Recycling Electricity (self charging battery)

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  • Опубликовано: 13 сен 2024
  • This is one of many ways to power 230 V load using 12 V battery. I just want to know if it's possible to put the output current back to the battery.
    Donation:
    paypal.me/okki...
    My fullname as on my id card: Joko Ari Moelyo Okki
    / okkimoeljadi
    My email address is: info@m-opensolutions.com
    Instagram: / okkimoeljadi

Комментарии • 62

  • @tonyrebeiro
    @tonyrebeiro 5 лет назад +8

    Also, You cannot charge and discharge an LA battery together. It does not work. You need to momentarily disconnect the load from the battery and give it a stored pulse, from a cap and then put back the load.

    • @AliasT.K
      @AliasT.K Год назад

      But we can with a voltaic pile

  • @rattedbug5003
    @rattedbug5003 7 лет назад +1

    I love seeing what you make Okki. Keep it up.

    • @OkkiMoeljadi
      @OkkiMoeljadi  7 лет назад

      Thanks for watching and your kind comment Ratted bug.

  • @jarvislark1816
    @jarvislark1816 Год назад

    Hello, Okki. I respect a lot your independence of thinking, you carry out your experiments according to your own ideas. I`d like to propose you not to put the load on the LC tank and to delete the diod but to put ANOTHER coil PREPENDICULAR, 90degrees to the primary and the secondary coils of the transformer; plus a capacitor to form a tank. Then you can put the diod (or a diod bridge, that is to rectify the current) and the lamp on THAT prependicular coil.There may be a capacitor paralel to the lamp. You should add yet ANOTHER COIL and a capacitor perpendicular to the primary and the secondary coils, rectify the current with a diod bridge and a capacitor and join them to the battery. The voltage conveyed to the battery should not exceed 14.4V, you know. These extra coils and tanks are meant to exclude the consumption of the current from the battery. The right angle serves the same purpose. If the primary and secondary coils are horizontal then the perpendicular coils are vertical. It's a pity I can`t experiment myself so I ask you to do it and write to me if you are going to carry out THIS experiment. If you aren`t - write back to me all the same.

  • @manwar999
    @manwar999 5 лет назад +2

    sir okki...very good work, try to impart permanent magnets into your circuit to give an extra boost of power...

  • @traderspatrion9242
    @traderspatrion9242 Год назад +1

    Very nice but you should have a dumping mechanism

  • @nikkitroublestrannyadventu5484
    @nikkitroublestrannyadventu5484 5 лет назад +3

    It looked like the lower battery voltage went low for running with no return loop, but then, it looked like it was starting to rise. You should keep it running for 15 minutes and measure the battery voltage again to see if it goes all the way back up and maybe even higher

    • @OkkiMoeljadi
      @OkkiMoeljadi  5 лет назад +1

      I have tried that. The battery voltage did not go higher. Unfortunately, this kind of overunity device does not exist.

    • @Birol731
      @Birol731 2 года назад

      I would like to ask the same question.Bedini also mentioned this effect, allegedly he was able to produce more output than input.......Was this not the case in your free energy system?

  • @emil.honganmaki5461
    @emil.honganmaki5461 4 месяца назад

    charging current is 230v 50W via Lamu 0.217 A and 50W power from a 12v battery is 4.166A, so a permanent charger is not possible.

  • @ishwar41
    @ishwar41 4 года назад +2

    Sir, can you give the detail of the components?

  • @Edmorbus
    @Edmorbus 7 лет назад +4

    Okki have you Transformer info 12v to 220v ?
    and thanks for sharing

    • @OkkiMoeljadi
      @OkkiMoeljadi  7 лет назад +3

      Hi Edmorbus. Here I don't use such a (12V/220V) Trafo. I use resonant trafo instead. Thanks for commenting.

  • @Ozzy3333333
    @Ozzy3333333 Год назад +1

    Of course there is switching losses, magnetic losses, diode losses, lamp losses, wire and connection losses, you are fighting a huge loss battle.
    The total killer on top of losses, 50w / 230v = 220mA, 50w / 12v = 4.2a, stepping up the voltage ~19 times and then needing a minimum of 19x the current to charge the battery just is not going to work.

  • @rodekmai2630
    @rodekmai2630 4 года назад +1

    Sangat tertarik bagaimana Bapak menghubungkan function generator langsung dengan swithcing unit via mosfet. Apakah mungkin kita bisa lihat diagram switching unitnya Pak?

    • @OkkiMoeljadi
      @OkkiMoeljadi  4 года назад

      Keluaran dari generator sinyal langsung disambungkan dengan Gate-nya Mosfet. Massanya tentu harus disambungkan juga.

  • @tonyrebeiro
    @tonyrebeiro 5 лет назад +3

    Your battery started off at 12.29 & within that short run, it came down to 12.20. So what's the big deal. Where is the Gain???

    • @artofwebdesign
      @artofwebdesign 3 года назад

      he doesn't state there is a gain. It's in your own mind.

    • @tonyrebeiro
      @tonyrebeiro 3 года назад +2

      @@artofwebdesign Ok. Then what's the basic purpose of the whole thing?? Just to waste time and effort??

    • @waynerawlings8599
      @waynerawlings8599 Год назад

      It’s just to show how you can waste power

  • @jonpiodinopol
    @jonpiodinopol 5 лет назад +1

    thanks for sharing...

  • @HAPPY-kv1fs
    @HAPPY-kv1fs 3 года назад +1

    Lamp is too powerful.
    Try LED's and a resistor to feedback MORE voltage.

