Other vids just show shortcuts or leave out certain things the teacher thinks unnecessary.... not here.
Can you help me with the volume of sphere one please? Maybe it’s a silly question, but… Pi is a constant, therefore its derivative supposed to be 0. Then why not 4/3 x 0 x r^2 = 0 Thank you
V = 4/3 * pi * r^3, dV/dr = d/dr (4/3 * pi * r^3) Take the constants outside the derivative: dV/dr = 4/3 * pi * d/dr (r^3) = 4/3 * pi * 3r^2 = 4*pi*r^2
It is indeed 4/3·π·r². If it were 4/3+π+r², it would be the deriv. of 4/3 + deriv. π + deriv. r². However, now it is the deriv. of 4/3·π·r² as a whole. If it is still unclear, you can approach it two ways to possibly make it easier. Otherwise feel free to skip the following as it may make it more confusing. You can multiply the π to the fraction 4/3 and get (4π/3), resulting in (4π/3)·r² (which holds the same value as 4/3·π·r², just rewritten). If it is still unclear, we can move the first part of the multiplication to a variable, let's say "s". v(r) = s·r³ Before using 4π/3, if s were "5", it would be v(r) = 5r³. And we know: v'(r) = 5·3·r² = 15r² However, s is 4π/3, so: s = 4π/3 v(r) = s·r³ v'(r) = (or: dv/dr =) s·3·r² = (4π/3)·3·r² = [(3·4π)/3]·r² = 4π·r²
![Derivatives of Trig Functions (Sin, Cos, Tan) in Calculus - [1-4]](http://i.ytimg.com/vi/ocuZkDGdy1Y/mqdefault.jpg)
![Derivatives of Trig Functions (Sin, Cos, Tan) in Calculus - [1-4]](/img/tr.png)
Awesome video! Thank you!
I never had the opportunity to take calculus. Thank you for the opportunity of a lifetime!
Learning from your videos, a person quickly becomes a technical master.
Other vids just show shortcuts or leave out certain things the teacher thinks unnecessary.... not here.
Thank you for this series! One step at a time, you've simplified a topic that otherwise is overwhelming!
Your teaching is excellent..❤❤❤
The derivative of Y(x+2)⁵...❤❤❤Please it's really helpful to me Sir❤❤❤
Thanks so much sir, we really appreciate
As always amazing!!!!
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Helpful video ! 10x sir 💕💕💕
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Can you help me with the volume of sphere one please? Maybe it’s a silly question, but…
Pi is a constant, therefore its derivative supposed to be 0.
Then why not 4/3 x 0 x r^2 = 0
Thank you
V = 4/3 * pi * r^3, dV/dr = d/dr (4/3 * pi * r^3)
Take the constants outside the derivative: dV/dr = 4/3 * pi * d/dr (r^3) = 4/3 * pi * 3r^2 = 4*pi*r^2
It is indeed 4/3·π·r². If it were 4/3+π+r², it would be the deriv. of 4/3 + deriv. π + deriv. r². However, now it is the deriv. of 4/3·π·r² as a whole.
If it is still unclear, you can approach it two ways to possibly make it easier. Otherwise feel free to skip the following as it may make it more confusing.
You can multiply the π to the fraction 4/3 and get (4π/3), resulting in (4π/3)·r² (which holds the same value as 4/3·π·r², just rewritten). If it is still unclear, we can move the first part of the multiplication to a variable, let's say "s".
v(r) = s·r³
Before using 4π/3, if s were "5", it would be v(r) = 5r³. And we know: v'(r) = 5·3·r² = 15r²
However, s is 4π/3, so:
s = 4π/3
v(r) = s·r³
v'(r) = (or: dv/dr =) s·3·r² = (4π/3)·3·r² = [(3·4π)/3]·r² = 4π·r²
@@thepedzed yeah, sure, since that i figured out i missed the multiplying rule :)
Thanks anyway
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You're welcome 😊
Please more lessons trigonometric I m form four
Will do!
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Makes me cry.. math scared me
Hopefully tears of joy!
mchew....🤣🤣🤣..all the time