  • @smokyatgroups
    @smokyatgroups 7 лет назад +1

    Hi Okki thanks for sharing your worK! is a good idea about the spark gap or anything else which delivers negative resistance by avalanche threshold effect.
    I doubt plates would have time to flex at 90KHz & any increase may only be surface charge on plates anyway.
    Go with your neg resistance approach.

    • @OkkiMoeljadi
      @OkkiMoeljadi  7 лет назад +1

      Hi Smoky, you are welcome. I have tried similar circuit with spark gap. Please take a look at this video ruclips.net/video/CtGK3epMuS8/видео.html
      I see some interesting effects with spark gap but until now I cannot capture any ambient energy. Anyway thanks for your comment.

    • @Birol731
      @Birol731 2 года назад

      ​@@OkkiMoeljadi Were you able to solve the problem ? If the system is working well, the empty battery is charged after a certain time of working, am I right?

    • @OkkiMoeljadi
      @OkkiMoeljadi  2 года назад +1

      @@Birol731 no, I haven't done further investigation after this. I think with correct setting, you can charge the battery.

    • @Birol731
      @Birol731 2 года назад

      @@OkkiMoeljadi What do you mean with correct setting, what is the condition that must be fulfilled to extract the energy from the ambient medium, may I ask you?

  • @mykedoes4099
    @mykedoes4099 7 лет назад +1

    you should add in paralel with high voltage caps a super capacitor dump bank cause the lead acid batt will not charge fast enough to capture any radient

    • @OkkiMoeljadi
      @OkkiMoeljadi  7 лет назад

      myke Does, thanks for your feedback. I will consider this in the future test.

    • @mykedoes4099
      @mykedoes4099 7 лет назад +2

      I think you need to put high speed switching diode in the direction of feed back to the positive terminal of source battery. So that the diode faces the positive terminal not to allow energy to flow towards the light bulb from positive terminal of source. Cause when the cap bank is charged it will act like a short and also you don't want your cap bank charging from source battery so the diode will isolate this from happening.

    • @OkkiMoeljadi
      @OkkiMoeljadi  7 лет назад

      Good point. Thanks again for the input!

    • @Birol731
      @Birol731 2 года назад

      ​@@OkkiMoeljadi Did you use the mentioned high speed switching diode? Did you get any positive results sir?

    • @OkkiMoeljadi
      @OkkiMoeljadi  2 года назад +1

      @@Birol731 I did use high speed diodes.

  • @spiritresonancejv
    @spiritresonancejv 7 лет назад +1

    you lost the high frequency receivers! you have to use both wireless power and cap discharge.

    • @OkkiMoeljadi
      @OkkiMoeljadi  7 лет назад +1

      Yes, I will try your suggestion. Thanks man.

  • @mykedoes4099
    @mykedoes4099 7 лет назад

    very nice

  • @fredieevangelista4435
    @fredieevangelista4435 3 года назад

    perfect

  • @filigenzilab9613
    @filigenzilab9613 4 года назад +1

    Did it actually somehow charge itself?

    • @OkkiMoeljadi
      @OkkiMoeljadi  4 года назад +1

      No, unfortunately not.

    • @filigenzilab9613
      @filigenzilab9613 4 года назад +1

      @@OkkiMoeljadi Sorry, let's just say I'm rather desperate for finding a new source of energy, my goal is radiant energy.

    • @OkkiMoeljadi
      @OkkiMoeljadi  4 года назад +3

      If you want free-energy, you'd better go for solar or wind. Radiant energy device like the one from Dr. T. Henry Moray is difficult to build. There is not enough information for replication.

    • @filigenzilab9613
      @filigenzilab9613 4 года назад

      Okki Moeljadi thanks

    • @Birol731
      @Birol731 2 года назад

      @@OkkiMoeljadi Is it not possible to build a free energy device according the radiant energy concept? Could you mention the main principle (Back EMF ?) of such devices where cold electricity comes into play, may I ask you?

  • @nukeelda
    @nukeelda 7 лет назад

    oki try to connect caduceus coil in some circuit you should get scalar wave and also more power...(Dielectricity)

    • @OkkiMoeljadi
      @OkkiMoeljadi  7 лет назад +2

      At the moment I don't have any caduceus coil. I will try to build one and test it. Thanks for commenting.

    • @Birol731
      @Birol731 2 года назад

      Are such non-inductive coils (caduceus or bifilar) necessary to extract the radiant energy from the ambient medium?

  • @AniketKumar-co6px
    @AniketKumar-co6px Год назад

    Were you able to recycle the electricity and recharge the batteries without using any outer power source?

  • @johnkoester7795
    @johnkoester7795 3 года назад

    Will this work for a voice box?

    • @johnkoester7795
      @johnkoester7795 3 года назад

      Also The Voice Box well have low power like 4.2 V

    • @OkkiMoeljadi
      @OkkiMoeljadi  3 года назад

      I don't understand what you mean with voice box.

    • @johnkoester7795
      @johnkoester7795 3 года назад

      @@OkkiMoeljadi like a woody doll I want to make a voice box for mine And is it possible to make a mini version of this? Mine is the woody doll made by Hasbro

  • @obagbemisoyejoseph212
    @obagbemisoyejoseph212 2 года назад

    Battery won't charge

  • @basileok2222
    @basileok2222 4 года назад

    Fake.

  • @ovidius2000
    @ovidius2000 Год назад

    Hm.nice.ButTheLimitationIsTheResistanceOf:SwitchingTranzistorsAndOfTheWire.
    iNeverThoughtAboutThisDesign:TheLoadInSeriesForTheFeedback.
    BecauseTheReturnCurentToRechargeBatteryShouldBeLowAtResonanceIImagineParalelOutputsWouldBeBetter.